Test: CAT Logical Reasoning & Data Interpretation- 7 (October 30) - CAT MCQ

From (2), Company A should have an MRP of Rs. 20 or Rs. 25.
From (4), Company D should have an MRP of Rs. 15 or Rs. 20 or Rs. 25.
From (6), he sold two ice-creams of Company B. He sold ice-cream of another company to Lacy and Kevin. Hence, Mr. Webster would have sold exactly one ice-cream of all the other companies.
From (5), Theon bought an ice-cream from ice-cream company with MRP of Rs. 15. Hence, Company D will not have Rs. 15 as MRP.
From (4), Mr. Webster sold an ice-cream at price of Rs. 23. This cannot be of Company D (since he sold an ice-cream at price of Rs. 11 of Company D).
Therefore, Company A will have an MRP of Rs. 25 and Company D will have an MRP of Rs. 20.
Mr. Webster could not have sold an ice-cream of Company A to Kevin, Lacy, Abigail, Avril, Lexie or Theon. Hence, Mr. Webster sold an ice-cream to Terry of Company A.
From (6), Company E will have an MRP of Rs. 15.
Also, from (3), he sold ice-creams to Kevin and Lacy of Company C.
From (5), Mr. Webster sold an ice-cream of Company E to Theon and sold an ice-cream of Company B to Lexie and Avril.

The following table presents this information.

Difference between the MRPs (in Rs.) of ice creams sold to Abigail and Terry = Rs. 25 - Rs. 20 = Rs. 5

Given that from September 1^st to September 4^th, he was in Hospital-2.
On September 4^th, he starts a journey. He cannot be travelling to Hospital-2 or Hospital-4, since he left Hospital-4 and reached Hospital-2 on September 1^st.
Hence, he could have travelled to Hospital-1 or Hospital-3.

On September 7^th, he could not have travelled to Hospital-2 or Hospital-4 because he left Hospital-4 and Hospital-2 on September 1^st and September 4^th respectively (in both cases, ten days have not elapsed). Hence, he could have travelled to Hospital-3 or Hospital-1 on September 7^th (depending on where he travelled to on September 4^th). Hence, on September 4^th and September 7^th, he must have travelled to Hospital-3 and Hospital-1 in any order.
On September 13^th, he could not have travelled to Hospital-2 (because he left Hospital-2 on September 4^th and cannot travel to Hospital-2 until after September 14^th. He could not have travelled to Hospital-3 or Hospital-1. Hence, he must have travelled to Hospital-4.

Case 1: Consider that he travelled to Hospital-1 on September 4^th and Hospital-3 on September 7^th.
On September 18^th, he could not have travelled to Hospital-3. Hence, he must have travelled to Hospital-2 or Hospital-1. On September 22^nd, he could not have travelled to Hospital-3 or Hospital-4. Hence, he must have travelled to Hospital-2 or Hospital-1 (depending on where he travelled to on September 18^th). Hence, on September 18^th and September 22^nd, he must have travelled to Hospital-2 and Hospital-1 in any order.
On September 26^th, he could not have travelled to Hospital-2, Hospital-1, or Hospital-4. Hence, he must have travelled to Hospital-3.
On October 1^st, he could not have travelled to Hospital-1 or Hospital-2 (because he would have left any Hospital earliest by September 22^nd). Hence, he must have travelled to Hospital-4.
On October 7^th, he could have travelled to Hospital-2 or Hospital-1. But he reached Hospital-2 on 13^th, hence, he must have travelled to Hospital-1 on October 7^th.

Case 2: We can consider the case that he travelled to Hospital-3 on September 4^th and Hospital-1 on September 7^th.
In this case, all the instances when he travelled to Hospital-1 in the previous case, he travelled to Hospital-3 and vice versa.
The possible cases are presented in the following table:

We cannot determine the answer.

Only one goal was scored in every odd-numbered game.

Emma recorded two goals in Game 4.

Goals scored in Game 1, Game 2 and Game 4 are in GP.
Let the common ratio be r.

