SEBI Grade A (IT) Mock Test - 2 Free Online Test 2026

The Correct answer is 'Option 3.'

Key Points

• Part C of the sentence i.e. 'are increasing steadily' is erroneous.
  • The subject of the sentence is "the number of people," which is singular.
  • The verb in the sentence 'has been' singular to agree with the subject. "Are increasing" is plural and does not agree with the singular subject.
  • Hence, The correct answer is 'C'
• The correct answer is " A recent study has shown that the number of people opting for online banking has been increasing steadily over the past few years."

Additional Information

• Option 1: "A recent study has shown that" - This part is grammatically correct.
• Option 2: "the number of people opting for online banking" - This part is grammatically correct.
• Option 4: "over the past few years" - This part is grammatically correct.

The correct answer is 'challenges'.

Key Points

• Challenges is the most appropriate word for the given blank.
• Challenges mean something new and difficult that forces you to make a lot of effort.
  • Example- Are you prepared for the challenges ahead?
• Problems a thing that is difficult to deal with or to understand.
• Investigations the action of investigating something or someone; formal or systematic examination or research.
• Obstacles are something that makes it difficult for you to do something or go somewhere.
• Hence, the correct answer is option 1.

Given:

I. x² - 27x + 182 = 0

II. y² – 28y + 196 = 0

Calculation:

I. x² - 27x + 182 = 0

⇒ x² – 13x – 14x + 182 = 0

⇒ x(x – 13) – 14(x – 14)= 0

⇒ (x – 13)(x – 14) = 0

⇒ x = 13, 14

II. y² – 28y + 196 = 0

⇒ y² – 14y – 14y + 196 = 0

⇒ y(y – 14) – 14(y – 14) =0

⇒ (y – 14)(y – 14) = 0

⇒ y = 14, 14

When we compared the values of ‘x’ and ‘y’ in the table above, we found that there are TWO relations between X and Y i.e. < and =. So, a relation between x and y is “x ≤ y”.

∴ After comparison, for all the values of x and y the relation is “x ≤ y”.

Calculations:

From I,

6x² + (1/2) = (7/2)x

⇒ 12x² - 7x+ 1 = 0

⇒ 12x² - 4x - 3x + 1 = 0

⇒ 4x(3x - 1) - 1(3x - 1) = 0

⇒ (4x - 1)(3x - 1) = 0

Taking,

⇒ 3x - 1 = 0 or 4x - 1 = 0

⇒ x = 1/3 or x = 1/4

From II,

12y² + 2 = 10y

⇒ 12y² - 10y + 2 = 0

⇒ 12y² - 6y - 4y + 2 = 0

⇒ 6y(2y - 1) - 2(2y - 1) = 0

Taking,

⇒ 2y - 1 = 0 or 6y - 2 = 0

⇒ y = 1/2 or y = 1/3

Comparison between x and y (via Tabulation):

​∴ x ≤ y.

Calculation:

Let x be the total number of population

Total number of population = (21/100)x – (15/100)x = 2184

⇒ (6/100)x = 2184

⇒ x = (218400/6) = 36400

Let y be the total male population

Total male population = (24/100)y – (18/100)y = 936

⇒ (6/100)y = 936

⇒ y = (93600/6) = 15600

Total number of female population in town C and D = 3900 + 3328 = 7228

∴ The total number of female population in town C and D is 7228.

Calculation:

Let x be the total population

Total number of population = (21/100)x – (15/100)x = 2184

⇒ (6/100)x = 2184

⇒ x = (218400/6) = 36400

Let y be the male population

Total number of male population = (24/100)y – (18/100)y = 936

⇒ (6/100)y = 936

⇒ y = (93600/6) = 15600

As per the given table we can deduce that males in town C is the highest

∴ The town in which the number of male is the highest is C.

Calculation:

Let x be the total population

Total number of population = (21/100)x – (15/100)x = 2184

⇒ (6/100)x = 2184

⇒ x = (218400/6) = 36400

Let y be the male population

Total number of male population = (24/100)y – (18/100)y = 936

⇒ (6/100)y = 936

⇒ y = (93600/6) = 15600

Difference between the number of male and female in the town A = 4212 – 2340 = 1872

Difference between the number of male and female in the town B = 2808 – 2652 = 156

Difference between the number of male and female in the town C = 3900 – 3744 = 156

Difference between the number of male and female in the town D = 3328 – 2496 = 832

Difference between the number of male and female in the town E = 2756 – 2340 = 416

Difference between the number of male and female in the town F = 3952 – 1872 = 2080

∴ The town in which the difference between the number of male and number of female is the highest is F.

Calculation:

Let x be the total population

Total number of population = (21/100)x – (15/100)x = 2184

⇒ (6/100)x = 2184

⇒ x = (218400/6) = 36400

Let y be the male population

Total number of male population = (24/100)y – (18/100)y = 936

⇒ (6/100)y = 936

⇒ y = (93600/6) = 15600

The total number of female in all the six towns = 36400 – 15600 = 20800

⇒ Difference between number of females and males = 20800 – 15600 = 5200

⇒ Required difference = (5200/15600) × 100 = 33.33%

∴ Approximate percentage of the total number of females from all the six towns is 33.33% more than that of the males from all the six towns.

Given:

870, 855, 840, 825, 810, 800

Calculation:

The logic follows here is;

870 - 15 = 855

855 - 15 = 840

840 - 15 = 825

825 - 15 = 810

810 - 15 = 795 ≠ 800

There should be 795 instead of 800.

∴ 800 is the wrong term.

Given:

Ram lent Rs.2.7 lakh amount to Pawan and Pooja

Lent money to Pawan and Pooja in ratio of 5 : 4

Pooja payback its amount after 3 years at 10% annual compound interest

Pawan payback its amount after 3 year at 15% annual compound interest

Concept:

A = P × (1 + R/100)^T

A = Final amount

P = Initial amount

R = Rate of interest

T = Time

Calculation:

Lent money to Pawan and Pooja in ratio of 5 : 4

Lent by Pawan = (5/9) × 270000

⇒ Rs.1,50,000

Lent by Pooja = (4/9) × 270000

⇒ Rs.1,20,000

Pawan payback to Ram = 150000 × (1 + 10/100)³

⇒ 150000 × (11/10) × (11/10) × (11/10)

⇒ Rs.1,99,650

Pooja payback to Ram = 120000 × (1 + 15/100)³

⇒ 120000 × (23/20)³

⇒ 120000 × (23/20) × (23/20) × (23/20)

⇒ Rs.1,82,505

Pawan payback to Ram – Pooja payback to Ram = 199650 – 182505

⇒ Rs.17,145

∴ At the end of time duration the amount received by Ram from Pawan was Rs.17145 more than that received from Pooja.

Persons: Azim, Bindu, Chaitra, Delphin, Eza, Fath, and Gayl

Dresses: Jean, Shirt, Kurta, Skirt, Saree, Salwar and Dhoti

Number of dresses: The number of dresses bought by each of them are in the consecutive multiples of 3. The total number of dresses bought by all people cannot exceed 85.

So, 3, 6, 9, 12, 15, 18 and 21 are the number of dresses bought by them.

1. Either Eza or Gayl bought 12 Skirts.

2. Delphin bought a number of Jeans, which is higher than only Fath.

3. So Fath bought 3 dresses and Delphin bought 6 jeans.

4. The number of Sarees bought is twice the number of Shirts bought.

5. Saree is bought for the second highest number. So, number of Saree is 18 and Shirt is 9.

6. Gayl bought twice the number of dresses of Delphin. So, Case 1 is invalid.

6. Chaithra bought the highest number of dresses but neither bought Saree nor Salwar.

So, the number is 21 and the dress left for it is Kurta.

7. Either Shirt or Dhoti is bought for the lowest number.

As Shirt is already 9, so the number of Dhoti bought is 3.

