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SRMJEEE Subject Wise & Full Length SRMJEE Mock Test - 7 (Medical) Free


Full Mock Test & Solutions: SRMJEE Mock Test - 7 (Medical) (125 Questions)

You can boost your JEE 2026 exam preparation with this SRMJEE Mock Test - 7 (Medical) (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of JEE 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 150 minutes
  • - Total Questions: 125
  • - Analysis: Detailed Solutions & Performance Insights
  • - Sections covered: Physics, Chemistry, Biology, Aptitude, English

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SRMJEE Mock Test - 7 (Medical) - Question 1
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A pIano-concave lens is made of glass of refractive index 1.5 and the radius of curvature of the curved face is 50 cm. The power of the lens is

Detailed Solution: Question 1


or f = -100 cm = -1 m
Power = -1 D which is the choice (1).

SRMJEE Mock Test - 7 (Medical) - Question 2
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Which of the following is incorrect about the sensitivity of a moving coil galvanometer?

Detailed Solution: Question 2

Current sensitivity is given by:

It can only be increased by increasing the number of turns in the coil, inserting a soft iron cylinder inside the coil and increasing the strength of the magnetic field.

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SRMJEE Mock Test - 7 (Medical) - Question 3
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In photoelectric effect, the K.E. of electrons emitted from the metal surface depends upon

Detailed Solution: Question 3

In photoelectric effect, the K.E. of electrons emitted from the metal surface depends upon frequency of incident light.
Also, the K.E. of photoelectrons depends upon frequency of incident light.

SRMJEE Mock Test - 7 (Medical) - Question 4
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What is the weight of a body at a distance 2r from the centre of Earth if the gravitational potential energy of the body at a distance r from the centre of Earth is U?

Detailed Solution: Question 4


SRMJEE Mock Test - 7 (Medical) - Question 5
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When one of the slits in Young's experiment is covered with a transparent sheet of thickness 3.6 10-3 cm, the central fringe shifts to a position originally occupied by the 30th bright fringe. If λ = 6000 Å, then the refractive index of the sheet is

Detailed Solution: Question 5

The position of the 30th bright fringe is given by

Hence the shift of the central fringe is

SRMJEE Mock Test - 7 (Medical) - Question 6
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A square loop is made by a uniform conductor wire as shown in figure

The net magnetic field at the centre of the loop if side length of the square is a

Detailed Solution: Question 6

The current will be equally divided at junction P. The field at the centre due to wires PQ and SR will be equal in magnitude but opposite in the direction, so its effective field will be zero. Similarly, net field due to wires PS and QR is zero. Therefore, the net field at the centre of the loop is zero.

SRMJEE Mock Test - 7 (Medical) - Question 7
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For Zn2+/Zn = - 0.76 V, Cl2/Cl- = 1.36 V, H+/(1/2)H2 = 0 V and Fe3+/Fe2+ = 0.77 V, the increasing order of strengths as a reducing agent is

Detailed Solution: Question 7

The substances with a lower value of reduction potential are stronger reducing agents.
Hence, the increasing order of the strengths as reducing agents is:
Cl2, Fe3+, H2, Zn

SRMJEE Mock Test - 7 (Medical) - Question 8
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Consider the following half reactions:
Zn2+ + 2e- → Zn(s); E0 = -0.76V
Cu2+ + 2e- → Cu(s); E0 = -0.34V
Which of the following reactions is spontaneous?

Detailed Solution: Question 8

Electrode potential of the cell must be +ve for spontaneous reaction.
Zn2+ → Zn; E0 = -0.76 V
Cu2+ → Cu; E0 = -0.34 V
Redox reaction is:

Ecell = E0cathode - E0anode
= -034 - (-0.76)
= +0.42 V
Ecell is positive, so the above reaction is feasible.
Hence, option (2) is the correct answer.