Goals scored should be a real number and total goals should be 14, so the only possible value of r is 2.

The game with the second highest number of goals scored is Game 6.
As the sum of scores is 14 and already in the above table 10 goals have been scored; in Game 6, the score will be 3 and the Game 8 score will be 1.

No two players had the same total number of goals.
So, their individuals score will be 2, 3, 4, and 5 as this is the only possible way for the sum to be 14.
Emma emerged as a dominant scorer – it means Emma scored 5 goals.
Hannah is known for her lowest scoring capabilities, and scored in Game 2 and Game 8.
The player with the highest number of goals achieved this feat scoring in exactly four games, including Game 3 and Game 7.

Olivia and Grace both scored 2 goals each in Game 4 and Game 6, respectively.

Either Olivia's score is 3 and Grace score's is 4 or Olivia's score is 4 and Grace's score is 3.
Based on the information provided:

Olivia scored 2 goals in Game 4 and she can score maximum 4 goals. Hence, she can score 1 goal each in two games.
Therefore, Olivia scored goals in maximum 3 games.

Only one goal was scored in every odd-numbered game.

Emma recorded two goals in Game 4.

Goals scored in Game 1, Game 2 and Game 4 are in GP.
Let the common ratio be r.

Goals scored should be a real number and total goals should be 14, so the only possible value of r is 2.

The game with the second highest number of goals scored is Game 6.
As the sum of scores is 14 and already in the above table 10 goals have been scored; in Game 6, the score will be 3 and the Game 8 score will be 1.

No two players had the same total number of goals.
So, their individuals score will be 2, 3, 4, and 5 as this is the only possible way for the sum to be 14.
Emma emerged as a dominant scorer – it means Emma scored 5 goals.
Hannah is known for her lowest scoring capabilities, and scored in Game 2 and Game 8.
The player with the highest number of goals achieved this feat scoring in exactly four games, including Game 3 and Game 7.

Olivia and Grace both scored 2 goals each in Game 4 and Game 6, respectively.

Either Olivia's score is 3 and Grace score's is 4 or Olivia's score is 4 and Grace's score is 3.
Based on the information provided:

Let the number of normal bookings in August be 'a'. The construction of the following table shall be useful.

Now, if we see the column for October,
Number of deliveries made in October = Number of normal bookings in September + Number of discounted bookings in August
790 = 272 + 1135 - a
Or, a = 617
Now, the value of 'a' can be verified from the column for November.
Number of deliveries made in November = Number of discounted bookings in September = 148 + a
Putting 'a' as 617 in the above equation, we get the number of deliveries in November as 148 + 617 = 765
This is given in the table.
Now, substituting the value of 'a' as 617 in the above table, we get the following table.

From the above table, it is evident that the number of tablets booked under discounted bookings in June were delivered in August i.e. 538 tablets. Hence, answer option (2) is correct.

From (2), Company A should have an MRP of Rs. 20 or Rs. 25.
From (4), Company D should have an MRP of Rs. 15 or Rs. 20 or Rs. 25.
From (6), he sold two ice-creams of Company B. He sold ice-cream of another company to Lacy and Kevin. Hence, Mr. Webster would have sold exactly one ice-cream of all the other companies.
From (5), Theon bought an ice-cream from ice-cream company with MRP of Rs. 15. Hence, Company D will not have Rs. 15 as MRP.
From (4), Mr. Webster sold an ice-cream at price of Rs. 23. This cannot be of Company D (since he sold an ice-cream at price of Rs. 11 of Company D).
Therefore, Company A will have an MRP of Rs. 25 and Company D will have an MRP of Rs. 20.
Mr. Webster could not have sold an ice-cream of Company A to Kevin, Lacy, Abigail, Avril, Lexie or Theon. Hence, Mr. Webster sold an ice-cream to Terry of Company A.
From (6), Company E will have an MRP of Rs. 15.
Also, from (3), he sold ice-creams to Kevin and Lacy of Company C.
From (5), Mr. Webster sold an ice-cream of Company E to Theon and sold an ice-cream of Company B to Lexie and Avril.

