SRMJEEE Subject Wise & Full Length SRMJEE Mock Test - 8 (Medical) Free

In the given circuit only diode D₁ will allow the current to pass through as it is forward-biased.
Hence, the current through the 100 ohm resistance is (∵ resistance of D₁ = 50 Ω)
I = A
= 0.02 A

Using the concept of escape velocity,

v_e = 11.2 10³ m/s

Here, F_CA = F_CB = F_C
Hence, the resultant force on the charge at C is

Given h_5th = 2 × h_6th. By solving we get u = 65 m s⁻¹

In the presence of friction, acceleration, a = (gsinθ − μgcosθ)

∴ Time taken to slide down the incline,

In the absence of friction, time taken to slide down the incline, 

According to the question, t₁ = 2t₂

sinθ = 4sinθ − 4μcosθ

The unit of K is mol L^-1 min^-1, which corresponds to a zero order reaction.
∴ Rate = K = Constant
Concentration of A which has reacted in 100 minutes = 100 × K = 100 × 1.0 × 10^-3 = 0.1 mol L^-1
∴ Concentration of B after 100 minutes = 2 × 0.1 = 0.2 mol L^-1

Second order reactions can be defined as chemical reactions wherein the sum of the exponents in the corresponding rate law of the chemical reaction is equal to two. The rate of such a reaction can be written as r = k[A]².
The half life of the reaction is 1/k[A].

As the tendency of polymerization increases, the compactness also increases. White phosphorous occurs as discrete molecules, red phosphorous is a linear chain polymer while black phosphorous has a layered structure like graphite.

The Beckmann rearrangement is an organic reaction used to convert an oxime to an amide under acidic conditions. The reaction begins by protonation of the alcohol group forming a better leaving group. The R group trans to the leaving group then migrates to the nitrogen, resulting in a carbocation and the release of a water molecule. This trans [1-2]-shift allows for the prediction of the regiochemistry of this reaction. The water molecule then attacks the carbocation and after deprotonation and tautomerization results in the final amide product.

The rusting of iron involves oxidation of iron.

Higher the oxidation potential, higher the tendency to get oxidised. The oxidation potential of Fe∣∣Fe²⁺ and Zn∣∣Zn²⁺ are 0.44 V and 0.76 V respectively.

Thus, the oxidation potential of Zn is higher than Fe. That's why Zn will get oxidised and Fe will remain protected.

Correct option is A

The internal and external lining of organs is formed by different types of epithelial tissue, based on the function of the organ. Example, alveoli- exchange of gases- squamous epithelium, skin-protection - keratinised epithelium and so on... . The function of different types of connective tissue is transport substances between various tissues and organs in the body (blood), bind tissue together (loose and dense) and to provide support (bone and cartilage), that i's they do not form linings of body organs.

All the other statements about connective tissue are true.

So, the correct answer is '(iv) only'

Normal blood pressure is 120/80 mm Hg. Blood pressure of 190/110 mm Hg is regarded as high blood pressure. It leads to heart diseases and also affects vital organs like brain and kidney.

The light-harvesting complexes (LHC) are made up of pigments that absorb different wavelengths of light, thus enhancing the efficiency of photosynthesis. These pigments help in capturing light energy and transferring it to the reaction centers, where the actual photochemical reactions occur.

Topic in NCERT: Roles various pigments play in photosynthesis

Line in NCERT: "these pigments help to make photosynthesis more efficient by absorbing different wavelengths of light."

• The epithelial cells of Bowman’s capsule called podocytes, which are arranged in an intricate manner so as to leave some minute spaces called filtration slits or slit pores.
• Blood is filtered so finely through these membranes, that almost all the constituents of the plasma except the proteins pass onto the lumen of the Bowman’s capsule.

Therefore, it is considered as a process of ultra filtration.