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GATE Engineering Sciences Mock Test - 1 - GATE Engineering Sciences MCQ


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30 Questions MCQ Test - GATE Engineering Sciences Mock Test - 1

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GATE Engineering Sciences Mock Test - 1 - Question 1

If θ is the angle, in degrees, between the longest diagonal of the cube and any one of the edges of the cube, then, cos θ =

GATE Engineering Sciences Mock Test - 1 - Question 2

Choose the word which is least like 'REMISS

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 2

The meaning of the word REMISS is lacking care or attention to duty; negligent.

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GATE Engineering Sciences Mock Test - 1 - Question 3


A transparent square sheet shown above is folded along the dotted line. The folded sheet will look like ________. 

GATE Engineering Sciences Mock Test - 1 - Question 4

How Many Triangles and Straight lines are there?

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 4

No. of Straight lines: AB, BC, CA, AD, AE, GD, GC, DF = 8
No. ofTriangles: ABC, ABD, ADE, AEC, ABE, ADC, AGC, BGC, BGD, DGC, GDH, HDI, GDI, DIE, IEC, DIC, AIC, AIJ, JIC, AGI, AGH, AHI = 22

GATE Engineering Sciences Mock Test - 1 - Question 5

Nine persons are standing in a 3 X 3 matrix arrangement. Reena is the tallest amongst the shortest persons of each row whereas Seema is the shortest amongst the tallest person in each column. Which of the following cannot be concluded based on these two statements?

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 5

We can have three possible scenarios:
(I) : Reena and Seema are in the same row. Since Reena is the shortest person in the row, Seema is taller than Reena.
(II) : Reena and Seema are in the same column; once again Seema is taller than Reena since Seema is tallest in the column.
(III) : Reena and Seema are neither in the same row nor in the same column. In this case, there has to a person 'X' who is in the same row as Reena and in the same column as Seema. Now, Reena is shorter than ' X' who is shorter than Seema; which again leads us to conclude that Seema is taller than Reena.

GATE Engineering Sciences Mock Test - 1 - Question 6

The number of students in three classes is in the ratio 3:13:6. If 18 students are added to each class, the ratio changes to 15:35:21.

The total number of students in all the three classes in the beginning was:

GATE Engineering Sciences Mock Test - 1 - Question 7

In a chess competition involving some boys and girls of a school, every student had to play exactly one game with every other student. It was found that in 45 games both the players were girls and in 190 games both were boys. The number of games in which one player was a boy and the other was a girl is

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 7

Number of games between two girls = gC2
Number of games between two boys = bC2

Also,


The total of games = 
Number of games in which one player is a boy and the other is a girl = 435 - 45  - 190 = 200

GATE Engineering Sciences Mock Test - 1 - Question 8

Let C be the boundary of the region R ∶ 0 ≤ x ≤ π, 0 ≤ y ≤ sin x in the xy-plane and α be the area of the region R. If C traverses once in the counter clockwise direction, then the value of the line integral  ∮c (2y dx + 5x dy) is equal to 

GATE Engineering Sciences Mock Test - 1 - Question 9

Given that i = √-1. The value of  is 

GATE Engineering Sciences Mock Test - 1 - Question 10

If the eigen values ofa 4 x 4 matrix A are 2, 4, 7, -3 then the rank ofa matrix A is

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 10

Given that the eigen values of A are 2, 4, 7, -3
⇒ all the eigen values of A are non-zero number but we know that
|A| =  product of eigen values of A
⇒ IAI = (2)(4)(7)(-3) ≠ 0
⇒ |A| ≠ 0
The rank of a matrix A4x4 is 4, ( since if Anxn I ≠ 0 then ρ(Anxn) = n

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 1 - Question 11

If the numerical approximation of the value of the integral  using the Trapezoidal rule with two subintervals is 9, then the value of the real constant α is __________________ (round off to one decimal place).


*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 1 - Question 12

Let the transformation y(x) = exv(x) reduce the ordinary differential equation   to  where α, β, γ are real constants. Then, the arithmetic mean of α, β, γ is ______________ (round off to three decimal places).


GATE Engineering Sciences Mock Test - 1 - Question 13

In a factory, machine A produces 40 % of the output and machine B produces 60 %. On an average, 9 items in 1000 produced by A are defective and 1 item in 250 produced by B is defective. An item drawn at random from a day's output is defective. What is the probability that it was produced by A?

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 13

Output produced by A = 40%
P(A) = 0.4
Output produced by B
P(B) = 0.6
Let, 
∴ 
similarly, 
 = Probability that product is produced by A given that it is defective.


