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WBJEE Mathematics Sample Paper I - JEE MCQ


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30 Questions MCQ Test - WBJEE Mathematics Sample Paper I

WBJEE Mathematics Sample Paper I for JEE 2024 is part of JEE preparation. The WBJEE Mathematics Sample Paper I questions and answers have been prepared according to the JEE exam syllabus.The WBJEE Mathematics Sample Paper I MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for WBJEE Mathematics Sample Paper I below.
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WBJEE Mathematics Sample Paper I - Question 1

The equations of the line parallel to X-axis and at a distance of c/2 from the X-axis is:

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 1

The equation of straight line is parallel to x-axis which means slope is 0
equation of straight line , y = mx + c
here, m = 0 , y = c
As it is given c = c/2
y = +-c/2

WBJEE Mathematics Sample Paper I - Question 2

The line which makes intercepts 3 and 4 on the x and the y axis respectively, has equation

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 2
Intercept form is
x/a +y/b =1
in this question
x/3 +y/4=1
by solving this equation, we get
4x + 3y =12
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WBJEE Mathematics Sample Paper I - Question 3

The length of the transverse axis of a hyperbola is 7 and it passes through the point (5, –2). The equation of the hyperbola is

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WBJEE Mathematics Sample Paper I - Question 4

If the eccentricity of the hyperbola x– y2 sec2 a = 5 is (√3) times the eccentricity of the ellipse x2 sec2 a + y2 = 25, then a value e of a is

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 4


WBJEE Mathematics Sample Paper I - Question 5

AB is a double ordinate of the hyperbola  such that DAOB (where `O' is the origin) is an equilateral triangle, then the eccentricity e of the hyperbola satisfies

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WBJEE Mathematics Sample Paper I - Question 6

The locus of the point of intersection of tangents drawn at the extremities of normal chords to hyperbola xy = c2

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 6

Polar is xy1 + x1y = 2c2.. (1)
Let  normal chord at (h,k) be
hx - ky = h2 - k2...... (2)
From 1 and
And hk = c2 eliminate h, k and λ

WBJEE Mathematics Sample Paper I - Question 7

The asymptotes of the hyperbola hx + ky = xy are

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 7

hx + ky - xy = 0
let asymptotes be hx + ky - xy + c = 0 ; This represents a pair of straight lines if Δ =  0
i.e. c =-hk ∴ asymptotes are xh+yk-xy-hk =0 ⇒ (x - k) (y - h) = 0

WBJEE Mathematics Sample Paper I - Question 8

The …… of a conic is the chord passing through the focus and perpendicular to the axis.

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The chord of a parabola through the focus and perpendicular to the axis is called the latus rectum.

WBJEE Mathematics Sample Paper I - Question 9

If the line x + y – 1 = 0 touches the parabola y2 = kx , then the value of k is

WBJEE Mathematics Sample Paper I - Question 10

Directrix of a parabola is x + y = 2. If it's focus is origin, then latus rectum of the parabola is equal to

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 10

Given directrix of parabola ⇒ x+y=2
and force is origin vertex is A(0,0)
We know that perpendicular distance from vertex  of the parabola to directrix is equal to 'a'  where 4a is the Latus Rectum of the 
Parabola 

*Multiple options can be correct
WBJEE Mathematics Sample Paper I - Question 11

There exists a triangle ABC satisfying the conditions

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 11

The sine formula is 
a/sinA = b/sinB 
⇒ a sin B = b sin A
(a) b sin A = a 
⇒ a sin B = a 
⇒ B = π/2 
Since, ∠A  < π/2 therefore, the triangle is possible.
(b) b sin A < a 
⇒ a sin B < a 
⇒ sinB < 1 
⇒ ∠B exists 
Now, b > a 
⇒ B > A since A < π/2 
∴ The triangle is possible.