SRMJEE Mock Test - 7 (Medical) - Question 9
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Among the following, the pair of paramagnetic complexes is

Detailed Solution: Question 9

SRMJEE Mock Test - 7 (Medical) - Question 10
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The hybridisation of the central atom and the shape of [IO2F5]2 ion, respectively, are

Detailed Solution: Question 10

[IO2F5]2- ion hybridisation is sp3d3 and shape is pentagonal bipyramidal.
Double bond causes more repulsion, so they would be on axial position at 180o angle to each other, so shape is

SRMJEE Mock Test - 7 (Medical) - Question 11
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Mercury is the only transition element that is liquid at room temperature. Which of the following is not the reason for the same?

Detailed Solution: Question 11

Mercury has a high value of ionisation energy because of fully-filled orbitals, and the electrons are less delocalised, which weakens the metallic bond.

SRMJEE Mock Test - 7 (Medical) - Question 12
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The chemical reaction, 2AgCI(g) + H2(g) → 2HCI(aq) + 2Ag(s) taking place in a galvanic cell is represented by the notation:

Detailed Solution: Question 12

2AgCI(s) + H2 (g) (1 bar) → 2HCI (aq) + 2 Ag(s)
The cell with this cell reaction can be represented as:
Pt(s), H2(g), 1 bar/1 M HCI(aq) || 1 M Ag+(aq)/Ag(s)
Silver is undergoing reduction (Ag+ → Ag) in this reaction, hence it will act as cathode in the cell.
Option (1) has KCI which is not present in the cell, so it is incorrect.
Option (2) at cathode Ag is being oxidised to Ag+ and at cathode oxidation does not take place. Hence, it is also incorrect.
Option (3) has AgCI(s) and AgCI which do not ionize. It is also incorrect.

SRMJEE Mock Test - 7 (Medical) - Question 13
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The method of zone refining of metals is based on the principle of

Detailed Solution: Question 13

Zone refining:-

It is based upon fractional crystallization as the impurity prefer to stay in the melt and on solidification, only pure metal solidifies on the surface of melt.

The principle in this process is solubility of the impurity in the metal in melt state is greater than in solid state.

SRMJEE Mock Test - 7 (Medical) - Question 14
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More number of oxidation states are exhibited by the actinoids than by the lanthanoids. The main reason for this is

Detailed Solution: Question 14

The 5f-orbitals extend into space beyond the 6s and 6p-orbitals and participate in bonding. This is in direct contrast to the lanthanides where the 4f-orbitals are buried deep inside in the atom, totally shielded by outer orbitals and thus unable to take part in bonding.

SRMJEE Mock Test - 7 (Medical) - Question 15
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Pick the odd one in each series and select the correct option:
(i) Areolar tissue, blood neuron, tendon
(ii) Salivary gland, gastric gland, tear gland, thyroid gland
(iii) Adrenal gland, sweat gland, milk gland, oil gland

Detailed Solution: Question 15

(i) Neuron is a part of neural tissue while the remaining three belong to connective tissue. 
(ii) Thyroid gland is an endocrine gland while the remaining three are exocrine glands 
(iii) Adrenal gland is an endocrine gland while the remaining three are exocrine glands.

SRMJEE Mock Test - 7 (Medical) - Question 16
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Which algae are used in the production of biofuels due to their high oil content?

Detailed Solution: Question 16

Some species of Chlorophyceae, such as Chlorella, are rich in oils and are explored for biofuel production, making Option B the correct answer.

SRMJEE Mock Test - 7 (Medical) - Question 17
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Which hormone is released by the JG cells in response to a fall in glomerular blood flow?

Detailed Solution: Question 17

  • When there is a decrease in glomerular blood flow, the JG (Juxtaglomerular) cells in the kidneys respond by releasing a hormone called renin.
  • Renin plays a crucial role in the renin-angiotensin mechanism. It converts angiotensinogen, a protein present in the blood, into angiotensin I, which is further converted to angiotensin II.
  • Angiotensin II acts as a potent vasoconstrictor, causing the blood vessels to narrow, which increases the glomerular blood pressure and subsequently the glomerular filtration rate (GFR).
  • The release of renin is part of a complex regulatory system that helps regulate blood pressure and maintain renal function.

