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BITSAT Chemistry Test - 6 - JEE MCQ


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30 Questions MCQ Test - BITSAT Chemistry Test - 6

BITSAT Chemistry Test - 6 for JEE 2024 is part of JEE preparation. The BITSAT Chemistry Test - 6 questions and answers have been prepared according to the JEE exam syllabus.The BITSAT Chemistry Test - 6 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BITSAT Chemistry Test - 6 below.
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BITSAT Chemistry Test - 6 - Question 1

Hydrogen bonding is maximum in

BITSAT Chemistry Test - 6 - Question 2

The organic compound which will answer the Fehling solution test is

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BITSAT Chemistry Test - 6 - Question 3

The energy of a hydrogen atom in its ground state is -13.6eV. The energy of the level corresponding to the energy level equal to 5 is

BITSAT Chemistry Test - 6 - Question 4

The number of electrons in the M shell of the element with atomic number 24 is

BITSAT Chemistry Test - 6 - Question 5

The most stable free radical among the following is

BITSAT Chemistry Test - 6 - Question 6

Which of the following is not a nucleophile?

BITSAT Chemistry Test - 6 - Question 7

In graphite, the electrons are

BITSAT Chemistry Test - 6 - Question 8

Amino acids are produced by the hydrolysis of

BITSAT Chemistry Test - 6 - Question 9

The enzyme which hydrolyses triglycerides to fatty acids and glycerol, is called

BITSAT Chemistry Test - 6 - Question 10

A is a higher phenol and B is an aromatic carboxylic acid. Separation of a mixture of A and B can be carried out easily by having a solution

BITSAT Chemistry Test - 6 - Question 11

Which of the following is a polar compound?

Detailed Solution for BITSAT Chemistry Test - 6 - Question 11

We know that greater the difference in electronegativity difference in electronegativity of two atoms forming a covalent bond. More is its polar nature.

In HF, there is a much difference in the electronegativities of hydrogen and fluorine. Therefore (HF) is a polar compound.

BITSAT Chemistry Test - 6 - Question 12

The law of mass action was given by

BITSAT Chemistry Test - 6 - Question 13

Which relation is correct ?

BITSAT Chemistry Test - 6 - Question 14

t1/4 can be taken as the time taken for the concentration of a reactant to drop to (3/4) of its initial value. If the rate constant for a first order reaction is K, the t1/4 can be written as

BITSAT Chemistry Test - 6 - Question 15

The name of the element with atomic number 100 was adopted in honour of

Detailed Solution for BITSAT Chemistry Test - 6 - Question 15

Fermium (symbol Fm and atomic number 100) was named for the American physicist Enrico Fermi. It is a synthetic, radioactive, metallic transuranic element of the actinide series.

BITSAT Chemistry Test - 6 - Question 16

The heat of combustion of methane at 298K is expressed by
C H 4 g + 2 O 2 g → C O 2 g + 2 H 2 O l , Δ H = − 890.2 k J . The magnitude of Δ E of the reaction at this temperature is

BITSAT Chemistry Test - 6 - Question 17

Which one of the following is an inner orbital complex as well as diamagnetic in behaviour?
(Atomic numbers : Zn = 30, Cr = 24, Co = 27, Ni = 28)

BITSAT Chemistry Test - 6 - Question 18

Which of the following compounds is aspirin?

BITSAT Chemistry Test - 6 - Question 19

Which of the following factors may be regarded as the main cause of lanthanide contraction?

BITSAT Chemistry Test - 6 - Question 20

How many moles of acidified FeSO₄ solution can be completely oxidised by one mole of KMnO₄?

BITSAT Chemistry Test - 6 - Question 21

The oxidation no. of nitrogen in NaNO₂ is

Detailed Solution for BITSAT Chemistry Test - 6 - Question 21

The formal oxidation state of the nitrogen atom in a nitrite is +3. This means that it is can be either oxidised to oxidation states +4 and +5 or reduced to oxidation states as low as -3.

BITSAT Chemistry Test - 6 - Question 22

A σ - bond is

BITSAT Chemistry Test - 6 - Question 23

Which one of the following will undergo meta-substitution on monochlorination ?

BITSAT Chemistry Test - 6 - Question 24

Iodoethane reacts with sodium in the presence of dry ether. The main product is

BITSAT Chemistry Test - 6 - Question 25

Nascent hydrogen consists of

Detailed Solution for BITSAT Chemistry Test - 6 - Question 25

When hydrogen molecule (H2) is dissociate into its atomic hydrogen, then these newly formed hydrogens were called as Nascent hydrogens. These hydrogen atoms were more reactive than normal hydrogen due to the excess energy. Hence, Nascent hydrogen can reduce elements and compounds that do not readily react with normal hydrogen.

 

Nascent hydrogen is hydrogen in the form of individual atoms, not paired into molecules as it is in the gaseous state. It is also called newly born Hydrogen

It is more reactive than ordinary hydrogen.

When ordinary hydrogen is passed through KMnO4

KMnO4+H2+H2SO4⟶no reaction

Zn+H2SO4⟶ZnSO4+2[H]

[H] - nascent hydrogen

2KMnO4+3H2SO4+10[H]⟶K2SO4+2MnSO4+8H2O

BITSAT Chemistry Test - 6 - Question 26

The pH of gastric juice is normally

BITSAT Chemistry Test - 6 - Question 27

The stereoisomers which are neither superimposable nor mirror-image are called

BITSAT Chemistry Test - 6 - Question 28

Which among MeX, RCH₂X, R₂CHX, R₃CX is most reactive towards SN2 reaction?

BITSAT Chemistry Test - 6 - Question 29

Wood charcoal is used to decolourise sugar because it

BITSAT Chemistry Test - 6 - Question 30

A deep brown gas is formed by mixing two colourless gases which are

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