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CAT Exam  >  CAT Tests  >  Test Level 3: Simple & Compound Interest (September 1) - CAT MCQ

Test Level 3: Simple & Compound Interest (September 1) - CAT MCQ


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30 Questions MCQ Test - Test Level 3: Simple & Compound Interest (September 1)

Test Level 3: Simple & Compound Interest (September 1) for CAT 2024 is part of CAT preparation. The Test Level 3: Simple & Compound Interest (September 1) questions and answers have been prepared according to the CAT exam syllabus.The Test Level 3: Simple & Compound Interest (September 1) MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test Level 3: Simple & Compound Interest (September 1) below.
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Test Level 3: Simple & Compound Interest (September 1) - Question 1
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Mr. Khanna pays 10% pa interest on an amount borrowed and lends this amount at 12% pa. If at the end of the year, he earns Rs. 2.4 crore as simple interest in the transaction, then what is the sum transacted?

Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 1

Net rate = 2%
SI at 2% of money transacted = 
x = 120 crore

Test Level 3: Simple & Compound Interest (September 1) - Question 2
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Amit invested two equal sums of Rs. 5000 for 2 years at 10%, one at compound interest payable yearly and the other at compound interest payable half-yearly. Find the difference between amounts that he will get at the end of 2 years.

Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 2

Amounts at compound interest yearly = 
Amounts at compound interest half yearly = 
Difference between amounts Amit will get = Rs. 5000 
= Rs. 5000(1.2155 - 1.21)
= Rs. 27.50

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Test Level 3: Simple & Compound Interest (September 1) - Question 3
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A certain sum of money lent at simple interest amounts to Rs. 1,300 in 4 years and Rs. 1,525 in 7 years. Find the sum.

Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 3

Let principal = P
Amount after 4 years = Rs. 1300
Amount after 7 years = Rs. 1525
Simple interest for 3 years = 1525 - 1300 = Rs. 225
Simple interest for 1 year = 225/3 = Rs. 75
Simple interest for 4 years = 4 × 75 = Rs. 300
Principal = Amount - SI
P = 1300 - 300 = Rs. 1000

Test Level 3: Simple & Compound Interest (September 1) - Question 4
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A man borrows a certain sum at 20% compounded annually and lends it at 25% simple interest. What is the maximum number of years for which he can wait, so that he does not bear any loss?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 4

 Let principal = P
Required time = t
Amount at 25% simple interest = P + (P × 25 × t)/100
Amount at 20% compound interest = 
According to the question,

If he waits up to 4 years, he will bear a loss.
So, he can wait for up to 3 years.

Test Level 3: Simple & Compound Interest (September 1) - Question 5
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Vivek purchased a bike costing Rs. 51,250 under finance with a down payment (which has to be paid at the beginning) of Rs. 9,575. Next month onwards, he has to pay Rs. 1,300 every month up to 36 months to clear the remaining payment. What is the rate of interest under simple interest?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 5

Cost of bike = Rs. 51,250
Down payment = Rs. 9,575
Monthly installment = Rs. 1300 for 36 Months
Amount paid for total installments = 36 × 1300 = Rs. 46,800
Total Amount paid = Rs. 46,800 + Rs. 9,575 = Rs. 56, 375
So, S. I. = Rs. 56,375 - Rs. 51,250 = Rs. 5125
Now, 
R = 10%

Test Level 3: Simple & Compound Interest (September 1) - Question 6
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Raghav has to repay a loan of Rs. 12,820 in three annual instalments. The first instalment is to be half of the second and one-third of the third. If the compound interest is calculated annually at a rate of 10%, then find the value of the third instalment that Raghav has to pay.
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 6

Given, initial amount = Rs. 12,820
Amount to be paid after one year = Rs. 12,820 + Rs. 1282 = Rs.14,102.
If Raghav`s first year instalment is `Rs. a`, then the principal for second year = Rs. (14,102 - a).
Amount to be paid after two years = Rs. 11/10 x (14,102 - a) = Rs. (15,512.2 - 1.1a)
If Raghav's second year instalment is 'Rs. 2a', then principal for third year = Rs. ( 15,512.2 - 1.1a - 2a) = Rs. (15,512.2 - 3.1a)
∴ Amount to be paid after three years = Rs. 11/10 x  (15,512.2 - 3.1a) = Rs. (17,063.42 - 3.41a)
Also, amount to be paid in third year = Rs. 3a
⇒ 17,063.42 - 3.41a = 3a
6.41a = 17063.42
a = 2662
Thus, third instalment = Rs. 3a = Rs. 7986

