Explore Exams
Login Signup
Sign in Open App
NEET Exam  >  NEET Test  >   Mock Test Series - Updated 2026 Pattern  >  Chemistry: Topic-wise Test- 1 - NEET MCQ

NEET Chemistry: Topic-wise Test- 1 Free Online Test 2026


MCQ Practice Test & Solutions: Chemistry: Topic-wise Test- 1 (45 Questions)

You can prepare effectively for NEET NEET Mock Test Series - Updated 2026 Pattern with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Chemistry: Topic-wise Test- 1". These 45 questions have been designed by the experts with the latest curriculum of NEET 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 45 minutes
  • - Number of Questions: 45

Sign up on EduRev for free to attempt this test and track your preparation progress.

Chemistry: Topic-wise Test- 1 - Question 1
Save

The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would be

Detailed Solution: Question 1

As vapour density of mixture is 25,

Molar mass of mixture is 2×25=50.

Now, assume mole % of B in mixture is x.

Chemistry: Topic-wise Test- 1 - Question 2
Save

Atomic mass of Cl is 35.5 g. Calculate the mass of 4.50 moles of chlorine gas, Cl2.​

Detailed Solution: Question 2

Mass of 1 mole of Cl2 is 71 g. Hence mass of 4.50 moles is 71 X 4.50 = 319.5 g

Clear all your doubts with EduRev
Chemistry: Topic-wise Test- 1 - Question 3
Save

Atomic mass of bromine is 80 g. The mass of four moles of molecular bromine (Br2) is:​

Detailed Solution: Question 3

Mass of one mole of Br2  is 160g. Hence mass of four moles of molecular bromine is 4 X 160 = 640 g.

Chemistry: Topic-wise Test- 1 - Question 4
Save

Modern periodic table is based on atomic no. experiments which proved importance of at no. was -

Detailed Solution: Question 4

Moseley's work on X-ray spectra proved the significance of the atomic number.

Chemistry: Topic-wise Test- 1 - Question 5
Save

Atomic wt. or Cl = 35.5 and of I = 127. According to doeberiner triad rule, At. wt. of Br will be -

Detailed Solution: Question 5

Chemistry: Topic-wise Test- 1 - Question 6
Save

Justification of putting H in VII A group is -

Detailed Solution: Question 6

The reason for the putting of VII A group is that the reaction of hydrogen with group 1 elements as the same as that of other halogens.

Chemistry: Topic-wise Test- 1 - Question 7
Save

There is no S-S bond in

Detailed Solution: Question 7


Chemistry: Topic-wise Test- 1 - Question 8
Save

A : tetracyanomethane B : carbon dioxide C : benzene D : 1,3-butadiene Ratio of σ and π bond is in order:

Detailed Solution: Question 8

Correct option: A

For tetracyanomethane: the central carbon is bonded to four cyano groups by four single (σ) bonds, and each cyano group contains a C≡N triple bond (one σ + two π). Thus total σ = 4 (central C-C) + 4 (one σ in each C≡N) = 8, total π = 4 × 2 = 8, so σ/π = 8/8 = 1.

For carbon dioxide: the structure is O=C=O with two C=O double bonds. Each C=O has one σ and one π, so total σ = 2, total π = 2, and σ/π = 2/2 = 1.

For benzene: there are six C-C σ bonds and six C-H σ bonds, so total σ = 6 + 6 = 12. There are three π bonds (one π per C=C representation in Kekulé form), so π = 3. Therefore σ/π = 12/3 = 4.

For 1,3-butadiene: there are three C-C σ bonds and six C-H σ bonds (total hydrogen atoms = 6), so total σ = 3 + 6 = 9. There are two C=C bonds giving π = 2, so σ/π = 9/2 = 4.5.

Comparing the ratios gives 1 (A) = 1 (B) < 4 (C) < 4.5 (D), hence A = B < C < D.



Chemistry: Topic-wise Test- 1 - Question 9
Save

Which of the following models best describes the bonding within a layer of the graphite structure ?

Detailed Solution: Question 9

Chemistry: Topic-wise Test- 1 - Question 10
Save

In  , the shape is square planer. The number of bond pair-lone pair repulsion at 90° are :

Detailed Solution: Question 10


⇒ No of bond pair-lone pair repulsion = 8

Chemistry: Topic-wise Test- 1 - Question 11
Save

The critical temperature of water is higher than that of O2 because the H2O molecules has :

Detailed Solution: Question 11

⇒ H2O is polar molecule
⇒ Hence  H2O has higher critical temp

Chemistry: Topic-wise Test- 1 - Question 12
Save

Among these canonical structures, the correct order of stability is

Chemistry: Topic-wise Test- 1 - Question 13
Save

Amongt these canonical structures which one is least stable ?

Chemistry: Topic-wise Test- 1 - Question 14
Save

CH2 = CH – CH = CH – CH3 is more stable than CH3 – CH = C = CH – CH3 because

Chemistry: Topic-wise Test- 1 - Question 15
Save

For phenol which ofthe following resonating structure is the most stable ?