= 0.6

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 1 - Question 14

For dy/dx = x + y2, given that y = 1 at x = 0;  value of y at 0.2, using Runge Kutta fourth order method (h = 0.2) will be ______ (Upto 4 decimal places)


Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 14

Give, xo = 0 yo = 1 h = 0.2

∴ 

GATE Engineering Sciences Mock Test - 1 - Question 15

Consider the fully-developed flow of a Newtonian fluid (density ρ ; viscosity μ) through a smooth pipe of diameter D and length L . The average velocity of the flow is V . If the length of the pipe is doubled, keeping V ,D, ρ, μ constant, the friction factor

GATE Engineering Sciences Mock Test - 1 - Question 16

The head loss (KL) associated with the flow entry of water to an internal passage depends on the shape of the entry. The following figure shows three different types of flow entry into a pipe. Which one of the following relationships correctly represents the head loss associated with the three different flow entries?

GATE Engineering Sciences Mock Test - 1 - Question 17

When a circular cylinder is placed in a uniform stream, a stagnation point is created on thecylinder as shown in Fig. a. If a small hole is located at this point, the stagnation pressure, pstag ,can be measured and used to determine the approach velocity, U.

How pstag  and U are related.

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 17

The velocity at the stagnation point is zero so the Bernoulli equation written between a point on thestagnation streamline upstream from the cylinder and the stagnation point gives

Thus,

GATE Engineering Sciences Mock Test - 1 - Question 18

If the flow curves of two viscous fluid are represented by

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 18

The above graph shows variation of shear stress vs. strain rate for a Newtonian fluid. For a Newtonian fluid, viscosity does not change with strain rate and the slope on shear stress vs. strain rate represents viscosity, greater the slope, greater is the viscosity. 'a' has more slope than 'b', hence it is more viscous than 'b'.

GATE Engineering Sciences Mock Test - 1 - Question 19

Which one of the following statements is TRUE about the continuity equation  (where u, v, w are the velocity components along the x, y, and z coordinates respectively):

GATE Engineering Sciences Mock Test - 1 - Question 20

A metal ball 'A' of density 3200 kg/m³ is dropped in water, while another metal ball 'B' of density 6000 kg/m³ is dropped in a liquid of density 1600 kg/m³. If both the balls have the same diameter and attain the same terminal velocity, the ratio of viscosity of water to that of the liquid is (Assume Re << 1).

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 20

From Stoke's law:

Fᴅ = 6πμrV

For a sphere, if the viscous force becomes equal to the net weight, then:

Fᴅ + Fʙ = W

Fᴅ = W − Fʙ

6πμrVₜ = (4/3)πr³(ρᵦ − ρₗ)g

Vₜ = (2/9) r² g (ρᵦ − ρₗ) / μ

(Vₜ)ₐ / (3200 − 1000) / μₓ = (Vₜ)ᵦ / (6000 − 1600) / μₗ

μᵥ / μₜ = 2200 / 4400

μᵥ / μₜ = 0.5

*Multiple options can be correct
GATE Engineering Sciences Mock Test - 1 - Question 21

A large thin plate is pulled through a narrow gap filled with a fluid ofviscosity on the upper side and a fluid of viscosity cg on the lower side. Derive an expressionfor the location of the plate in the gap for the total force to be minimum.

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 21

The force will not be minimum if the plate is centrally located as the viscosity are notequal. Let the plate be located at a distance of y from the lower surface on the side where theviscosity is cμ. Let the gap size be h, the total force for unit area will be

At the minimum conditions the slope i.e., the derivative dF/dy should be zero.

,
Equating to zero yields, y2 = c x(h - y)2

Taking the root,

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 1 - Question 22

A two-dimensional incompressible fluid flow is described thestream function ψ = xy3 m2/s on the Cartesian x-y plane. If thedensity and dynamic viscosity of the fluid are 1 kg/m3 and 0.1kg/ms respectively, the magnitude of pressure gradient in the x-N/m3.direction at x = 1 m and y = 1m is


Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 22

Using the definition of stream function:


Using Navier-Stokes equation of motion along the x-direction {As the fluid is viscous}:

ρg= 0 (No body forces(weight) act in x direction)

At (1, 1)
ax = 9 - 6 = 3

Thus:

dp/dx = -3.6 N/m3
Since only magnitude is asked, we will put the answer without sign.

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 1 - Question 23

A two-dimensional Eulerian velocity field is given (in m/s) by  where x and y are the coordinates (in meters) in a Cartesian coordinate system. The magnitude of the acceleration (in m/s2, up to one decimal place) of a fluid particle at x = 1 m and y = −1 m is ______.  


GATE Engineering Sciences Mock Test - 1 - Question 24

During the isothermal heat rejection process of a Carnot cycle, the working fluid experiences an entropy change of -1.3 kJ/K. If the temperature of the heat sink is 35°C, then the total entropy generation during this process is closest to...

