JEE Exam  >  JEE Tests  >  Test: Electric Dipole(30 Oct) - JEE MCQ

Test: Electric Dipole(30 Oct) - JEE MCQ


Test Description

10 Questions MCQ Test - Test: Electric Dipole(30 Oct)

Test: Electric Dipole(30 Oct) for JEE 2024 is part of JEE preparation. The Test: Electric Dipole(30 Oct) questions and answers have been prepared according to the JEE exam syllabus.The Test: Electric Dipole(30 Oct) MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Electric Dipole(30 Oct) below.
Solutions of Test: Electric Dipole(30 Oct) questions in English are available as part of our course for JEE & Test: Electric Dipole(30 Oct) solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Electric Dipole(30 Oct) | 10 questions in 20 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
Test: Electric Dipole(30 Oct) - Question 1

The electric intensity due to a dipole of length and having a charge of , at a point on the axis at a distance from one of the charges in air, is

Detailed Solution for Test: Electric Dipole(30 Oct) - Question 1

Test: Electric Dipole(30 Oct) - Question 2

Intensity of an electric field (E) depends on distance r, due to a dipole, is related as

Detailed Solution for Test: Electric Dipole(30 Oct) - Question 2

Intensity of electric field due to a Dipole

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Electric Dipole(30 Oct) - Question 3

If the dipole of moment 2.57 × 10−17 Cm is placed into an electric field of magnitude 3.0 × 104 N/C such that the fields lines are aligned at 30 with the line joining P to the dipole, what torque acts on the dipole?

Detailed Solution for Test: Electric Dipole(30 Oct) - Question 3

Test: Electric Dipole(30 Oct) - Question 4
An electric dipole is placed at an angle of with an electric field of intensity , It experiences a torque of . Calculate the charge on the dipole if the dipole length is .
Detailed Solution for Test: Electric Dipole(30 Oct) - Question 4
Torque,

or,
Dipole moment,
Test: Electric Dipole(30 Oct) - Question 5
On decreasing the distance between the two charges of a dipole which is perpendicular to electric field and decreasing the angle between the dipole and electric field, the torque on the dipole
Detailed Solution for Test: Electric Dipole(30 Oct) - Question 5
Since on decreasing the distance between the two charges, and on decreasing angle between the dipole and electric field, decreases therefore torque decreases.
Test: Electric Dipole(30 Oct) - Question 6

Two point dipoles of dipole moment p1 and p2 are at a distance x from each other and . The force between the dipoles is:

Detailed Solution for Test: Electric Dipole(30 Oct) - Question 6

Given
Two parallel dipoles at distance x
Axial electric field of dipole P1

Force on dipole P2 due to electric field of P1

The correct option is 3

Test: Electric Dipole(30 Oct) - Question 7
An electric dipole, consisting of two opposite charges of each separated by a distance is placed in an electric field of . Torque acting on the dipole is
Detailed Solution for Test: Electric Dipole(30 Oct) - Question 7
Charges , Distance and electric field (E) . Torque q.d.

Test: Electric Dipole(30 Oct) - Question 8

In the figure, the net electric flux through the area  when the system is in air. On immersing the system in water the net electric flux through the area

Detailed Solution for Test: Electric Dipole(30 Oct) - Question 8

Since electric field decreases inside water, therefore flux also decreases.

Test: Electric Dipole(30 Oct) - Question 9
A charge is placed at the centre of the open end of a cylindrical vessel. The flux of the electric field through the surface of the vessel is
Detailed Solution for Test: Electric Dipole(30 Oct) - Question 9
Given that, A charge q is placed at the center of open end Q a cylindrical vessel, we have to find the flux through the surface of the vessel. So, when charge is placed at the center of open end of a cylindrical vessel then only half of the charge will contribute to the flux, because half will lie inside the surface and half will lie outside the surface. so, flux through the surface of vessel is
Test: Electric Dipole(30 Oct) - Question 10

A hollow cylinder has a charge coulomb within it. If is the electric flux in units of voltmeter associated with the curved surface , the flux linked with the plane surface in units of voltmeter will be

Detailed Solution for Test: Electric Dipole(30 Oct) - Question 10

Since ,
where is the total charge. As shown in the figure, flux associated with the curved surface is
Let us assume flux linked with the plane surfaces and be
Therefore,

Information about Test: Electric Dipole(30 Oct) Page
In this test you can find the Exam questions for Test: Electric Dipole(30 Oct) solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Electric Dipole(30 Oct), EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE