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Electronics and Communication Engineering (ECE) Exam  >  Electronics and Communication Engineering (ECE) Test  >  RRB JE Mock Test Series for ECE 2026  >  RRB JE ECE (CBT II) Mock Test- 1 - Electronics and Communication Engineering (ECE) MCQ

RRB JE ECE (CBT II) Mock Test- 1 Free Online Test 2026


Full Mock Test & Solutions: RRB JE ECE (CBT II) Mock Test- 1 (150 Questions)

You can boost your Electronics and Communication Engineering (ECE) 2026 exam preparation with this RRB JE ECE (CBT II) Mock Test- 1 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of Electronics and Communication Engineering (ECE) 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 120 minutes
  • - Total Questions: 150
  • - Analysis: Detailed Solutions & Performance Insights

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RRB JE ECE (CBT II) Mock Test- 1 - Question 1
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Which is/are abiotic component?
I. Sunlight
II. Plants
III. Water
IV. Animals
V. Soil
VI. Insects

Detailed Solution: Question 1

The natural environment components can be classified into two

  1. Abiotic components
  2. Biotic components

Abiotic components
These components are not living but can support other living organisms. Some kinds of such organisms are given below:

  • Inorganic substances: The elements which are taken up by the plants with the help of sunlight and converted into food. The examples of such inorganic elements are like nitrogen, calcium, phosphorus, hydrogen, carbon dioxide and oxygen.
  • Organic substances: The substances which are taken in the form of inorganic materials from the food source and are again sent back to the environment after decomposition by decomposers. E.g. Carbohydrates, proteins, fats etc.
  • Physical factors: These factors have a direct effect on living organisms, which are climatic conditions like temperature, rainfall, wind, humidity, soil and light energy which is used by the plants for the preparation of food.
  • Lithosphere: The outermost layer of the earth (i.e.) soil or land.
  • Hydrosphere: Part of the earth having water resources like oceans, rivers, ponds, and lakes.
  • Atmosphere: It is a cover around the earth composed by a variety of gases which protects the living organisms from various harmful cosmic radiations.

Biotic components
The area in which life is possible is called as a biosphere. All living organism in the biosphere depends upon one another and these organisms exist in the biosphere forming the following community.

  • Producers: The green plants present on earth surface which produces their own food only once by the process of photosynthesis in sunlight, water, and carbon dioxide forms food for other organisms. E.g. Sugar, carbohydrates etc.
  • Consumer: This organisms directly (or) indirectly depend upon the green plants for the source of food. E.g. All animals including man.
  • Decomposers: These are micro-organisms which decompose the complex compounds in the dead organic matter of plants and animals and again recycle the elements into the environment. E.g. Bacteria and fungi.

​So for the given conditions:

  • Biotic Components – Plants, Animals, Fungi, Insects
  • Abiotic Components – Sunlight, Water, Soil.

RRB JE ECE (CBT II) Mock Test- 1 - Question 2
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A duplexer in radar is also called as:

Detailed Solution: Question 2

  • A duplexer is a device that isolates transmitter while receiving an isolated receiver while transmitting
  • A duplexer is basically an electronic switch
  • It acts like a transmit/ Receive switch and is also called as TR Switch

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RRB JE ECE (CBT II) Mock Test- 1 - Question 3
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Which force is required to maintain a body in Uniform circular Motion?

Detailed Solution: Question 3

  • The Centripetal force is required to maintain a body in Uniform Circular Motion.
  • Centripetal Force acts when a body moves around the other body, the force that causes this acceleration and keeps the body moving along a circular path is acting towards the centre

RRB JE ECE (CBT II) Mock Test- 1 - Question 4
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Very large values of modulation index (greater than 3.24) lead to

Detailed Solution: Question 4

Modulation index is used to determine the strength and quality of transmitted signal. If the modulation index is small, then the amount of variation in the carrier amplitude is small. Very large values of modulation index (greater than 3.24) lead to a square AC output voltage.

