Reasoning Ability Test - 3 - Bank Exams MCQ

1) E is the mother of F.

2) E is the daughter of D, who is wife of B.

3) E is the only child (imply daughter) of her parents.

4) A is the son in law of B, it means A is the husband of E and father of F.

5) C is the uncle of F. As E is the only child of B and D it imply that C is the brother of A.

6) There are equal number of male and female B, D, C are male and E, D, F are female.

Hence, C is the brother of A.

1) E is the mother of F.

2) E is the daughter of D, who is wife of B.

3) E is the only child (imply daughter) of her parents.

4) A is the son in law of B, it means A is the husband of E and father of F.

5) C is the uncle of F. As E is the only child of B and D it imply that C is the brother of A.

6) There are equal number of male and female B, D, C are male and E, D, F are female.

All except E - C are from different generation.

Given statements: C > D ≥ T, A = M ≥ R, D = K < M < E

On combining: C > D = K < M ≥ R, E> M = A, D ≥ T

Conclusion:

I. E ≥ R →False (As E > M ≥ R)

II. C ≥ R →False (As C > D = K < M ≥ R thus clear relation between C and R cannot be determined)

Hence, neither conclusion I nor II is true.

As per the given information,

1)B is the father-in-law of O.

2) P is the brother-in-law of O. O and P has same gender.

3) S is the only daughter of V, who is the maternal grandmother of H.

4) P has only one brother. H is the niece of G.

Hence, G is the brother of S.

As per the given information,

1) B is the father-in-law of O.

2) P is the brother-in-law of O. O and P has same gender.

3) S is the only daughter of V, who is the maternal grandmother of H.

4) P has only one brother. H is the niece of G.

Hence, V has three children is the correct answer.

As per the given information,

1)B is the father-in-law of O.

2) P is the brother-in-law of O. O and P has same gender.

3) S is the only daughter of V, who is the maternal grandmother of H.

4) P has only one brother. H is the niece of G.

Hence, Both G and P are the uncles of H.

Given:

Seven persons - A, B, C, D, E, F, and G - Facing North

1) B sits second from one of the ends.

2) Only two persons are sitting between B and A.

3) The number of persons sitting to the left of A is the same as the right of G.

4) The number of persons sitting between A and G is the same as between E and F.

5) E and G are not immediate neighbours.

6) C sits to the right of E but is not an immediate neighbour of B. This is not possible in Case II so it gets eliminated.

Thus, the final arrangement is -

D, who sits second to the left of G, sits immediate left of B.

Hence, the correct answer is The one who sits second to the left of G.

Given:

Seven persons - A, B, C, D, E, F, and G - Facing North

1) B sits second from one of the ends.

2) Only two persons are sitting between B and A.

3) The number of persons sitting to the left of A is the same as the right of G.

4) The number of persons sitting between A and G is the same as between E and F.

5) E and G are not immediate neighbours.
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6) C sits to the right of E but is not an immediate neighbour of B. This is not possible in Case II so it gets eliminated.

Thus, the final arrangement is -

One person is between C & A and E & F.

In the similar way, G, who sits third from the left end is related to D.

Hence, the correct answer is The one who sits third from the left end.

Given:

Seven persons - A, B, C, D, E, F, and G - Facing North

1) B sits second from one of the ends.

2) Only two persons are sitting between B and A.

3) The number of persons sitting to the left of A is the same as the right of G.

4) The number of persons sitting between A and G is the same as between E and F.

5) E and G are not immediate neighbours.

6) C sits to the right of E but is not an immediate neighbour of B. This is not possible in Case II so it gets eliminated.

Thus, the final arrangement is -

Three persons are sitting between C and G.

Hence, the correct answer is Three.

Given:

Seven persons - A, B, C, D, E, F, and G - Facing North

1) B sits second from one of the ends.

2) Only two persons are sitting between B and A.

3) The number of persons sitting to the left of A is the same as the right of G.