Test Level 3: Simple & Compound Interest (September 1) - Question 7
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For a loan of Rs. 32,400 that I gave to my friend Anil, he promised to pay me the amount in monthly installments, starting with a certain amount and increasing the installments every month with a fixed amount of Rs. 100. In this way, he could clear off the loan in 24 months. How much was the first installment?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 7

Let the 1st installment be Rs. x.
According to the given condition, = Rs. 32,400
2x + 2300 = Rs. 2700
2x = Rs. 400
x = Rs. 200

Test Level 3: Simple & Compound Interest (September 1) - Question 8
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A sum of Rs. 9400 is divided into three parts, such that the simple interests accrued on these sums for three, four and five years are equal. Find the amount deposited for five years.
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 8

Let the amount deposited for 4 years be 15d.
Let the rate of deposited per annum be i.
Let the amount deposited for 3 years be a.
Let the amount deposited for 5 years be c.
So, a x 3 x i = 15 x d x 4 x i
Or, a = 20d ... (i)
Also,
c x 5i = 15d x 4 x i
Or, c = 12d ... (ii)
Now, a + 15d + c = Rs. 9400 ... (iii)
20d + 15d + 12d = 9400
d = 200
Plugging in values of a, and c from equations (i) and (ii) into equation (iii), and solving for d, we get d = Rs. 200
Thus, amount deposited for 5 years = 12d = 12 x Rs. 200 = Rs. 2400

Test Level 3: Simple & Compound Interest (September 1) - Question 9
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If a person repaid Rs. 22,500 after 10 years of borrowing a loan, at 10% per annum simple interest  find out what amount did he take as a loan?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 9

At 10% simple interest per year, the amount would double in 10 years. Thus, the original borrowin would be 22500/2 = 11250.

Test Level 3: Simple & Compound Interest (September 1) - Question 10
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Mr. X , a very industrious person, wants to establish his own unit. For this he needs an instant loan of Rs. 5,00,000 and, every five years he requires an additional loan of Rs.100,000. If he had to clear all his outstandings in 20 years, and he repays the principal of the first loan equally over the 20 years, find what amount he would have to pay as interest on his initial borrowing if the rate of interest is 10% p.a. Simple Interest.
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 10

The simple interest would be defined on the basis of the sum of the AP. 50000 + 47500 + 45000 + … + 2500 = 525000. 

Test Level 3: Simple & Compound Interest (September 1) - Question 11
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A and B work together for 8 days to complete a piece of work and B and C work together for 12 days to complete the same work. C alone can complete the work in 24 days and A is twice as efficient as B. How much time does it take to complete the work if all the three work together?  
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 11

1/A + 1/B = 1/8 ... (i)
1/B + 1/C = 1/12 ... (ii)
1/C = 1/24 ... (iii)
On solving, we get A = 12, B = 24 and C = 24
Therefore, 1/A + 1/B + 1/C = 1/6
All three together can complete the work in 6 days.

Test Level 3: Simple & Compound Interest (September 1) - Question 12
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A, B and C can do a piece of work in 20, 30 and 40 days, respectively. A and C started the work and B joined 4 days later. A left 8 days before the completion of work and C was also absent for 5 days in between. How many days will it take for the work to be completed?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 12

Assume that it takes 'd' days for the work to be completed.
A works for (d - 8) days,
B works for (d - 4) days,
C works for (d - 5) days.

6d - 48 + 4d - 16 + 3d - 15 = 120
13d = 199
d =  days

Test Level 3: Simple & Compound Interest (September 1) - Question 13
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A group of employees is working on a project. If 10 more employees join them, then the project will be completed in 2/3 of the time. If the work has to be completed in 1/3 of the time, then how many more employees have to join?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 13

Let M be number of employees present initially and d be the number of days taken by M employees to complete the work.
Md = (M + 10) 2/3 d
Solving, M = 20 
To complete the work in 1/3 of the time, the number of employees should be 3 times (60).
So, 40 more employees have to join.

