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Full Mock Test & Solutions: GATE Engineering Sciences Mock Test - 5 (65 Questions)

You can boost your GATE Engineering Sciences 2026 exam preparation with this GATE Engineering Sciences Mock Test - 5 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of GATE Engineering Sciences 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 180 minutes
  • - Total Questions: 65
  • - Analysis: Detailed Solutions & Performance Insights
  • - Sections covered: General Aptitude, Engineering Mathematics (XE-A), Engineering Sciences (XE-B) & (XE-E)

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GATE Engineering Sciences Mock Test - 5 - Question 1

What is the difference between the total of the first 2n natural numbers and the total of the first n odd natural numbers? This value is ____.

GATE Engineering Sciences Mock Test - 5 - Question 2

What is the value of  given the information from the image above?

GATE Engineering Sciences Mock Test - 5 - Question 3

Every town that has a pool hall is home to some undesirable individuals. This occurs because pool halls draw in gamblers, and all gamblers are considered undesirable.

Which of the following, if true, cannot be deduced from the statement above?

Detailed Solution: Question 3

The statement's conclusion is that all towns have unsavoury characters. This conclusion is false. According to the passage, only towns with pool halls have unsavoury characters and since we cannot infer that all towns have pool halls, conclusion (C) is wrong. Altematives (A) and (B) are stated in the passage, while alternatively (D) can be deduced.

GATE Engineering Sciences Mock Test - 5 - Question 4

The repo rate refers to the interest rate at which the Reserve Bank of India (RBI) provides funds to commercial banks, while the reverse repo rate denotes the interest rate at which the RBI secures loans from commercial banks.

Which of the following conclusions can be drawn from the passage above?

GATE Engineering Sciences Mock Test - 5 - Question 5

Determine the value of  where C is defined by the condition |z-1| = 1.

Detailed Solution: Question 5

z=π/2 = 3.14/2 = 1.57  is a pole of order 2 lies inside C

GATE Engineering Sciences Mock Test - 5 - Question 6

Calculate the integral 

Detailed Solution: Question 6


On differentiating both side, we get

On integrating both side, we get
I = tan-1b

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 7

The real solution to the equation x3 - 3x2 3x — 5 = 0 is determined using the Newton-Raphson method. The total number of distinct values of xo for which the Newton-Raphson method is unsuccessful for this equation is


Detailed Solution: Question 7

Newton-Raphson method fails if f' (x) = 0

f′(x)=3x2−6x+3=0
3(x2−2x+1)=0
(x−1)2=0
⇒ x=1

For only one value, Newton-Raphson method fails.

GATE Engineering Sciences Mock Test - 5 - Question 8

Which of the following curves has a tangent line at the origin?

Detailed Solution: Question 8

LHD = RHD. Thus, option: b) has tangent at the origin.
Option: c)

GATE Engineering Sciences Mock Test - 5 - Question 9

A person flying over a particular continent is exposed to cosmic radiation, which is represented as a normal random variable with a mean of 4.35 units. Determine the standard deviation such that the probability of exposure during the flight being at least 5.50 units is 0.0256, given that the cumulative distribution function value at 1.95 is 0.4744.

Detailed Solution: Question 9

Given μ = 4.35
Let X be the amount of cosmic radiations exposed.
As given that P(X ≥ 5.50) = 0.0256
0.5 - P(X = 5.50) = 0.0256
P(X = 5.50) = 0.4744
We define, z = (x - μ) / σ
Given that P(Z = 1.95) = 0.4744

*Multiple options can be correct
GATE Engineering Sciences Mock Test - 5 - Question 10

Which of the following statement(s) are true regarding streamlines in a steady, incompressible flow?

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 11

According to Torricelli's theorem, the speed of fluid exiting from a hole in a tank is , where h represents the height of water above the opening as depicted in the figure. Suppose the area of the hole is Ao = 10 cm2 and the bottom area of the cylindrical tank is Ab = 2 m2. What is the time in seconds required to drain the tank from an initial depth of ho = 10 m? Take g = 10 m/s2.


Detailed Solution: Question 11

given Ab = 2 m2

 

A = 10 cm² = 10 x 10-4
h₀ = 10 m

∴ Time required to drain the tank from an initial depth is

GATE Engineering Sciences Mock Test - 5 - Question 12

A rectangular plate measuring 6 m in height and 5 m in width obstructs the end of a fresh water channel that is 5 m deep, as illustrated in the figure. The plate is pivoted around a horizontal axis at its upper edge at point A and is prevented from opening by a fixed ridge located at point B.

The force applied to the plate by the ridge is (in kN). Use ρw = 1000 kg/m³ for calculations.

It is assumed that atmospheric pressure is acting on both sides of the plate.

Detailed Solution: Question 12

Pressure at centroid:
Pc = ρgh
Pc = (1000 × 9.81 × 5) / (2 × 1000)
Pc = 24.52 kPa

The resultant hydrostatic force on each wall:
FR = Pc × A
FR = (24.52) × (5 × 5)
FR = 613 kN

Taking moment about point A:
ΣMA = 0
FR × (1 + (2h / 3)) = Fridge × AB
613 × (1 + (2 × 5) / 3) = Fridge × 6

Fridge = 442.72 kN

GATE Engineering Sciences Mock Test - 5 - Question 13

Consider a steady two-dimensional, incompressible, and Newtonian fluid characterized by the velocity component u = x². Assume that the x-axis is the streamline and disregard the influence of gravitational forces. What is the pressure gradient in the x-direction?

Detailed Solution: Question 13

From the continuity equation:
∂u/∂x + ∂v/∂y = 0
⇒ ∂v/∂y = -∂u/∂x

Given u = x²:
∂v/∂y = -∂(x²)/∂x
∂v/∂y = -2x

Integrating with respect to y:
∫ dv = −∫ 2x dy
v = −2xy + f(x)

Since the x-axis is streamline, v = 0 along this axis.
∴ f(x) = 0 ⇒ v = −2xy

Pressure gradient in the x-direction is given by Navier-Stokes equation:
ρ (∂u/∂t + u ∂u/∂x + v ∂u/∂y + w ∂u/∂z) = −∂p/∂x + ρgx + μ (∂²u/∂x² + ∂²u/∂y² + ∂²u/∂z²) ----------- (2)

Given it is 2D, incompressible, and Newtonian fluid:
∴ Equation (2) becomes:

u ∂u/∂x + v ∂u/∂y = −(1/ρ) ∂p/∂x + μ/ρ (∂²u/∂x² + ∂²u/∂y²)

x²(2x) + (−2xy)0 = −(1/ρ) ∂p/∂x + μ/ρ (2 + 0)

2x³ = −(1/ρ) ∂p/∂x + μ/ρ (2)

∂p/∂x = 2μ − 2ρx³

⇒ 2x³ = −(1/ρ) ∂p/∂x + μ/ρ (2)

⇒ ∂p/∂x = 2μ − 2ρx³

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 14

A rectangular tank is divided into two sections, A and B, which hold water (yw = 9.8 kN/m3) and oil (Yoil = 7.2 kN/m3), respectively, as illustrated in the figure. A differential manometer filled with another type of oil (Yoil2 = - 12 kN/m3) is also present. If the total pressure force acting on wall CD is zero, then the deflection δ is ___________ mm.


Detailed Solution: Question 14

From Manometric balance:
P₀ + 9800 × 1 - 12000 × δ - 7200(h × (1 + δ)) = P₀

⇒ 98 - 120δ - 72h + 72δ = 0
⇒ 488 = 170 - 72h ⇒ (1)

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 15

Water moves through a horizontal smooth pipe with an average velocity, v of 10 m/s and a diameter, d of 5 cm. The friction factor, f is 0.02. The head loss is calculated using the Darcy-Weisbach relation . The fluid pressures, p, measured at different stations are shown in the table below. The length of the pipe, l, from station 0 to station 6 is 6 m.

Given that the acceleration due to gravity, g = 10 m/s2 and the density of water is 1000 kg/m3, what is the fluid pressure at station 6 in kPa (rounded to one decimal place)?


*Multiple options can be correct
GATE Engineering Sciences Mock Test - 5 - Question 16

At what conditions do real gases exhibit CP = CV?

Detailed Solution: Question 16

dψ = T dp + (T / p²) dV
ψ = f(p, V)
dψ = (∂ψ / ∂p)ᵥ dp + (∂ψ / ∂V)ₚ dV
(∂ψ / ∂p)ᵥ = M = T
(∂ψ / ∂V)ₚ = N = T / p²
(∂M / ∂V) = 0
(∂N / ∂p) = -2T / p³

(∂M / ∂V) ≠ (∂N / ∂p) → hence ψ is not a property.

dϕ = f(T) dT + (T / V) dV
ϕ = f(T, V)
dϕ = (∂ϕ / ∂T)ᵥ dT + (∂ϕ / ∂V)ₜ dV

(∂ϕ / ∂T)ᵥ = f(T) = M
(∂M / ∂V) = 0
(∂ϕ / ∂V)ₐₜ = T / V = N

(∂N / ∂T) = 1 / V
(∂M / ∂V) ≠ (∂N / ∂T) → Hence ϕ is also not a property.