8. The number of Sarees bought is twice the number of Shirts bought, which is not bought by Azim.

So, he bought 15 salwar.

9. Neither Azim nor Bindu bought 18 dresses.

10. Saree is bought for the second highest number. So, number of Saree is 18 and Shirt is 9.

The final arrangement is,

Everyone except Gayl bought an odd number of dresses, whereas Gayl bought an even number of dresses.

So, Gayl is the odd one out.

Persons: Azim, Bindu, Chaitra, Delphin, Eza, Fath, and Gayl

Dresses: Jean, Shirt, Kurta, Skirt, Saree, Salwar and Dhoti

Number of dresses: The number of dresses bought by each of them are in the consecutive multiples of 3. The total number of dresses bought by all people cannot exceed 85.

So, 3, 6, 9, 12, 15, 18 and 21 are the number of dresses bought by them.

1. Either Eza or Gayl bought 12 Skirts.

2. Delphin bought a number of Jeans, which is higher than only Fath.

3. So Fath bought 3 dresses and Delphin bought 6 jeans.

4. The number of Sarees bought is twice the number of Shirts bought.

5. Saree is bought for the second highest number. So, number of Saree is 18 and Shirt is 9.

6. Gayl bought twice the number of dresses of Delphin. So, Case 1 is invalid.

6. Chaithra bought the highest number of dresses but neither bought Saree nor Salwar.

So, the number is 21 and the dress left for it is Kurta.

7. Either Shirt or Dhoti is bought for the lowest number.

As Shirt is already 9, so the number of Dhoti bought is 3.

8. The number of Sarees bought is twice the number of Shirts bought, which is not bought by Azim.

So, he bought 15 salwar.

9. Neither Azim nor Bindu bought 18 dresses.

10. Saree is bought for the second highest number. So, number of Saree is 18 and Shirt is 9.

The final arrangement is,

So, Azim and Fath bought the third highest and lowest number of dresses respectively.

Given number:- 7125126543456

If all the odd digits are increased by 2, then

Now all the digits are arranged in ascending order from the left end -

2233445667779

The first four digits from the right end are 9, 7, 7, 7 and their sum is 9 + 7 + 7 + 7 = 30

Hence, the correct answer is 30.

The least possible Venn diagram according to the above statement is:

I. All Laptop being Cable is a possibility → False (As only a few Laptops are Cables, hence the possibility of all will be false.)

II. Some Radio being Cable is a possibility → True (Some Radio being Cable is definitely a possibility as no direct relation is given between them.)

III. All Radio are Laptop → False (All Radio being Laptop is a possibility but its not definite.)

Hence, Only II follows is the correct answer.

Given:

Ten persons: M, N, O, P, Q, V, W, X, Y and Z

Five different floors of a building

Two flats: flat-1 and flat-2 from west to east such that flat-1 is to the west of flat-2.

Now,

1) V lives on an odd numbered floor but dose not lives on an even numbered flat.

2) More than one floor is there between the floor of M and the floor on which N lives.

3) U lives to the east of V on the same floor.

4) One floor is there between V who is not on the lowermost floor and the floor on which R lives, both lives on the same flat number.

5) M lives to the west of P and dose not lives on an even numbered floor.

As V cannot be on the lowermost floor thus, CASE 1 gets eliminated

6) O who lives to the North-West of T is not on the fifth floor.

7) Only one floor gap is there between the floor of Q and the floor on which S lives.

8) T is not an immediate neighbour of S. M does not live above Q.

More than one floor is there between the floor of M and the floor on which N lives, also, M lives to the west of P and dose not lives on an even numbered floor.

In CASE 3, there is not a gap of more than one floor between M and N, thus CASE 3 gets eliminated.

In CASE 1(a), we are not getting the exact position of Q and S, but in CASE 2 all the conditions of the question are being fulfilled, thus we have the final arrangement in CASE 2.

Hence, the correct answer is "N".

