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Nuclei(23 Jan) - Free MCQ Practice Test with solutions, JEE


MCQ Practice Test & Solutions: Test: Nuclei(23 Jan) (10 Questions)

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Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

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Test: Nuclei(23 Jan) - Question 1

The nuclide 92U238 has all the following except​

Detailed Solution: Question 1

The nuclide (nucleus) consists of neutrons and protons (when combined called nucleons).
Thus,
No. of protons in 92U238 = 92,
No. of neutrons = 146 (238 – 92)
No. of nucleons = 238 (146 + 92)

Test: Nuclei(23 Jan) - Question 2

Which one of the following statements about the atomic nucleus is accurate?

Detailed Solution: Question 2

Most nuclei are approximately spherical. The average radius of a nucleus with A nucleons is R = R0A1/3, where R0 = 1.2*10-15 m. The volume of the nucleus is directly proportional to the total number of nucleons. This suggests that all nuclei have nearly the same density.

Test: Nuclei(23 Jan) - Question 3

Nucleus ”a” contains 5 protons and 5 neutrons and has radius R. The radius of nucleus ”b”, which contains 35 protons and 45 neutrons, is closest to:​

Detailed Solution: Question 3

R∝A1/3
A(mass no.)=n+p
R/x=(10/80)1/3
R/x=(13/23)1/3
R/x=1/2
X=2R

Test: Nuclei(23 Jan) - Question 4

Binding energy per nucleon is the ratio of

Detailed Solution: Question 4

Binding energy per nucleon is the ratio of the binding energy of a nucleus to the number of the nucleons.

Binding energy per nucleon = (Total binding energy) / (Number of nucleon)

Measure of stability of the nucleus: Larger the binding energy per nucleon, the greater the work that must be done to remove the nucleon from the nucleus, the more stable the nucleus.

Test: Nuclei(23 Jan) - Question 5

The atomic number Z of the nucleus is

Detailed Solution: Question 5

The atomic number or proton number (symbol Z) of a chemical element is the number of protons found in the nucleus of every atom of that element. The atomic number uniquely identifies a chemical element. It is identical to the charge number of the nucleus

Test: Nuclei(23 Jan) - Question 6

Artificial disintegration with alpha particles of which of the following led to the discovery of neutron?

Detailed Solution: Question 6

James Chadwick set up an experiment to test his hypothesis. Chadwick put a piece of beryllium in a vacuum chamber with some polonium. The polonium emitted alpha rays, which struck the beryllium. When struck, the beryllium emitted the mysterious neutral rays.

Test: Nuclei(23 Jan) - Question 7

In a nuclear reactor:

Detailed Solution: Question 7

A moderator is used in nuclear reactors in order to slow down the speed of neutrons.
In nuclear engineering, a neutron moderator is a medium that reduces the speed of fast neutrons, thereby turning them into thermal neutrons capable of sustaining a nuclear chain reaction involving uranium-235 or a similar fissile nuclide.
Clearly, an obvious way to make a reactor work, and to make use of this characteristic of the 235U(n,f) cross-section, is to slow down the fast, fission neutrons. This can be accomplished, for example, when the neutrons collide with nuclei and scatter in some substance (a moderator).

Test: Nuclei(23 Jan) - Question 8

What is the binding energy of the hydrogen nucleus?​

Detailed Solution: Question 8

Nucleus of hydrogen has only one proton. Hence its binding energy will be zero. The nuclear binding energy is the energy it takes to separate all the nucleons in a nucleus from each other. Since there is only the one nucleon, it's already separated from any other nucleons.

Test: Nuclei(23 Jan) - Question 9

The fusion of hydrogen into helium is more likely to take place:

Detailed Solution: Question 9

The fusion of hydrogen into helium is more likely to take place at high temperature and high pressure, like the sun.

Test: Nuclei(23 Jan) - Question 10

Given M = mass of the nucleus, A = atomic mass. What is packing fraction?

Detailed Solution: Question 10

Packing fraction: - It tells about the stability of a nucleus.
Packing fraction=isotonic mass=molecular mass (atomic mass)/atomic mass
p.f.=M-A/A

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