Atomic Structure- 1 - JEE MCQ

4l – 2

4l + 2

2l + 2

2n²

8

16

32

4

0.53 Å

1.06 Å

0.17 Å

0.265 Å

5 → 2

4 → 1

2 → 5

3 → 2

1.51 eV

3.4 eV

6.04 eV

13.6 eV

n = 6 to n = 1

n = 5 to n = 4

n = 6 to n = 5

n = 5 to n = 3

The magnitude of the potential energy is double that of its kinetic energy on an average.

The probability density of finding the electron is maximum at the nucleus.

The total energy of the electron is maximum when it is at a distance a₀ from the nucleus

The electron can be found at a distance 2a0 from the nucleus.

8.0 × 10^–26 kg m s^–1

8.0 kg m s^–1

50 kg m s^–1

5.0 × 10^–26 kg m s^–1

4.77

1.06

0.13

2.12

2

6

0

14

 Equation can be used to calculate the change in energy when the electron changes orbit.

Larger the value of n, the larger is the orbit radius.

The negative sign in equation simply means that the energy of electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus.

For n=1, the electron has a more negative energy than it does for n=6 which means that the electron is more loosely bound in the smallest allowed orbit.

6.67 × 10¹⁵

6.67 × 10¹¹

4.42 × 10^–15

4.42 × 10^–18

34

36

38

40

Avogadro discovered a difference between animal and plant cell.

Avogadro made a distinction between electrons and neutrons.

Avogadro made a distinction between atoms and molecules.

Avogadro discovered electrons.

0.40 N and 0.05 N         

0.05 N and 0.35 N           

0.50 N and 0.25 N         

0.40 N and 0.5 N

0.11 mole of I₂                

0.22 mole of I₂                 

0.055 mole of I₂            

0.44 mole of I₂

64.2

51.0            

48.4                       

25.5