WBJEE Mathematics Sample Paper I - Question 12

In a ΔABC, (b +c) cos A + (c + a) cos B + (a + b) cos C is equal to

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 12

(b+c) cos A + (c + a) cos B + (a + b) cos C
⇒ b cos A + c cos A + c cos B + a cos B + a cos C + b cos C
⇒ (b cos C + c cos B) + (c cos A + a cos C) + (a cos B + b cos A) ...(1)
Using projection formula,
a = (b cos C + c cos B) ...(2)
b = (c cos A + a cos C) ...(3)
c = (a cos B + b cos A) ...(4)

On adding the projection formula, we get the initial expression
i.e. (2) + (3) + (4) = (1)
∴ (b + c) cos A + (c + a) cos B + (a + b) cos C = a + b + c

WBJEE Mathematics Sample Paper I - Question 13

The period of the function y = sec x is

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 13

y = sec x is periodic function. The period of y = sec x is 2π.

WBJEE Mathematics Sample Paper I - Question 14

The value of 

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WBJEE Mathematics Sample Paper I - Question 15

Evaluate: 

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 15

xex = t
(xex + ex) dx = dt
= ex(x + 1) dx = dt
= ∫dt/sin2t
= ∫cosec2t dt
= -cot(xex) + c

WBJEE Mathematics Sample Paper I - Question 16

If A and B matrices are of same order and A + B = B + A, this law is known as

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 16

Commutative law, in mathematics, either of two laws relating to number operations of addition and multiplication, stated symbolically: a + b = b + a and ab = ba

WBJEE Mathematics Sample Paper I - Question 17

For which of the following values of m , is the area of the region bounded by the curve y = x - x2 and the line y = mx equal to 9/2 ?

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WBJEE Mathematics Sample Paper I - Question 18

The area of the region bounded by the parabola (y−2)2 = x−1,the tangent to yhe parabola at the point (2 , 3) and the x – axis is equal to

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 18


Therefore, tangent at (2, 3) is y – 3 = ½ (x – 2). i.e. x – 2y +4 = 0 . therefore required area is 

WBJEE Mathematics Sample Paper I - Question 19

The area of the loop between the curve y = a sin x and the x – axis and x = 0 , x = π. is

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WBJEE Mathematics Sample Paper I - Question 20

If the three points A(1,6), B(3, –4) and C(x, y) are collinear then the equation satisfying by x and y is

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WBJEE Mathematics Sample Paper I - Question 21

If     and θ lies in the second quadrant, then cosθ is equal to

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θ in 2nd quad Cosθ < 0

WBJEE Mathematics Sample Paper I - Question 22

The solutions set of inequation cos–1x < sin–1x is

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 22

cos–1x < sin–1x is

WBJEE Mathematics Sample Paper I - Question 23

The number of solutions of 2sinx + cos x = 3 is

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 23

√5<3  No solution

WBJEE Mathematics Sample Paper I - Question 24

Let     and    then α + β is

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WBJEE Mathematics Sample Paper I - Question 25

If   

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WBJEE Mathematics Sample Paper I - Question 26

If sinθ and cosθ are the roots of the equation ax2 – bx + c = 0, then a, b and c satisfy the relation

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WBJEE Mathematics Sample Paper I - Question 27

If A and B are two matrices such that A+B and AB are both defined, then

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 27

Addition is defined if order of A is equal to order of B
A B
nxm nxm is defined if m = n
⇒ A, B are square matrices of same order

WBJEE Mathematics Sample Paper I - Question 28

   is a symmetric matrix, then the value of x is

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 28

A = AT

WBJEE Mathematics Sample Paper I - Question 29

If   

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 29


= Real

WBJEE Mathematics Sample Paper I - Question 30

The equation of the locus of the point of intersection of the straight lines x sin θ + (1 – cos θ) y = a sin θ and x sin θ – (1 + cos θ) y + a sin θ = 0 is

Detailed Solution for WBJEE Mathematics Sample Paper I - Question 30

y = a sin θ
x = a cos θ.

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