Test Level 3: Simple & Compound Interest (September 1) - Question 14
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A can do a piece of work in 20 days, working 8 hours a day and B can do the same work in 30 days, working 10 hours a day. If both A and B work together for 5 hours a day, how many days will they take to complete the same work?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 14

A needs 160 hours and B needs 300 hours to complete the work individually.
So, time required by A and B together


Number of days required when A and B work 5 hours a day 

Test Level 3: Simple & Compound Interest (September 1) - Question 15
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A and B together can complete a piece of work in 25 days. B and C together can complete the same work in 30 days. How many days would A and C take to complete the work?  
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 15

A and B can do 1/25 th of the work in 1 day.
B and C can do 1/30th of the work in 1 day.
From this, we cannot say anything about A and C.

Test Level 3: Simple & Compound Interest (September 1) - Question 16
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The amount of work done by a man on nth day after starting a piece of work is n times the amount of work that can be done on the first day. If 8 men start the work, it can be completed in 10 days. How many men should work if the work has to be completed in 4 days?  
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 16

Let each of the 8 men do x units of work on the first day.
Total work done = 8(x + 2x + 3x + 4x + 5x + 6x + 7x + 8x + 9x + 10x) = 440x
To do the same 440x units work in 4 days, let n men be required.
So, n(x + 2x + 3x + 4x) = 440x
⇒ n = 44

Test Level 3: Simple & Compound Interest (September 1) - Question 17
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A man started a piece of work on the first day. The second day, one more person joined him. The next day, one more person joined. Everyday, one new person joined until the work got completed. If the work was completed in 15 days, how many days would 10 men take to complete the same work, given that they worked regularly and efficiency of all men is the same?  
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 17

Let one day work of a man = x units
∵1st day = x
2nd day = 2x
……………..
……………
15th day = 15x
Total work done in 15 days = x + 2x + 3x + ... + 15x = 120x 
So, time taken to complete 120x work by 10 men is  120x/10x = 12 days

Test Level 3: Simple & Compound Interest (September 1) - Question 18
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If 300 men could do a piece of work in 16 days, then how many men would do 1/4 of the same work in 15 days?  
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 18

300 men do 1 work in 16 days.
So, M1 = 300, D1 = 16, W1 = 1
Let y men do 1/4 work in 15 days.
Then, M2 = y, D2 = 15, W2 = 1/4
According to the formula:
M1D1W2 = M2D2W1
300 x 16 x (1/4) = y x 15 x 1

Test Level 3: Simple & Compound Interest (September 1) - Question 19
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A alone can finish a piece of work in 12 days and B alone can do it in 18 days. If they work together and finish it, then out of total wages of Rs. 50, A will get  
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 19

A can finish the work in 12 days.
B can finish the work in 18 days.
∴ Ratio of their one-day work = 1/12 : 1/18 = 3 : 2
∴ If they work together and finish the work, they get the assigned amount in the ratio 3 : 2. That is, A will get Rs. 30 and B will get Rs. 20 (∵ total amount = Rs. 50).

Test Level 3: Simple & Compound Interest (September 1) - Question 20
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Two inlet pipes A and B can fill a tank in 24 hours and 30 hours, respectively. An outlet pipe C can empty the tank in 60 hours. The pipe C is continuously open and the pipes A and B work on alternate hours, starting with A. How much time does it take to fill the tank?  
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 20

In the first hour, A and C operate 

In the second hour, B and C operate 

Let V be the total volume of the tank. 
Time taken to fill 5/10th of the total volume of tank = 2 hours
Time taken to fill the total volume of the tank 

So, in 48 hours, the tank will be full.

Test Level 3: Simple & Compound Interest (September 1) - Question 21
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Directions: Read the information carefully and answer the question.
Three companies L, M and N participated for campus recruitment in college Z. All the three companies selected an equal number of candidates. There were 60 candidates who were selected by L and M both. The number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M. There were 28 candidates who got placed in all the 3 companies. This number was 50% less than the number of candidates selected by both L and N. The total number of candidates selected by both L and N was 91.88% less than total number of candidates selected by all the three company.