*Multiple options can be correct
GATE Engineering Sciences Mock Test - 5 - Question 17

A producer asserts that he has created a table fan that utilizes 25 W of electrical power to expel air at a rate of 0.8 kg/s with a velocity of 8 m/s. Is his assertion valid?

Detailed Solution: Question 17

Power consumed by fan, E1 = 25 W

Power delivered to air, E2 = (1/2)ṁv² = (1/2)0.8 x 8² = 25.6 W

Since E2 > E1, this fan violates the first law of thermodynamics. Hence, the claim of the inventor is impossible.

*Multiple options can be correct
GATE Engineering Sciences Mock Test - 5 - Question 18

In a vapor compression refrigeration cycle, if the pressure in the condenser rises,
1. The specific volume at the condenser inlet increases
2. The volume of water circulating in the condenser for heat removal rises
3. The volumetric efficiency declines
4. The irreversibility during the compression process increases
Which of the statements are correct?

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 19

A Carnot engine operates with a blend of gases as its working fluid, characterized by γ = 1.33. The heat input is 82 kJ, and the adiabatic expansion ratio is 16:1. The temperature of the heat source is 800 K. What is the quantity of heat expelled to the sink in kJ? (Round your answer to two decimal places)


Detailed Solution: Question 19

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 20

The change in saturation pressure with respect to saturation for a liquid is 0.2 bar/K at a temperature of 450 K. The specific volumes of dry saturated vapor and saturated liquid at 450 K are 0.321 m3/kg and 0.002 m3/kg, respectively. Utilizing the Clausius Clapeyron equation, the latent heat of vaporization is _____________ kJ/kg.


Detailed Solution: Question 20

GATE Engineering Sciences Mock Test - 5 - Question 21

An iron block weighing 50 kg and a copper block weighing 20 kg,
(ciron = 0.45 kJ/kg·°C and ccopper = 0.386 kJ/kg·°C),
both starting at a temperature of 80°C, are submerged in a vast lake at 15°C. After some time, thermal equilibrium is reached due to the heat exchange between the blocks and the lake water. The overall change in entropy for this process is expressed as:

Detailed Solution: Question 21

Qrej to lake = mc(80 - 15) (Copper) + mc(80 + 15) (Iron)
= 501.8 + 146.25
= 1964.3 kJ

ΔSlake = 1964.3 / 288
= 6.82 kJ/K

ΔSiron = 50 × 0.45 × ln(288 / 353)
= -4.579

ΔSCu = 20 × 0.386 × ln(288 / 353)
= -1.571

ΔSuniv = 0.6699 = 0.67 kJ/K

GATE Engineering Sciences Mock Test - 5 - Question 22

In the scenario where a gas conforms to the specified equation of state

In which B' is solely a function of T, then

Detailed Solution: Question 22

∴ on integration

where C̄p0 (integration constant) is the value of C̄p at very low values of pressure.

GATE Engineering Sciences Mock Test - 5 - Question 23

A Rankine cycle's turbines function between pressures of 4 MPa and 10 kPa, achieving an efficiency of 84 percent. When the steam is reheated at 400 kPa to a temperature of 400°C, with a maximum temperature of 600°C, what is the efficiency of the cycle in percent? Neglect the work of the pump.
At 10 kPa, h1 = 192 kJ/kg, hg = 2585 kJ/kg,
At 10 kPa, sf = 0.649 kJ/kgK, sfg = 7.501 kJ/kgK
h3 = 3674 kJ/kg, h4 = 2960 kJ/kg, hs = 3273 kJ/kg
s3 = 7.369 kJ/kgK, ss = 7.899 kJ/kgK

Detailed Solution: Question 23

h₂ = h₁ = 192 kJ/kg
h₃ = 3674 kJ/kg
h₅ = 3273 kJ/kg
s₆ = s₅ = 7.899 = 0.649 + 7.501x₆
⇒ x₆ = 0.9665
∴ h₆ = 192 + (0.9665)(2393) = 2505 kJ/kg

The actual work from the turbine to be:
Wₜ = ηₜ(h₃ − h₄) + ηₜ(h₅ − h₆)
Wₜ = (0.84)(3674 − 2960) + (0.84)(3273 − 2505)
Wₜ = 1245 kJ/kg

GATE Engineering Sciences Mock Test - 5 - Question 24

A cylinder with a diameter of 25 cm is equipped with a frictionless piston and is initially loaded with a weight of 1200 N. The piston starts at a position 30 cm above the bottom, and the area below the piston contains CO2 gas at a temperature of 290 K. An electric heater supplying 3600 J of heat is used during the process, with the assumption that no heat is lost to the environment. Determine the distance (in mm) that the piston will move outward while heating for a duration of 1 hour. Consider the barometric pressure to be 1 bar and the specific heat capacity (Cp) of CO2 to be 820 J/kg — K.

