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JEE Main Chemistry Test- 8 - JEE MCQ


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25 Questions MCQ Test - JEE Main Chemistry Test- 8

JEE Main Chemistry Test- 8 for JEE 2024 is part of JEE preparation. The JEE Main Chemistry Test- 8 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Chemistry Test- 8 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Chemistry Test- 8 below.
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JEE Main Chemistry Test- 8 - Question 1

The molal depression constant for water is 1.86. The depression constant for 100g is

Detailed Solution for JEE Main Chemistry Test- 8 - Question 1
JEE Main Chemistry Test- 8 - Question 2

Urea is added to 2 litre of water to such an extent that becomes equal to 1/100. The weight of urea added is

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JEE Main Chemistry Test- 8 - Question 3

The moleucular weight of NaCl (degree of dissociation=x) determined by the osmotic pressure method, is found to be different from its actual molecular wieght (M).Which of the following relationship is correct ?

JEE Main Chemistry Test- 8 - Question 4
The osmotic pressure of glucose solution (400mm),on dilution, decreased to 100 mm. The extent of dilution is
JEE Main Chemistry Test- 8 - Question 5
At what temperature does an aqueous solution containing molecules of a noneelectrolyte substance in 250g of water freeze ?
JEE Main Chemistry Test- 8 - Question 6
The vapour pressure of a solvent decreased by 10mmHg when a nonvolatile solute was added to the solvent. The mole fraction of the solute in the solution
is 0.2. What would be the mole fraction of the solvent if the decrease in the vapour pressure is to be 20 mmHg
Detailed Solution for JEE Main Chemistry Test- 8 - Question 6
The equation governing the change in the vapor pressure when you use a nonvolatile liquid or solid is just a special case of Raoult's Law, Ptot = PaXa + PbXb. Since the second component has a negligible vapor pressure (nonvolatile), Raoult's law reduces to

P = P0X
where P is the vapor pressure of the mixture, P0 is the vapor pressure of the pure solvent and X is the mole fraction of the solvent.
Mole fraction of solute = 0.2
so mole fraction of solvent = 0.8 
So
P-10 = 0.8(P)
So P= 10/0.2 = 50
 
In second case
50-20 = x.50
30/50= x
So mole fraction of solvent = 0.6
JEE Main Chemistry Test- 8 - Question 7

Ethyl chloride is converted into diethyl ether by

JEE Main Chemistry Test- 8 - Question 8

A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is

Detailed Solution for JEE Main Chemistry Test- 8 - Question 8
For an FCC cubic lattice:
r=a√2/4
where,
r is the radius of atom
a is the edge length of unit cell   
r=408x1.414/4 
=144.228 pm
Therefore, diameter of metal atom = 2 x 144.228 pm = 288.456 pm
JEE Main Chemistry Test- 8 - Question 9
Alkene R–CH–CH = reacts with in the presence of  to give
JEE Main Chemistry Test- 8 - Question 10
The order of reactivity of the following alcohols towards conc. HCl is
i.                     ii.

 iii.                     iv.
JEE Main Chemistry Test- 8 - Question 11
Alcohol can be obtained by all methods except
Detailed Solution for JEE Main Chemistry Test- 8 - Question 11
Bcz water
 or alcohols would protonate and thus 
destroy the Grignard reagent
, because the 
Grignard
 carbon is highly nucleophilic.

JEE Main Chemistry Test- 8 - Question 12
Increasing order of acid strength among tertiary butanol,isopropanol and ehanol is
JEE Main Chemistry Test- 8 - Question 13
Chlorobenzene on fusing with solid NaOH gives
JEE Main Chemistry Test- 8 - Question 14
For the reaction the order of reactivity is
JEE Main Chemistry Test- 8 - Question 15
Benzyl alcohol on reaction with gives
JEE Main Chemistry Test- 8 - Question 16

In the reaction   the product (A) has the structure

JEE Main Chemistry Test- 8 - Question 17
Propene is allowed to react with HI. The product (A) is then treated with
to give a new product (B)

The final product (B) is
JEE Main Chemistry Test- 8 - Question 18
The reaction
  is an example of
JEE Main Chemistry Test- 8 - Question 19
The utility of the polymers in various fields is due to their mechanical properties like tensile strength,elasticity, toughness etc.These properties mainly depend upon intermolecular forces like van der Waal’s forces and hydrogen bonding operating in polymer molecules. Polymers have been classified on this
basis,e.g.(1) Elastomers (2) Thermoplacstics (4) Thermosetting. Hence
The molecular forces of attraction are weakest in
JEE Main Chemistry Test- 8 - Question 20
The utility of the polymers in various fields is due to their mechanical properties like tensile strength,elasticity, toughness etc.These properties mainly depend upon intermolecular forces like van der Waal’s forces and hydrogen bonding operating in polymer molecules. Polymers have been classified on this
basis,e.g.(1) Elastomers (2) Thermoplacstics (4)Thermosetting. Hence
Which of the following have usually a linear structure
*Answer can only contain numeric values
JEE Main Chemistry Test- 8 - Question 21

Given length of side of HCP is 100/√2 pm. The volume  of HCP unit cell is (in pm3) x × 10then x will be–


Detailed Solution for JEE Main Chemistry Test- 8 - Question 21

*Answer can only contain numeric values
JEE Main Chemistry Test- 8 - Question 22

The radius of A+ in ionic compound AB is .225Å If AB has ZnS structure, the ideal radius of B will be (in PM)


Detailed Solution for JEE Main Chemistry Test- 8 - Question 22

*Answer can only contain numeric values
JEE Main Chemistry Test- 8 - Question 23

K[Co(CO)4], K­3[Co(CN)6] Find the difference between oxidation number of central metal in the given complexes.


*Answer can only contain numeric values
JEE Main Chemistry Test- 8 - Question 24

Total no. of unpaired electrons in [Fe(H2O)6]2+ are?


*Answer can only contain numeric values
JEE Main Chemistry Test- 8 - Question 25

Number of chiral carbon atoms in the given compounds are W, X, Y and Z respectively then Calculate the I, II, III & IV value of W + X + Y– Z.


Detailed Solution for JEE Main Chemistry Test- 8 - Question 25


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