Q. How many candidates were selected by company L?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 21

The Venn diagram for the given problem is as given in figure 1.
Firstly, there are 28 candidates placed in all the 3 companies.
So, 28 goes into the common region.
Then, 60 candidates were selected by both L and M.
So, 60 - 28 = 32 goes into the region common only to L and M.
Now, number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M.
Thus, number of candidates selected by both M and N = 2 × 60 - 68 = 120 - 68 = 52
Thus, 52 - 28 = 24 goes into the region common to both M and N.
Now, number of candidates selected by both L and N = 2 × 28 = 56
Thus, 56 - 28 = 28 goes into the region common to both L and N.
Now, let the total number of candidates selected = T
Number of candidates selected by both L and N = 56
So, 56 = T(1 - 0.9188) or T = 690
As equal number of candidates were selected by the 3 companies, the number of candidates in each company = 690/3 = 230
Thus, 230 - (32 + 28 + 28) = 230 - 88 = 142 goes into the region exclusive to L.
230 - (28 + 28 + 24) = 230 - 80 = 150 goes into the region exclusive to N.
230 - (32 + 28 + 24) = 230 - 84 = 146 goes into the region exclusive to M.
So, number of candidates selected by company L = 230
Hence, answer option (2) is correct.

Test Level 3: Simple & Compound Interest (September 1) - Question 22
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Directions: Read the information carefully and answer the question.
Three companies L, M and N participated for campus recruitment in college Z. All the three companies selected an equal number of candidates. There were 60 candidates who were selected by L and M both. The number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M. There were 28 candidates who got placed in all the 3 companies. This number was 50% less than the number of candidates selected by both L and N. The total number of candidates selected by both L and N was 91.88% less than total number of candidates selected by all the three company.

Q. Find the total number of candidates who were selected only by company L or M.
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 22

The Venn diagram for the given problem is as given in figure 1.
Firstly, there are 28 candidates placed in all the 3 companies.
So, 28 goes into the common region.
Then, 60 candidates were selected by both L and M.
So, 60 - 28 = 32 goes into the region common only to L and M.
Now, number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M.
Thus, number of candidates selected by both M and N = 2 × 60 - 68 = 120 - 68 = 52
Thus, 52 - 28 = 24 goes into the region common to both M and N.
Now, number of candidates selected by both L and N = 2 × 28 = 56
Thus, 56 - 28 = 28 goes into the region common to both L and N.
Now, let the total number of candidates selected = T
Number of candidates selected by both L and N = 56
So, 56 = T(1 - 0.9188) or T = 690
As equal number of candidates were selected by the 3 companies, the number of candidates in each company = 690/3 = 230
Thus, 230 - (32 + 28 + 28) = 230 - 88 = 142 goes into the region exclusive to L.
230 - (28 + 28 + 24) = 230 - 80 = 150 goes into the region exclusive to N.
230 - (32 + 28 + 24) = 230 - 84 = 146 goes into the region exclusive to M.
From the Venn diagram, it is clear that number of candidates selected by only L or M = Number of candidates selected by L or M and not by N = 142 + 32 + 146 = 320
Hence, answer option (3) is correct.

Test Level 3: Simple & Compound Interest (September 1) - Question 23
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Directions: Read the information carefully and answer the question.
Three companies L, M and N participated for campus recruitment in college Z. All the three companies selected an equal number of candidates. There were 60 candidates who were selected by L and M both. The number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M. There were 28 candidates who got placed in all the 3 companies. This number was 50% less than the number of candidates selected by both L and N. The total number of candidates selected by both L and N was 91.88% less than total number of candidates selected by all the three company.

Q. What is the total number of candidates who were placed in exactly two companies only?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 23

The Venn diagram for the given problem is as given in figure 1.
Firstly, there are 28 candidates placed in all the 3 companies.
So, 28 goes into the common region.
Then, 60 candidates were selected by both L and M.
So, 60 - 28 = 32 goes into the region common only to L and M.
Now, number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M.
Thus, number of candidates selected by both M and N = 2 × 60 - 68 = 120 - 68 = 52
Thus, 52 - 28 = 24 goes into the region common to both M and N.
Now, number of candidates selected by both L and N = 2 × 28 = 56
Thus, 56 - 28 = 28 goes into the region common to both L and N.
Now, let the total number of candidates selected = T
Number of candidates selected by both L and N = 56
So, 56 = T(1 - 0.9188) or T = 690
As equal number of candidates were selected by the 3 companies, the number of candidates in each company = 690/3 = 230
Thus, 230 - (32 + 28 + 28) = 230 - 88 = 142 goes into the region exclusive to L.
230 - (28 + 28 + 24) = 230 - 80 = 150 goes into the region exclusive to N.
230 - (32 + 28 + 24) = 230 - 84 = 146 goes into the region exclusive to M.
From the Venn diagram, it is clear that total number of candidates placed in exactly 2 companies only = 32 + 28 + 24 = 84
Hence, answer option (3) is correct.

Test Level 3: Simple & Compound Interest (September 1) - Question 24
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Directions: Study the given information and answer the following question.
A talent hunt competition was being conducted by a TV Channel. As they were expecting variations in the type of talent, they appointed 7 different judges: Karan Johar, Geeta Basra, Himesh Reshamia, Anu Malik, Mika, Farah Khan and Pritam. In the first round, 6 contestants namely Rahul, Reema, Ram, Rita, Raju and Riya appeared before the panel for selection. Accidentally, the organisers forgot to mention the marks for which they were to be evaluated; therefore, each of the judges evaluated the contestants on a different total marks. The total marks for which the judges evaluated all the contestant were 100, 150, 50, 125, 150, 50 and 75 in the exact order of judges as mentioned above, respectively. The table mentioned below presents the percentage score of the contestants by each of the judges.

Q. What is the ratio of the total marks obtained by Rita from Karan Johar, Geeta Basra and Anu Malik to the total marks obtained by Rahul from Pritam, Mika and Farah Khan?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 24

Marks obtained by Rita from Karan Johar, Geeta Basra and Anu Malik = 88% of 100 + 70% of 150 + 60% of 125 = 88 + 105 + 75 = 268
Marks obtained by Rahul from Pritam, Mika and Farah Khan = 88% of 75 + 88% of 150 + 68% of 50 = 66 + 132 + 34 = 232
Required ratio = 268 : 232 = 67 : 58

Test Level 3: Simple & Compound Interest (September 1) - Question 25
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Directions: Study the given information and answer the following question.
A talent hunt competition was being conducted by a TV Channel. As they were expecting variations in the type of talent, they appointed 7 different judges: Karan Johar, Geeta Basra, Himesh Reshamia, Anu Malik, Mika, Farah Khan and Pritam. In the first round, 6 contestants namely Rahul, Reema, Ram, Rita, Raju and Riya appeared before the panel for selection. Accidentally, the organisers forgot to mention the marks for which they were to be evaluated; therefore, each of the judges evaluated the contestants on a different total marks. The total marks for which the judges evaluated all the contestant were 100, 150, 50, 125, 150, 50 and 75 in the exact order of judges as mentioned above, respectively. The table mentioned below presents the percentage score of the contestants by each of the judges.

Q. If the total marks given by Geeta and Pritam to Riya are one mark less than marks granted to Rahul by Geeta and Himesh, then what is the overall percentage of marks obtained by Riya?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 25

From the table we can find out that the percentage of marks obtained by Riya from Geeta and Pritam is missing.
So, assume the marks obtained by Riya from these two judges to be x + y.
Marks obtained by Rahul from Geeta and Himesh = 92% of 150 + 94% of 50 = 138 + 47 = 185
As per the statement, x + y + 1 = 185, so x + y = 184 
Total marks obtained by Riya = 82% of 100 + x + 88% 50 + 80% of 125 + 70% of 150 + 86% of 50 + y
= 82 + x + 44 + 100 + 105 + 43 + y
= 374 + x + y
= 374 + 184
= 558
Therefore, overall percentage of marks obtained by Riya = (558 x 100)/700 = 79.71%

Test Level 3: Simple & Compound Interest (September 1) - Question 26
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Directions: Study the given information carefully to answer the question that follows:
In a college, there are 2400 students studying in different branches - Electronics, Mechanical, Electrical, IT, and Computer Science. The ratio of the number of boys to that of girls is 5 : 3. 12% boys study in the Electronics branch. 24% girls study in the Mechanical branch. The ratio of the number of boys to that of girls in the Electronics branch is 6 : 11. One-ninth of girls study in the Computer Science branch. 42% boys study in the IT branch. The number of girls studying in the IT branch is 10% of the boys studying in the same branch. The remaining girls study in the Electrical branch. The total number of students studying in the Computer Science branch is 285. 22% boys study in the Electrical branch. The remaining boys study in the Mechanical branch.

Q. What percentage of the total girls in the college do the girls in the IT branch constitute?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 26

Total number of students = 2400
Ratio of the number of boys to that of girls = 5 : 3
Number of boys = (5/8) × 2400 = 1500
Number of girls = (3/8) × 2400 = 900
42% boys studying in the IT branch = 42% of 1500 = 630
The number of girls in studying IT is 10% of the boys studying in the same branch = 10% of 630 = 63
Suppose x% of the total girls in the college are studying in the IT branch.
63 = x% of 900
x = 7

Test Level 3: Simple & Compound Interest (September 1) - Question 27
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Directions: Study the given information carefully to answer the question that follows:
In a college, there are 2400 students studying in different branches - Electronics, Mechanical, Electrical, IT, and Computer Science. The ratio of the number of boys to that of girls is 5 : 3. 12% boys study in the Electronics branch. 24% girls study in the Mechanical branch. The ratio of the number of boys to that of girls in the Electronics branch is 6 : 11. One-ninth of girls study in the Computer Science branch. 42% boys study in the IT branch. The number of girls studying in the IT branch is 10% of the boys studying in the same branch. The remaining girls study in the Electrical branch. The total number of students studying in the Computer Science branch is 285. 22% boys study in the Electrical branch. The remaining boys study in the Mechanical branch.

Q. The number of boys studying in the Mechanical branch is approximately what percentage of the total number of boys in the college?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 27

Total number of students = 2400
Ratio of the number of boys to that of girls = 5 : 3
Number of boys = (5/8) × 2400 = 1500
Number of girls = (3/8) × 2400 = 900
12% boys studying in Electronics = 12% of 1500 = 180
24% girls studying in Mechanical = 24% of 900 = 216
Ratio of the number of boys to that of girls in Electronics = 6 : 11
Number of girls studying in Electronics = 11 × 30 = 330 [Number of boys studying in Electronics = 180]
One-ninth of girls studying in Computer Science = (1/9) × (900) = 100
42% boys studying in IT = 42% of 1500 = 630
The number of girls studying in IT is 10% of the boys studying in the same branch = 10% of 630 = 63
The remaining girls are studying in Electrical = 900 - (216 + 330 + 100 + 63) = 191
Total number of students studying in Computer Science = 285
Number of boys studying in Computer science branch = 285 - 100 = 185
22% boys studying in Electrical = 22% of (1500) = 330
Number of boys studying in Mechanical = 1500 - (180 + 630 + 185 + 330) = 175
Suppose the number of boys studying in Mechanical is y percentage of the total number of boys in the college.
175 = y% of 1500
y = 11.66 or 11.67%

Test Level 3: Simple & Compound Interest (September 1) - Question 28
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Directions: Read the following information and answer the question that follows.

Four actresses - Deepita, Anishka, Kiara and Shrashta have dedicated some of their crew members to look after their public relations image in some top news agencies - Paradigm, Zeanal, Suncast, Brewner, Regal, Tialife and Aborf.

  • Not more than 9 crew members are dedicated to one agency by any actress.
  • Deepita and Shrashta have dedicated the greatest number of crew members an actress can send to Tialife and Zeanal, respectively.
  • Anishka, Kiara and Shrashta have dedicated 4, 5 and 2 members less than the number of crew members dedicated by Deepita to Tialife.
  • Sum of crew members of Deepita dedicated to Tialife and to Suncast is 17.
  • Number of crew members of Anishka dedicated to Regal, Kiara dedicated to Aborf and Shrashta dedicated to Paradigm as well as to Aborf is the same as the number of crew members of Deepita dedicated to Suncast.
  • Number of crew members of Shrashta dedicated to Tialife and to Suncast is the same and the number of crew members of Shrashta dedicated to Suncast and to brewner are consecutive numbers.
  • Number of crew members of Deepita, Anishka, Kiara and Shrashta dedicated to Brewner, Paradigm, Paradigm and Brewner, respectively is the same.
  • Sum of crew members of Shrashta dedicated to Brewner and to Regal is 11.
  • Shrashta has the greatest number of crew members dedicated to news agencies, while Deepita has 6 less and Kiara has 15 less.
  • Number of crew members dedicated by Shrashta to Regal is the same as the number of crew members of Kiara dedicated to Suncast and of Deepita dedicated to Paradigm.
  • Deepita has 7 members each, dedicated both to Zeanal and to Aborf.
  • Anishka has 10 crew members less than Deepita.
  • Crew members of Deepita dedicated to Aborf are the same as the crew members of Anishka dedicated to Brewner.
  • Anishka has 3 and 4 members dedicated to Zeanal and to Suncast, respectively. Kiara has 2 and 7 members dedicated to Zeanal and to Regal, respectively.
  • Number of crew members of Deepita dedicated to Regal is not the same as the number of crew numbers of Anishka dedicated to Aborf.

