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Physics Class 12 Mini Mock - 1 - Free MCQ Practice Test with solutions,


Full Mock Test & Solutions: Test: Physics Class 12 Mini Mock - 1 (45 Questions)

You can boost your NEET 2026 exam preparation with this Test: Physics Class 12 Mini Mock - 1 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of NEET 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 45 minutes
  • - Total Questions: 45
  • - Analysis: Detailed Solutions & Performance Insights

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Test: Physics Class 12 Mini Mock - 1 - Question 1

In Concave Mirror

Detailed Solution: Question 1

In a concave mirror, the reflecting surface is the inner surface of a hollow sphere, that is, the surface facing towards the centre of the sphere. When a hollow sphere is cut and its outer surface painted, the inner surface acts as the reflecting surface, forming a concave mirror. This type of mirror is also known as a converging mirror because it reflects light to converge at a point.

Therefore, the correct option is Reflecting surface is towards the centre of the sphere of which it can be considered as a cut off portion, which is option a.

Test: Physics Class 12 Mini Mock - 1 - Question 2

The control rods in a nuclear reactor

Detailed Solution: Question 2

Control rods are used in nuclear reactors to control the fission rate of uranium and plutonium. They are composed of chemical elements such as boron, silver, indium and cadmium that are capable of absorbing many neutrons without themselves fissioning.

Test: Physics Class 12 Mini Mock - 1 - Question 3

The Gaussian surface for a point charge will be

Detailed Solution: Question 3

A point charge is single dimensional. The three dimensional imaginary enclosed surface of a point charge will be sphere.

Test: Physics Class 12 Mini Mock - 1 - Question 4

Optical analogue of an equipotential surface is

Detailed Solution: Question 4

Definition based

Test: Physics Class 12 Mini Mock - 1 - Question 5

A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad s-1 in a uniform horizontal magnetic field of magnitude 3×10-2 T. If the coil resistance is 10Ω, maximum emf induced in the coil,maximum value of current in the coil and average power loss due to Joule heating are

Detailed Solution: Question 5

e = NBAω = 20 x 3 x 10-2 x (3.14 x 0.08 x 0.08) x 50 = 0.603C

average power loss due to joule heating

Test: Physics Class 12 Mini Mock - 1 - Question 6

The average lifetime of the first excited level of a hydrogen atom is 1.0 ×10−8 s. In the Bohr model, how many orbits does an electron in the n = 2 level complete before returning to the ground level?

Detailed Solution: Question 6

Test: Physics Class 12 Mini Mock - 1 - Question 7

In electrolysis, the amount of mass deposited orliberated at an electrode is directly proportionalto [2000]

Detailed Solution: Question 7

By Faraday's Ist Law
Amount deposited (m) = Zit = Zq
m ∝ q
Amount deposited is directly proportional
to charge.

Test: Physics Class 12 Mini Mock - 1 - Question 8

Negative mutual potential energy corresponds to attraction between two charges

Detailed Solution: Question 8

Definition based

Test: Physics Class 12 Mini Mock - 1 - Question 9

A particle having a mass of 10–2 kg carries a charge of 5 × 10–C. The particle is given an initial horozontal velocity of 105 ms–1 in the presence of electric field   and magnetic field  . To  keep the particle moving in a horizontal direction, it is necessary that

(1)  should be perpendicular to the direction of velocity and should be along the direction of velocity.

(2) Both   and  should be along the direction of velocity.

(3) Both   and  are mutually perpendicular and perpendicular to the direction of velocity.

(4)  should be along the direction of velocity and should be perpendicular to the direction of velocity

Which one of the following pairs of statements is possible?

Detailed Solution: Question 9

Case 1:- In figure 1 if FE​=FB​ ⇒ particle will always move in a straight line.(option (iii))
Case 2:- In figure 2 particle will always move in a straight line.(option (ii))

Test: Physics Class 12 Mini Mock - 1 - Question 10

A car battery has ________ resistance than a dry cell.

Detailed Solution: Question 10

a car battery of 12V provides a current of about 200A, which is the current needed to operate a starter motor. So a battery has a very small internal resistance.
also,The cause of non-correctable battery problems and.A weak cell holds less capacity and is discharged more quickly.

Test: Physics Class 12 Mini Mock - 1 - Question 11

What is the binding energy of the hydrogen nucleus?​

Detailed Solution: Question 11

Nucleus of hydrogen has only one proton. Hence its binding energy will be zero. The nuclear binding energy is the energy it takes to separate all the nucleons in a nucleus from each other. Since there is only the one nucleon, it's already separated from any other nucleons.

