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Physics Class 12 Mini Mock - 3 - Free MCQ Practice Test with solutions,


Full Mock Test & Solutions: Test: Physics Class 12 Mini Mock - 3 (45 Questions)

You can boost your NEET 2026 exam preparation with this Test: Physics Class 12 Mini Mock - 3 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of NEET 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 45 minutes
  • - Total Questions: 45
  • - Analysis: Detailed Solutions & Performance Insights

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Test: Physics Class 12 Mini Mock - 3 - Question 1

The constant μo is called​

Detailed Solution: Question 1

The permeability of free space, μ0, is numerically equal to 4π x 10-7. For air and other non-magnetic materials, the absolute permeability is the same constant. For magnetic materials, absolute permeability is not a fixed constant but varies non-linearly with the flux density.

Test: Physics Class 12 Mini Mock - 3 - Question 2

Oscillating circuits produce

Detailed Solution: Question 2

An oscillator is a circuit which produces a continuous, repeated, alternating waveform without any input. Oscillators basically convert unidirectional current flow from a DC source into an alternating waveform which is of the desired frequency, as decided by its circuit components.

Test: Physics Class 12 Mini Mock - 3 - Question 3

The work function of a metallic surface is 5.01 eV. The photo-electrons are emitted when light of wavelength 2000 Å falls on it. The potential difference applied to stop the fastest photo-electrons is [ h = 4.14 x 10-15 eV sec]

Detailed Solution: Question 3

Energy of incident light E = 12375/2000 = 6.18 eV
According to relation E = W0 + eV

Test: Physics Class 12 Mini Mock - 3 - Question 4

Diffraction pattern cannot be observed with:

Detailed Solution: Question 4

For diffraction, the width of the slit must be less than the wavelength of the incident ray.

Test: Physics Class 12 Mini Mock - 3 - Question 5

Point charges + 4q, –q and +4q are kept on theX-axis at points x = 0, x =a and x = 2a respectively.

Detailed Solution: Question 5

Net force on each of the charge due to the other charges is zero. However, disturbance in any direction other than along the line on which the charges lie, will not make the charges return.

Test: Physics Class 12 Mini Mock - 3 - Question 6

A constant current I is maintained in a solenoid. Which of the following quantities will not increase if an iron rod is inserted in the solenoid along its axis?

Detailed Solution: Question 6

When an iron rod is inserted inside a solenoid the magnetic field inside the solenoid increases due to the high magnetic permeability of iron. Due to the increased magnetic field, the magnetic flux also increases. The self-inductance of the solenoid also increases because self-inductance (L) of the coil is directly proportional to the permeability of the material inside the solenoid. The rate of joule heating doesn’t change.

Test: Physics Class 12 Mini Mock - 3 - Question 7

The magnetic induction left behind in the sample after the magnetizing field has been removed is called

Detailed Solution: Question 7

Remanence or remanent magnetization or residual magnetism is the magnetization left behind in a ferromagnetic material (such as iron) after an external magnetic field is removed. It is also the measure of that magnetization. Colloquially, when a magnet is "magnetized" it has remanence.The remanence of magnetic materials provides the magnetic memory in magnetic storage devices, and is used as a source of information on the past Earth's magnetic field in paleomagnetism.The equivalent term residual magnetization is generally used in engineering applications. In transformers, electric motors and generators a large residual magnetization is not desirable (see also electrical steel) as it is an unwanted contamination, for example a magnetization remaining in an electromagnet after the current in the coil is turned off. Where it is unwanted, it can be removed by degaussing.Sometimes the term retentivity is used for remanence measured in units of magnetic flux density.

Test: Physics Class 12 Mini Mock - 3 - Question 8

Two α-partides have the ratio of their velocities as 3 : 2 on entering the field. If they move in different circular paths, then the ratio of the radii of their paths is

Detailed Solution: Question 8

As qvB = mv2/r

Test: Physics Class 12 Mini Mock - 3 - Question 9

If the number of turns per unit length of a coil ofsolenoid is doubled, the self-inductance of thesolenoid will [1991]

Detailed Solution: Question 9

Self inductance of a solenoid = 

So, self induction ∝ n2
So, inductance becomes 4 times when n is doubled.

Test: Physics Class 12 Mini Mock - 3 - Question 10

If a long straight wire carries a current of 40 A, then the magnitude ol the field B at a point 15 cm away from the wire is 

Detailed Solution: Question 10

I = 40A
r = 15 cm = 15 x 10-2 m
∴  = 5.34 x 10-5 T

Test: Physics Class 12 Mini Mock - 3 - Question 11

1 microfarad is equal to​:

Detailed Solution: Question 11

The microfarad (symbolized µF) is a unit of capacitance, equivalent to 0.000001 (10 to the -6th power) farad. 

Test: Physics Class 12 Mini Mock - 3 - Question 12

Electric field is steepest in the direction in which the potential

Detailed Solution: Question 12

In the direction of electric field the electric potential decreases. This is because electric potential is the work done against the direction of the electric field.

Test: Physics Class 12 Mini Mock - 3 - Question 13

An electric dipole, consisting of two opposite charges of 2 × 10-6 C each separated by a distance 3 cm is placed in an electric field of 2 × 105 N/C. Torque acting on the dipole is    [1995]

Detailed Solution: Question 13

Charges (q) = 2 × 10-6 C,

Distance (d) = 3 cm = 3 × 10-2 m

and electric field (E) = 2 × 105 N/C. Torque (t) = q.d.

E = (2 × 10-6) × (3 × 10-2) × (2 × 105)

= 12 × 10-3N-m.

Test: Physics Class 12 Mini Mock - 3 - Question 14

A convergent lens made of crown glass (refractive index 1.5) has focal length 20cm in air. If it is immersed in a liquid of refractive index 1.60, its focal length will be:​

Detailed Solution: Question 14

When the lens is in air, we have (from lens maker's equation), 1/20 = [(1.5/1) - 1) (1/R1- 1/R2). 
We are not bothered about the signs of R1 and R2 since they are unknown quantities. 
Even though we know that the convergent lens will become divergent in the denser medium, we write the lens maker's equation without bothering about the sign of its unknown focal length in the liquid. If if is the focal length in the liquid, we can write, 
1/f = ((1.5/1.6) - 1) (1/R1 - 1/R2). 
Dividing the first equation by the second, we obtain f/20 = 0.5x1.6/(-0.1) from which f = -160 cm

Test: Physics Class 12 Mini Mock - 3 - Question 15

Dipole moment depends on _______

Detailed Solution: Question 15

Dipole is defined as two equal but opposite charges, kept at a small distance and having a dipole moment. The dipole moment is simply the product of the electric charge and length of the dipole. The dielectric constant of the medium doesn’t affect the dipole moment i.e. dipole moment of an electric dipole will be the same in water as well as in the air.

Test: Physics Class 12 Mini Mock - 3 - Question 16

What percentage of the mass of an atom is concentrated in the nucleus?

Detailed Solution: Question 16

More than 99.99% of the mass of any atom is concentrated in its nucleus. If the mass of protons and neutrons (which are in the nucleus of every atom) is approximately one atomic mass unit, then the relative mass of an electron is 0.0005 atomic mass units.

Test: Physics Class 12 Mini Mock - 3 - Question 17

Wavelength of visible Spectrum ranges from

Detailed Solution: Question 17

The visible light spectrum is the segment of the electromagnetic spectrum that the human eye can view. More simply, this range of wavelengths is called visible light. Typically, the human eye can detect wavelengths from 380 to 700 
All electromagnetic radiation is light, but we can only see a small portion of this radiation—the portion we call visible light. Cone-shaped cells in our eyes act as receivers tuned to the wavelengths in this narrow band of the spectrum. Other portions of the spectrum have wavelengths too large or too small and energetic for the biological limitations of our perception.
As the full spectrum of visible light travels through a prism, the wavelengths separate into the colors of the rainbow because each color is a different wavelength. Violet has the shortest wavelength, at around 380 nanometers, and red has the longest wavelength, at around 700 nanometers.
 

Test: Physics Class 12 Mini Mock - 3 - Question 18

A particle of mass 1 mg has the same wavelengthas an electron moving with a velocity of 3×10ms–1. The velocity of the particle is:    [2008]
(mass of electron = 9.1×10–31 kg)

Detailed Solution: Question 18

Wavelength of

where v is the velocity of the particle.
Wave length of electron

Test: Physics Class 12 Mini Mock - 3 - Question 19

γ (Gamma) rays are​

Detailed Solution: Question 19

A gamma ray, or gamma radiation, is a penetrating form of electromagnetic radiation arising from the radioactive decay of atomic nuclei. It consists of the shortest wavelength electromagnetic waves and so imparts the highest photon energy.