Chemistry: Topic-wise Test- 1 - Question 16
Save

Among these three canonical structures (through more are possible) what would be their relative contribution in the hybrid

Chemistry: Topic-wise Test- 1 - Question 17
Save

The most stable resonating structure of following compound is

Chemistry: Topic-wise Test- 1 - Question 18
Save

Which of the following is not a possible termination step in the free radical chlorination of methane?

Detailed Solution: Question 18

Termination is the last step. So there shouldn't be any free radical atom remaining. In first option there is Cl• remaining it can't be termination step.The steps in free radical halogenation are as

Chemistry: Topic-wise Test- 1 - Question 19
Save

The major monobromination product which results when ethyl cyclohexane is subjected to free radical bromination, is

Detailed Solution: Question 19


Free radical bromination reaction is highly selective, occurs mainly at the carbon where most stable free radical is formed.
We know that the stability of free radical is in the order,
Tertiary radical > Secondary radical > Primary radical
In (a), (b) and (c), the bromination occurs at secondary carbon whereas in (d) the bromination occurs at tertiary carbon. Since, tertiary radicals are more stable than secondary radical the major product of monobromination of ethyl cyclohexane is (d).
The stability of tertiary radical is due to the higher number of α−Hygrogens which give more hyperconjugation effect than secondary.

Chemistry: Topic-wise Test- 1 - Question 20
Save

Which set of reagent(s) in correct order would accomplish the following transformation?

Chemistry: Topic-wise Test- 1 - Question 21
Save

The major product of the following reaction is

Chemistry: Topic-wise Test- 1 - Question 22
Save

Direction (Q. Nos. 1 - 7) This section contains 7 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. What is true about the reaction given below?

Chemistry: Topic-wise Test- 1 - Question 23
Save

What is major product in the following reaction?

Chemistry: Topic-wise Test- 1 - Question 24
Save

Direction (Q. Nos. 12 and13) This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

Caryophyllene (C15H24) contain a six membered ring and on ozonolysis gives following product.

Q. The structure of caryophyllene is

Chemistry: Topic-wise Test- 1 - Question 25
Save

Caryophyllene (C15H24) contain a six membered ring and on ozonolysis gives following product.

Q. If caryophyllene is treated with 1.0 mole of HCI, a ring closure reaction takes place to form monochloride. What is the most likely product of this reaction?

Chemistry: Topic-wise Test- 1 - Question 26
Save

Ethanol has a higher boiling point than dimethyl ether though they have the same molecular weight. This is due to :

Detailed Solution: Question 26


⇒ due to intermolecular H-bond, it has higher b.p. than CH3OCH3

Chemistry: Topic-wise Test- 1 - Question 27
Save

Arrange the following in order of decreasing boiling point :

(I) n-Butane (II) n-Butanol (III) n-Butyl chloride (IV) Isobutane

Detailed Solution: Question 27

(I) H3C—CH2—CH2—CH3 n-butane




II > III >I > IV
As H-bond>d Interaction
> st. chain > Branch chain

Chemistry: Topic-wise Test- 1 - Question 28
Save

Which of the following compounds would have significant intermolecular hydrogen bonding ?

HF, CH3OH, N2O4, CH4

Detailed Solution: Question 28


⇒ due to intermolecular H-bond, it has higher b.p. than CH3OCH3

Chemistry: Topic-wise Test- 1 - Question 29
Save

For H2O2, H2S, H2O and HF , the correct order of decreasing extent of hydrogen bonding is :

Detailed Solution: Question 29

Chemistry: Topic-wise Test- 1 - Question 30
Save

A simplified application of MO theory to the hypothetical `molecule' OF would give its bond order as

Detailed Solution: Question 30

View more questions
1 videos|19 docs|61 tests
Join Course
Information about Chemistry: Topic-wise Test- 1 Page
In this test you can find the Exam questions for Chemistry: Topic-wise Test- 1 solved & explained in the simplest way possible. Besides giving Questions and answers for Chemistry: Topic-wise Test- 1, EduRev gives you an ample number of Online tests for practice
Download as PDF

About this NEET Practice Test

This test contains 45 MCQs on Chemistry: Topic-wise Test- 1 with detailed solutions for each question. It is part of the NEET Mock Test Series - Updated 2026 Pattern course on EduRev, designed to align with the current NEET syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

Explore more NEET Study Resources

If you found this Chemistry: Topic-wise Test- 1 MCQ Test helpful, you can further enhance your NEET preparation with in-depth courses on EduRev, for all the subjects and topics available in NEET Mock Test Series - Updated 2026 Pattern course. The course offers:
  • Video Lectures: covering all the topics of NEET Mock Test Series - Updated 2026 Pattern
  • Notes for Revision: offering revision notes, important questions, summaries, flashcards, cheatsheets & more for NEET preparation
  • MCQ Test: variety of questions as per the pattern of NEET exam
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup