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Electric Potential - Free MCQ Practice Test with solutions, GATE EE Electromagnetic


MCQ Practice Test & Solutions: Test: Electric Potential (10 Questions)

You can prepare effectively for Electrical Engineering (EE) Electromagnetic Fields Theory (EMFT) with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Electric Potential". These 10 questions have been designed by the experts with the latest curriculum of Electrical Engineering (EE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Test: Electric Potential - Question 1

Potential difference is the work done in moving a unit positive charge from one point to another in an electric field. State True/False.

Detailed Solution: Question 1

Answer: a
Explanation: The electric potential is the ratio of work done to the charge. Also it is the work done in moving a unit positive charge from infinity to a point in an electric field.

Test: Electric Potential - Question 2

A point charge 2nC is located at origin. What is the potential at (1,0,0)?

Detailed Solution: Question 2

Answer: d
Explanation: V = Q/(4πεr), where r = 1m
V = (2 X 10-9)/(4πε x 1) = 18 volts

Test: Electric Potential - Question 3

Six equal point charges Q = 10nC are located at 2,3,4,5,6,7m. Find the potential at origin.

Detailed Solution: Question 3

Answer: d
Explanation: V = (1/4πεo) ∑Q/r = (10 X 10-9/4πεo)
(0.5 + 0.33 + 0.25 + 0.2 + 0.166 + 0.142) = 143.35 volts.

Test: Electric Potential - Question 4

A point charge 0.4nC is located at (2, 3, 3). Find the potential differences between (2, 1, 3)m and (-2, 3, 3)m due to the charge.

Test: Electric Potential - Question 5

Find the potential of V = 60sin θ/r2 at P(3,60,25)

Detailed Solution: Question 5

Answer: a
Explanation: V = 60sin θ/r2, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/32 = 5.774 volts.

Test: Electric Potential - Question 6

Given E = 40xyi + 20x2j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3).

Detailed Solution: Question 6

Answer: b
Explanation: V = -∫ E.dl = -∫ (40xy dx + 20x2 dy + 2 dz), from (2,1,3) to (1,-1,0), we get Vpq on integrating from Q to P. Vpq = 106 volts.

Test: Electric Potential - Question 7

The potential difference in an open circuit is

Detailed Solution: Question 7

Answer: c
Explanation: In an open circuit no current exists due to non-existence of loops. Also voltage/potential will be infinity in an open circuit.

Test: Electric Potential - Question 8

The potential taken between two points across a resistor will be

Detailed Solution: Question 8

Answer: b
Explanation: The resistor will absorb power and dissipate it in the form of heat energy. The potential between two points across a resistor will be negative.

Test: Electric Potential - Question 9

What is the potential difference between 10sinθcosφ/r2 at A(1,30,20) and B(4,90,60)?

Detailed Solution: Question 9

Answer: c
Explanation: Potential at A, Va = 10sin30cos20/12 = 4.6985 and Potential at B, Vb = 10sin90cos60/42 = 0.3125. Potential difference between A and B is, Vab = 4.6985 – 0.3125 = 4.386 volts.

Test: Electric Potential - Question 10

The voltage at any point in an ac circuit will be

Detailed Solution: Question 10

Answer: b
Explanation: In any ac circuit, the voltage measured will not be exact maximum. In order to normalise, we assume the instantaneous voltage at any point be 70.7% of the peak value, which is called the root mean square (RMS)voltage.

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