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Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Mechanical Engineering MCQ


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20 Questions MCQ Test - Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 below.
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Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 1

In an open U tube containing mercury, kerosene of specificgravity 0·8 is poured into one of its limbs so that the length ofcolumn of kerosene is about 40 cm. The level of mercury columnin that limb is lowered approximately by how much? 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 1

Ans. (b) 0.8 x 40 = 13.6 x (2h) ⇒ h = 1.2 cm

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 2

Which of following are the beneficial effects of air vessel fitted to delivery side of a reciprocating pump?  
1. Constant rate of discharge can be ensured
2. Power consumption can be reduced
3. Discharge can be increased
4. Constant velocity of the piston can be ensured
Select the correct answer using the codes given below:
Codes:

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 2

Ans. (b) The function of air-vessel are:
1. On suction side
i) To reduce accelerating head. This will reduced the total vacuum head,
reducing the possibility of separation and saving in power required for supplying accelerating head.
ii) Pump can be run on higher speed.
iii) Length of suction pipe below the air vessel can be increased.
2. On delivery side
i) To reduce the accelerating head and affecting in large amount of power
consumed in supplying the accelerating head.
ii) A uniform rate of discharge is ensured.

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Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 3

Match List-I with List-II and select the correct answer using the codes given below the lists: 

 



Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 3

Ans. (c)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 4

Assertion (A): Aircraft wings are slotted to control separation of boundary layer especially at large angles of attack.  
Reason (R): This helps to increase the lift and the aircraft can take off from, and land on, short runways.

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 4

Ans. (c)

*Answer can only contain numeric values
Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 5

Figure shows a differential manometer connected at two points A and B. At A air pressure is 100 kN/m2 . Find the absolute pressure at B in kPa


Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 5

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 6

An automobile with projected area 2.6 m2m2 is running on a road with a speed of 120 km per hour. The mass density and the kinematic viscosity of air are 1.2 kg/m3kg/m3 and 1.5×10−5m2/s1.5×10−5m2/s, respectively. The drag coefficient is 0.30.

The metric horse power required to overcome the drag force is

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 6

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 7

For solid spheres falling vertically downwards under gravity in aviscous fluid, the terminal velocity, V1 varies with diameter 'D' of thesphere as  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 7

Ans. (b) Terminal velocity V1 ∞Dfor all diameters. Stokes’ formula forms the
basis for determination of viscosity of oils which consists of allowing a sphere of known diameter to fail freely in the oil. After initial acceleration. The sphere attains a constant velocity known as Terminal Velocity which is reached when the external drag on the surface and buoyancy, both acting upwards and in opposite to the motions, become equal to the downward force due to gravity.

*Answer can only contain numeric values
Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 8

If a cylinder of radius r = 3 cm and length l = 50 cm is rotating at n = 1000 rpm in air where a wind velocity U = 10 m/s, how much lift L is produced on the cylinder? Assume that r = 1.205 kg/m3 and that air on the cylinder surface does not separate


Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 8

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 9

A cylindrical object is rotated with constant angular velocity about its symmetry axis in auniform flow field of an ideal fluid producing stream lines as shown in the figure given above.At which point(s), is the pressure on the cylinder surface maximum? 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 9

Ans. (d)

*Answer can only contain numeric values
Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 10

A car, frontal projection area 2 m2 , is running at 60 km/h in the calm air of temperature 20C and standard atmospheric pressure. What is the drag D on the car in Newtons? Assume that the resistance coefficient is 0.4.


Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 10

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 11

Flow over a half body is studied by utilising a free stream velocity of 5m/s superimposed on a source at the origin. The body has a maximumwidth of 2 m. The co-ordinates of the stagnation point are:  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 11



Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 12

In given figure, if the pressure of gas in bulb A is 50 cm Hg vacuum and Patm = 76 cm Hg, then height of column H is equal to     

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 12

Ans. (b) If the pressure of gas in bulb A is atm. H = zero.
If we create a pressure of gas in bulb A is 1 cm Hg vacuum then the vacuum will lift 1 cm liquid, H = 1 cm.
If we create a pressure of gas in bulb A is 2 cm Hg vacuum then the vacuum will lift 2 cm liquid, H = 2 cm.
If we create a pressure of gas in bulb A is 50 cm Hg vacuum then the vacuum will lift 50 cm liquid, H = 50 cm.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 13

The pressure gauges Gand G2 installed on the system show pressures of PG1 = 5.00 bar and PG2 = 1.00 bar. The value of unknown pressure P is? (Atmospheric pressure1.01 bars) 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 13

Ans. (d) Pressure in the right cell = PG2 + Atmospheric pressure = 1.01 + 1.0 = 2.01 bar
Therefore P = PG1 + Pressure on right cell = 5 + 2.01 = 7.01 bar

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 14

Refer to Figure, the absolute pressure ofgas A in the bulb is:  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 14

Ans. (a) Use ‘hs’ formula;

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 15

Hydrostatic law of pressure is given as 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 15

Ans. (a)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 16

A mercury-water manometer has a gauge difference of 500 mm(difference in elevation of menisci). What will be the difference in pressure? 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 16

Ans. (b)

m of light fluid or h = 0.5

= 6.3m of water.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 17

Pressure drop of flowing through a pipe (density 1000 kg/m3) between two points is measured by using a vertical U-tube manometer. Manometer uses a liquid with density 2000 kg/m3.The difference in height of manometric liquid in the two limbs of the manometer is observed to be 10 cm. The pressure drop between the two points is: 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 17

Ans. (b)

of light fluid or h = 0.1

= 0.1m of light fluid

The pressure dropbetween the two points is = hρg = 0.1 x 9.81 x 1000 = 981N/m2

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 18

Differential pressure head measured by mercury oil differential manometer (specific gravity of oil is 0.9) equivalent to a 600 mm difference of mercury levels will nearly be:  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 18

Ans. (d)

m of light fluid or h = 0.600

= 8.47m of oil

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 19

Pressure drop of water flowing through a pipe (density 1000kg/m3) between two points is measured by using a vertical Utube manometer. Manometer uses a liquid with density 2000 kg /m3. The difference in height of manometric liquid in the two limbs of the manometer is observed to be 10 cm. The pressure drop between the two points is: 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 19

Ans. (b)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 20

A U-tube manometer is connected to a pipeline conveying water as shown in the Figure. The pressure head of water in the pipeline is    

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 20

Ans. (c) Use ‘hs’ formula;

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