JEE Exam  >  JEE Tests  >  Hyperbola - 1 - JEE MCQ

Hyperbola - 1 - JEE MCQ


Test Description

29 Questions MCQ Test - Hyperbola - 1

Hyperbola - 1 for JEE 2024 is part of JEE preparation. The Hyperbola - 1 questions and answers have been prepared according to the JEE exam syllabus.The Hyperbola - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Hyperbola - 1 below.
Solutions of Hyperbola - 1 questions in English are available as part of our course for JEE & Hyperbola - 1 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Hyperbola - 1 | 29 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
Hyperbola - 1 - Question 1

Equation of the common tangent to y2 = 8x and 3x2 - y2 = 3 is

Detailed Solution for Hyperbola - 1 - Question 1

 a = 2 and c2 = a2m2 - b2

Hyperbola - 1 - Question 2

Equation of the chord of the hyperbola 25x2 - 16y2 = 400, which is bisected at the point (6, 2) is

Detailed Solution for Hyperbola - 1 - Question 2

Equation of the chord S1 = S11

1 Crore+ students have signed up on EduRev. Have you? Download the App
Hyperbola - 1 - Question 3

The equation of the transverse and conjugate axes of a hyperbola are respectively x + 2y – 3 = 0, 2x – y + 4 = 0 and their respective lengths are √2 and 2/√3. The equation of the hyperbola is

Detailed Solution for Hyperbola - 1 - Question 3

Equation of the hyperbola is 

Where a1x + b1y + c1 = 0, b1x - a1y + c2 = 0 are conjugate and transverse axes respectively and a, b are lengths of semitransverse and semiconjugate axes respectively.

Hyperbola - 1 - Question 4

A hyperbola, having the transverse axis of length 2 sin θ, is confocal with the ellipse 3x2 + 4y2 = 12. Then its equation is:

Detailed Solution for Hyperbola - 1 - Question 4

The given ellipse is 

Hence, the eccentricity  e1, of the hyperbola  is given by
1 = e1 sinθ ⇒ e1 = cosec θ ⇒ b2 = sin2θ (cosec2θ - 1) = cos2θ

Hyperbola - 1 - Question 5

The number of tangents and normals to the hyperbola  of the slope 1 is

Detailed Solution for Hyperbola - 1 - Question 5

Equation of tangents and normal with slope 'm' will be 

Hyperbola - 1 - Question 6


Detailed Solution for Hyperbola - 1 - Question 6


Hyperbola - 1 - Question 7

If (4, 0) and (–4, 0) be the vertices and (6, 0) and (–6, 0) be the foci of a hyperbola, then its eccentricity is-

Detailed Solution for Hyperbola - 1 - Question 7


Hyperbola - 1 - Question 8

If centre, vertex & focus of hyperbola are (2, 0) (4, 0) & (8, 0) then length of latus rectum

Detailed Solution for Hyperbola - 1 - Question 8


Hyperbola - 1 - Question 9

Consider the set of hyperbola xy = k, k ∈ R. Let e1 and e2 be the eccentricities when k = 16 and k = 25 respectively then the value of e12 – e22 equals -

Detailed Solution for Hyperbola - 1 - Question 9

These both are rectangular hyperbola

So e1 = e2 = √2

Hence e12 – e22 = 0

Hyperbola - 1 - Question 10


Detailed Solution for Hyperbola - 1 - Question 10


Hyperbola - 1 - Question 11


Detailed Solution for Hyperbola - 1 - Question 11


Hyperbola - 1 - Question 12

A rectangular hyperbola whose centre is C is cut by any circle of radius r in four points P, Q, R and S. then CP2 + CQ2 + CR2 + CS2 is equal to -

Detailed Solution for Hyperbola - 1 - Question 12


Hyperbola - 1 - Question 13

PM and PN are the perpendiculars from any point on a rectangular hyperbola to its asymptotes. If Q divides MN in the ratio 3 : 1, then the locus of Q is -

Detailed Solution for Hyperbola - 1 - Question 13


Hyperbola - 1 - Question 14


Detailed Solution for Hyperbola - 1 - Question 14


Hyperbola - 1 - Question 15

A common tangent to 9x2 – 16y2 = 144 and x2 + y2 = 9 is -

Detailed Solution for Hyperbola - 1 - Question 15


Hyperbola - 1 - Question 16


Detailed Solution for Hyperbola - 1 - Question 16

Hyperbola - 1 - Question 17


Detailed Solution for Hyperbola - 1 - Question 17


Hyperbola - 1 - Question 18


Detailed Solution for Hyperbola - 1 - Question 18





Hyperbola - 1 - Question 19


Detailed Solution for Hyperbola - 1 - Question 19

Hyperbola - 1 - Question 20

From any point on a hyperbola xy = c2 tangents are drawn to another hyperbola xy = a2 which has the same asymptotes. Then the chord of contact cuts off a constant area from the asymptotes:

Detailed Solution for Hyperbola - 1 - Question 20

Hyperbola - 1 - Question 21


Detailed Solution for Hyperbola - 1 - Question 21


Hyperbola - 1 - Question 22

A point P moves in such a way that the sum of the slopes of the normals drawn from itto the hyperbola xy = 4 is equal to the sum of the ordinates of feet of the normals. The locus of P is a parabola x2 = 4y. Then the least distance of this parabola from the circle x2 – y2 – 24x + 128 = 0 is -

Detailed Solution for Hyperbola - 1 - Question 22


Hyperbola - 1 - Question 23


Detailed Solution for Hyperbola - 1 - Question 23

Hyperbola - 1 - Question 24

Let ax + by = 1 be a chord of the curve 3x2 – y2 – 2x + 4y = 0 intersecting the curve at the points A and B such that AB subtends a right angle at the origin O. If the triangle OAB is isosceles then the area of Δ cannot exceed

Detailed Solution for Hyperbola - 1 - Question 24


Hyperbola - 1 - Question 25

The distance between the directrices of the hyperbola x = 8 sec θ, y = 8 tan θ is-

Detailed Solution for Hyperbola - 1 - Question 25


Hyperbola - 1 - Question 26

If xy = m2 – 9 be a rectangular hyperbola whose branches lie only in the second and fourth quadrant, then -

Detailed Solution for Hyperbola - 1 - Question 26


Hyperbola - 1 - Question 27


Detailed Solution for Hyperbola - 1 - Question 27


Hyperbola - 1 - Question 28

The product of the lengths of perpendiculars drawn from any point on the hyperbola x2 – 2y2 – 2 = 0 to its asymptotes, is -

Detailed Solution for Hyperbola - 1 - Question 28


Hyperbola - 1 - Question 29

Conjugate hyperbola of hyperbola 2x2 – 3y2 = – 6 is :

Detailed Solution for Hyperbola - 1 - Question 29


Information about Hyperbola - 1 Page
In this test you can find the Exam questions for Hyperbola - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for Hyperbola - 1, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE