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MCQ Practice Test & Solutions: Chain Rule - MCQ 1 (20 Questions)

You can prepare effectively for Regulatory Body Exams NABARD Grade A & Grade B Preparation with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Chain Rule - MCQ 1". These 20 questions have been designed by the experts with the latest curriculum of Regulatory Body Exams 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 40 minutes
  • - Number of Questions: 20

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Chain Rule - MCQ 1 - Question 1

A contractor undertakes to do a job in 18 days. He employees certain number of men, but 12 of them being absent from the very first day, the rest can complete the work in 30 days. The number of men originally employed?

Detailed Solution: Question 1

Answer – c) 30 Explanation : Let ‘m’ men are originally employed m*18 = (m -12)*30 m = 30

Chain Rule - MCQ 1 - Question 2

 A contractor employed 60 men to do a piece of work in 76 days. After 50 days, he employed 10 more men and the work was finished 2 day earlier. How many days he would have been behind, if he had not employed additional men?

Detailed Solution: Question 2

Answer –b) 2 days Explanation : Total work = 60*50 + 70*24 Now days = D D*60 = 60*50 + 70*24
We get D = 78, so 2 more days

Chain Rule - MCQ 1 - Question 3

 In a dairy farm, 20 horses eat 40 bags of husk in 40 days. In how many days 10 horses will eat 30 bags of husks?

Detailed Solution: Question 3

Answer – b) 60 Explanation : Horse*Days = Bags 20*40 = 40 and 10*D = 30 (20*40)/(10*D) = 40/30
We get D = 60 days

Chain Rule - MCQ 1 - Question 4

28 pipes can empty a tank in 4 days working 8 hours a day. If 84 pipes are used to for 5 hours each day, then the same work will be completed in –

Detailed Solution: Question 4

Answer – d) 2.(2/15) Explanation : 28*4*8 = 84*5*D
D = 2.2/15 days

Chain Rule - MCQ 1 - Question 5

If 10 labourers can dig a well 40 m deep in 18 days, working 9 hours a day, how many additional labourers should be engaged to dig a similar well 80 m deep in 6 days, each labourer working 9 hours a day?

Detailed Solution: Question 5

Answer – c) 50 Explanation : 10*18*9 = 40 ……..(1)
L*9*6 = 40 ……..(2)
Divide both equations We get L = 60, so additional 50 men must be employed

Chain Rule - MCQ 1 - Question 6

If 12 pumps can raise 4800 tonnes of oil in 10 days, working 8 hours a day, in how many days will 16 pumps raise 6000 tonnes of oil, working 12 hours a day?

Detailed Solution: Question 6

Answer – c) 6.25 days Explanation : (12*10*8)/(16*D*12) = 4800/6000
D = 25/4 days = 6.25 days

Chain Rule - MCQ 1 - Question 7

An army camp of 6600 men had provisions for 64 days, when given at the rate of 850 grams per head. At the end of 14 days, a troop arrives and it was found that the provisions will last 34 days more, when given 825 grams per head.What is the strength of new troop?

Detailed Solution: Question 7

Answer – e) 3400 Explanation : 6600*64*850 = 6600*14*850 + M*34*825
we get M = 10000 so new troops = 10000 – 6600 = 3400

Chain Rule - MCQ 1 - Question 8

 In a school there is a meal for 60 girls and 100 boys. If 50 boys have taken their meal, how many girls will be catered with the remaining meal?

Detailed Solution: Question 8

Answer – b) 30 Explananion : 50 boys taken the meal means only 1/2 meal is remaining So, G/60 = 1/2, we get G =30

Chain Rule - MCQ 1 - Question 9

A job that can be completed by 2 men and 6 women in 10 days will be completed by 4 men and 12 women in how many days?

Detailed Solution: Question 9

Answer – d) 5 Explanation : 2m + 6w = 1/10, m + 3w = 1/20 D is the days required We have to find 4m + 12w = 1/d, 4*(m +3w) = 1/d 4*1/20 = 1/d We get d = 5

Chain Rule - MCQ 1 - Question 10

If 10 men can reap 40 hectares of a field in 5 days then how many hectares of field can 30 men reap in 10 days?

Detailed Solution: Question 10

Answer – c) 240 Explanation : 10*5 = 40…….(1)
30*10 = H…….(2)
Divide both equations to get H We get h = 240

Chain Rule - MCQ 1 - Question 11

10 machines can wash 20 cars in 6 hours. In how many hours can 15 machines wash 40 cars?

Detailed Solution: Question 11

A) 8
Explanation: Washing cars is a work, so M1*H1*W2 = M2*H2*W1
10*6*40 = 15*H2*20
Solve, H2 = 8 hrs

Chain Rule - MCQ 1 - Question 12

 To build a house, 5 men take 60 days working 8 hours each day. In how many days 2 such houses can be built by 8 men working 10 hours each day?

