α = (4n + 1) π – tan –1 2

α = (4n + 2) π – tan –1 2

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JEE Exam > JEE Tests > Vector Algebra - 1 - JEE MCQ

Vector Algebra - 1 - JEE MCQ

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30 Questions MCQ Test - Vector Algebra - 1

Vector Algebra - 1 for JEE 2024 is part of JEE preparation. The Vector Algebra - 1 questions and answers have been prepared according to the JEE exam syllabus.The Vector Algebra - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Vector Algebra - 1 below.

Solutions of Vector Algebra - 1 questions in English are available as part of our course for JEE & Vector Algebra - 1 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Vector Algebra - 1 | 30 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions

Vector Algebra - 1 - Question 1

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If P₁(x₁, y₁, z₁) and P₂(x₂, y₂, z₂) are any two points, then the vector joining P1 and P2is the vector P1P2. Magnitude of the vector

Detailed Solution for Vector Algebra - 1 - Question 1

If P₁(x₁, y₁, z₁) and P₂(x₂, y₂, z₂) are any two points, then the vector joining P1 and P2is the vector P1P2, then ;

Vector Algebra - 1 - Question 2

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Find the scalar and vector components of the vector with initial point (2, 1) and terminal point (– 5, 7).

Detailed Solution for Vector Algebra - 1 - Question 2

The scalar and vector components of the vector with initial point (2, 1) and terminal point (– 5, 7) is given by : (- 5 – 2) i.e. – 7 and (7 – 1) i.e. 6. Therefore, the scalar components are – 7 and 6 .,and vector components are

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Vector Algebra - 1 - Question 3

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Find , if and

A.
17√2
B.
19√3
C.
8√3
D.
19√5

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Vector Algebra - 1 - Question 4

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are any three vectors then the correct expression for distributivity of scalar product over addition is

Detailed Solution for Vector Algebra - 1 - Question 4

are any three vectors then the correct expression for distributivity of scalar product over addition is :

Vector Algebra - 1 - Question 5

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Vector equation of the line 6x – 2 = 3y + 1 = 2z – 2 is :

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Vector Algebra - 1 - Question 6

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A.
2p²
B.
p²
C.
p²/2
D.
None of these

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Vector Algebra - 1 - Question 7

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A.
real and equal roots
B.
real unequal roots
C.
unreal roots
D.
both roots real and positive

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Vector Algebra - 1 - Question 8

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Vector Algebra - 1 - Question 9

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Vector Algebra - 1 - Question 10

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Vector Algebra - 1 - Question 11

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A.
4
B.
–4
C.
2
D.
–2

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Vector Algebra - 1 - Question 12

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A. 1125
B. ERROR
C. ERROR
D. ERROR

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Vector Algebra - 1 - Question 13

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A. 48
B. ERROR
C. ERROR
D. ERROR

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Vector Algebra - 1 - Question 14

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A.
21/25
B.
1/3
C.
7/13
D.
21/5

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Vector Algebra - 1 - Question 15

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A.
11
B.
13
C.
15
D.
17

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Vector Algebra - 1 - Question 16

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Detailed Solution for Vector Algebra - 1 - Question 16

Vector Algebra - 1 - Question 17

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A.
for no real value of a
B.
for all real values of a
C.
for one real value of a
D.
for two real values of a

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Vector Algebra - 1 - Question 18

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A.
1
B.
2
C.
3
D.
None of these

Detailed Solution for Vector Algebra - 1 - Question 18

Vector Algebra - 1 - Question 19

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A.
16
B.
18
C.
19
D.
20

Detailed Solution for Vector Algebra - 1 - Question 19

Vector Algebra - 1 - Question 20

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A.
32
B.
12
C.
50
D.
16

Detailed Solution for Vector Algebra - 1 - Question 20

Vector Algebra - 1 - Question 21

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Detailed Solution for Vector Algebra - 1 - Question 21

Vector Algebra - 1 - Question 22

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A.
(0, 0)
B.
(1, –1)
C.
(–1, 1)
D.
(1, 1)

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Vector Algebra - 1 - Question 23

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Vector Algebra - 1 - Question 24

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A.
α = 1, β = –1
B.
α = 1, β = ±1
C.
α = –1, β = ±1
D.
α = ±1, β = 1

Detailed Solution for Vector Algebra - 1 - Question 24

Vector Algebra - 1 - Question 25

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A.
2
B.
3
C.
4
D.
9

Detailed Solution for Vector Algebra - 1 - Question 25

Vector Algebra - 1 - Question 26

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Vector Algebra - 1 - Question 27

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Vector Algebra - 1 - Question 28

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Detailed Solution for Vector Algebra - 1 - Question 28

Vector Algebra - 1 - Question 29

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A.
α = (4n + 1) π – tan^–1 2
B.
α = (4n + 2) π – tan^–1 2
C.
α = (4n + 1) π + tan^–1 2
D.
α= (4n + 2) π + tan^–1 2

Detailed Solution for Vector Algebra - 1 - Question 29

Vector Algebra - 1 - Question 30

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A.
5, –1, 4
B.
5, –1, 4√2
C.
–1, –5, 4√2
D.
none of these

Detailed Solution for Vector Algebra - 1 - Question 30

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