The following table presents this information.

The maximum retail price of an ice-cream that can be sold of Company E is Rs. 15.

From (2), Company A should have an MRP of Rs. 20 or Rs. 25.
From (4), Company D should have an MRP of Rs. 15 or Rs. 20 or Rs. 25.
From (6), he sold two ice-creams of Company B. He sold ice-cream of another company to Lacy and Kevin. Hence, Mr. Webster would have sold exactly one ice-cream of all the other companies.
From (5), Theon bought an ice-cream from ice-cream company with MRP of Rs. 15. Hence, Company D will not have Rs. 15 as MRP.
From (4), Mr. Webster sold an ice-cream at price of Rs. 23. This cannot be of Company D (since he sold an ice-cream at price of Rs. 11 of Company D).
Therefore, Company A will have an MRP of Rs. 25 and Company D will have an MRP of Rs. 20.
Mr. Webster could not have sold an ice-cream of Company A to Kevin, Lacy, Abigail, Avril, Lexie or Theon. Hence, Mr. Webster sold an ice-cream to Terry of Company A.
From (6), Company E will have an MRP of Rs. 15.
Also, from (3), he sold ice-creams to Kevin and Lacy of Company C.
From (5), Mr. Webster sold an ice-cream of Company E to Theon and sold an ice-cream of Company B to Lexie and Avril.

The following table presents this information.

He could have sold an ice-cream of selling price less than or equal to Rs. 5 to Avril.
Thus the maximum selling price at which he can sell the ice cream is the same as the MRP of the ice cream i.e. Rs. 5

Given that from September 1^st to September 4^th, he was in Hospital-2.
On September 4^th, he starts a journey. He cannot be travelling to Hospital-2 or Hospital-4, since he left Hospital-4 and reached Hospital-2 on September 1^st.
Hence, he could have travelled to Hospital-1 or Hospital-3.

On September 7^th, he could not have travelled to Hospital-2 or Hospital-4 because he left Hospital-4 and Hospital-2 on September 1^st and September 4^th respectively (in both cases, ten days have not elapsed). Hence, he could have travelled to Hospital-3 or Hospital-1 on September 7^th (depending on where he travelled to on September 4^th). Hence, on September 4^th and September 7^th, he must have travelled to Hospital-3 and Hospital-1 in any order.
On September 13^th, he could not have travelled to Hospital-2 (because he left Hospital-2 on September 4^th and cannot travel to Hospital-2 until after September 14^th. He could not have travelled to Hospital-3 or Hospital-1. Hence, he must have travelled to Hospital-4.

Case 1: Consider that he travelled to Hospital-1 on September 4^th and Hospital-3 on September 7^th.
On September 18^th, he could not have travelled to Hospital-3. Hence, he must have travelled to Hospital-2 or Hospital-1. On September 22^nd, he could not have travelled to Hospital-3 or Hospital-4. Hence, he must have travelled to Hospital-2 or Hospital-1 (depending on where he travelled to on September 18^th). Hence, on September 18^th and September 22^nd, he must have travelled to Hospital-2 and Hospital-1 in any order.
On September 26^th, he could not have travelled to Hospital-2, Hospital-1, or Hospital-4. Hence, he must have travelled to Hospital-3.
On October 1^st, he could not have travelled to Hospital-1 or Hospital-2 (because he would have left any Hospital earliest by September 22^nd). Hence, he must have travelled to Hospital-4.
On October 7^th, he could have travelled to Hospital-2 or Hospital-1. But he reached Hospital-2 on 13^th, hence, he must have travelled to Hospital-1 on October 7^th.

Case 2: We can consider the case that he travelled to Hospital-3 on September 4^th and Hospital-1 on September 7^th.
In this case, all the instances when he travelled to Hospital-1 in the previous case, he travelled to Hospital-3 and vice versa.
The possible cases are presented in the following table:

In both the cases, Mr. Smith stayed in Hospital-2 for total 5 days.

