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GATE ECE (Electronics) Test: Random Variables Free Online Test 2026


MCQ Practice Test & Solutions: Test: Random Variables (20 Questions)

You can prepare effectively for Electronics and Communication Engineering (ECE) GATE ECE (Electronics) Mock Test Series 2027 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Random Variables". These 20 questions have been designed by the experts with the latest curriculum of Electronics and Communication Engineering (ECE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 60 minutes
  • - Number of Questions: 20

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Test: Random Variables - Question 1

The number of cars arriving at ICICI bank drive-in window during 10-min period is Poisson random variable X with b = 2.

Que : The probability that more than 3 cars will arrive during any 10 min period is

Detailed Solution: Question 1

Test: Random Variables - Question 2

The number of cars arriving at ICICI bank drive-in window during 10-min period is Poisson random variable X with b = 2.

Que: The probability that no car will arrive is

Detailed Solution: Question 2

Test: Random Variables - Question 3

The power reflected from an aircraft of complicated shape that is received by a radar can be described by an exponential random variable W. The density of W is

where W0 is the average amount of received power. The probability that the received power is larger than the power received on the average is

Detailed Solution: Question 3

Test: Random Variables - Question 4

Delhi averages three murder per week and their occurrences follow a poission distribution

Que: The probability that there will be five or more murder in a given week is

Detailed Solution: Question 4

Test: Random Variables - Question 5

Delhi averages three murder per week and their occurrences follow a poission distribution

Que: On the average, how many weeks a year can Delhi expect to have no murders ?

Detailed Solution: Question 5

average number of week, per year with no murder

Test: Random Variables - Question 6

Delhi averages three murder per week and their occurrences follow a poission distribution.

Que:How many weeds per year (average) can the Delhi expect the number of murders per week to equal orexceed the average number per week ?

Detailed Solution: Question 6

 

Average number of weeks per year that number of murder exceeds the average

Test: Random Variables - Question 7

A discrete random variable X has possible values x i = i2  i =1, 2, 3, 4 which occur with probabilities 0.4, 0.25, 0.15, 0.1,. The mean value 

Detailed Solution: Question 7

Test: Random Variables - Question 8

The random variable X is defined by the density

The expected value of g(X)  = X3 is

Detailed Solution: Question 8

Test: Random Variables - Question 9

The random variables X and Y have variances 0.2 and 0.5 respectively. Let Z= 5X-2Y. The variance of Z is?

Detailed Solution: Question 9

Var(X) = 0.2, Var(Y) = 0.5
Z = 5X – 2Y
Var(Z) = Var(5X-2Y)
           = Var(5X) + Var(2Y)
           = 25Var(X) + 4Var(Y)
Var(Z) = 7.

Test: Random Variables - Question 10

The variance of the random variable X with probability density function  is

Detailed Solution: Question 10

Test: Random Variables - Question 11

A Random variable X is uniformly distributed on the interval (-5, 15). Another random variableY =  e -X/5 is formed. The value of E[Y ] is

Detailed Solution: Question 11

Test: Random Variables - Question 12

A joint sample space for two random variable X and Y has four elements (1, 1), (2, 2), (3, 3) and (4, 4). Probabilities of these elements are 0.1, 0.35, 0.05 and 0.5 respectively.

Que: The probability of the event {X ≤ 2.5, Y ≤ 6} is

Detailed Solution: Question 12

Test: Random Variables - Question 13

A joint sample space for two random variable X and Y has four elements (1, 1), (2, 2), (3, 3) and (4, 4). Probabilities of these elements are 0.1, 0.35, 0.05 and 0.5 respectively.

Que: The probability of the event {X ≤ 3} is

Detailed Solution: Question 13

= 0.1+ 0.35 + 0.05 = 0.5

Test: Random Variables - Question 14

The statistically independent random variable X and Y have mean values  .and   They have second moments    and   Consider a random variable W = 3X - Y.

Que: The second moment of W is

Detailed Solution: Question 14

Test: Random Variables - Question 15

The statistically independent random variable X and Y have mean values  .and   They have second moments    and   Consider a random variable W = 3X - Y.

Que: The variance of the random variable is

Detailed Solution: Question 15

Test: Random Variables - Question 16

Two random variable X and Y have the density function

The X and Y are

Detailed Solution: Question 16

Test: Random Variables - Question 17

The value of σx2 , σy2 , RXY and ρ are respectively

Detailed Solution: Question 17

Test: Random Variables - Question 18

The mean value of the random variable

W = (X + 3Y)2  + 2X + 3  is

Detailed Solution: Question 18

Test: Random Variables - Question 19

If machine is not properly adjusted, the product resistance change to the case where ax = 1050Ω . Now the rejected fraction is

Detailed Solution: Question 19

Test: Random Variables - Question 20

Suppose Y is a random variable representing the number of successes in 5 independent Bernoulli trials with success probability p = 0.6. What is the probability that Y equals 3?

Detailed Solution: Question 20

Y follows a Binomial distribution with parameters n = 5 (number of trials) and p = 0.6 (probability of success).

The probability mass function for a binomial random variable is:

P(Y = k) = C(n, k) * p^k * (1 - p)^(n - k)

Where C(n, k) is the combination of n items taken k at a time.

For Y = 3:

C(5, 3) = 10

P(Y = 3) = 10 * (0.6)^3 * (0.4)^2

Calculate:

(0.6)3 = 0.216

(0.4)2 = 0.16

P(Y = 3) = 10 * 0.216 * 0.16 = 10 * 0.03456 = 0.3456

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