Given:

Ten persons: M, N, O, P, Q, V, W, X, Y and Z

Five different floors of a building

Two flats: flat-1 and flat-2 from west to east such that flat-1 is to the west of flat-2.

Now,

1) V lives on an odd numbered floor but dose not lives on an even numbered flat.

2) More than one floor is there between the floor of M and the floor on which N lives.

3) U lives to the east of V on the same floor.

4) One floor is there between V who is not on the lowermost floor and the floor on which R lives, both lives on the same flat number.

5) M lives to the west of P and dose not lives on an even numbered floor.

As V cannot be on the lowermost floor thus, CASE 1 gets eliminated

6) O who lives to the North-West of T is not on the fifth floor.

7) Only one floor gap is there between the floor of Q and the floor on which S lives.

8) T is not an immediate neighbour of S. M does not live above Q.

More than one floor is there between the floor of M and the floor on which N lives, also, M lives to the west of P and dose not lives on an even numbered floor.

In CASE 3, there is not a gap of more than one floor between M and N, thus CASE 3 gets eliminated.

In CASE 1(a), we are not getting the exact position of Q and S, but in CASE 2 all the conditions of the question are being fulfilled, thus we have the final arrangement in CASE 2.

Hence, the correct answer is "both V and U".

Given word:- SIGNATURE

Forward Pair - NR, AE, TU

Backward Pair - TR

Thus, there are four such pairs of letters in the word “SIGNATURE” which have as many letters between them as in the English alphabetical series (both in forward and backward directions).

Hence, the correct answer is Four.

Row 1 A, B, C, D, and E are sitting facing south
Row 2 P, Q, R, S, and T are sitting facing north.

1. A sits second from the end.

2.The number of persons sitting to the right of A is equal to the number of persons sitting to the right of Q.

3. D sits Immediate next to the one who is facing Q.

4. One persons sit between D and E, who does not sit next to C.

5. S sits three places away from Q. T sits to the right of S. Hence Case 2.1A, case 2.1 and Case 2 gets eliminated.

6. Two persons sit between R and T. The person who sits opposite to T sits four places away from C. Case 1.1 gets eliminated.

7.B sits to the left of A. At most two person sits right of D. Hence case 1 gets eliminated

Final arrangement

One who faces A is R and One who faces E is T hence two person sits in between them.

Row 1 A, B, C, D, and E are sitting facing south
Row 2 P, Q, R, S, and T are sitting facing north.

1. A sits second from the end.

2.The number of persons sitting to the right of A is equal to the number of persons sitting to the right of Q.

3. D sits Immediate next to the one who is facing Q.

4. One persons sit between D and E, who does not sit next to C.

5. S sits three places away from Q. T sits to the right of S. Hence Case 2.1A, case 2.1 and Case 2 gets eliminated.

6. Two persons sit between R and T. The person who sits opposite to T sits four places away from C. Case 1.1 gets eliminated.

7.B sits to the left of A. At most two person sits right of D. Hence case 1 gets eliminated

Final arrangement

S is sitting immediate left of R.

Row 1 A, B, C, D, and E are sitting facing south
Row 2 P, Q, R, S, and T are sitting facing north.

1. A sits second from the end.

2.The number of persons sitting to the right of A is equal to the number of persons sitting to the right of Q.

3. D sits Immediate next to the one who is facing Q.

4. One persons sit between D and E, who does not sit next to C.

5. S sits three places away from Q. T sits to the right of S. Hence Case 2.1A, case 2.1 and Case 2 gets eliminated.

6. Two persons sit between R and T. The person who sits opposite to T sits four places away from C. Case 1.1 gets eliminated.

7. B sits to the left of A. At most two person sits right of D. Hence case 1 gets eliminated

Final arrangement

After interchanging the position we get

P will be exactly opposite to E when position of E and D interchanged.

The correct option is (1)

INT

Concept:-

The sum() function calculates the sum of a set of values. MYSQL supports the SQL standard integer types INTEGER (or INT) and SMALLINT. INT in MYSQL is an integer data type, which is a whole number. It allows numbers to be written without fractional parts.

SUM(column), returns the sum of the values for the specified column.

For example, MySQL > SELECT SUM(price) FROM INVENTORY; Output is 4608733.00

Key Points

• Use SQL's SUM method if you need to add a set of numbers to your table. If there are no rows in the result set, NULL is returned. One of the categories of aggregate functions, it.
• Multiple Row Functions is another name for aggregate functions. These functions operate on an entire collection of records and give a single value for each column of the records they affect.
• The string data types are CHAR, VARCHAR, BINARY, VARBINARY, BLOB, TEXT, ENUM, and SET.

c) GROUP BY is used to group the result set by one or more columns.

The GROUP BY clause groups rows based on the values in one or more columns and, typically, is used in combination with aggregate functions to return a single result row for each group.

Additional InformationWHERE clause is used to filter the result set of a SELECT, UPDATE, DELETE statement. It is used to specify a condition that rows have to meet in order to be selected or affected.

ORDER BY is used to sort the result set in a specific order. It is used to sort the result set by one or more columns in ascending or descending order.

The FROM clause is used to specify the table or tables from which to retrieve the data and it is usually one of the first clauses in a SELECT statement.

Statement (a): Overloading a function gives the capability to an existing operator to operate on other data types.

This statement is incorrect. Operator overloading is a type of polymorphism in which an operator is overloaded to give a different meaning or user defined meaning. It allows to change the way an operator can work. It gives the capability to an existing operator to operate on other data types.

Statement (b): Inheritance in object-oriented programming provides support to reusability.

This statement is correct. When a class acquires the properties of another class, this is known as inheritance. The class which acquire the properties and method is known as derived class and other one is parent or base class. Inheritance another name for reusability.

Statement (c): When object of a derived class is defined, first the constructor of derived class is executed then constructor of a base class is executed.

This statement is incorrect Constructor is a special member function of class that is automatically executed or called when objects of that class will be created. As when object of derived class is defined, automatically derived class constructor and base class constructor will execute inside them.

Statement (d): Overloading is a type of polymorphism.

This statement is correct. Operator is a type of polymorphism in which an operator is overloaded to give a different meaning or user defined meaning. It allows to change the way an operator can work.

The correct answer is Cybersecurity.

Key Points

• Cryptography is a specialized area of Cybersecurity.
• Cryptography is also defined as the study of secure communications techniques that allow only the sender and intended recipient of a message to view its contents.
• It covers the obfuscation of information in images using techniques such as microdots or merging.
• It is used to protect written documents.
• The main purpose of cryptography appears to be making content and images undecipherable, the true goal of cryptography in an information technology context is to ensure the confidentiality and integrity of any information technology system.

• Queue is data structure which is First in First Out (FIFO) or Last in Last Out (LILO) which means the element which is inserted first comes out first form the queue or the elements inserted last comes out last from the queue
• Stack is data structure which is Last in First Out (LIFO) or First in Last Out (FILO) which means the element which is popped last from stack is pushed first in stack, or element which is pushed first in stack is popped last from stack

Heap

• A heap is a specialized tree-based data structure that satisfies the heap property.
• A heap can be classified into two categories i.e. Max heap and Min heap.
• In a max heap, the keys of parent nodes are always greater than or equal to those of the children and the highest key is in the root node.

The correct answer is option 3.

Key Points

• A firewall is a security device that monitors and controls incoming and outgoing network traffic based on predetermined security rules.
• It acts as a barrier between an untrusted network (like the internet) and a trusted network (like a company's internal network) to prevent unauthorized access to the trusted network.
• Firewalls can be either hardware or software-based and are an essential component of network security.

Additional Information

• Hub: It is a network device that connects multiple devices in a network, but it does not provide any security features.
• Router: It is a network device that directs traffic between networks, but it has limited security features compared to a firewall.
• Bridge: It is a network device that connects two network segments, but it also does not provide any security features.