Given that from September 1^st to September 4^th, he was in Hospital-2.
On September 4^th, he starts a journey. He cannot be travelling to Hospital-2 or Hospital-4, since he left Hospital-4 and reached Hospital-2 on September 1^st.
Hence, he could have travelled to Hospital-1 or Hospital-3.

On September 7^th, he could not have travelled to Hospital-2 or Hospital-4 because he left Hospital-4 and Hospital-2 on September 1^st and September 4^th respectively (in both cases, ten days have not elapsed). Hence, he could have travelled to Hospital-3 or Hospital-1 on September 7^th (depending on where he travelled to on September 4^th). Hence, on September 4^th and September 7^th, he must have travelled to Hospital-3 and Hospital-1 in any order.
On September 13^th, he could not have travelled to Hospital-2 (because he left Hospital-2 on September 4^th and cannot travel to Hospital-2 until after September 14^th. He could not have travelled to Hospital-3 or Hospital-1. Hence, he must have travelled to Hospital-4.

Case 1: Consider that he travelled to Hospital-1 on September 4^th and Hospital-3 on September 7^th.
On September 18^th, he could not have travelled to Hospital-3. Hence, he must have travelled to Hospital-2 or Hospital-1. On September 22^nd, he could not have travelled to Hospital-3 or Hospital-4. Hence, he must have travelled to Hospital-2 or Hospital-1 (depending on where he travelled to on September 18^th). Hence, on September 18^th and September 22^nd, he must have travelled to Hospital-2 and Hospital-1 in any order.
On September 26^th, he could not have travelled to Hospital-2, Hospital-1, or Hospital-4. Hence, he must have travelled to Hospital-3.
On October 1^st, he could not have travelled to Hospital-1 or Hospital-2 (because he would have left any Hospital earliest by September 22^nd). Hence, he must have travelled to Hospital-4.
On October 7^th, he could have travelled to Hospital-2 or Hospital-1. But he reached Hospital-2 on 13^th, hence, he must have travelled to Hospital-1 on October 7^th.

Case 2: We can consider the case that he travelled to Hospital-3 on September 4^th and Hospital-1 on September 7^th.
In this case, all the instances when he travelled to Hospital-1 in the previous case, he travelled to Hospital-3 and vice versa.
The possible cases are presented in the following table:

In case 1, Mr. Smith stayed in Hospital-1 for 10 days and in case 2, he stayed in Hospital-1 for 9 days.
So, option 4 is correct.

Only one goal was scored in every odd-numbered game.

Emma recorded two goals in Game 4.

Goals scored in Game 1, Game 2 and Game 4 are in GP.
Let the common ratio be r.

Goals scored should be a real number and total goals should be 14, so the only possible value of r is 2.

The game with the second highest number of goals scored is Game 6.
As the sum of scores is 14 and already in the above table 10 goals have been scored; in Game 6, the score will be 3 and the Game 8 score will be 1.

No two players had the same total number of goals.
So, their individuals score will be 2, 3, 4, and 5 as this is the only possible way for the sum to be 14.
Emma emerged as a dominant scorer – it means Emma scored 5 goals.
Hannah is known for her lowest scoring capabilities, and scored in Game 2 and Game 8.
The player with the highest number of goals achieved this feat scoring in exactly four games, including Game 3 and Game 7.

Olivia and Grace both scored 2 goals each in Game 4 and Game 6, respectively.

Either Olivia's score is 3 and Grace score's is 4 or Olivia's score is 4 and Grace's score is 3.
Based on the information provided:

Only one goal was scored in every odd-numbered game.

Emma recorded two goals in Game 4.

Goals scored in Game 1, Game 2 and Game 4 are in GP.
Let the common ratio be r.

Goals scored should be a real number and total goals should be 14, so the only possible value of r is 2.

The game with the second highest number of goals scored is Game 6.
As the sum of scores is 14 and already in the above table 10 goals have been scored; in Game 6, the score will be 3 and the Game 8 score will be 1.