RRB JE ECE (CBT II) Mock Test- 1 - Question 5
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In Cellular communication circular cells are not preferred because:

Detailed Solution: Question 5

  • The problem with circular cells is, that they cannot cover the entire geographical location without leaving gaps or without overlapping with the adjacent cells
  • Hexagon cells on the other hand are able to cover the entire area without overlapping or leaving gaps

RRB JE ECE (CBT II) Mock Test- 1 - Question 6
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Insulators at room temperature have:

Detailed Solution: Question 6

  • In insulators, band gap is large typically greater than 3 eV
  • Thermal energy is not sufficient to excite electrons from valence band to conduction band
  • Thus, the valence band is completely filled and conduction band is completely empty

RRB JE ECE (CBT II) Mock Test- 1 - Question 7
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A microprocessor retrieves instructions from:

Detailed Solution: Question 7

Primary Storage/ Main Storage:

  • Primary storage is the collection methods and technologies used to capture and retain digital information that is in active use and critical for an organization’s operations
  • Primary storage data is frequently accessed by applications or other hardware systems and business users
  • Instructions are fetched from main memory

Cache Memory:

  • This is a small memory, faster than the main memory
  • Memory caching is effective because most programs access the same data or instructions over and over
  • By keeping as much of this information as possible in SRAM, the computer avoids accessing the slower DRAM

RRB JE ECE (CBT II) Mock Test- 1 - Question 8
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In Linux and Unix CTRL+D is used to _______.

Detailed Solution: Question 8

​CTRL + D closes the command line shell. This sends an EOF (End of file) marker to shell, and shell exits when it receives this marker. This is similar to running the exit command.

RRB JE ECE (CBT II) Mock Test- 1 - Question 9
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If the refractive index of glass is 1.732, find the Brewster’s angle–

Detailed Solution: Question 9

We know, μ = tan ip

Where ip = Polarization or Brewster’s angl

∴ ip = tan-1 μ = tan-1(1.732) = 60°

RRB JE ECE (CBT II) Mock Test- 1 - Question 10
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Which of the following is a DMA controller?

Detailed Solution: Question 10

8257 : DMA Controller

8255 : PPI (Programmable Peripheral Interface)

8251 : USART (Universal Synchronous and Asynchronous Receiver Transmitter)

8259 : PIC(Programmable Interrupt Controller)

8253, 8254 : Programmable Timers

RRB JE ECE (CBT II) Mock Test- 1 - Question 11
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Slew rate in an op-amp limits:

Detailed Solution: Question 11

The slew rate of the op-amp is given by:
Vo = dVi/dt
Let
Vi = Vi cos ωt
Vo = -AVi cos ωt
dVo / dt = AViω sinωt
A maximum value of change of output voltage is AViw
If the slew rate is 1V/sec
Then AV¡ω ≤ 1
The maximum value of the rate of change of output is a function of input frequency ω
Hence slew rate limits the maximum frequency of operation in an op-amp

RRB JE ECE (CBT II) Mock Test- 1 - Question 12
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A double beam oscilloscope has

Detailed Solution: Question 12

The dual beam oscilloscope has two separate electron beams, and therefore two completely separate vertical channels

The two channels may have a common time base system or they have an independent time base system

An independent time base allows different sweeps rates for the two channels but increase the size and weight of the oscilloscope

RRB JE ECE (CBT II) Mock Test- 1 - Question 13
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Control bus in a microprocessor are:

Detailed Solution: Question 13

Control Bus is a group of conducting wires, which is used to generate timing and control signals to control the associated peripherals, the microprocessor uses control bus to process data.

Some control signals are:

Memory read

Memory write

I/O read

I/O Write

Opcode fetch

RRB JE ECE (CBT II) Mock Test- 1 - Question 14
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Which is an 8-bit microprocessor?

Detailed Solution: Question 14

In 1979, Intel introduced the 8088, the 8-bit microprocessor. (external 8-bit data bus) instead of a 16-bit bus of 8086.

8085 is called 8-bit microprocessor because the accumulator is 8 bits in size. This means that the primary data size is 8 bits.

8086 is a 16-bit microprocessor.

RRB JE ECE (CBT II) Mock Test- 1 - Question 15
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The data is stored in a Hard disk as

Detailed Solution: Question 15

All data stored on storage media – whether that’s hard disk drives (HDDs), solid-state drives (SSDs), external hard drives, USB flash drives, SD cards etc – can be converted to a string of bits, otherwise known as binary digits. These binary digits have a value of 1 or 0, and the strings can make up photos, documents, audio and video. A byte is the most common unit of storage and is equal to 8 bits.
Binary data (0 and 1) is primarily stored on the hard disk drive (HDD). The device is made up of a spinning disk (or disks) with magnetic coatings and heads that can both read and write information in the form of magnetic patterns. In addition to hard disk drives, floppy disks and tapes also store data magnetically.

RRB JE ECE (CBT II) Mock Test- 1 - Question 16
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Which of the following operating system works for both mobile and personal computer?