Detailed Solution: Question 12

D) 60
Explanation: Building 1 house is 1, 2 houses is 2, so M1*D1*H1*W2 = M2*D2*H2*W1
5*60*8*(2) = 8*D2*10*(1)
Solve, D2 = 60

Chain Rule - MCQ 1 - Question 13

2 men and 4 women can complete a job in 5 days. Also same job can be completed by 3 men and 8 women in 3 days. In how many days, twice the job can be completed by 3 men and 3 women?

Detailed Solution: Question 13

B) 8
Explanation: 2m + 4w = 5D, so 10m + 20w = 1D 3m + 8w = 3D, so 9m + 24w = 1D So, 10m + 20w = 9m + 24w Solve, 1m = 4w From 1st equation(2m + 4w = 5D), 2*4w + 4w = 5D, or 12 women can do in 5 days, so 1 women in 12*5 = 60 days.
Now 3m+3w = 3*4w + 3w = 15 w 1 women in 60 days, so 15 women in 60/15 = 4 days But we are required to find twice work, so 15 women 1 work in 4 days so twice work in 8 days

Chain Rule - MCQ 1 - Question 14

A job that can be completed by 2 men and 6 women in 10 days will be completed by 5 men and 15 women in how many days?

Detailed Solution: Question 14

D) 4
Explanation: 2m + 6w = 10 D Or 2(1m + 3w) = 10D Or 1m + 3w = 20D So 5(1m + 3w) = 20/5 Or 5m + 15w = 4D

Chain Rule - MCQ 1 - Question 15

There is sufficient food for 40 men for a 15 days picnic. If after 6 days 4 men leave, how many more days can the remaining men intake food?

Detailed Solution: Question 15

D) 1
Explanation: After 6 days, now food is left for 40 men for (15-6) = 9 days, now same food is eaten by (40-4) = 36 men, let it last for x days, so 40*9 = 36*x Solve, x = 10 The food which was to last for 9 days for 40 men, now will last for 10 days for 36 men, so extra 1 day.

Chain Rule - MCQ 1 - Question 16

 A job is completed by 5 men or 7 women in 40 days, then in how many days thrice the job as previous will be completed by 5 men and 3 women?

Detailed Solution: Question 16

D) 84
Explanation: 5 m or 7 w 5m + 3w Cross multiply and put in denominator Days = 40*5*7/ [5*3 +7*5] = 28 so for thrice work, days = 28*3

Chain Rule - MCQ 1 - Question 17

10 women completed 2/7th of work in 18 days working 6 hours each day. After this 5 women left and 2 men joined. In how many days working same number of hours, the remaining work will get completed if 1 man is equal to 2 women?

Detailed Solution: Question 17

A) 50
Explanation: Remaining work = 1 – 2/7 = 5/7 After 18 days, 5 women left and 2 men joined so 4 women joined (1m = 2w), now number of women is 5+4 = 9, so 10*18*6*(5/7) = 9*D2*6*(2/7)
Solve, D2 = 50

Chain Rule - MCQ 1 - Question 18

20 carpets are to weave by 40 women in 50 days working 8 hours per day. After 20 days, order of 6 more carpets came. To complete the total work on time, how many more hours per day they will have to work?

Detailed Solution: Question 18

B) 4
Explanation: First find the number of carpets weave in first 20 days, after which order of more carpets came. So, In 50 days, 20 carpets, so in 20 days 20*20/50 = 8 carpets So in remaining 30 days, (20-8) = 12 carpets can be weave working 8 hrs each day Now number of carpets is (12+6) = 18, let no of hours is x, so H1*W2 = H2*W1
8*18 = x*12 Solve, x = 12 hrs So more hrs = 12-8 = 4 hrs

Chain Rule - MCQ 1 - Question 19

 A work is to completed. 10 men started the work and completed 1/6th of the work in 5 days working 3 hrs each day. 2 more men are employed. In how many days will the total number of men complete four times work as before working 5 hours each day?

Detailed Solution: Question 19

C) 10
Explanation: M2 = (10+2) = 12 men, W2 = 4*(1/6) = 4/6 So 10*5*3*(4/6) = 12*D2*5*(1/6)
Solve, D2 = 10

Chain Rule - MCQ 1 - Question 20

2 men or 4 women or 5 children can complete a piece of work in 38 days. In how many days will 1 man, 1 woman and 1 child complete the same work?

Detailed Solution: Question 20

B) 40
Explanation: 2 men or 4 women or 5 children = 38 D So 1m + 1w + 1c = 38*2*4*5/(2*4 + 4*5 + 5*2)

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