No two players had the same total number of goals.
So, their individuals score will be 2, 3, 4, and 5 as this is the only possible way for the sum to be 14.
Emma emerged as a dominant scorer – it means Emma scored 5 goals.
Hannah is known for her lowest scoring capabilities, and scored in Game 2 and Game 8.
The player with the highest number of goals achieved this feat scoring in exactly four games, including Game 3 and Game 7.

Olivia and Grace both scored 2 goals each in Game 4 and Game 6, respectively.

Either Olivia's score is 3 and Grace score's is 4 or Olivia's score is 4 and Grace's score is 3.
Based on the information provided:

Given that from September 1^st to September 4^th, he was in Hospital-2.
On September 4^th, he starts a journey. He cannot be travelling to Hospital-2 or Hospital-4, since he left Hospital-4 and reached Hospital-2 on September 1^st.
Hence, he could have travelled to Hospital-1 or Hospital-3.

On September 7^th, he could not have travelled to Hospital-2 or Hospital-4 because he left Hospital-4 and Hospital-2 on September 1^st and September 4^th respectively (in both cases, ten days have not elapsed). Hence, he could have travelled to Hospital-3 or Hospital-1 on September 7^th (depending on where he travelled to on September 4^th). Hence, on September 4^th and September 7^th, he must have travelled to Hospital-3 and Hospital-1 in any order.
On September 13^th, he could not have travelled to Hospital-2 (because he left Hospital-2 on September 4^th and cannot travel to Hospital-2 until after September 14^th. He could not have travelled to Hospital-3 or Hospital-1. Hence, he must have travelled to Hospital-4.

Case 1: Consider that he travelled to Hospital-1 on September 4^th and Hospital-3 on September 7^th.
On September 18^th, he could not have travelled to Hospital-3. Hence, he must have travelled to Hospital-2 or Hospital-1. On September 22^nd, he could not have travelled to Hospital-3 or Hospital-4. Hence, he must have travelled to Hospital-2 or Hospital-1 (depending on where he travelled to on September 18^th). Hence, on September 18^th and September 22^nd, he must have travelled to Hospital-2 and Hospital-1 in any order.
On September 26^th, he could not have travelled to Hospital-2, Hospital-1, or Hospital-4. Hence, he must have travelled to Hospital-3.
On October 1^st, he could not have travelled to Hospital-1 or Hospital-2 (because he would have left any Hospital earliest by September 22^nd). Hence, he must have travelled to Hospital-4.
On October 7^th, he could have travelled to Hospital-2 or Hospital-1. But he reached Hospital-2 on 13^th, hence, he must have travelled to Hospital-1 on October 7^th.

Case 2: We can consider the case that he travelled to Hospital-3 on September 4^th and Hospital-1 on September 7^th.
In this case, all the instances when he travelled to Hospital-1 in the previous case, he travelled to Hospital-3 and vice versa.
The possible cases are presented in the following table:

From the above table it is clear that if Mr. Smith stayed in Hospital-3 on September 19, then on October 10th he stayed in Hospital-3.

Given that from September 1^st to September 4^th, he was in Hospital-2.
On September 4^th, he starts a journey. He cannot be travelling to Hospital-2 or Hospital-4, since he left Hospital-4 and reached Hospital-2 on September 1^st.
Hence, he could have travelled to Hospital-1 or Hospital-3.

On September 7^th, he could not have travelled to Hospital-2 or Hospital-4 because he left Hospital-4 and Hospital-2 on September 1^st and September 4^th respectively (in both cases, ten days have not elapsed). Hence, he could have travelled to Hospital-3 or Hospital-1 on September 7^th (depending on where he travelled to on September 4^th). Hence, on September 4^th and September 7^th, he must have travelled to Hospital-3 and Hospital-1 in any order.
On September 13^th, he could not have travelled to Hospital-2 (because he left Hospital-2 on September 4^th and cannot travel to Hospital-2 until after September 14^th. He could not have travelled to Hospital-3 or Hospital-1. Hence, he must have travelled to Hospital-4.

