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SRMJEEE Subject Wise & Full Length SRMJEE Aptitude Mock Test - 3 Free Online


Full Mock Test & Solutions: SRMJEE Aptitude Mock Test - 3 (20 Questions)

You can boost your JEE 2026 exam preparation with this SRMJEE Aptitude Mock Test - 3 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of JEE 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 25 minutes
  • - Total Questions: 20
  • - Analysis: Detailed Solutions & Performance Insights

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SRMJEE Aptitude Mock Test - 3 - Question 1
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What number should be added to each of the numbers 35, 115, 53 and 165, so that the resulting numbers are in continued proportion?

Detailed Solution: Question 1

Let x be the number added to each of the numbers 35, 115, 53 and 165.
According to the question,

Now,
⇒ (35 + x)(165 + x) = (53 + x) (115 + x)
⇒ 5775 + 165x + 35x + x2 = 6095 + 115x + 53x + x2
⇒ 200x - 168x = 320
⇒ 32x = 320
⇒ x = 10
Hence, 10 should be added to each of the numbers 35, 115, 53 and 165, so that the resulting numbers are in continued proportion.

SRMJEE Aptitude Mock Test - 3 - Question 2
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The point P(a, b) is first reflected in origin to P1 and P1 is reflected in Y-axis to (4, -3). What are the coordinates of point P?

Detailed Solution: Question 2

P(a, b) is reflected in origin to P1. Change the sign of both X and Y coordinates.
Coordinates of P1 = (-a, -b)
Now, point P1 is reflected in Y-axis. The Y-coordinate remains the same. Change the X-co-ordinate.
The coordinates of the next point should be (a, -b), which is equal to (4, -3).
So, a = 4 and b = 3
Therefore, the coordinates of point P are (4, 3).

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SRMJEE Aptitude Mock Test - 3 - Question 3
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What is the difference between a single discount of 30% and a single discount equivalent to two successive discounts of 25% and 5% being given on the shopping of Rs. 2,000?

Detailed Solution: Question 3

Discount = = Rs. 600
Single equivalent discount for discounts of 25% and 5%
=
= (30 - 1.25)% = 28.75%
Therefore, discount = = Rs. 575
∴ Difference = (600 – 575) = Rs. 25
Hence, option 1 is correct.

SRMJEE Aptitude Mock Test - 3 - Question 4
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A person sells an article at a profit of 12%. If he had purchased it for 12% less and sold if for Rs. 9 less, he would have gained 27%. What is the original cost price of the article?

Detailed Solution: Question 4

Let the cost price (CP1) of the article be Rs. 100.
Then the selling price (SP1) would be Rs. 112.
Let new cost price (12% less) = Rs. 88
New selling price (27% profit) = 127% of 88 = Rs. 111.76
Now, difference between the two selling prices = 112 – 111.76 = Rs. 0.24
When the difference is 0.24, then CP = Rs. 100
When the difference is 9, then CP = 100 × = Rs. 3750
Hence, the cost price of the article is Rs. 3750.

SRMJEE Aptitude Mock Test - 3 - Question 5
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The value of is

Detailed Solution: Question 5


SRMJEE Aptitude Mock Test - 3 - Question 6
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In ΔABC, AD bisects ∠A and intersects BC at D. If BC = a, AC = b and AB = c, then BD = ?

Detailed Solution: Question 6

Given information:
In ΔABC, AD is the bisector of angle BAC, AB = c, BC = a and AC = b.

From the properties of Angle Bisector Theorem, if AD is the bisector of angle BAC, then we will get the following result:

Therefore, BD =

SRMJEE Aptitude Mock Test - 3 - Question 7
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If the given number 925x85 is divisible by 11, then the smallest value of x is:

Detailed Solution: Question 7

- To check if 925x85 is divisible by 11, calculate the difference between the sum of the digits in odd positions and even positions.
- Odd position sum: 9 + 5 + 8 = 22
- Even position sum: 2 + x + 5 = 7 + x
- Set up the equation: 22 - (7 + x) = 15 - x
- For divisibility by 11, this should equal a multiple of 11: 15 - x = 11a.
- For the smallest value of x, set a = 1: 15 - x = 11 gives x = 4.
- Thus, the smallest value of x is 4.

SRMJEE Aptitude Mock Test - 3 - Question 8
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Solve the following:

Detailed Solution: Question 8





Hence, answer option 3 is correct.

SRMJEE Aptitude Mock Test - 3 - Question 9
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Find the greatest value of b so that 30a68b (a > b) is divisible by 11.

Detailed Solution: Question 9

If the difference between the sum of the digits at odd places and that at even places is equal to 0 or divisible by 11, the number is divisible by 11.
(3 + a + 8) - (0 + 6 + b) = 0 or 11
11 + a - 6 - b = 0 or 11
5 + a - b = 0 or 11
5 + a - b ≠ 0 [a > b] Let 5 + a - b = 11
a - b = 6
For a = 9, b = 3 ∵ [a > b]
9 - 3 = 6
The greatest value of b is 3, when 30a68b (a > b) is divisible by 11.

SRMJEE Aptitude Mock Test - 3 - Question 10
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What is the percentage increase in the number of audience in screen 1 from second show to third show?

