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RRB JE Test: Ratio and Proportion- 4 Free Online Test 2026


MCQ Practice Test & Solutions: Test: Ratio and Proportion- 4 (20 Questions)

You can prepare effectively for Mechanical Engineering RRB JE Mock Test Series for Mechanical Engineering (ME) 2027 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Ratio and Proportion- 4". These 20 questions have been designed by the experts with the latest curriculum of Mechanical Engineering 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 20

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Test: Ratio and Proportion- 4 - Question 1

Divide Rs.2340 into three parts, such that first part be double that of second part and second part be 1/3 of the third part.Find the Third part amount?

Detailed Solution: Question 1

Answer – B.Rs.1170 Explanation : First: Second: Third = 2:1:3 Third part = 3*2340/6 = 1170

Test: Ratio and Proportion- 4 - Question 2

The ratio of income of A and B is 2:3. The sum of their expenditure is Rs.8000 and the amount of savings of A is equal to the amount of expenditure of B.What is the their ratio of  sum of income to their sum of savings?

Detailed Solution: Question 2

Answer -A.5:3 Explanation : 2I-E + E = 8000
I = 4000
Sum of their Income = 5*I = 5*4000 = 20,000 Sum of their Savings = 20000-8000 = 12,000 20000:12000 = 5:3

Test: Ratio and Proportion- 4 - Question 3

There are 2 containers of equal capacity. The ratio of milk to water in the first container is 4:5 and in the second container is 3:7.If they are mixed up then the ratio of milk to water in the mixture will be

Detailed Solution: Question 3

Answer – D.67:113 Explanation : 4+5 = 9=> 40:50
3+7 = 10=> 27:63
40+27 : 50:63 = 67:113

Test: Ratio and Proportion- 4 - Question 4

There are two numbers. When 25% of the first number is added to the second number, the resultant number is 1.5times th first number.What is the ratio of 1st number to the 2nd number ?

Detailed Solution: Question 4

Answer – C.4:5 Explanation : A+25/100 + B = 1.5A
A/4 + B = 15A/10
10A+40B/40 =60A/40
10A+40B = 60A
50A = 40B
A/B = 4/5

Test: Ratio and Proportion- 4 - Question 5

A bag contains 10p,25p and Rs50p coins in the ratio of 5:2:1 respectively. If the total money in the bag is Rs.120.Find the number of 25p coins in that bag?

Detailed Solution: Question 5

Answer – A.160 Explanation : 10*5 : 25*2 : 50*1 = 50:50:50 = 1:1:1
120/3 = Rs.40 Rs. 1 = 4 Rs.40 = 4*40 = 160 coins

Test: Ratio and Proportion- 4 - Question 6

The ratio of Ganesh’s age and his mother’s age is 5:12.The difference of their ages is 21.The ratio of their ages after 4 years will be

Detailed Solution: Question 6

Answer – D.19:40 Explanation : 12x – 5x = 21 7x = 21 X = 3
5:12 = 15:36
After 4 years = 19:40

Test: Ratio and Proportion- 4 - Question 7

The ratio of students of three classes is 2:3:4. If 15 students are increased in each classes then their ratio turns into 13:18:23. What was the total number of students in all the three classes originally ?

Detailed Solution: Question 7

Answer – C.225 Explanation : 50:75:100
15 students increased 65:90:115  => 13:18 :23
Total no of students = 50+75+100 = 225

Test: Ratio and Proportion- 4 - Question 8

Ravi and Govind have money in the ratio 5 : 12 and Govind and Kiran also have money in the same ratio 5 : 12. If Ravi has Rs. 500, Kiran has

Detailed Solution: Question 8

Answer – B.Rs.2880 Explanation : Ravi : Kiran = 5/12* 5/12 = 25/144 Kiran  = 144*500/25 = 2880

Test: Ratio and Proportion- 4 - Question 9

A town with a population of 1000 has provision for 30days, after 10 days 600 more men added, how long will the food last at the same rate ?

Detailed Solution: Question 9

Answer – C.12 ½ days Explanation : 1000*20/1600 = 12 1/2 days

Test: Ratio and Proportion- 4 - Question 10

A man spends Rs.2480 to buy lunch box Rs.120 each and bottles at Rs.80 each,What will be the ratio of maximum number of bottles to lunch box are bought ?

Detailed Solution: Question 10

Answer – A.13:12 Explanation : Check the ans using option 13*80+ 12*120 = 1040+1440 = 2480

Test: Ratio and Proportion- 4 - Question 11

Three cars travel same distance with speeds in the ratio 2 : 4 : 7. What is the ratio of the times taken by them to cover the distance?