Q. What is the sum of crew members of all actresses that are dedicated to Suncast and to Tialife?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 28

Tabulating the given information, we get

Sum of crew members of all actresses that are dedicated to Tialife and to Suncast = 8 + 4 + 5 + 7 + 9 + 5 + 4 + 7
Total crew members dedicated to Tialife and to Suncast = 49

Test Level 3: Simple & Compound Interest (September 1) - Question 29
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Directions: Read the following information and answer the question that follows.

Four actresses - Deepita, Anishka, Kiara and Shrashta have dedicated some of their crew members to look after their public relations image in some top news agencies - Paradigm, Zeanal, Suncast, Brewner, Regal, Tialife and Aborf.

  • Not more than 9 crew members are dedicated to one agency by any actress.
  • Deepita and Shrashta have dedicated the greatest number of crew members an actress can send to Tialife and Zeanal, respectively.
  • Anishka, Kiara and Shrashta have dedicated 4, 5 and 2 members less than the number of crew members dedicated by Deepita to Tialife.
  • Sum of crew members of Deepita dedicated to Tialife and to Suncast is 17.
  • Number of crew members of Anishka dedicated to Regal, Kiara dedicated to Aborf and Shrashta dedicated to Paradigm as well as to Aborf is the same as the number of crew members of Deepita dedicated to Suncast.
  • Number of crew members of Shrashta dedicated to Tialife and to Suncast is the same and the number of crew members of Shrashta dedicated to Suncast and to brewner are consecutive numbers.
  • Number of crew members of Deepita, Anishka, Kiara and Shrashta dedicated to Brewner, Paradigm, Paradigm and Brewner, respectively is the same.
  • Sum of crew members of Shrashta dedicated to Brewner and to Regal is 11.
  • Shrashta has the greatest number of crew members dedicated to news agencies, while Deepita has 6 less and Kiara has 15 less.
  • Number of crew members dedicated by Shrashta to Regal is the same as the number of crew members of Kiara dedicated to Suncast and of Deepita dedicated to Paradigm.
  • Deepita has 7 members each, dedicated both to Zeanal and to Aborf.
  • Anishka has 10 crew members less than Deepita.
  • Crew members of Deepita dedicated to Aborf are the same as the crew members of Anishka dedicated to Brewner.
  • Anishka has 3 and 4 members dedicated to Zeanal and to Suncast, respectively. Kiara has 2 and 7 members dedicated to Zeanal and to Regal, respectively.
  • Number of crew members of Deepita dedicated to Regal is not the same as the number of crew numbers of Anishka dedicated to Aborf.

Q. What is the sum of crew members of Deepita, Kiara and Shrashta that are dedicated to Regal?
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 29

Tabulating the given information, we get

Sum of crew members of Deepita, Kiara and Shrashta dedicated to Regal = 2 + 7 + 5
Crew members of Deepita, Kiara and Shrashta dedicated to Regal = 14

Test Level 3: Simple & Compound Interest (September 1) - Question 30
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Directions: Answer the question on the basis of the information given below.
Anisha has a big collection of tops. The top with her is of one or the other of the four brands namely Being Humane, Diesel, Fashion and Levis. The colour of the tops with her is either pink or green. Out of the tops with her, Anisha has bought only a few of them whereas the rest are gifted to her by one or the other of her six friends namely Ankita, Rajkumari, Usha, Hanshika, Sunita and Soha. Anisha does not know the exact number of tops gifted to her but she knows that the number of green tops of each brand gifted to her by each of her mentioned friends is at least 3 and at most 18. Further, the number of pink tops of each brand gifted to her by each of his mentioned friends is at least 7 and at most 25.

Anisha asked her boyfriend to help her determine the number of tops gifted to her by each of her mentioned friends. In turn, her boyfriend provided her with the information listed in the table given below:

Q. Out of the green tops gifted to Anisha by Rajkumari, Hanshika and Soha, the number of green tops of brand 'Being Humane' is definitely less than the number of green tops of brand:
Detailed Solution for Test Level 3: Simple & Compound Interest (September 1) - Question 30

The following table lists down the range of the total number of green tops of each brand gifted to Anisha by her mentioned friends:

Since, the maximum possible number of green tops of brand 'Being Humane' gifted to Anisha is less than the minimum possible number of green tops of brand 'Fashion' gifted to Anisha, therefore the number of green tops of brand 'Being Humane' gifted to Anisha is definitely less than the number of green tops of brand 'Fashion' gifted to Anisha.

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