40 Questions MCQ Test - Sample BITSAT Chemistry Test
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The weight of one molecule of a compound C₆₀H₁₂₂ is
Detailed Solution for Sample BITSAT Chemistry Test - Question 7
The Molecule iS C₆₀H₁₂₂
Molecular mass of C₆₀H₁₂₂ --- [60x12+1x122]
=842 Unified mass
Weight of one molecule of C₆₀H₁₂₂ :
=molecular weight of C₆₀H₁₂₂ / Avogadro's number
∴The weight of a molecule of a compound C₆₀H₁₂₂ is 1.4x10⁻²¹ g
Detailed Solution for Sample BITSAT Chemistry Test - Question 11
Potassium superoxide is a yellow paramagnetic solid that is air and moisture sensitive. Its formula is KO2 and because potassium is +1, the superoxide has a charge of -1. ... The unpaired electron in the pi* orbital accounts for the paramagnetic behavior or potassium superoxide.
Which one of the following is an incorrect statement?
Detailed Solution for Sample BITSAT Chemistry Test - Question 15
The electron affinity of fluorine is unexpectedly less than that of Cl. Because the size of F atom is quite small, as a result, the electron-electron repulsions in the relatively compact 2p-subshell are comparitively large and hence the incoming electron is not accepted with the same ease as in the case with Cl.
The rate of a gaseous reaction is given by the expression K [A][B]. If the volume of the reaction vessel is suddenly reduced to 1/4th of the initial volume, the reaction rate relating to original rate will be
Detailed Solution for Sample BITSAT Chemistry Test - Question 16
Rate = kab. When volume is reduced to 1/4th, concentrations will become 4 times.
Detailed Solution for Sample BITSAT Chemistry Test - Question 18
The third law was developed by the chemist Walther Nernst during the years 1906-1912. It is often referred to as Nernst’s theorem or Nernst’s postulate. Nernst proposed that the entropy of a system at absolute zero would be a well-defined constant. Instead of being 0, entropy at absolute zero could be a nonzero constant, due to the fact that a system may have degeneracy (having several ground states at the same energy).
Detailed Solution for Sample BITSAT Chemistry Test - Question 19
An acid is a compound which can donate the protons easily.Carboxylic acids are termed as acids because they follow the definition of acid.So, the presence of -COOH group is not the criteria for being an acid.
In case of Picric acid, the phenolic -OH group readily give away proton as the resulting phenoxide ion is significantly stabilized by delocalization over three nitro groups situated at 2-,4-,6- positions.So it is also an acid.
Detailed Solution for Sample BITSAT Chemistry Test - Question 22
A common dry cell is the zinc-carbon cell, sometimes called the dry Leclanche cell, with a nominal voltage of 1.5 volts, the same as the alkaline cell (since both use the same zinc–manganese dioxide combination).
Chlorobenzene on heating with aq NH₃ under pressure in the presence of cuprous chloride gives
Detailed Solution for Sample BITSAT Chemistry Test - Question 28
Aniline is an organic compound with the formula C6H5NH2. Consisting of a phenyl group attached to an amino group, aniline is the prototypical aromatic amine. Its main use is in the manufacture of precursors to polyurethane and other industrial chemicals. Like most volatile amines, it has the odor of rotten fish.
Benzene and toluene form nearly ideal solutions. At 20oC, vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20oC for a solution containing 78 g of benzene and 46 g of toluene is ___ torr.
Detailed Solution for Sample BITSAT Chemistry Test - Question 36
Since benzene and toulene form nearly ideal solutions, we can apply raoult`s law
that is the partial pressure of benzene= mole fraction * vapour pressure of benzene in pure form
The adsorption of solids, from a solution, is called
Detailed Solution for Sample BITSAT Chemistry Test - Question 40
When a solute(here solid ) is adsorbed from a solution is called Positive adsorption vice versa when a solvent is adsorbed it is called negative adsorption.
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