GATE Computer Science Engineering(CSE) 2027 Test: Multiplexers Free Online


MCQ Practice Test & Solutions: Test: Multiplexers (14 Questions)

You can prepare effectively for Computer Science Engineering (CSE) GATE Computer Science Engineering(CSE) 2027 Mock Test Series with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Multiplexers ". These 14 questions have been designed by the experts with the latest curriculum of Computer Science Engineering (CSE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 42 minutes
  • - Number of Questions: 14

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Test: Multiplexers - Question 1

Consider the following Boolean function of four variables: 

The function is

Detailed Solution: Question 1

The K-map would be


So, the minimized expression would
be x'z + xz'.
So, option B. 

Test: Multiplexers - Question 2

Consider the following Boolean function of four variables

The function is

Detailed Solution: Question 2

Test: Multiplexers - Question 3

The simplified SOP (Sum of Product) from the Boolean expression

1s

Detailed Solution: Question 3

Test: Multiplexers - Question 4

Consider the 4-to-1 multiplexer with two select lines S1 and S0 given below

The minimal sum-of-products form of the Boolean expression for the output F of the multiplexer is

Detailed Solution: Question 4

S1 and S0 are used to select the input given to be given as output.


 

Test: Multiplexers - Question 5

Consider the following Boolean expression for F: 

The minimal sum of products form of F is

Detailed Solution: Question 5



Hence, option A is correct.

Test: Multiplexers - Question 6

Consider the following minterm expression F for :

The minterms 2, 7, 8 and 13 are 'do not care' terms. The minimal sum-of-products form for F is

Detailed Solution: Question 6

While putting the terms to K-map the 3rd and 4th columns are swapped so do 3rd and 4th rows. So, term 2 is going to (0,3) column instead of (0,2), 8 is going to (3,0) instead of (2,0) etc..


Solving this k-map gives B) as the answer.

Test: Multiplexers - Question 7

Consider the two cascade 2 to 1 multiplexers as shown in the figure .

 

The minimal sum of products form of the output X is 

Detailed Solution: Question 7


Test: Multiplexers - Question 8

The output F of the below multiplexer circuit can be represented by

Detailed Solution: Question 8

Test: Multiplexers - Question 9

A multiplexer with a 4 - bit data select input is a

Detailed Solution: Question 9

for n bit data select input

Test: Multiplexers - Question 10

It is possible for an enable or strobe input to undergo an expansion of two or more MUX ICs to the digital multiplexer with the proficiency of large number of

Detailed Solution: Question 10

It is possible for an enable or strobe input to undergo an expansion of two or more MUX ICs to the digital multiplexer with the proficiency of large number of inputs.

Test: Multiplexers - Question 11

Consider a multiplexer with X and Y as data inputs and Z the as control input. Z = 0 selects input X, and Z = 1 selects input Y. What are the connections required to realize the 2-variable Boolean function F = T + R, without using any additional hardware?

Detailed Solution: Question 11

Z'X + ZY..
Put Z = T, X = R, Y = 1 in Z'X + ZY..
= T'R + 1*T
= (T+T') (T+R)
= T + R

Test: Multiplexers - Question 12

The circuit shown below implements a 2-input NOR gate using two 2  4 MUX (control signal 1 selects the upper input).
What are the values of signals x,y and z?

Detailed Solution: Question 12


Test: Multiplexers - Question 13

Suppose only one multiplexer and one inverter are allowed to be used to implement any Boolean function of  variables.
What is the minimum size of the multiplexer needed?

Detailed Solution: Question 13

2n - 1
We will map  variables  to select lines and  variable to input line

Test: Multiplexers - Question 14

The following circuit implements a two-input AND gate using two 2-1 multiplexers.

What are the values of X1,X2,X3?

Detailed Solution: Question 14

F = (bX1' + aX1)X3 + X2X3'
Put X1 = b, X2 = 0, X3 = a to get F = ab.

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