Detailed Solution: Question 24

Absolute gas pressure,
P = gauge pressure + atmospheric pressure

Since the piston carries a dead weight, the situation corresponds to constant pressure, and for a constant pressure the heat supplied equals mCpdT. Therefore,

Change in internal energy, dU = mCp(T2 − T1) = 0.0334 x 631 x (417.62 − 290) = 2689.64 J
From non-flow energy equation,
Q1−2 = W1−2 + dU; 3600 = W1−2 + 2689.64
∴ Displacement work, W1−2 = 3600 − 2689.64 = 910.36 J
The work done equals the product of load and the distance by which the piston is raised.
That is
910.36 = 1250 × x
∴ x = 0.728 m
= 728 mm

*Multiple options can be correct
GATE Engineering Sciences Mock Test - 5 - Question 25

The illustration below depicts how the internal energy U varies with the volume V of 2.0 mol of an ideal gas during a cyclic process labeled abcda. The temperatures of the gas at points b and c are 500 K and 300 K, respectively. Calculate the amount of heat absorbed by the gas (in Joules) throughout the cyclic process abcda.

Detailed Solution: Question 25

Given:

Number of moles of gas, 

n = 2 moles

The system's volume is constant for lines bc and da. Therefore,
ΔV = 0
Thus, work done for paths da and bc is zero.
⇒ W_da = W_bc = 1
Since the process is cyclic, ΔU is equal to zero.

Using the first law, we get
ΔW = ΔQ
ΔW = ΔW_ab + ΔW_cd

Since the temperature is kept constant during lines ab and cd, these are isothermal processes. Work done during an isothermal process is given by:
W = nRT ln(Vf / Vi)

If Vf and Vi are the initial and final volumes during the isothermal process, then
W = nRT1 ln(2V0 / V0) + nRT2 ln(V0 / 2V0)
W = 2 × 8.314 × 0.693 × 200
W = 2305.31 J

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 26

The following data pertains to water vapour:
Reduced pressure = 0.905
Reduced temperature = 1.225
Critical pressure = 22.09 bar
Critical temperature = 647.3 K
Compressibility factor Z = 0.83
Characteristic gas constant R = 0.4615 kJ/kg - K.
Assuming water vapour behaves as an ideal gas, the actual specific volume of water vapour is __________ m3/kg (Round off to three decimal places).


Detailed Solution: Question 26

Actual specific volume of water vapour is vact = z videal
Pressure
P = Pr x Pcr
= 0.905 x 22.09
P = 19.99 bar
Temperature
T = Tr x Tcr
= 1.225 x 647.3 K
T = 792.94 K
From ideal gas equation 

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 27

A container with a volume of 0.05 m3 holds a combination of saturated water and saturated steam at a temperature of 250°C. Given that the mass of the liquid present is 8 kg, calculate the enthalpy of the mixture in kJ/kg.
At 250°C, hf = 1085.36 kJ/kg, hfg = 1716.2 kJ/kg, Vf = 0.0012512 m3/kg, vg = 0.05013 m3/kg


Detailed Solution: Question 27

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 28

An air-water vapor mixture is maintained at a temperature of 35°C and standard atmospheric pressure, exhibiting an absolute humidity of 0.02 kg of vapor per kg of dry air. What is its humid volume (in m³ per kg of dry air)?
(At 35°C, Psat = 5.6291 kPa, Patm = 101.325 kPa)


Detailed Solution: Question 28

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 29

In a cylinder of an air motor, the internal energy of the compressed air is measured at 450 kJ/kg at the start of the expansion process and decreases to 220 kJ/kg following the expansion. Given that the work accomplished by the air during this expansion is 120 kJ/kg, what is the amount of heat expelled by the cylinder in kJ/kg?


Detailed Solution: Question 29

Internal energy at beginning of the expansion, u₁ = 450 kJ/kg
Internal energy after expansion, u₂ = 220 kJ/kg
Work done by the air during expansion, W = 120 kJ/kg

By first law:
δq = du + δw
δq = (u₂ − u₁) + δW
δq = (220 − 450) + 120 = 230 + 120 = 110 kJ/kg

Hence, heat rejected by air = 110 kJ/kg

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 5 - Question 30

A rigid container holds 4 kg of air (considered as an ideal gas) at a temperature of 200°C and a pressure of 4 MPa. This serves as the hot energy source for a heat engine, which operates with its cold side at 20°C before coming to a halt. The energy output of the heat engine is _________ kj.


Detailed Solution: Question 30


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