Test: Physics Class 12 Mini Mock - 3 - Question 20

Which of the following laws give the direction of induced e.m.f

Detailed Solution: Question 20

Lenz’s law is used for determining the direction of induced current.

Lenz’s law of electromagnetic induction states that the direction of induced current in a given magnetic field is such that it opposes the induced change by changing the magnetic field.

Following is the formula of Lenz’s law:

ϵ=−N (∂ϕB/∂t)

Where,

  • ε is the induced emf

  • ∂ΦB is the change in magnetic flux

  • N is the number of turns in the coil

Lenz’s law finds application in electromagnetic braking and in electric generators

Test: Physics Class 12 Mini Mock - 3 - Question 21

Which of the following will not increase the size and effect of eddy current?

Detailed Solution: Question 21

  • Stronger magnetic field, thicker material and low resistivity material will increase the size and effect of eddy current whereas thinner material will reduce the effect of eddy currents.

Test: Physics Class 12 Mini Mock - 3 - Question 22

The quantization of charge has little practical consequence and can be ignored at the

Detailed Solution: Question 22

Gain or loss of charge in terms of few electrons each carrying very small charge is unobservable at macroscopic level.

Test: Physics Class 12 Mini Mock - 3 - Question 23

As a result of change in the magnetic flux linkedto the closed loop shown in the Fig,

an e.m.f. V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once  along the loop is

[2005]

Detailed Solution: Question 23

Test: Physics Class 12 Mini Mock - 3 - Question 24

Which of the following figure represents the electric field lines due to a single positive charge?

Detailed Solution: Question 24

The field lines of a single positive charge are radially outward.

Test: Physics Class 12 Mini Mock - 3 - Question 25

A photodiode is used preferably in

Detailed Solution: Question 25

Photo diode is used to detect light. 
In a reverse biased condition, the width of the depletion region increases as the applied reverse bias voltage increases across the diode. So, by applying a larger voltage, more of the incident photons are converted to electric current thereby increasing the efficiency.
In forward biased conditions, the width of the depletion region decreases so only a small portion of the incident photons get converted to electric current and hence the efficiency is less.
Hence photo diode in reverse biased condition detects light.

Test: Physics Class 12 Mini Mock - 3 - Question 26

A watch shows the time as 3 : 25. What will be the time that appears when seen through a plane mirror ?

Detailed Solution: Question 26

The relation between actual time and given time is:
Actual time=11:60 −given time
Actual time=11:60−3:25=8:35

Test: Physics Class 12 Mini Mock - 3 - Question 27

The polarized dielectric is equivalent to ________

Detailed Solution: Question 27

A polarized dielectric is equivalent to two charged surfaces with induced charges (polarization charges). 

Test: Physics Class 12 Mini Mock - 3 - Question 28

Two thin lenses of focal lengths f1 and f2 are in contact and coaxial. The power of the combination is: [2008]

Detailed Solution: Question 28

The focal length of the combination

∴ Power of the combinations

Test: Physics Class 12 Mini Mock - 3 - Question 29

In a p-n junction, as the diffusion process continues the width of the depletion zone

Detailed Solution: Question 29

In reverse biasing, the positive terminal of the battery is connected to the n-type whereas the negative terminal is connected to the p-type junction. So the positive terminal tends to pull the electrons (near to the depletion layer) in n-type towards itself whereas the negative terminal pulls the holes towards itself which results in an increase in the width of the depletion layer.

Test: Physics Class 12 Mini Mock - 3 - Question 30

In a region of uniform magnetic inductionB = 10–2 tesla, a circular coil of radius 30 cm andresistance π2 ohm is rotated about an axis whichis perpendicular to the direction of B and whichforms a diameter of the coil. If the coil rotates at 200 rpm the amplitude of the alternating currentinduced in the coil is [1988]

Detailed Solution: Question 30

Given, n = 1, B = 10–2 T,
A = π(0.3)2m2, R = π2
f= (200/60) and ω = 2π(200/60)
Substituting these values and solving, we
get
I0 = 6 × 10–3 A = 6mA

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