Test: Physics Class 12 Mini Mock - 1 - Question 12

Damping in galvanometers is based on

Detailed Solution: Question 12

The coil of a galvanometer is wound on a light metallic frame (such as aluminium). When the coil rotates in the magnetic field of the permanent magnet, eddy currents are induced in the metallic frame. These eddy currents create magnetic fields that oppose the motion of the coil (according to Lenz's Law), thus providing electromagnetic damping. This damping helps the coil to return to zero quickly and prevents oscillations.

Test: Physics Class 12 Mini Mock - 1 - Question 13

According to ‘plum pudding model’ atoms on the whole are electrically neutral because

Detailed Solution: Question 13

The plum pudding model is one of several scientific models of the atom. According to J.J. Thomson atomic models the positive particles in the atom form something like the "batter" in a plum pudding, while the negative electrons are scattered through this "batter".

Test: Physics Class 12 Mini Mock - 1 - Question 14

What happens to the magnifying power of microscope, when its length increases?​

Detailed Solution: Question 14

Magnification in microscope is  m=− lD/f0​​fe
where, l is length of tube and D is least distance for clear vision
f0​ is focal length of objective
fe​ is the focal length of the eyepiece.
So, as l increases m increases.
Hence, the magnifying power of a microscope increases with increase in tube length.
 

Test: Physics Class 12 Mini Mock - 1 - Question 15

The alpha particle scattering experiment was carried out by:

Detailed Solution: Question 15

Rutherford Alpha Particle Scattering Experiment.Rutherford directed beams of alpha particles (which are the nuclei of helium atoms and hence positively charged) at thin gold foil to test this model and noted how the alpha particles scattered from the foil.

Test: Physics Class 12 Mini Mock - 1 - Question 16

A hollow metal sphere of radius 10 cm is chargedsuch that the potential on its surface is 80 V. Thepotential at the centre of the sphere is [1994]

Detailed Solution: Question 16

Potential at the centre of the sphere
= potential on the surface = 80 V.

Test: Physics Class 12 Mini Mock - 1 - Question 17

1  ampere current is equivalent to

Detailed Solution: Question 17

Q = It also Q = ne [e = 1.6 × 10−19C]
∴ ne = It or
= 6.25 × 1018 electrons s−1

Test: Physics Class 12 Mini Mock - 1 - Question 18

If the electron in H atom jumps from the third orbit to second orbit, the wavelength of the emitted radiation is given by

Detailed Solution: Question 18

We know that
1/λ​=R(1/n21​−1/n22​​)
1/λ=R(1/22) − (1/32​)⇒R(1/4)−(1/9​)
1/λ​=(9−4​/36)R=5R​/36⇒λ=36​/5R

Test: Physics Class 12 Mini Mock - 1 - Question 19

An unpolarised beam of intensity Io is incident on a polarizer and analyser placed in contact. The angle between the transmission axes of the polarizer and the analyser is θ. What is the intensity of light emerging out of the analyser?​

Detailed Solution: Question 19

 Suppose the angle between the transmission axes of the analyser and the polarizer is θ. The completely plane polarized light form the polarizer is incident on the analyser. If E0 is the amplitude of the electric vector transmitted by the polarizer, then intensity I0 of the light incident on the analyser is
I ∞ E02
 
The electric field vector E0 can be resolved into two rectangular components i.e E0 cosθ and E0 sinθ. The analyzer will transmit only the component ( i.e E0 cosθ ) which is parallel to its transmission axis. However, the component E0sinθ will be absorbed by the analyser. Therefore, the intensity I of light transmitted by the analyzer is,
 
I ∞ ( E0 x cosθ )2
 
I / I0 = ( E0 x cosθ )2 / E02 = cos2θ
 
I = I0 x cos2θ
when light passes from polarizer it's intensity becomes half and when passed through analyser it becomes,
I = I0 x cos2θ/2
 

Test: Physics Class 12 Mini Mock - 1 - Question 20

The ground state energy of H-atom 13.6 eV. Theenergy needed to ionize H-atom from its secondexcited state. [1991]

Detailed Solution: Question 20

Second excited state corresponds to n = 3

Test: Physics Class 12 Mini Mock - 1 - Question 21

Electric field lines provide information about

Detailed Solution: Question 21

Electric field lines are essential for understanding various aspects of electric fields. They illustrate:

  • Field strength: The density of lines indicates how strong the electric field is; closer lines mean a stronger field.
  • Direction: The arrows on the lines show the direction a positive charge would move within the field.
  • Nature of charge: Lines emanate from positive charges and terminate at negative charges, visually representing their nature.