Case 1: Consider that he travelled to Hospital-1 on September 4^th and Hospital-3 on September 7^th.
On September 18^th, he could not have travelled to Hospital-3. Hence, he must have travelled to Hospital-2 or Hospital-1. On September 22^nd, he could not have travelled to Hospital-3 or Hospital-4. Hence, he must have travelled to Hospital-2 or Hospital-1 (depending on where he travelled to on September 18^th). Hence, on September 18^th and September 22^nd, he must have travelled to Hospital-2 and Hospital-1 in any order.
On September 26^th, he could not have travelled to Hospital-2, Hospital-1, or Hospital-4. Hence, he must have travelled to Hospital-3.
On October 1^st, he could not have travelled to Hospital-1 or Hospital-2 (because he would have left any Hospital earliest by September 22^nd). Hence, he must have travelled to Hospital-4.
On October 7^th, he could have travelled to Hospital-2 or Hospital-1. But he reached Hospital-2 on 13^th, hence, he must have travelled to Hospital-1 on October 7^th.

Case 2: We can consider the case that he travelled to Hospital-3 on September 4^th and Hospital-1 on September 7^th.
In this case, all the instances when he travelled to Hospital-1 in the previous case, he travelled to Hospital-3 and vice versa.
The possible cases are presented in the following table:

Mr. Smith did not travel from Hospital-2 to Hospital-4 during the given period.

From (2), Company A should have an MRP of Rs. 20 or Rs. 25.
From (4), Company D should have an MRP of Rs. 15 or Rs. 20 or Rs. 25.
From (6), he sold two ice-creams of Company B. He sold ice-cream of another company to Lacy and Kevin. Hence, Mr. Webster would have sold exactly one ice-cream of all the other companies.
From (5), Theon bought an ice-cream from ice-cream company with MRP of Rs. 15. Hence, Company D will not have Rs. 15 as MRP.
From (4), Mr. Webster sold an ice-cream at price of Rs. 23. This cannot be of Company D (since he sold an ice-cream at price of Rs. 11 of Company D).
Therefore, Company A will have an MRP of Rs. 25 and Company D will have an MRP of Rs. 20.
Mr. Webster could not have sold an ice-cream of Company A to Kevin, Lacy, Abigail, Avril, Lexie or Theon. Hence, Mr. Webster sold an ice-cream to Terry of Company A.
From (6), Company E will have an MRP of Rs. 15.
Also, from (3), he sold ice-creams to Kevin and Lacy of Company C.
From (5), Mr. Webster sold an ice-cream of Company E to Theon and sold an ice-cream of Company B to Lexie and Avril.

The following table presents this information.

Let the number of normal bookings in August be 'a'. The construction of the following table shall be useful.

Now, if we see the column for October,
Number of deliveries made in October = Number of normal bookings in September + Number of discounted bookings in August
790 = 272 + 1135 - a
Or, a = 617
Now, the value of 'a' can be verified from the column for November.
Number of deliveries made in November = Number of discounted bookings in September = 148 + a
Putting 'a' as 617 in the above equation, we get the number of deliveries in November as 148 + 617 = 765
This is given in the table.
Now, substituting the value of 'a' as 617 in the above table, we get the following table.

et the price be Rs. 100.
So, the premium is Rs. 5 per premium booking and the discount is Rs. 2 per discounted booking.
Let us now evaluate the total premium collected and the total discount given month wise.
The construction of the following table shall be useful.

From the above table, it is evident that the premium collected was more than the discount given for the months of May, August and September i.e. for 3 months.

Let the number of normal bookings in August be 'a'. The construction of the following table shall be useful.

Now, if we see the column for October,
Number of deliveries made in October = Number of normal bookings in September + Number of discounted bookings in August
790 = 272 + 1135 - a
Or, a = 617
Now, the value of 'a' can be verified from the column for November.
Number of deliveries made in November = Number of discounted bookings in September = 148 + a
Putting 'a' as 617 in the above equation, we get the number of deliveries in November as 148 + 617 = 765
This is given in the table.
Now, substituting the value of 'a' as 617 in the above table, we get the following table.

The construction of the following table shall be useful now.

From the above table, it is obvious that the number of premium bookings as a percentage of total number of bookings is the highest for the month of August. Hence, answer option (1) is correct.

From (2), Company A should have an MRP of Rs. 20 or Rs. 25.
From (4), Company D should have an MRP of Rs. 15 or Rs. 20 or Rs. 25.
From (6), he sold two ice-creams of Company B. He sold ice-cream of another company to Lacy and Kevin. Hence, Mr. Webster would have sold exactly one ice-cream of all the other companies.
From (5), Theon bought an ice-cream from ice-cream company with MRP of Rs. 15. Hence, Company D will not have Rs. 15 as MRP.
From (4), Mr. Webster sold an ice-cream at price of Rs. 23. This cannot be of Company D (since he sold an ice-cream at price of Rs. 11 of Company D).
Therefore, Company A will have an MRP of Rs. 25 and Company D will have an MRP of Rs. 20.
Mr. Webster could not have sold an ice-cream of Company A to Kevin, Lacy, Abigail, Avril, Lexie or Theon. Hence, Mr. Webster sold an ice-cream to Terry of Company A.
From (6), Company E will have an MRP of Rs. 15.
Also, from (3), he sold ice-creams to Kevin and Lacy of Company C.
From (5), Mr. Webster sold an ice-cream of Company E to Theon and sold an ice-cream of Company B to Lexie and Avril.

The following table presents this information.

Mr. Webster sold Company C ice-creams to two customers.

Let the number of normal bookings in August be 'a'. The construction of the following table shall be useful.

Now, if we see the column for October,
Number of deliveries made in October = Number of normal bookings in September + Number of discounted bookings in August
790 = 272 + 1135 - a
Or, a = 617
Now, the value of 'a' can be verified from the column for November.
Number of deliveries made in November = Number of discounted bookings in September = 148 + a
Putting 'a' as 617 in the above equation, we get the number of deliveries in November as 148 + 617 = 765
This is given in the table.
Now, substituting the value of 'a' as 617 in the above table, we get the following table.

There were 577 discounted bookings of tablets in May.

Let the number of normal bookings in August be 'a'. The construction of the following table shall be useful.

Now, if we see the column for October,
Number of deliveries made in October = Number of normal bookings in September + Number of discounted bookings in August
790 = 272 + 1135 - a
Or, a = 617
Now, the value of 'a' can be verified from the column for November.
Number of deliveries made in November = Number of discounted bookings in September = 148 + a
Putting 'a' as 617 in the above equation, we get the number of deliveries in November as 148 + 617 = 765
This is given in the table.
Now, substituting the value of 'a' as 617 in the above table, we get the following table.

From July to August, there was the highest increase in premium bookings of tablets, i.e 362 - 183 = 179

Only one goal was scored in every odd-numbered game.

Emma recorded two goals in Game 4.

Goals scored in Game 1, Game 2 and Game 4 are in GP.
Let the common ratio be r.

Goals scored should be a real number and total goals should be 14, so the only possible value of r is 2.

The game with the second highest number of goals scored is Game 6.
As the sum of scores is 14 and already in the above table 10 goals have been scored; in Game 6, the score will be 3 and the Game 8 score will be 1.

No two players had the same total number of goals.
So, their individuals score will be 2, 3, 4, and 5 as this is the only possible way for the sum to be 14.
Emma emerged as a dominant scorer – it means Emma scored 5 goals.
Hannah is known for her lowest scoring capabilities, and scored in Game 2 and Game 8.
The player with the highest number of goals achieved this feat scoring in exactly four games, including Game 3 and Game 7.

Olivia and Grace both scored 2 goals each in Game 4 and Game 6, respectively.

Either Olivia's score is 3 and Grace score's is 4 or Olivia's score is 4 and Grace's score is 3.
Based on the information provided:

Sum of goals scored in Game 6, Game 7 and Game 8 = 3 + 1 + 1 = 5
Sum of goals scored in Game 4 and Game 5 = 4 + 1 = 5
So, statement (i) is correct.
Statement (ii) is wrong.