4) The number of persons sitting between A and G is the same as between E and F.

5) E and G are not immediate neighbours.
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6) C sits to the right of E but is not an immediate neighbour of B. This is not possible in Case II so it gets eliminated.

Thus, the final arrangement is -

F is third to the left of D.

Hence, the correct answer is Third to the right.

1) A is heavier than B but lighter than C.

2) D is lighter C than but not the lightest.

C > A/D > A/D > B

3) C is not heaviest. since we don't know definite position of D and A.

E > C > A/D > A/D > B

4) Number of persons heavier than A and number of persons lighter than C are equal. Here no. of persons lighter than C is 3. Then no. of persons heavier than A should be 3

E > C > D > A > B

5) Weight of the second lightest is 45kg.

E > C > D > A (45 kg) > B

Hence, The third heaviest is D.

1) A is heavier than B but lighter than C.

2) D is lighter C than but not the lightest.

C > A/D > A/D > B

3) C is not heaviest. since we don't know definite position of D and A.

E > C > A/D > A/D > B

4) Number of persons heavier than A and number of persons lighter than C are equal. Here no. of persons lighter than C is 3. Then no. of persons heavier than A should be 3

E > C > D > A > B

5) Weight of the second lightest is 45 kg.

E > C > D > A (45 kg) > B

Since C and D is 2nd and 3rd in weights respectively

Hence, The answer is None.

Given statement,

C > H ≥ K = Y > F ≤ J

Conclusions:

I. C < F → False (As we can see that C > H ≥ K = Y > F, so C < F is false)

II. H ≥ J → False (As we can see that H ≥ K = Y > F ≤ J, here the relation between H and J cannot be determined. So, H ≥ J is false)

Hence, neither I nor II follows.

Given statement,

H ≤ A > N = Y < S = D

Conclusions:

I. D > A → False (As we can see that A > N = Y < S = D, here the relation between D and A cannot be determined. So, D > A is false)

II. A > S → False (As we can see that A > N = Y < S, here the relation between A and S cannot be determined. So, A > S is false)

Hence, neither I nor II follows.

Eight boxes: 1 to 8

Eight books: History, Geography, Physics, Chemistry, Botany, Zoology, Mathematics, and Computer.

1) Mathematics is kept in the topmost box.

2) Only three boxes are kept below Geography.

3) Physics is kept immediately above History and immediately below Computer.

4) Only two boxes are kept between Geography and History. (This eliminates Case 2)

5) Botany is kept above Zoology and kept below Chemistry.

Hence, 'History' is kept at the bottom most box.

Eight boxes: 1 to 8

Eight books: History, Geography, Physics, Chemistry, Botany, Zoology, Mathematics, and Computer.

1) Mathematics is kept in the topmost box.

2) Only three boxes are kept below Geography.

3) Physics is kept immediately above History and immediately below Computer.

4) Only two boxes are kept between Geography and History. (This eliminates Case 2)

5) Botany is kept above Zoology and kept below Chemistry.

Hence, 'two' boxes are there between the box on which Chemistry is kept and the box on which Geography is kept.

Eight boxes: 1 to 8

Eight books: History, Geography, Physics, Chemistry, Botany, Zoology, Mathematics, and Computer.

1) Mathematics is kept in the topmost box.

2) Only three boxes are kept below Geography.

3) Physics is kept immediately above History and immediately below Computer.

4) Only two boxes are kept between Geography and History. (This eliminates Case 2)

5) Botany is kept above Zoology and kept below Chemistry.

The number of boxes above the box on which Botany is kept is 2 and the same as the number of boxes below the box on which Computer is kept is also 2.

Hence, Computer is the correct answer.

Eight boxes: 1 to 8

Eight books: History, Geography, Physics, Chemistry, Botany, Zoology, Mathematics, and Computer.

1) Mathematics is kept in the topmost box.

2) Only three boxes are kept below Geography.

3) Physics is kept immediately above History and immediately below Computer.

4) Only two boxes are kept between Geography and History. (This eliminates Case 2)

5) Botany is kept above Zoology and kept below Chemistry.

All the boxes are kept in the odd number box except Physics, while Physics is kept in the even number box.

Hence, 'Physics' does not belong to that group.

Eight boxes: 1 to 8

Eight books: History, Geography, Physics, Chemistry, Botany, Zoology, Mathematics, and Computer.

1) Mathematics is kept in the topmost box.

2) Only three boxes are kept below Geography.

3) Physics is kept immediately above History and immediately below Computer.

4) Only two boxes are kept between Geography and History. (This eliminates Case 2)

5) Botany is kept above Zoology and kept below Chemistry.

Hence, Zoology is kept in box number 5.

Person: K, L, M, N, O, P, Q, and R.

Month: January, April, June, and August

Dates: 8^th & 15^th

1) K delivers his lecture on the 8^th of a month which has only 30 days.

2) Only three lectures were delivered between K and L.

3) O delivers the lecture immediately after L.

(Here 2 cases are possible, Case1: K delivers his lecture on the 8^th of April, Case2: K delivers his lecture on the 8^th of June.

Case 1:

Case 2:

4) Number of persons who give the lecture after O is the same as the number of persons who give the lecture before P.

5) Only two persons give lectures between P and M.

Case 1:

Case 2:

6) Q and M give their lectures in the same month.

(From here Case 1 is eliminated because no vacant position for Q as according to statement 6 Q and M give their lecture in the same month)

7) N gives the lecture before R.

The final arrangement will be as follows:

Hence, P gives the lecture on 8th August.

Person: K, L, M, N, O, P, Q, and R.

Month: January, April, June, and August

Dates: 8th & 15th

1) K delivers his lecture on the 8th of a month which has only 30 days.

2) Only three lectures were delivered between K and L.

3) O delivers the lecture immediately after L.

(Here 2 cases are possible, Case1: K delivers his lecture on the 8th of April, Case2: K delivers his lecture on the 8th of June.

Case 1:

Case 2:

4) Number of persons who give the lecture after O is the same as the number of persons who give the lecture before P.

5) Only two persons give lectures between P and M.

Case 1:

Case 2:

6) Q and M give their lectures in the same month.

(From here Case 1 is eliminated because no vacant position for Q as according to statement 6 Q and M give their lecture in the same month)

7) N gives the lecture before R.

The final arrangement will be as follows:

Hence, 5 lectures were delivered after Q.

Person: K, L, M, N, O, P, Q, and R.

Month: January, April, June, and August

Dates: 8th & 15th

1) K delivers his lecture on the 8th of a month which has only 30 days.

2) Only three lectures were delivered between K and L.

3) O delivers the lecture immediately after L.

(Here 2 cases are possible, Case1: K delivers his lecture on the 8th of April, Case2: K delivers his lecture on the 8th of June.

Case 1:

Case 2:

4) Number of persons who give the lecture after O is the same as the number of persons who give the lecture before P.

5) Only two persons give lectures between P and M.

Case 1:

Case 2:

6) Q and M give their lectures in the same month.

(From here Case 1 is eliminated because no vacant position for Q as according to statement 6 Q and M give their lecture in the same month)

7) N gives the lecture before R.

The final arrangement will be as follows:

Hence, L doesn’t deliver the lecture in the month having 30 days.

Person: K, L, M, N, O, P, Q, and R.

Month: January, April, June, and August

Dates: 8th & 15th

1) K delivers his lecture on the 8th of a month which has only 30 days.

2) Only three lectures were delivered between K and L.

3) O delivers the lecture immediately after L.

(Here 2 cases are possible, Case1: K delivers his lecture on the 8th of April, Case2: K delivers his lecture on the 8th of June.

Case 1:

Case 2:

4) Number of persons who give the lecture after O is the same as the number of persons who give the lecture before P.

