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JEE Main & Advanced Physics Test- 8 Free Online Test 2026


MCQ Practice Test & Solutions: JEE Main Physics Test- 8 (25 Questions)

You can prepare effectively for JEE JEE Main & Advanced Mock Test Series 2026 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "JEE Main Physics Test- 8". These 25 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 60 minutes
  • - Number of Questions: 25

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JEE Main Physics Test- 8 - Question 1

Two charges of magnitude +Q and two charges of magnitude -q are placed at the opposite corners of a square of side length ‘a’. If the resultant force on a charge Q is zero than

JEE Main Physics Test- 8 - Question 2

Work done in carrying a charge ‘Q’ from ‘A’ to ‘B’ (as shown in figure) on a circle of radius ‘r’ with a charge ‘Q’ at the centre is 

Detailed Solution: Question 2

A circle around a point charge represents an equipotential surface (V= Kq/r throughout the perimeter), and work done on an equipotential surface is zero.

JEE Main Physics Test- 8 - Question 3

Two spheres having radii of 5 cm and 10 cm bear identical charge of 6.6 nC. Find the potential of spheres after they have been connected by a conductor, assume that the spheres are at large distance from each other

JEE Main Physics Test- 8 - Question 4

An ideal electrical cell does 5 joule of work in carrying 10 coulomb of charge around a closed circuit. The heat loss or energy consumption in the circuit outside the battery is

JEE Main Physics Test- 8 - Question 5

A charged particle of mass 0.1 g is in equilibrium in an electric field E = 98 N/C. The charge on the particle is

JEE Main Physics Test- 8 - Question 6

An electric charge ‘q’ is lying at the open end of a cylindrical vessel. The flux coming out of the cylinder will be

Detailed Solution: Question 6

If you put a another cylinder on it then charge will completely in side and flux will distribute half half so flux =q/2εₒ

JEE Main Physics Test- 8 - Question 7

On moving a charge of 20 coulombs by 2cm, 2J of work is done, then the potential difference between the points is

Detailed Solution: Question 7

Va - Vb =W/q.
W= work done :2Jq= charge : 20C Va - Vb = 2/20 = 0.1

JEE Main Physics Test- 8 - Question 8

The capacitance of a parallel plate condenser does not depend upon 

JEE Main Physics Test- 8 - Question 9

A semi-circular are of radius ‘a’ is charged uniformly and the charge per unit length is . The electric field at its centre is

JEE Main Physics Test- 8 - Question 10

Which of the following cannot be the units of electric intensity?

JEE Main Physics Test- 8 - Question 11

The unit of permittivity of free space ∈0  is

Detailed Solution: Question 11

Answer :- a

Solution :- By coulomb's law the electrostatic force

F = 1/4πε0(q1q2/r2)

⇒ε0 = 1/4πF(q1q2/r2)

Substituting the unit for q, r,and F , we abtain unit of

ε0 = coulomb×coulomb newton−(metre)2

= (coulumb)2 newton −(meter)2

=C2N−m2

JEE Main Physics Test- 8 - Question 12

Ampere hour is a unit of 

JEE Main Physics Test- 8 - Question 13

Six resistors each of value 10, are connected to a 5 V battery as shown in the figure. The reading of ammeter'A' is 

Detailed Solution: Question 13

where ampere is placed it should be 2A as 0.5A in each resistor and 4 resistors ahead so total current will be 4x0.5=2A going through the ammeter. 

JEE Main Physics Test- 8 - Question 14

The potential difference between points ‘A’ and ‘B( -)' in the figure if R=0.7 is

Detailed Solution: Question 14

Ans) Applying Kirchhoff's first law
Va - 6 - 2(3) + 9 - (0.7)(3) =Vb
Vb - Va = 9- 6 - 6 - 2.1
=- 3 - 2.1
= - 5.1

JEE Main Physics Test- 8 - Question 15

If 2% of the main current is to be passed through the galvanometer of resistance G. the resistance of shunt required is

Detailed Solution: Question 15

Let total current through the circuit be I.
Then, 0.02I current is to be passed through galvanometer of resistance G.
Let the resistance of shunt is Rs . 
∵ Shunt are in parallel combination with Galvanometer.
∴ 0.02I * G = (1 - 0.02)I * Rs 
⇒0.02G = 0.98 * Rs 
⇒Rs = 0.02G/0.98 = G/49 

Hence answer is G/49

JEE Main Physics Test- 8 - Question 16

The thermo e.m.f. of a thermocouple is given by e = 2164 t - 6.2 t2 . The neutral temperature and a temperature of inversion are

JEE Main Physics Test- 8 - Question 17

The relation between Faraday constant F, electron charge e, and Avogadro's Number N is

JEE Main Physics Test- 8 - Question 18

In the circuit as shown in Fig. The heat produced by 6 resistance due to current flowing in it is 60 calories per second. The heat generated across 3 ohm resistance per second will be 

JEE Main Physics Test- 8 - Question 19

A thin bar magnet of length 2l and breadth 2b, pole strength p and magnetic moment M is divided into four equal parts with length and breadth of each part being half of the original magnet. Then the pole strength of each part is

JEE Main Physics Test- 8 - Question 20

Susceptibility is positive and small for a ........substance: 

*Answer can only contain numeric values
JEE Main Physics Test- 8 - Question 21

A battery of internal resistance 4 ohm is connected to the network of resistance as shown. In the order that the maximum power can be delivered to the network, the value of R in ohm should be :-


Detailed Solution: Question 21

Condition for maximum power is
r = R

R = 2

*Answer can only contain numeric values
JEE Main Physics Test- 8 - Question 22

A capacitor of capacitance 5 μF is connected as shown in the fig. The internal resistance of the cell is 0.5 Ω. The amount of charge on the capacitor plate is :- (μC) :-


*Answer can only contain numeric values
JEE Main Physics Test- 8 - Question 23

Consider two concentric non-conducting uniformly charged spherical shells of radius 3m and 6m having charges 10 µC and 200 µC respectively. Find the interaction potential energy between two spheres in joules.


Detailed Solution: Question 23

*Answer can only contain numeric values
JEE Main Physics Test- 8 - Question 24

Diagram shows a part of circuit. Find VB–VA when current I is 5A and it is decreasing at a rate of 10+3 A/s ?


Detailed Solution: Question 24

*Answer can only contain numeric values
JEE Main Physics Test- 8 - Question 25

A current of 4 A flows in a coil when connected to a 12 V d.c. source. If the same coil is connected to a 12 V, 50 rad/s, a.c. source, a current of 2.4 A flows in the circuit. Determine the reactance (in Ω) of coil.


Detailed Solution: Question 25

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