Test: Mealy Machine - Computer Science Engineering (CSE) MCQ

The automaton may be allowed to change its state without reading the input symbol using epsilon but this does not mean that epsilon has become an input symbol. On the contrary, one assumes that the symbol epsilon does not belong to any alphabet.

An e-NFA consist of 5 tuples: A=(Q, S, d, q0. F)
Note: e is never a member of S.

e-NFA do come up with a convenient feature but nothing new.They do not extend the class of languages that can be represented.

The epsilon closure of the set q is the set that contains q, together with all the states which can be reached starting at q by following only epsilon transitions.

The epsilon closure set of f2 consist of the elements:{f2, f3}. Thus the count of the element in the closure set is 2.

The given are the steps followed while eliminating epsilon transitions from a NFA or converting an e-NFA to just NFA.

Yes, the language is preserved during the dteps of construction: L(N)=L(N1)=L(N2)=L(3).