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UPSC Exam  >  UPSC Test  >  CSAT Preparation  >  Test: Simple Interest- 1 - UPSC MCQ

Simple Interest- 1 - Free MCQ Practice Test with solutions, UPSC


MCQ Practice Test & Solutions: Test: Simple Interest- 1 (10 Questions)

You can prepare effectively for UPSC CSAT Preparation with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Simple Interest- 1". These 10 questions have been designed by the experts with the latest curriculum of UPSC 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Test: Simple Interest- 1 - Question 1
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How much time will it take for an amount of Rs. 900 to yield Rs. 81 as interest at 4.5% per annum of simple interest?

Detailed Solution: Question 1

Answer: A. 2 years.

S.I. = P × R × T / 100

Here, P = Rs. 900, S.I. = Rs. 81, R = 4.5%. Substitute these into the formula.

T = (100 × S.I.) ÷ (P × R)

T = (100 × 81) ÷ (900 × 4.5) = 8100 ÷ 4050 = 2

Therefore, the time required is 2 years, so option A is correct.

Test: Simple Interest- 1 - Question 2
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Arun took a loan of Rs. 1400 with simple interest for as many years as the rate of interest. If he paid Rs.686 as interest at the end of the loan period, what was the rate of interest?

Detailed Solution: Question 2

Simple Interest (SI) = P N R / 100

P is the Principal loan amount = Rs.1400

N is the number of years of deposit

R is the rate of interest

It is given that the loan period is as many years as the rate of interest.

So, N = R

Interest at the end of the loan period (SI ) = Rs.686

So,

686 = 1400 * R * R /100

R2 = 686*100 /1400

R2 = 49

R = 7%

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Test: Simple Interest- 1 - Question 3
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A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is :

Detailed Solution: Question 3

S.I. for 1 year = Rs. (854 - 815) = Rs. 39.

S.I. for 3 years = Rs.(39 * 3) = Rs. 117.

 Principal = Rs. (815 - 117) = Rs. 698.

Test: Simple Interest- 1 - Question 4
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A sum fetched a total simple interest of Rs. 929.20 at the rate of 8 p.c.p.a. in 5 years. What is the sum?

Detailed Solution: Question 4

Given, SI = Rs 929.20
P = ?
T = 5 years
R = 8%
P = (100 x SI) / RT
⇒ (100 x 929.20) / (8 x 5)
⇒ Rs. 2323

Test: Simple Interest- 1 - Question 5
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Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?

Detailed Solution: Question 5

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x)

⇒ 28x - 22x = 350800 - (13900 * 22)
⇒ 6x = 45000
⇒ x = 7500
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400

Test: Simple Interest- 1 - Question 6
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Suresh for 2 years invested Rs. 500 in SBI. He also invested Rs. 300 in ICICI for 4 years. At the end he received Rs. 220 from both banks as simple interest. What must have been rate of interest? (assuming the rate of interest for both banks is same)

Detailed Solution: Question 6

Simple Intrest = SI = PRT/100
Where P = Principal, R = Rate of intrest and T = time period
Total SI = SI from SBI and SI from ICICI
∴ 220 = (500 x R x 2)/100 + (300 x R x 4)/100
⇒ 220 = 10R + 12R
⇒ R = 10% = Rate of intrest

Test: Simple Interest- 1 - Question 7
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What will be the ratio of simple interest earned by certain amount at the same rate of interest for 5 years and that for 15 years?

Detailed Solution: Question 7

Simple Interest = PRT / 100
Here P = Principal, R = Rate of interest and T = time period
Hence, Simple Interest ∝ T
Required Ratio = (Simple Interest for 5 years) / (Simple Interest for 15 years)
⇒ T1/ T2 = 5 / 15
⇒ 1 / 3 = 1 : 3

Test: Simple Interest- 1 - Question 8
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A sum of money amounts to Rs.9800 after 5 years and Rs.12005 after 8 years at the same rate of simple interest. The rate of interest per annum is

Detailed Solution: Question 8

We can get SI of 3 years = 12005 - 9800 = 2205

SI for 5 years = (2205/3)*5 = 3675 [so that we can get principal amount after deducting SI]

Principal = 9800 - 3675 = 6125 

So Rate = (100*3675)/(6125*5) = 12%

Test: Simple Interest- 1 - Question 9
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A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?

Detailed Solution: Question 9

SI = P × R × T / 100

Given SI = Rs. 1750 and T = 7 years, so P × R = 1750 × 100 / 7 = 25000.

If the rate increases by 2%, the extra interest = P × 2 × 7 / 100 = (14/100) × P.

Using P × R = 25000 gives P = 25000 / R, so extra interest = (14/100) × 25000 / R = 3500 / R. This depends on the (unknown) rate R.

Therefore the exact additional interest cannot be determined from the given data.

Answer: Option D

Test: Simple Interest- 1 - Question 10
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A man took loan from a bank at the rate of 8% p.a. simple interest. After 4 years he had to pay Rs. 6200 interest only for the period. The principal amount borrowed by him was:

Detailed Solution: Question 10

SI = PRT / 100
⇒ (SI x 100) / RT = P
⇒ P = (6200*100) / 32
⇒ P = 19375

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About this UPSC Practice Test

This test contains 10 MCQs on Simple Interest- 1 with detailed solutions for each question. It is part of the CSAT Preparation course on EduRev, designed to align with the current UPSC syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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