Detailed Solution: Question 11

B) 14 : 7 : 4
Explanation: s = d/t Since distance is same, so ratio of times: 1/2 : 1/4 : 1/7 = 14 : 7 : 4

Test: Ratio and Proportion- 4 - Question 12

Section A and section B of 7th class in a school contains total 285 students.Which of the following can be a ratio of the ratio of the number of boys and number of girls in the class?

Detailed Solution: Question 12

B) 10 : 9
Explanation: The number of boys and girls cannot be in decimal values, so the denominator should completely divide number of students (285).
Check each option: 6+5 = 11, and 11 does not divide 285 completely. 10+9 = 19, and only 19 divides 285 completely among all.

Test: Ratio and Proportion- 4 - Question 13

180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C and D in ratio 3 : 4. What is the number of sweets received by the brothers together?

Detailed Solution: Question 13

B) 84
Explanation: A/B = N1/D1 B/C = N2/D2 C/D = N3/D3
A : B : C : D = N1*N2*N3 : D1*N2*N3 : D1*D2*N3 : D1*D2*D3
A/B = 2/3 B/C = 2/5 C/D = 3/4
A : B : C : D
2*2*3 : 3*2*3 : 3*5*3 : 3*5*4
4 : 6 : 15 : 20
B and C together = [(6+15)/(4+6+15+20)] * 180

Test: Ratio and Proportion- 4 - Question 14

Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys?

Detailed Solution: Question 14

B) 54.8%
Explanation: Total students in both = 6x+11x = 17x Boys in class 4 = (60/100)*6x = 360x/100 Boys in class 5 = (52/100)*11x = 572x/100 So total boys = 360x/100 + 572x/100 = 932x/100 = 9.32x % of boys = [9.32x/17x] * 100

Test: Ratio and Proportion- 4 - Question 15

Consider two alloys A and B. 50 kg of alloy A is mixed with 70 kg of alloy B. A contains brass and copper in the ratio 3 : 2, and B contains them in the ratio 4 : 3 respectively. What is the ratio of copper to brass in the mixture?

Detailed Solution: Question 15

E) 5 : 7
Explanation: Brass in A = 3/5 * 50 = 30 kg, Brass in B = 4/7 * 70 = 40 kg Total brass = 30+40 = 70 kg So copper in mixture is (50+70) – 70 = 50 kg So copper to brass = 50 : 70

Test: Ratio and Proportion- 4 - Question 16

Ratio of A and B is in the ratio 5 : 8. After 6 years, the ratio of ages of A and B will be in the ratio 17 : 26. Find the present age of B.

Detailed Solution: Question 16

A) 72
Explanation: A/B = 5/8 , A+6/B+6 = 17/26
Solve both, B = 72

Test: Ratio and Proportion- 4 - Question 17

A bag contains 25p, 50p and 1Re coins in the ratio of 2 : 4 : 5 respectively. If the total money in the bag is Rs 75, find the number of 50p coins in the bag.

Detailed Solution: Question 17

D) 40
Explanation: 2x, 4x, 5x (25/100)*2x + (50/100)*4x + 1*5x = 75 x = 10, so 50 p coins = 4x = 40

Test: Ratio and Proportion- 4 - Question 18

A is directly proportional to B and also directly proportional to C. When B = 6 and C = 2, A = 24. Find the value of A when B = 8 and C = 3.

Detailed Solution: Question 18

D) 48
Explanation: A directly proportional B, A directly proportional to C: A = kB, A = kC Or A = kBC When B = 6 and C = 2, A = 24: 24 = k*6*2 k = 2 Now when B = 8 and C = 3: A = 2*8*3

Test: Ratio and Proportion- 4 - Question 19

A is directly proportional to B and also inversely proportional to the square of C.When B = 16 and C = 2, A = 36. Find the value of A when B = 32 and C = 4.

Detailed Solution: Question 19

C) 18
Explanation: A = kB, A = k/C2 Or A = kB/ C2
When B = 16 and C = 2, A = 36: 36 = k*16/ 22 k = 9 Now when B = 32 and C = 4: A = 9*32/ 42

Test: Ratio and Proportion- 4 - Question 20

A is directly proportional to the inverse of B and also inversely proportional to C. When B = 36 and C = 9, A = 42. Find the value of A when B = 64 and C = 21.

Detailed Solution: Question 20

A) 24
Explanation: A = k√B, A = k/C Or A = k√B/C When B = 36 and C = 9, A = 42: 42 = k√36/9 k = 63 Now when B = 64 and C = 21: A = 63*√64/21

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