Detailed Solution: Question 10

In screen 1,
number of audience from 2nd show (in '00 units) = 3
number of audience from 3rd show (in '00 units) = 6
% increase = × 100 = 100%

SRMJEE Aptitude Mock Test - 3 - Question 11
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For the second show, the number of audience in screen 3 is how much more than the number of audience in screen 1?

Detailed Solution: Question 11

For the second show,
number of audience in screen 3 = 700
number of audience in screen 1 = 300
Required difference = 700 - 300 = 400

SRMJEE Aptitude Mock Test - 3 - Question 12
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What is the percentage increase in the total number of audience from second show to third show?

Detailed Solution: Question 12

Total audience in 2nd show (in '00 units) = 3 + 4.5 + 7 = 14.5
Total audience in 3rd show (in '00 units) = 6 + 4 + 7.5 = 17.5
% increase =
=
= 20.69%

SRMJEE Aptitude Mock Test - 3 - Question 13
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If the tickets for screens 1, 2 and 3 are Rs. 350, Rs. 300 and Rs. 250, respectively, then which of the following screens has/have the maximum total revenue for three shows?

Detailed Solution: Question 13

Ticket price for screen 1 = Rs. 350
Total audience for screen 1 = 500 + 300 + 600 = 1400
Revenue for screen 1 = 350 × 1400 = Rs. 4,90,000
Similarly, revenue for screen 2 = 300 × (600 + 450 + 400) = Rs. 4,35,000
Revenue for screen 3 = 250 × (650 + 700 + 750) = Rs. 5,25,000

SRMJEE Aptitude Mock Test - 3 - Question 14
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A dish is made up of ingredients A and B in the ratio 2 : 5. The price of A is three times that of B. The overall cost of the dish is Rs. 5.20 per kg, including cost of other ingredients and fuel is at 80 paise per kg. What is the cost of B per kg?

Detailed Solution: Question 14

Let the price of B per kg be Rs. X.
Then, the price of A per kg = Rs. 3X
1 kg of dish contains 2/7 kg of A and 5/7 kg of B.
Price of 1 kg of dish
By the given condition,

Hence, price of B per kg = Rs. 2.80

SRMJEE Aptitude Mock Test - 3 - Question 15
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D and E are points on sides AB and AC of ΔABC. DE is parallel to BC. If AD : DB = 1 : 4 and area of ADE is 6 sq. cm, then what is the ratio of area of ΔADE : Area of quadrilateral BDEC?

Detailed Solution: Question 15


Triangle ABC and triangle ADE are two similar triangles, where ABC is the larger triangle.
Ratio of areas is square of sides of two triangles.
AD : DB = 1 : 4
AD = x, DB = 4x and AB = 5x
Area of ADE/Area of ABC = (AD/AB)2
Area of ADE/Area of ABC = (x/5x)2
Area of ADE/Area of ABC = 1/25
Area of ABC = 25 × 6 = 150
Area of BDEC = 150 - 6 = 144
Area of ADE/Area of BDEC = 6/144 = 1/24

SRMJEE Aptitude Mock Test - 3 - Question 16
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B is an intermediate station along a river, equidistant from stations A and C. A boat can move from A to B and come back in 6 hours, and can move from A to C in 4 hours. How long would it take for the boat to go from C to A?

Detailed Solution: Question 16

Time taken by the boat to move from A to C = 4 hours
∴ Time taken by the boat to move from A to B = 2 hours (since B is intermediate)
Also, time taken by the boat to move from A to B and B to A = 6 hours
∴ Time taken by the boat to move from B to A = 6 - 2 = 4 hours
Time taken by the boat to move from C to A = 2 × 4 = 8 hours

SRMJEE Aptitude Mock Test - 3 - Question 17
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In ΔABC, MN || BC, the area of quadrilateral MBCN = 130 sq. cm. If AN : NC = 4 : 5, then the area of ΔMAN is:

Detailed Solution: Question 17

Given- AN : CN = 4 : 5
Let AN = 4x and CN = 5x
Therefore, AC = AN + NC
= 4x + 5x = 9x
In △ABC, MN || BC,

Therefore, area of ΔMAN be 16 units and that of ΔBAC be 81 units.
Area of quadrilateral MBCN = 130 sq. cm
Area of ΔBAC - area of ΔMAN = 130 sq. cm
81 units - 16 units = 130 cm2
x  = 130/65
x = 2 units
Therefore, Area of ΔMAN = 16 units = 16 × 2
= 32 sq. cm
Thus, ΔMAN = 32 sq. cm.

SRMJEE Aptitude Mock Test - 3 - Question 18
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If A = 2B = 4C, what is the value of A : B : C?

Detailed Solution: Question 18

A = 2B = 4C
Dividing by 4, we have
A/4 = B/2 = C/1
⇒ A : B : C = 4 : 2 : 1

SRMJEE Aptitude Mock Test - 3 - Question 19
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What is the reflection of the point (-1, 3) in the line x = -4?

Detailed Solution: Question 19

SRMJEE Aptitude Mock Test - 3 - Question 20
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is equal to:

Detailed Solution: Question 20

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About this JEE Mock Test

This mock test contains 20 questions designed to replicate the pattern, difficulty level and time pressure of the actual JEE exam. It is part of SRMJEEE Subject Wise & Full Length Mock Tests 2026 on EduRev, covering all the topics that are being asked as per the current JEE syllabus. Attempting this test under timed conditions will help you assess your exam readiness, identify subject-wise weak areas, and improve your speed and accuracy before the actual exam.

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