These characteristics together provide a comprehensive view of the electric field's behaviour and effects.

Test: Physics Class 12 Mini Mock - 1 - Question 22

In the phenomenon of electric discharge throughgases at low pressure, the coloured glow in thetube appears as a result of: [2008]

Detailed Solution: Question 22

Collisions between charged particles emitted from cathode and atoms of gas.The discharge of electricity through liquefied gases is an interesting phenomenon which can be systematically studied with the help of a discharge tube.In discharge tube collision between charged particles emitted from cathode and atoms of the gas results to colorless glow in tube.

Test: Physics Class 12 Mini Mock - 1 - Question 23

A convex lens of focal length 0.15 m is made of a material of refractive index 3/2. When it is placed in a liquid, its focal length is increased by 0.225 m. The refractive index of the liquid is

Detailed Solution: Question 23

f= 0.15 m,μ= 3/2,fe = 0.225+0.15
From lens formula,

Test: Physics Class 12 Mini Mock - 1 - Question 24

Sodium has body-centered packing. The distance between the two nearest atoms is 3.7 Å. The lattice parameter is:
[2009]

Detailed Solution: Question 24

Test: Physics Class 12 Mini Mock - 1 - Question 25

An electric dipole is placed as shown in the figure. 

The electric potential (in 102 V) at point P due to the dipole is (ϵ0 = permittivity of free space and  :

Detailed Solution: Question 25

Test: Physics Class 12 Mini Mock - 1 - Question 26

When ultraviolet radiation is incident on asurface, no photoelectrons are emitted. If asecond beam causes photoelectrons to beejected, it may consists of    [2002]

Detailed Solution: Question 26

Energy of photon of X-rays is more than
energy of photon of ultraviolet rays. Because
frequency of X rays is more than ultraviolet
rays.

Test: Physics Class 12 Mini Mock - 1 - Question 27

The speed of electromagnetic waves in free space is given by  .
Here μ0 is ___________and ε0 is ________________ of free space.

Detailed Solution: Question 27

The speed of electromagnetic waves in free space depends on two important properties: permeability and permittivity. In this context:

  • μ0 represents the permeability of free space, which indicates how well magnetic fields can pass through a vacuum.
  • ε0 signifies the permittivity of free space, reflecting how electric fields interact with the vacuum.

These properties are fundamental to understanding how electromagnetic waves propagate in free space.

Test: Physics Class 12 Mini Mock - 1 - Question 28

The minimum velocity v with which charge q should be projected so that it manages to reach the centre of the ring starting from the position shown in figure is

Detailed Solution: Question 28

Test: Physics Class 12 Mini Mock - 1 - Question 29

In the adjoining figure, SS is a spherical surface separating two media of refractive indices n1 and n2 where n1 > n2. C is the centre of curvature of the spherical surface. An observer, keeping his eye beyond C in the medium of refractive index n2 views the refracted image of an object AB placed as shown in the medium of refractive index n1. The image will be:

Detailed Solution: Question 29


The image will be virtual, upright and diminished.

Test: Physics Class 12 Mini Mock - 1 - Question 30

Whenever the magnetic flux () linked with a coil changes the emf is induced in the circuit, This emf lasts

Detailed Solution: Question 30

A current-carrying wire produces a magnetic field, as described by Biot-Savart’s law. The reverse effect, where a magnetic field generates an electric current, was discovered by Michael Faraday and is known as Faraday's Law of Electromagnetic Induction.

Faraday demonstrated this through an experiment: when a bar magnet is moved relative to a conducting loop connected to an ammeter (without any external emf source), a current is induced. Key observations include:

  1. Current appears only when there is relative motion between the magnet and the loop.
  2. Faster motion produces a stronger current.
  3. The direction of current depends on the magnet’s motion (towards or away) and its pole orientation.

This induced current is caused by a change in magnetic flux, which is the number of magnetic field lines passing through the loop. The induced emf persists as long as the magnetic flux changes. The emf always opposes the change in flux, as per Lenz’s Law.

In conclusion, the process of producing induced current and emf is called electromagnetic induction. The correct answer is Option A.

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