Detailed Solution: Question 16

Windows 10 Mobile was announced on January 21, 2015, as a mobile operating system for smartphones and tablets running on ARM architecture; Its primary focus is unification with Windows 10
Debian is a Unix-like operating system composed entirely of free software packaged by a team of volunteers
Microsoft Disk Operating System is an operating system for x-86 based personal computers.
Android is a mobile operating system developed by Google

RRB JE ECE (CBT II) Mock Test- 1 - Question 17
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Which one of the following is a basic unit of MS Excel?

Detailed Solution: Question 17

Each worksheet is made up of cells and cells are a result of the intersection of rows and columns
They are basic units for storing data
Each cell gets its name from this intersection
The address of a cell that is in column A and has its row number as 4 is referred to as cell A4
Thus the letter and number of the intersecting column and row is the cell address
A group of contiguous cells is called a range
An example of a cell range would be G1: G3​

RRB JE ECE (CBT II) Mock Test- 1 - Question 18
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An op-amp has a common mode gain of 0.001 and a differential mode gain of 107. Its CMRR would be

Detailed Solution: Question 18

CMRR is the ratio of differential mode gain to common mode gain
CMRR = Ad/Acm
CMRR = 107/10-3 = 1010
CMRR value is usually expressed in Decibels and can be converted using 20 Log (CMRR)

RRB JE ECE (CBT II) Mock Test- 1 - Question 19
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Which of the following pattern is enough to represent a pixel in a black and white image?

Detailed Solution: Question 19

Images are also represented by bit patterns. In its simplest form, an image is composed of a matrix of pixels (picture elements), where each pixel is a small dot. The size of the pixel depends on the resolution. For example, an image can be divided into 1000 pixels or 10,000 pixels.

After an image is divided into pixels, each pixel is assigned a bit pattern. The size and the value of the pattern depend on the image. For an image made of only black-and-white dots, a 1-bit pattern is enough to represent a pixel.
Hence, the correct option is (B)

RRB JE ECE (CBT II) Mock Test- 1 - Question 20
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The gates required to build a half-adder are

Detailed Solution: Question 20

The truth table for half-adder is
 
The expression for the sum is
S = A'B + AB' = A ⊕ B
and for carry is
C = AB
Thus, to implement sum we required 1 EXOR gate and to implement carry we required AND gate
Hence, the correct option is (C)

RRB JE ECE (CBT II) Mock Test- 1 - Question 21
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Degree to which a material can be magnetized is given by

Detailed Solution: Question 21

Permeability is the measure of the degree to which a material can be magnetized

B = μ H

μ = B/H
Hence, the correct option is (C)

RRB JE ECE (CBT II) Mock Test- 1 - Question 22
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Which of the following is the most preferable management of waste?

Detailed Solution: Question 22

The order of waste management hierarchy, from most to least favoured is:
Prevention-Reuse-Recycle-Recovery-Disposal

Prevention: Preventing and reducing waste generation.
Reuse: Giving the products a second life before they become waste.
Recycle: Any recovery operation by which waste materials are reprocessed into products, materials or substances whether for the original or other purposes.
Recovery: Some waste incineration based on a political non-scientific formula that upgrades the less inefficient incinerators.
Disposal: Different processes to dispose of the waste are landfilling, incineration, pyrolysis, gasification and other finalist solutions.

RRB JE ECE (CBT II) Mock Test- 1 - Question 23
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If a program uses Inline Function, then the function is expanded inline at _______.

Detailed Solution: Question 23

  • The inline functions are a C++ enhancement feature to increase the execution time of a program.
  • Functions can be instructed to compiler to make them inline so that compiler can replace those function definition wherever those are being called.
  • The compiler replaces the function call with the corresponding function code and doesn't branch to the function for its execution.

RRB JE ECE (CBT II) Mock Test- 1 - Question 24
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Atmospheric layer important for human beings is:

Detailed Solution: Question 24

Our atmosphere is divided into five layers starting from the earth’s surface;

  1. Troposphere: Average height is 13 km. The air we breathe exists here. This layer contains dust particles and water vapour. All changes in climate and weather take place in this layer. Almost all the weather phenomena like cloud, rainfall, fog and hailstorm occur in this layer.  This is the most important layer for all biological activity.
  2. Stratosphere: up to an altitude of 50 km from the earth’s surface. Almost free from clouds, most ideal for flying aeroplanes, Contains a layer of ozone gas (Ozonosphere). Temperature increases with height in this layer.
  3. Mesosphere: Up to an altitude of 80 km. Meteorites burn up in this layer on entering from the space. Temperature decreases with height in this layer.
  4. Thermosphere: It extends between 80-400 km. In thermosphere temperature rises very rapidly with increasing height. The ionosphere is a part of this layer. It contains electrically charged particles known as ions, and hence, it is known as the ionosphere. Radio waves transmitted from the earth are reflected back to the earth by this layer. This layer helps in radio transmission. The International Space Station and satellites orbit in this layer. Temperature increases with height in this layer.
  5. Exosphere: The uppermost layer of the atmosphere is known as an exosphere. This layer has very thin air. Light gases like helium and hydrogen float into space from here.

