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Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Mechanical Engineering MCQ


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30 Questions MCQ Test - Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2

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Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 1

It is proposed to coat a 1 mm diameter wire with enamel paint (k = 0.1W/mK) to increase heat transfer with air. If the air side heat transfer coefficient is 100 W/m2K, then optimum thickness of enamel paint should be:  

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 1

Ans. (b) Critical radius of insulation (rc) =

= 1mm

∴ Critical thickness of enamel point = = 0.5 mm

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 2

Two rods, one of length L and the other of length 2L are made of thesame material and have the same diameter. The two ends of the longerrod are maintained at 100°C. One end of the shorter rod Is maintainedat 100°C while the other end is insulated. Both the rods are exposed tothe same environment at 40°C. The temperature at the insulated end ofthe shorter rod is measured to be 55°C. The temperature at the midpointof the longer rod would be:  

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 2

Ans. (c)

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Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 3

Upto the critical radius of insulation 

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 3

Ans. (c) The thickness upto which heat flow increases and after which heat flow decreases is termed as Critical thickness. In case of cylinders and spheres it is called 'Critical radius'.

 

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 4

A hollow pipe of 1 cm outer diameter is to be insulated by thick cylindrical insulation having thermal conductivity 1 W/mK. The surfaceheat transfer coefficient on the insulation surface is 5 W/m2K. What isthe minimum effective thickness of insulation for causing the reduction in heat leakage from the insulated pipe?  

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 4

Ans. (c) Critical radius of insulation = 0.2m = 20cm
∴ Critical thickness of insulation ( Δr)C = rc − r1 = 20 - 0.5 = 19.5cm

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 5

A copper wire of radius 0.5 mm is insulated with a sheathing ofthickness 1 mm having a thermal conductivity of 0.5 W/m – K. Theoutside surface convective heat transfer coefficient is 10 W/m2 – K. Ifthe thickness of insulation sheathing is raised by 10 mm, then theelectrical current-carrying capacity of the wire will: 

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 5

Ans. (a)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 6

A copper pipe carrying refrigerant at – 200 C is covered by cylindrical insulation of thermal conductivity 0.5 W/m K. The surface heat transfer coefficient over the insulation is 50 W/m2 K. The critical thickness ofthe insulation would be: 

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 6

Ans. (a) Critical radius of insulation ( rc) =
= 0.5m = 0.01m

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 7

The temperature variation in a largeplate, as shown in the given figure,would correspond to which of thefollowing condition (s)?


1. Unsteady heat
2. Steady-state with variation of k
3. Steady-state with heat generation
Select the correct answer using the codes given below: 
Codes:

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 7

Ans. (a)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 8

Water jacketed copper rod “D” m in diameter is used to carry the current. The water, which flows continuously maintains the rod temperature at Toi C during normal operation at “I” amps. The electrical resistance of the rod is known to be “R” Ω /m. If the coolant water ceased to be available and the heat removal diminished greatly, the rod would eventually melt. What is the time required for melting to occur if the melting point of the rod material is Tmp?  
[Cp = specific heat, ρ = density of the rod material and L is the length of the rod]

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 8

Ans. (a)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 9

Consider the following statements: 
1. Under certain conditions, an increase in thickness of insulation may increase the heat loss from a heated pipe.
2. The heat loss from an insulated pipe reaches a maximum when theoutside radius of insulation is equal to the ratio of thermalconductivity to the surface coefficient.
3. Small diameter tubes are invariably insulated.
4. Economic insulation is based on minimum heat loss from pipe.

Of these statements

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 9

Ans. (c)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 10

Consider the following statements:

1. Under certain conditions, an increase in thickness of insulation mayincrease the heat loss from a heated pipe.

2. The heat loss from an insulated pipe reaches a maximum when theoutside radius of insulation is equal to the ratio of thermalconductivity to the surface coefficient.

3. Small diameter tubes are invariably insulated.

4. Economic insulation is based on minimum heat loss from pipe.Of these statements

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 10

Ans. (c)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 11

An electric cable of aluminium conductor (k = 240 W/mK) is to be insulated with rubber (k = 0.15 W/mK). The cable is to be located in air (h = 6W/m2). The critical thickness of insulation will be:

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 11

Ans. (c)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 12

Match List-I (Parameter) with List-II (Definition) and select the correct answer using the codes given below the lists:  


Nomenclature: h: Film heat transfer coefficient, ksolid: Thermal conductivity of solid, kfluid: Thermal conductivity of fluid, ρ: Density,
c: Specific heat, V: Volume, l: Length.