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 24

Heat rejected by working fluid = (273 + 35) × 1.3 ≈ 400 kJ
Entropy increase of sink = 400 / 308 = 1.3 kJ/K
Total entropy change for the process = -1.3 + 1.3 = 0 kJ/K

GATE Engineering Sciences Mock Test - 1 - Question 25

The device 'D' shown below violates

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 25

The device shown does not violate any law because work can be completely converted into heat, but the reverse is not true.

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 1 - Question 26

A saturated liquid at 1500 KPa and 500 K, with an enthalpy of 750 kJ/Kg, is throttled to a liquid-vapour mixture at 150 kPa and 300 K. At the exit conditions, the enthalpy of the saturated liquid is 500 kJ/Kg and the enthalpy of the saturated vapour is 2500 kJ/Kg. The percentage of the original liquid which vaporizes is?


Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 26

During throttling, h1 = h2
h1 = 750 kJ/Kg (given)
h2 = 750 kJ/Kg
h2 = hf + x(hg - hf)
750 = 500 + x(2500 - 500)
x = 0.125
x = mv / (mv + mL) => 0.125 = mv / mt
mt = Total mass

Originally, total mass was in the liquid state, and in the final state, 0.125 of the liquid vaporizes.

Therefore, 12.5% of liquid vaporizes.

GATE Engineering Sciences Mock Test - 1 - Question 27

A rigid vessel having a capacity of 0.85 m³ contains steam at 12 bar and 0.92 quality. Steam is blown off until the pressure drops to 6 bar. The valve is then closed, and the vessel is cooled until the pressure is 4 bar. Assuming that during the blowing-off period, enthalpy per kg of steam remains constant in the vessel, the quantity of steam blown off is ______.

(Treat water as incompressible with density 1000 kg / m3)

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 27

Since enthalpy is the same during the blowing off period:
h₁ = h₂

h₁ = 798.4 + 0.92 × 1984.3 = 2623.95 kJ/kg
h₂ = 670.42 + x₂ × 2085 = 2623.95 kJ/kg
x₂ = 0.936

Since the volume of the vessel remains constant:
0.85 = x₁ × v₉₁ × m₁ = 0.92 × 0.1632 × m₁
m₁ = 5.66 kg

Also:
0.85 = x₂ × (v₉₂ - 0.001) × m₂
⇒ m₂ = 2.887 kg

Therefore, mass blown off = m₁ - m₂ = 2.77 kg

GATE Engineering Sciences Mock Test - 1 - Question 28

Two streams of air, one at 1 bar, 27°C and velocity of 30 m/s, and the other at 5 bar, 227°C and 50 m/s velocity, mix in equal proportion in a chamber from which heat at the rate of 100 kJ/kg is removed.
The mixture is then passed through an adiabatic nozzle. The velocity of the stream issuing out of the nozzle is given by ______ in (m/s), assuming the temperature of air leaving the nozzle is 27°C and its Cp = 1.005 kJ/kg·K.

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 28

From steady flow energy equation

By assuming mass flow rate is unit ( 1 kg / s)

​​​​​

GATE Engineering Sciences Mock Test - 1 - Question 29

An engine operating on the Diesel cycle has the following particulars: Pressure and volume at the beginning of isentropic compression is 100 kPa. Pressure after isentropic compression is 4.2 MPa. Pressure after isentropic expansion is 200 kPa. Determine the fuel cut-off ratio.

Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 29

P1 = 100 kPa, P2 = P3 = 4200 kPa, P4 = 200 kPa

Compression Ratio (rk):
rk = (P2 / P1)(1 / γ)
rk = (4200 / 100)(1 / 1.4) = 14.4365

Expansion Ratio (re):
re = (P3 / P4)(1 / γ)
re = (4200 / 200)(1 / 1.4) = 8.8

Fuel Cut-off Ratio (rc):
rc = rk / re = 14.4365 / 8.8 = 1.64

Answer: 1.6

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 1 - Question 30

An insulated rigid tank contains 42 kg of air at 550 kPa and 400 K. A valve connected to the tank is now opened, and air is allowed to escape until the mass of air inside the tank is 14 kg. The air temperature during the process is maintained constant by an electric resistance heater placed in the tank. The electrical energy (in kJ) supplied to air during the process is ______.


Detailed Solution for GATE Engineering Sciences Mock Test - 1 - Question 30

By writing energy balance for control volume, 

where,
mₑ = mass entering the control volume,
mₑ = mass leaving the control volume,
hᵢ = enthalpy of air entering the control volume,
hₑ = enthalpy of air leaving the control volume.

[Negative sign indicated that work is done on the system]

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