RRB JE ECE (CBT II) Mock Test- 1 - Question 25
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Discrete energy level formed due to doping in n-type material is called:

Detailed Solution: Question 25

In a n type material, the donor atom is a pentavalent atom having one electron more than the base semiconductor.

This extra electron is not free but loosely bound to the donor atom.

The extra electron forms an energy level just below the conduction level and this energy level is called donor energy level

RRB JE ECE (CBT II) Mock Test- 1 - Question 26
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A 50 micro ampere meter has resistance of 100 Ω. If the meter has to measure 100 mA then what will be the magnitude of current through the shunt?

Detailed Solution: Question 26

We know that
Ish = Shunt current, Im = Meter current
I sh = I - I m = 100 -(50 x 10-3) = 99.95 mA

RRB JE ECE (CBT II) Mock Test- 1 - Question 27
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Which method of waste disposal is most effective at reducing the volume of solid waste?

Detailed Solution: Question 27

Combustion or Burning:

  • Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives off heat
  • Waste like plastic and rubber tires can be burned using this combustion process
  • These make use of the heat energy generated by the combustion & incineration process to electricity
  • It is the most effective method of waste disposal at reducing the volume of solid waste
  • It is not an acceptable practice, as it creates lots of pollution and it is harmful to both environment and as well as organisms

Important Points:

Recycling:

  • It is the process of converting waste materials into reusable objects to prevent waste
  • The materials from which the items are made can be reprocessed into new products
  • Recycling such material saves the product and it also reduces the amount of manufacture to make new products
  • It also helps in energy saving and reducing global climate change

Landfill or Burying:

  • Landfill refers to the disposal of waste material by burying it
  • It is an extended storage area for non-biodegradable waste
  • A landfill is an area, which prevent contamination from the waste entering the area surrounding by soil and water and it also helps to reduce odour and pests

Composting:

  • Due to lack of adequate space for landfills, biodegradable yard waste is allowed to decompose in a medium designed for the purpose
  • Only biodegradable waste materials are used in composting
  • Good quality environmentally friendly manure is formed from the compost and can be used for agricultural purposes

RRB JE ECE (CBT II) Mock Test- 1 - Question 28
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Determine the flux (in Wb) through a coil when the reluctance of the coil is 4 Amp-turns/Wb and the produced mmf is 48 Amp-turns.

Detailed Solution: Question 28

Given that, mmf = 48 Amp-turns

Reluctance = 4 Amp-turns/wb

Flux through the coil (Ф) = 15 Wb

Reluctance = mmf / flux ⇒ 4 = 48/flux ⇒ flux = 12 web

RRB JE ECE (CBT II) Mock Test- 1 - Question 29
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When did Emperor Aurangzeb died?

Detailed Solution: Question 29

  • Aurangzeb was a ruler of Mughal dynasty.
  • He was the son of Shah Jahan.
  • He died in the year 1707.
  • He imposed Jizya, a military tax on non-Muslims who were not fighting for Mughal Empire.
  • He was succeeded by his son Bahadur Shah I.
  • Aurangzeb was also known as 'Zinda Pir' because of his simple lifestyle.

RRB JE ECE (CBT II) Mock Test- 1 - Question 30
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Hardware includes

Detailed Solution: Question 30

Computer hardware is the collection of all the parts of the computer you can physically touch. For example - computer case, monitor, keyboard and mouse etc.

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About this Electronics and Communication Engineering (ECE) Mock Test

This mock test contains 150 questions designed to replicate the pattern, difficulty level and time pressure of the actual Electronics and Communication Engineering (ECE) exam. It is part of RRB JE Mock Test Series for ECE 2026 on EduRev, covering all the topics that are being asked as per the current Electronics and Communication Engineering (ECE) syllabus. Attempting this test under timed conditions will help you assess your exam readiness, identify subject-wise weak areas, and improve your speed and accuracy before the actual exam.

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If you found this RRB JE ECE (CBT II) Mock Test- 1 helpful, you can further enhance your Electronics and Communication Engineering (ECE) preparation with complete mock tests, previous year questions & practice tests available in RRB JE Mock Test Series for ECE 2026 course on EduRev. The course offers:
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