Topic in NCERT: RENIN-ANGIOTENSIN MECHANISM

Line in NCERT: "The JG cells to release renin which converts angiotensinogen in blood to angiotensin I and further to angiotensin II."

SRMJEE Mock Test - 7 (Medical) - Question 18
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Correct sequence of layers of bacterial cell envelope from outward to inward is

Detailed Solution: Question 18

Glycocalyx is the outermost layer of the cell envelope. Cell wall lies between plasma membrane andd glycocalyx.

Topic in NCERT: Cell Envelope and Modifications

Line in NCERT: "The cell envelope consists of a tightly bound three layered structure i.e., the outermost glycocalyx followed by the cell wall and then the plasma membrane."

SRMJEE Mock Test - 7 (Medical) - Question 19
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Which of the statements given above is/are correct?

i. Lipids are generally water soluble and include simple fatty acids.

ii. Fatty acids can be either saturated (without double bonds) or unsaturated (with one or more double bonds).

iii. Glycerol is a simple sugar that can be esterified with fatty acids to form triglycerides.

iv. Phospholipids are found in cell membranes and contain phosphorus.

Detailed Solution: Question 19

To determine the correct statements:

  • Statement i is incorrect because lipids are generally water insoluble, not soluble.
  • Statement ii is correct as it accurately describes the types of fatty acids.
  • Statement iii is incorrect because glycerol is not a simple sugar; it is a trihydroxy alcohol (trihydroxy propane) that combines with fatty acids to form triglycerides.
  • Statement iv is correct as phospholipids are indeed found in cell membranes and contain phosphorus.

Thus, the correct statements are ii and iv, making Option A the right choice.

SRMJEE Mock Test - 7 (Medical) - Question 20
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Arrange the following in the increasing order of their size:

Detailed Solution: Question 20

The correct order from smallest to largest is virus, PPLO (Mycoplasma), typical bacteria, and typical eukaryotic cell. Viruses are the smallest, usually only visible with an electron microscope. PPLOs are slightly larger than the largest viruses but smaller than typical bacteria. Typical bacteria are larger than viruses and PPLOs and are visible under light microscopes. Eukaryotic cells are the largest, significantly bigger than viruses, PPLOs, and typical bacteria, making Option A the correct choice.

Topic in NCERT: PROKARYOTIC CELLS

Line in NCERT: "Typical bacteria (1-2 µm) PPLO (about 0.1 µm) A typical eukaryotic cell (10-20 µm) Viruses (0.02-0.2 µm)"

SRMJEE Mock Test - 7 (Medical) - Question 21
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Which one of the following microbes is used in the commercial production of ethanol?

Detailed Solution: Question 21

Saccharomyces cerevisiae
Compared to other types of microoganisms, yeasts especially Saccharomyces cerevisiae is the common microbes employed in ethanol production due to its high ethanol productivity, high ethanol tolerance and ability of fermenting wide range of sugars.

NCERT Topic: Microbes in industrial products

NCERT Line: "Yeast (Saccharomyces cerevisiae) is used for commercial production of ethanol."

SRMJEE Mock Test - 7 (Medical) - Question 22
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Refer to the given diagram. What does it represent?
image

Detailed Solution: Question 22

The given diagram represents post-transcriptional processing resulting in the formation of mRNA. Since, introns and exons are present, it is transcription in eukaryotes.

NCERT Topic: transcription in eukaryotes

NCERT Line: "Figure 5.11 Process of Transcription in Eukaryotes"

SRMJEE Mock Test - 7 (Medical) - Question 23
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How does the Law of Segregation explain the inheritance of traits in offspring?

Detailed Solution: Question 23

The Law of Segregation clarifies that alleles segregate independently during gamete formation, ensuring that each gamete receives only one of the two factors or alleles from a parent. This segregation process underlies the inheritance of traits and explains why both parental traits are not always visible in the F1 generation. Heterozygous parents, which carry two different alleles for a trait, produce gametes with equal proportions of each allele, contributing to genetic diversity in offspring.

