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SSC CGL Exam  >  SSC CGL Test  >   Tier 2 - Study Material, Online Tests, Previous Year  >  Test: Simplification- 5 - SSC CGL MCQ

Simplification- 5 - Free MCQ Practice Test with solutions, SSC CGL


MCQ Practice Test & Solutions: Test: Simplification- 5 (20 Questions)

You can prepare effectively for SSC CGL SSC CGL Tier 2 - Study Material, Online Tests, Previous Year with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Simplification- 5". These 20 questions have been designed by the experts with the latest curriculum of SSC CGL 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 20

Sign up on EduRev for free to attempt this test and track your preparation progress.

Test: Simplification- 5 - Question 1
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69 ÷ 3 * 0.85+ 14.5 – 3 = ?

Detailed Solution: Question 1

69 ÷ 3 * 0.85 = 23 * 0.85 = 19.55
19.55 + 14.5 – 3 = 31.05

So option E is correct

Test: Simplification- 5 - Question 2
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4.5 + 23.50 + 14.58 – 17.68 * 0.5 = ?

Detailed Solution: Question 2

17.68 * 0.5 = 8.84
42.58 – 8.84 = 33.74

So option B is correct

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Test: Simplification- 5 - Question 3
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23.56 + 4142.25 + 134.44 = ?

Detailed Solution: Question 3

To solve the problem:

  1. Add 23.56 and 4142.25:
    • Whole numbers: 23 + 4142 = 4165
    • Decimals: 0.56 + 0.25 = 0.81
    • Total: 4165.81
  2. Add the result to 134.44:
    • Whole numbers: 4165 + 134 = 4299
    • Decimals: 0.81 + 0.44 = 1.25
    • Adding decimals to whole number: 4299 + 1.25 = 4300.25

Thus, the correct answer is D. 4300.25.

Test: Simplification- 5 - Question 4
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(√ 7744 * 66 ) ÷ (203 + 149)= ?

Detailed Solution: Question 4

√7744 = 88
(√7744 * 66) = 5808; 

5808/352 = 16.5

So option E is correct

Test: Simplification- 5 - Question 5
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5/9 of 504 + 3/8 of 640 =  ?

Detailed Solution: Question 5

Test: Simplification- 5 - Question 6
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Solve for y: 

(786 × 74) ÷ y = 1211.75

Detailed Solution: Question 6

(786 × 74) ÷ y = 1211.75

Step 1: Multiply 786 × 74
786 × 74 = 58164

Step 2: Write the equation
58164 ÷ y = 1211.75

Step 3: Multiply both sides by x and then divide
y = 58164 ÷ 1211.75

y = 48

Final Answer: (d) 48

Test: Simplification- 5 - Question 7
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18² + √? = 350

Detailed Solution: Question 7

18² + √? = 350
√? = 350 – 324 = 26
? = 676

So option A is correct

Test: Simplification- 5 - Question 8
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140% of 500 + 24% of 750 = ?

Detailed Solution: Question 8

140% of 500 is 700

24% of 750 is 180

700 + 180 = 880

So option D is correct

Test: Simplification- 5 - Question 9
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4900 ÷ 28 * 444 ÷ 12 = ?

Detailed Solution: Question 9

4900 ÷ 28 = 175
444 ÷ 12 = 37
175 * 37 = 6475

So option C is correct

Test: Simplification- 5 - Question 10
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1221 + 1117 = x% of 6680 

Detailed Solution: Question 10

First, calculate the sum of 1221 and 1117:

  • 1221 + 1117 = 2338

Next, determine what percentage 2338 is of 6680 using the formula for percentage:

  • x% = (2338 / 6680) × 100
  • x% = 0.35 × 100
  • x% = 35%

Since none of the provided options (26, 32, 43, 17) match the calculated value of 35%, the correct answer is not among the given choices.

Test: Simplification- 5 - Question 11
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√3840.56 × [(501.01)2 / 250] × 0.987 = ? *1000

Detailed Solution: Question 11

To solve the problem, follow these steps:

  • Compute √3840.56 ≈ 62.
  • Calculate (501.01)2 = 251,011.0201.
  • Divide by 250: 251,011.0201 / 250 ≈ 1004.44408.
  • Multiply all components: 62 × 1004.44408 × 0.987 × 1000 ≈ 61,457,110.

None of the options A-D (56, 76, 43, 51) match the result. Therefore, none are correct.

Test: Simplification- 5 - Question 12
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1/[2 + (1/(4+(1/(5 – 1/3))))] = ?

Detailed Solution: Question 12

1/[2 + (1/(4+(1/(5 – 1/3))))] = 1/[2+(1/(4+(3/14)))] = 1/[2+(14/59)] =1/[118+14/59] =1/(132/59)
=59/132

So option D is correct

Test: Simplification- 5 - Question 13
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1399.99 ÷ 20.21 = ? + 425.5 - (310 ÷ 6 × 20.3)

Detailed Solution: Question 13

1399.99 ÷ 20.21 = ? + 425.5 - (310 ÷ 6 × 20.3)
(1400/20) = x + 426 – (312/6) * 20
70 – 426 + 1040 = x
x = 684 = 680 

Test: Simplification- 5 - Question 14
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3√ 0.000001728 = ?

Detailed Solution: Question 14

To find the cube root of 0.000001728, we calculate a number x such that:

x3 = 0.000001728.

Testing option A:

  • 0.012 × 0.012 × 0.012 = 0.000001728.

Thus, the correct answer is 0.012, which corresponds to option A.

Test: Simplification- 5 - Question 15
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1(2/3) + 2(4/9)  – 3(7/15) =  ?

Detailed Solution: Question 15

2/3 + 8/9 - 21/15 

28/18 - 21/15

140-126/90

7/45 = 0.15

So option A is correct

Test: Simplification- 5 - Question 16
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√3/7 × 1124 – ? = 21

Detailed Solution: Question 16

0.4 *1124 = 449.6 = 450
450-9 = 441
441 = 21*21

So option C is correct

Test: Simplification- 5 - Question 17
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If a – b = 7 and a2 + b2 = 53, find the value of ab.

Detailed Solution: Question 17

2ab = (a2 + b2) – (a – b)2
2ab = 53-49 =4
ab =4/2 = 2

So option E is correct

Test: Simplification- 5 - Question 18
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45% of 870 + 67% of 1250 – 21% of 540 = ?

Detailed Solution: Question 18

The final answer to the problem, after calculating each percentage and summing them appropriately, results in 1115.6. However, since this exact value isn't among the provided options and considering typical examination practices where rounding may be applied, the closest option is:

  • B

Test: Simplification- 5 - Question 19
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17 × 756 ÷ √2916 = ? +540

Detailed Solution: Question 19

17*756÷54 = ? +540
17*14 = ? +540
238 = ? + 540
? =238-540 = -302

So option C is correct

Test: Simplification- 5 - Question 20
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√[16+(1/21)] ÷ √[16+(21/84)] × 702/27 = ? 

Detailed Solution: Question 20

= √(337/21 )÷ √(1365/84) × 26
= 16÷16 ×26 = 26

So option A is correct

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About this SSC CGL Practice Test

This test contains 20 MCQs on Simplification- 5 with detailed solutions for each question. It is part of the SSC CGL Tier 2 - Study Material, Online Tests, Previous Year course on EduRev, designed to align with the current SSC CGL syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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