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Test: Gaseous State - 2 - Chemistry MCQ


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30 Questions MCQ Test - Test: Gaseous State - 2

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Test: Gaseous State - 2 - Question 1

A gas will approval ideal behaviour at:

Test: Gaseous State - 2 - Question 2

The rms velocity of hydrogen is times the rms velocity of nitrogen. It T is the temperature of the gas:

Detailed Solution for Test: Gaseous State - 2 - Question 2

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Test: Gaseous State - 2 - Question 3

The compressibility of a gas is less than unity at STP. Therefore,

Test: Gaseous State - 2 - Question 4

At 100°C and 1 at m if the density of the liquid water is 1.0 g cm–3 and that of water vapour is 0.0006 g cm–3, then the volume occupied by water molecules in 1 L of steam at this temperature is: 

Test: Gaseous State - 2 - Question 5

The root mean square velocity of an ideal gas at constant pressure varies with density (d) as

Test: Gaseous State - 2 - Question 6

Which of the following volume (V) temperature (T) plots presents the behaviour of one mole of an ideal gas at the atmospheric pressure?

Test: Gaseous State - 2 - Question 7

Positive deviation from ideal behaviour takes place because of:

Detailed Solution for Test: Gaseous State - 2 - Question 7

For positive deviations Z>1 the condition when repulsive forces predominates Also at high P,V is small and b cannot be ignored but the factor a/V2 can be neglected in comparison to P Thus.

Test: Gaseous State - 2 - Question 8

For a monatomic gas kinetic energy = E. The relation with rms velocity is:

Test: Gaseous State - 2 - Question 9

If helium and methane are allowed to diffuse out of the container under the similar conditions of temperature and pressure, then the ratio of rate of diffusion of helium to methane is:

Detailed Solution for Test: Gaseous State - 2 - Question 9

Test: Gaseous State - 2 - Question 10

The term that corrects for the attractive forces present in a real gas in the van der Waals’ equation is:

Test: Gaseous State - 2 - Question 11

The intermolecular interaction that is dependent on the inverse cube of distance between the molecule is:

Detailed Solution for Test: Gaseous State - 2 - Question 11

Ion-ion interaction α Z+ Z-/r2 

Ion- dipole interaction α 1/r3 

London Dispersion forces α 1/r6 

Hydrogen bond force α 1/r

Hence D is correct.

Test: Gaseous State - 2 - Question 12

One mole of a monoatomic real gas sat isfied the equation p(V – b) = RT where b is a constant. The relationship of interatomic potential V ( r) and interatomic distance r for the gas is given by:

Detailed Solution for Test: Gaseous State - 2 - Question 12

For a real gas

(P + an2/V2)(V – nb) = nRT

ATQ: P (V-nb) = RT

The extra term “an2/V2” comes because of the attractive forces, hence with a certain decrease in r V(r) remains constant.

But after a huge decrease repulsive forces will dominate and hence V(r) will increase abruptly.

Hence C is correct.

Test: Gaseous State - 2 - Question 13

Two closed bulbs of equal volume (V) containing an ideal gas initially at pressure pi and temperature T1 are connected through a narrow tube of negligible volume as shown in the figure below. The temperature of one of the bulb is then raised to T2. The final pressure pf is:

Detailed Solution for Test: Gaseous State - 2 - Question 13

Test: Gaseous State - 2 - Question 14

For one mole of a van der Waals’ gas when b = 0 and T = 300 K, the PV vs. 1/V plot is shown below. The value of the van der Waals’ constant a (atm. litre2 mo l–2) is:

Test: Gaseous State - 2 - Question 15

The factor,  represents (k is Boltzman’s constant):

Test: Gaseous State - 2 - Question 16

If Z is a compressibility factor, van der Waals’ equation at low pressure can be written as:

Test: Gaseous State - 2 - Question 17

A kid has been playing with an inflated balloon. Suddenly, a reaction happens inside the balloon. This causes the inside surface of the balloon to become sticky, so that some of the air molecules inside which collide against the surface get stuck to it. As a result, immediately after the reaction, the balloon will:

Test: Gaseous State - 2 - Question 18

The non-bonded interactions between two molecules consist of electrostatic (El) and van der Waals’ (vdW) forces. Which of the following is a correct description of the distance dependence intermolecular interactions between two molecules?

Test: Gaseous State - 2 - Question 19

The state of a certain amount of a gas, not necessarily ideal, is changed from A to B in various hypothetical paths, as shown below. The total amount of the gas remains constant. Which of the following paths are physically realizable:

Detailed Solution for Test: Gaseous State - 2 - Question 19

A is correct. All of them are possible.

Test: Gaseous State - 2 - Question 20

Real gases behave differently from ideal gases because:

(I) The molecules of real gases are in constant motion.
(II) Molecules of real gases collide with the walls of the containers.
(III) Molecules of real gases have vo lume
(IV) Molecules of real gases attract each other.

Test: Gaseous State - 2 - Question 21

The relationship between the van der Waals’ b coefficient of N2 and O2 is:

Test: Gaseous State - 2 - Question 22

From the kinetic theory of gases, the ratio of most probable speed (Cmp) to root mean square speed (Crms) is:

Test: Gaseous State - 2 - Question 23

According to the equipartition principle of energy, the molar heat capacity at constant volume for CO2(g), SO2(g) and H2O(g) follows the trends:

Test: Gaseous State - 2 - Question 24

The average speed H2, N2 and O2 gas molecules is in the order:

Test: Gaseous State - 2 - Question 25

Based on the principle of equipartition of energy, the mo lar heat capacity of CO2 at constant volume Cv,m is:

Test: Gaseous State - 2 - Question 26

The molar internal energy of a gas at temperature T is Um (T). The mo lar internal energy at T = 0 is Um (0). The correct expression that relates these two with appropriate contributions is:

Test: Gaseous State - 2 - Question 27

For an ideal gas, the plot that is non-linear is:

Test: Gaseous State - 2 - Question 28

Consider, the two identical containers, one with 1 mole of H2 and the other with 1 mole of He. If the root mean square (RMS) velocities of the two gases are the same, then the ratio of the temperature, is:

Detailed Solution for Test: Gaseous State - 2 - Question 28

V = (3RT/M)1/2
Vrms H2 = (3RTH2/2)1/2
Vrms He = (3RTHe/4)1/2
(3RTH2/2)1/2 = (3RTHe/2)1/2
TH2/THe= 1/2

Test: Gaseous State - 2 - Question 29

Given that the most probable speed of oxygen gas is 1000 ms–1, the mean/average speed (ms–1) under the same conditions is:

Detailed Solution for Test: Gaseous State - 2 - Question 29

Test: Gaseous State - 2 - Question 30

The Maxwell-Boltzmann distribution for molecular speeds is shown in the following figure

In the figure, H is the height of the peak, L is the location of the maximum and W is the width at half height. As the temperature is decreased:

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