Topic in NCERT: Law of Segregation

Line in NCERT: "Though the parents contain two alleles during gamete formation, the factors or alleles of a pair segregate from each other such that a gamete receives only one of the two factors."

SRMJEE Mock Test - 7 (Medical) - Question 24
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A human male produces sperms with the genotypes AB, Ab, aB, ab pertaining to two diallelic characters in equal proportions. What is the corresponding genotype of this person?

Detailed Solution: Question 24

  • If the genotype is AaBb the alleles that are produced will be AB, Ab, aB, ab, since there are two diallelic characters in the genotypes the person must be heterozygous for both genes. AABB is homozygous. So, the correct answer is "AaBb".

Fig: Diallelic characters in the genotype

Hence, the correct option is B.

NCERT Reference: Topic - INHERITANCE OF TWO GENES” of chapter "Principles of Inheritance and Variation"  of NCERT 

SRMJEE Mock Test - 7 (Medical) - Question 25
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In an exam, the minimum passing marks have been set at 40%. A student scores 164 marks and fails by 76 marks. Find out the maximum marks of that exam.

Detailed Solution: Question 25

Minimum passing marks = Marks obtained + Marks failed by
= 164 + 76 = 240
Minimum passing marks = 240
Minimum passing percentage = 40%
Maximum Marks = × 100
= 600

SRMJEE Mock Test - 7 (Medical) - Question 26
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From the top of a platform 5 metre high, the angle of elevation of a tower is 30 degrees. If the platform is positioned 40√3 metres away from the tower, how tall is the tower?

Detailed Solution: Question 26

AD = Height of the tower.

C is the top of the platform.

BC = DE = 40√3 m

Calculating:

tan 30° = AB / BC
1 / √3 = AB / 40√3

AB = 40 m

Height of the tower = AB + Height of the platform
AD = 40 + 5 = 45 m

Thus, the tower is 45 metres tall.

SRMJEE Mock Test - 7 (Medical) - Question 27
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Directions: Read the given information carefully and answer the questions given below:
Rana drove 8 miles due west, then 66 miles due north, then 3 miles due east and then 6 more miles due north. The distance between the initial and final position is _______.

Detailed Solution: Question 27

Consider the following direction diagram,

According to the question we can form the following diagram, where Rana starts from point O.

OE = 8−3 = 5 miles

DE = 12 miles

∴ OD = √122 + 52 (Using theorem of right triangle)

OD = 13 miles

Hence, the distance between initial and final position is 13 miles.

SRMJEE Mock Test - 7 (Medical) - Question 28
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If x − 1/x = 5, then find the value of x⁴ + 1/x⁴.

Detailed Solution: Question 28

Let x - 1/x = 5.

Square both sides: (x - 1/x)² = 5² x² - 2 + 1/x² = 25 x² + 1/x² = 27.

Now, square x² + 1/x² to find x⁴ + 1/x⁴: (x² + 1/x²)² = 27² x⁴ + 2 + 1/x⁴ = 729 x⁴ + 1/x⁴ = 729 - 2 = 727.

Thus, the correct answer is A) 727

SRMJEE Mock Test - 7 (Medical) - Question 29
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Which of following is true about equity ownership in different countries?

Detailed Solution: Question 29

Last paragraph of the passage says, "While cross-country comparisons are somewhat difficult given that the reporting of equity ownership data is not uniform ..." So, option 3 is correct.

SRMJEE Mock Test - 7 (Medical) - Question 30
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Directions: Choose the word/group of words which is most similar in meaning to the word printed in underline as used in the passage.

Comparable

Detailed Solution: Question 30

Comparable, in the passage, refers to comparing the related things, i.e. holdings in companies in India and other countries. So, option 2 is correct.

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This mock test contains 125 questions designed to replicate the pattern, difficulty level and time pressure of the actual JEE exam. It is part of SRMJEEE Subject Wise & Full Length Mock Tests 2026 on EduRev, covering all the topics that are being asked as per the current JEE syllabus. Attempting this test under timed conditions will help you assess your exam readiness, identify subject-wise weak areas, and improve your speed and accuracy before the actual exam.

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