Time And Work - MCQ 2 - Railways MCQ

Efficiency of Kiran = 4%
Efficiency of Ravi = 2%
[(4+2)*10] = 60%
The remaining work done by Sumit = 40%.
40% of 600 = 240

The days ratio of (Angel + Bala + Chitra) : (Bala + Chitra) = X:3X/2 = 2X:3x;
Efficiency ratio = 3X:2X
Efficiency of Angel = x.
(480/3X) = Rs.160
Amount received by Bala = Rs.120 & Chitra = 200
160:120:200 =4:3:5
1/4:1/3:1/5= 15:20:12;
(1/15+1/12+1/20)*Y = 1
Y = 5 days

Angel’s 5 days work = 50%
Balu’s 5 days work = 33.33%
Chitra’s 2 days work = 16.66%
[100- (50+33.33)]
Ratio of work of Angel, Balu and Chitra = 3: 2: 1
Angel’s total share = Rs. 3000
Balu’s total share = Rs. 2000
Chitra’s total share = Rs. 1000
Angel’s one day’s wage = Rs.600
Balu’s one day’s wage = Rs.400
Chitra’s one day’s wage = Rs.500

Let the work lasted for x days,
Ravi’s 4 day’s work + Rakesh (x – 3) day’s work + Geeta’s x day’s work = 1
⇒ (4/16) + (x – 3) / (64/5) + x/32 = 1
⇒ 5(x – 3)/64 + x/32 = 1 – 1/4
⇒ [5(x – 3) + 2x] / 64 = 3/4
⇒ 7x – 15 = 48
∴ x = (48 + 15)/7 = 63/7 = 9 days

Let Rohit, Harsh and Sanjeev can type x, y and z pages respectively in 1 h. Therefore, they together can type 4(x + y + z) pages in 4 h
∴ 4(x + y + z) = 228
⇒ x + y + z = 57 …..(i)
Also, z – y = y – x
i.e., 2y = x + z ……(ii)
5z = 7x ……(iii)
From Eqs. (i) and (ii), we get
3y = 57
⇒ y = 19
From Eq. (ii), x + z = 38
x = 16 and z = 22

Efficiency (A : B) = 5 : 4
Number of days(A : B) = 4x : 5x = 4x : 25
∴ Number of days required by A to finish the work alone = 4x
= 4 x 5 = 20.
A and B work together for last 5 days = 5 x 9 = 45%
Efficiency of A = 5% and B’s efficiency = 4%
∴ No. of days taken by A to complete 55% work = 55/5 = 11days

Let extra hours a day are x.
According to the formula,
(M1D1T1) / W1 = (M2D2T2) / W2
⇒ [1 x 1 x (8 + 6)] / 1 = [1 x 1 x (8 + 8 + x)] / 3/2
⇒ (3/2) x 14 = 16 + x
⇒ 21= 16 + x
∴ x = 21 – 16 = 5

M1 = 150, M2 = 150 – n, D1 = 72, D2 = 90
W1= 2/3 and W2 = 1/3
According to the formula,
(M1D1) / W1 = (M2D2) / W2
⇒ [150 x 72] / 2 = [(150 – n) x 90] / 1
⇒ (150 x 72) / (2 x 60) = (150 – n)
⇒ (150 – n) = 60
∴ n = 150 – 60 = 90

Efficiency of Sanjay = (100/50) = 2%
Rest work = 75%
∴ Efficiency of Ajit = 75/25 = 3%
∴ Combined efficiency of Sanjay and Ajit = 5%
∴ Number of days required by Sonu and Abhijeet, to work together = 100/5 = 20 days.

Efficiency of Kiran and Kumar = 11.11 + 5.55 = 16.66%
Work done in 3 days = 3 x 16.66 = 50%
Rest work done by Kiran, Kumar and Sanjay = 50/50 = 1 day
Work can be completed in 4 days.

Total days Mohan worked = 3+3 = 6
6/15 = 2/5
So 3/5 = 3/x
x = 5

Arun, Bipasha and rahul’s 1 day work = 1/10 + 1/50 = 6/50 = 3/25
Arun’s 1 day work = Bipasha + Rahul ‘s 1 day work
2*(Arun’s 1 day work) = 3/25
Arun’s 1 day work = 3/50
Bipasha’s 1 day work = 1/10 – 3/50 = 2/50 = 1/25

Assume the total work to be 600 units. (LCM of all the numbers) Then Sandeep’s 1 day work = 8 units.
All three’s 1 day work = 40 units.All work together in the first 2 days
Work done in the first 2 days = 40 × 2 = 80 units
Sandeep alone works during the last 40 days
Work done in the last 40 days = 40 × 8 = 320 units
Remaining work = 600 – (320 + 80) = 200 units
This work is done by pradeep and sandeep in 10 days.
Pradeep and Sandeep together’s 1 day work = 20 units
Sekar’s 1 day work = All three 1 day work – Pradeep and Sandeep together’s 1 day
work = 40 units – 20 units = 20 units
Sekar can do the work of 600 units in 30 days.

Dinesh work done = 20*5/4 = 25 days
1/5 workdone by Dinesh and gokul in 3days.
Whole work done = 15 days
Dinesh 1 days work = 1/25
Dinesh and gokul’s 1 day work = 1/15
Gokul’s 1 day work = 1/15 – 1/25 = 2/75
Gokul alone in 75/2 days or 37 ½ days.

Hari + vijay 20 days work = 1/30 *20 = 2/3
Remaining work = 1/3
1/3 work in 20 days so whole work in 60 days.

Let the work be 100 units.
Madhavan’s 1 hour work = 100/5 = 20 units
Manohar and Manjima’s 1 day work = 3/4 × 20 = 15 units.
Mohan and Mani’s 1 day work = 1/5 × 20 = 4 units.
In one day all five of them can do = 20 + 15 + 15 + 4 + 4 = 58 units of work. Hence they can complete the work in 100/58 days.

1/P = 1/10
1/P + 1/Q + 1/R = 1/10 + ¼ = 7/20
In 20 hours, working together, they will complete 7 booklets.
Thus, in 40 hours they will complete 14 booklets.

Number of products made by Nakul in 1 hour = 32/6 = 16/3
Number of products made by Ram in 1 hour = 40/5 = 8
Number of products made by both in 1 hour = 16/3 + 8 = 40/3
Time taken by both to make 110 products = 110* 3/40 = 8 ¼ hrs

Assume there are 360 units of work (LCM of 90, 40 and 12).
Hence, they can do 4,9 and 30 units per day or together 43 units every 3 days.
So In 24 days, 43×8=344 units of work is completed.
In the next 2 days, 13 unitsare completed and on 27th day,Santhosh takes 1/10 thof a day to finish the rest.
So, gopal and vikash worked for 9 days each and have hence put in 36 and 81 units respectively, and the rest of the 243 units is put in by santhosh.
The wages shall also be distributed in the same ratio as: Rs 36, Rs 81 and Rs 243.

Fraction of work completed by Karthik on day 1 and day 2 = 2* 1/30 = 1/15
Fraction of work left after 2 days = 14/15
Fraction of work completed by Both = 1/25 + 1/30 = 11/150
Number of days after day 2 to complete work = 14*150/15*11 = 13 days
So after 2+13 = 15 days works will be completed