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 12

Ans. (a)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 13

What is the critical radius of insulation for a sphere equal to?k = thermal conductivity in W/m-K  
h = heat transfer coefficient in W/m2K

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 13

Ans. (b) Critical radius of insulation for sphere in 2k/h and for cylinder is k/h

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 14

In current carrying conductors, if the radius of the conductor is lessthan the critical radius, then addition of electrical insulation isdesirable, as 

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 14

Ans. (b)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 15

Provision of fins on a given heat transfer surface will be more it thereare:  

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 15

Ans. (c)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 16

In current carrying conductors, if the radius of the conductor is lessthan the critical radius, then addition of electrical insulation is desirable, as  

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 16

Ans. (b)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 17

Which one of the following is correct? 
The effectiveness of a fin will be maximum in an environment with

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 17

Ans. (a) The effectiveness of a fin can also be characterized as

It is a ratio of the thermal resistance due to convection to the thermal resistance
of a fin. In order to enhance heat transfer, the fin's resistance should be lower
than that of the resistance due only to convection.

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 18

On heat transfer surface, fins are provided  

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 18

Ans. (c) By the use of a fin, surface area is increased due to which heat flow rate
increases. Increase in surface area decreases the surface convection resistance,
whereas the conduction resistance increases. The decrease in convection
resistance must be greater than the increase in conduction resistance in order to
increase the rate of heat transfer from the surface. In practical applications of
fins the surface resistance must be the controlling factor (the addition of fins
might decrease the heat transfer rate under some situations).

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 19

In order to achieve maximum heat dissipation, the fin should be designed in such a way that: 

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 19

Ans. (a)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 20

Consider the following statements pertaining to large heat transferrate using fins: 
1. Fins should be used on the side where heat transfer coefficient is small
2. Long and thick fins should be used
3. Short and thin fins should be used
4. Thermal conductivity of fin material should be large
Which of the above statements are correct?

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 20

Ans. (d)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 21

Assertion (A): Nusselt number is always greater than unity.

Reason (R): Nusselt number is the ratio of two thermal resistances, onethe thermal resistance which would be offered by the fluid, if it wasstationary and the other, the thermal resistance associated with convective heat transfer coefficient at the surface.  

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 21

Ans. (a)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 22

Assertion (A): In a liquid-to-gas heat exchanger fins are provided in thegas side.  
Reason (R): The gas offers less thermal resistance than liquid

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 22

Ans. (c)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 23

Extended surfaces are used to increase the rate of heat transfer. When the convective heat transfer coefficient h = mk, the addition ofextended surface will: 

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 23

Ans. (c)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 24

Consider the following statements pertaining to heat transfer throughfins: 
1. Fins are equally effective irrespective of whether they are on thehot side or cold side of the fluid.
2. The temperature along the fin is variable and hence the rate of heattransfer varies along the elements of the fin.
3. The fins may be made of materials that have a higher thermalconductivity than the material of the wall.
4. Fins must be arranged at right angles to the direction of flow of theworking fluid.Of these statements:

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 24

Ans. (d)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 25

Addition of fin to the surface increases the heat transfer if is:  

 

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 25

Ans. (c) Addition of fin to the surface increases the heat transfer if  << 1

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 26

A fin of length 'l' protrudes from a surface held at temperature togreater than the ambient temperature ta. The heat dissipation from thefree end' of the fin is assumed to be negligible. The temperaturegradient at the fin tip  is:  

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 26

Ans. (a)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 27

The insulated tip temperature of a rectangular longitudinal fin having an excess (over ambient) root temperature of θo is: 

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 27

Ans. (d)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 28

A metallic rod of uniform diameter and length L connects two heat sources each at 500°C. The atmospheric temperature is 30°C. The temperature gradient at the centre of the bar will be:  

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 28

Ans. (d)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 29

The efficiency of a pin fin with insulated tip is: 

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 29

Ans. (b)

Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 30

A fin of length l protrudes from a surface held at temperature To; it being higher than the ambient temperature Ta. The heat dissipationfrom the free end of the fin is stated to be negligibly small, What is the temperature gradienat the tip of the fin?  

Detailed Solution for Test: Critical Thickness of Insulation & Heat Transfer From Extended Surfaces (Fins) - 2 - Question 30

Ans. (a)



= Negligibly small.

Therefore, the temperature gradient


at the tip will be negligibly small
i.e. zero.

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