Number System - MCQ 5 - Telangana Police Constable MCQ

From ans…150
40% of numb = 60
60% of 150 = 90
90+60 = 150

(9x/16)-(x/2) = 51
X = 51*16 = 816

See the last digit 06…..go for 7
Last digit ..37+(37*37) = 7+49 = 16
So ans: 37

0.01 = 10^-2
(0.0001)² = 10^-8
10^-2/10^-8 = 10⁶

25*5+10*16 = 285
Rs 16 = 1600
No of 10p = 1600*16/285 = 89.82 = 90

a³ + b³ – c³ = -3(abc) = -3(30) = -90

Equation will be satisfied when a=b=c=1
(a+b)/c = (1+1)/(1+1) = 2/2 = 1

a³ + b³ + c³ - 3 a b c = ( a + b + c ) ( a² + b² + c² - bc - ab - ac ) .
(a³ +b³ +c³ -3abc)/(a+b+c)
= 1/2[(a-b) ²+(b-c)² +(c-a)²]
= ½(1+4+9)
= 14/2 = 7

Given the expression: 43*561+500-100/10

And the symbol replacements:

• * becomes +
• / becomes -
• + becomes *
• - becomes /

Substituting the symbols, the expression becomes:

43 + 561 * 500 / 100 - 10

Now, we solve step-by-step:

1. 561 * 500 = 280500
2. 280500 / 100 = 2805

Now the expression is:

43 + 2805 - 10

Continuing with addition and subtraction:

1. 43 + 2805 = 2848
2. 2848 - 10 = 2838

The correct answer is: (d) 2838

(2/3)x = (25/216)(1/x)
X² = (25×3)/(216×2) = 25/144
X = 5/12

{4(1/2)[X+2(1/2)]+3}/[1(1/5)] = 25
(9X/2)+(45/4)+3 = 25×(6/5)
9X/2 =63/4 X=7/2 or 3(1/2)

Divident = Quotient × Divisor +Remainder
Divisor = 6×2 = 12
Q = 12/3 = 4
Divident = 4×12+3 =48+2 = 50

X + Y = 24
Greatest Product then x and y must be equal
Possibility of getting 24 12+12= 24
12×12 = 144

X² – 20X = 96
X²-20X-96 = 0
(X-24)(X+4) = 0
X= 24, -4
positive integer = 24

X ×(X+2) = 6723
X² + 2X = 6723
X²+2X-6723 = 0
(X – 81)(X+83) = 0
Greatest number = 83

2X+X+(2X/3) = 264
(6X+3X+2X)/3 = 264
11X/3 = 264
X= (264×3)/11 = 72

Unit digit= x ; Ten’s digit = (8-x)
[10(8-x)+x] – [10x+(8-x)] = 18
80-10x+x-10x-8+x = 18
-18x = 18-80+8
18x = 54
X = 54/18 = 3
8 – x = 8 – 3 = 5
Hence the number is 35

4x+(4x+4)+(4x+8) = 72
12x+12 = 72
X=(72-12)/12
X=5
Largest number = 4(5)+8 = 20+8 = 28