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Study of Nitrogen Functional Group - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Study of Nitrogen Functional Group (14 Questions)

You can prepare effectively for NEET Chemistry Class 12 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Study of Nitrogen Functional Group". These 14 questions have been designed by the experts with the latest curriculum of NEET 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 14 minutes
  • - Number of Questions: 14

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Test: Study of Nitrogen Functional Group - Question 1

 What is the common name of the given compound?

Detailed Solution: Question 1

o-Toluidine (ortho-toluidine) is an organic compound with the chemical formula CH3C6H4NH2. It is the most important of the three isomeric toluidines. 

Test: Study of Nitrogen Functional Group - Question 2

Acrylonitrile is the common name of:

Detailed Solution: Question 2

Acrylonitrile is an organic compound with the formula CH2CHCN. It is a colorless volatile liquid, although commercial samples can be yellow due to impurities.

Test: Study of Nitrogen Functional Group - Question 3

 Ambident group among the following are:

Detailed Solution: Question 3

Ambident groups are those which can attack from both sides. So option a is correct because cyanides is C-N and carbon forms bonds here. Isocyanides are N-C in which nitrogen contains lone pairs which initiates reaction and attaches from nitrogen side.

Test: Study of Nitrogen Functional Group - Question 4

 The IUPAC name of

Detailed Solution: Question 4

THe IUPAC name of p-bromoaniline is 4-bromoaniline. Carbon attached with NH2 acts  as first position and then numbering is done.

Test: Study of Nitrogen Functional Group - Question 5

 Reduction of alkanenitriles with sodium and alcohol or LiAlH4 is called:

Detailed Solution: Question 5

The reaction is a Mendius reaction as because in this reaction the organic nitrile is reduced by nascent hydrogen(from sodium in ethanol) to a primary amine. (RCN+2H2=RCH2NH2).
where as LiAlH4 is a strong reducing agent and can be used as an abstract source of H neucophile.

Test: Study of Nitrogen Functional Group - Question 6

   is a tertiary amine with IUPAC name:

Detailed Solution: Question 6

The IUPAC name of tertiary methyl amine is N,N-Dimethyl-methanamine.

Test: Study of Nitrogen Functional Group - Question 7

The carbylamine reaction is given by compounds having:

Detailed Solution: Question 7

-NH2 group.

Carbyl amine reaction is given by aliphatic and aromatic primary amines.

Test: Study of Nitrogen Functional Group - Question 8

 Alkyl cyanides are isomeric with:

Detailed Solution: Question 8

An isocyanide (also called isonitrile or carbylamine) is an organic compound with the functional group -N≡C. It is the isomer of the related cyanide (-C≡N), hence the prefix is isocyano. The organic fragment is connected to the isocyanide group via the nitrogen atom, not via the carbon.

Test: Study of Nitrogen Functional Group - Question 9

Hydrolysis of methyl cyanides with dil. mineral acids gives:

Detailed Solution: Question 9

Test: Study of Nitrogen Functional Group - Question 10

Identify the most basic compound from the following.

Detailed Solution: Question 10

CH3 is a electron donating group and benzene is a electron withdrawing group so option A and B are easily eliminated. Among C and D the +I effect of CH3 dominates over the stearic hindrance factor so D is most basic.

Test: Study of Nitrogen Functional Group - Question 11

 Write the IUPAC name of the given compound.

Detailed Solution: Question 11

The correct answer is option A

The IUPAC name for the given compound is 
N-Methylethanamine
 

Test: Study of Nitrogen Functional Group - Question 12

 Pyridine is less basic than triethylamine because:

Detailed Solution: Question 12

Basicity of amines is due to availability of an unshared pair (lone pair) of electrons on nitrogen. This lone pair of electrons is available for the formation of a new bond with a proton or Lewis acid. Pyridine is less basic than triethylamine because lone pair of nitrogen in pyridine is delocalised.

Test: Study of Nitrogen Functional Group - Question 13

IUPAC name of NH2CH2CH2CH2COOH is :

Detailed Solution: Question 13

NH2CH2CH2 CH2   COOH  is  4-Aminobutanoic acid , here carboxy group gets preferred over amino group as a main chain.  

Test: Study of Nitrogen Functional Group - Question 14

Methyl cyanide on hydrolysis gives:

Detailed Solution: Question 14

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