5) Only two persons give lectures between P and M.

Case 1:

Case 2:

6) Q and M give their lectures in the same month.

(From here Case 1 is eliminated because no vacant position for Q as according to statement 6 Q and M give their lecture in the same month)

7) N gives the lecture before R.

The final arrangement will be as follows:

Hence, M gives the lecture on 15th April.

Persons:- J, K, L, M, N and O

Colours:- Black, Blue, Red, Grey, Yellow and Pink

1) Four persons buy shirt between K and J, who buys Red shirt.

2) K buys neither Pink nor Black shirt and is not the last to buy the shirt.

3) N buys grey colour shirt and three persons bought shirt between N and K.

4) M buys Yellow shirt and no person buys shirt between K and M.

5) O buys immediately before L and doesn’t buy Pink and Blue shirt.

Hence, we can conclude that L likes Pink colour. K likes Blue colour and O likes Black colour.

Hence, L buys shirt of pink colour.

Persons:- J, K, L, M, N and O

Colours:- Black, Blue, Red, Grey, Yellow and Pink

1) Four persons buy shirt between K and J, who buys Red shirt.

2) K buys neither Pink nor Black shirt and is not the last to buy the shirt.

3) N buys grey colour shirt and three persons bought shirt between N and K.

4) M buys Yellow shirt and no person buys shirt between K and M.

5) O buys immediately before L and doesn’t buy Pink and Blue shirt.

Hence, we can conclude that L likes Pink colour. K likes Blue colour and O likes Black colour.

After arranging, only position of N remains unchanged.

Hence, “One” is the correct answer.

Persons:- J, K, L, M, N and O

Colours:- Black, Blue, Red, Grey, Yellow and Pink

1) Four persons buy shirt between K and J, who buys Red shirt.

2) K buys neither Pink nor Black shirt and is not the last to buy the shirt.

3) N buys grey colour shirt and three persons bought shirt between N and K.

4) M buys Yellow shirt and no person buys shirt between K and M.

5) O buys immediately before L and doesn’t buy Pink and Blue shirt.

Hence, we can conclude that L likes Pink colour. K likes Blue colour and O likes Black colour.

Hence, O buys Black colour shirt.

Persons:- J, K, L, M, N and O

Colours:- Black, Blue, Red, Grey, Yellow and Pink

1) Four persons buy shirt between K and J, who buys Red shirt.

2) K buys neither Pink nor Black shirt and is not the last to buy the shirt.

3) N buys grey colour shirt and three persons bought shirt between N and K.

4) M buys Yellow shirt and no person buys shirt between K and M.

5) O buys immediately before L and doesn’t buy Pink and Blue shirt.

Hence, we can conclude that L likes Pink colour. K likes Blue colour and O likes Black colour.

Hence, L buys shirt immediately after the one who buys Black shirt.

Venn diagram for the given statements are follows.

Conclusions

I. All Ball being Tennis is a possibility - True (Because the definite relation is not given between Ball and Tennis thus All Ball being Tennis is a possibility follows)

II. Some Tennis are Football - False (Because the definite relation is not given between Tennis and Football thus Some Tennis are Football not follows)

Hence, Only I follows.

Given statements:

F ≤ D; A < B = C; D ≤ E < C

On combining we get: A < B = C > E ≥ D ≥ F

Conclusions:

I. E > F → False (as E ≥ D ≥ F → E ≥ F)

II. E = F → False (as E ≥ D ≥ F → E ≥ F)

Note: Conclusion I and II are complementary pairs.

Hence, either conclusion I or II is true.

The possible diagram from the given information,

Conclusions:

I. All Samsung is MI. → False (as only a few Samsung is MI that means some Samsung is MI and Some Samsung is not MI)

II. Some Samsung are MI. → True (as only a few Samsung is MI that means some Samsung is MI and Some Samsung is not MI)

Hence, only conclusion II follows.