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BITSAT Chemistry Test Free Online Test 2026


MCQ Practice Test & Solutions: BITSAT Chemistry Test (40 Questions)

You can prepare effectively for JEE BITSAT Mock Tests Series & Past Year Papers 2026 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "BITSAT Chemistry Test". These 40 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 50 minutes
  • - Number of Questions: 40

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BITSAT Chemistry Test - Question 1

Which of the following reactions is used for detecting presence of carbonyl group ?

BITSAT Chemistry Test - Question 2

α-particles can be detected using

BITSAT Chemistry Test - Question 3

Carbolic acid is

BITSAT Chemistry Test - Question 4

An element has 2 electrons is K-shell, 8 electrons in L-shell, 13 electrons in M-shell and one electron in N-shell. The element is

BITSAT Chemistry Test - Question 5

1 mol of CH₄ contains

BITSAT Chemistry Test - Question 6

Which of the following alkyl group has the maximum + I effect?

Detailed Solution: Question 6

BITSAT Chemistry Test - Question 7

The volume of 1.0 g of hydrogen in litres at N.T.P. is

Detailed Solution: Question 7

1mole of gas at NTP occupies =22.4L no. of moles of H2 = mass/molar mass = 1/2 = 0.5moles then required vol = 0.5×22.4 =11.2L

BITSAT Chemistry Test - Question 8

The bromination of benzene in presence of FeBr₃ is an example of

BITSAT Chemistry Test - Question 9

The no. of essential amino acids in human body is

Detailed Solution: Question 9

The human body requires 9 essential amino acids that cannot be synthesized by the body and must be obtained through diet. These essential amino acids include histidine, isoleucine, leucine, lysine, methionine, phenylalanine, threonine, tryptophan, and valine.

BITSAT Chemistry Test - Question 10

Toluic acid on reaction with Br₂ + Fe gives

Detailed Solution: Question 10

BITSAT Chemistry Test - Question 11

A chemical reaction will be spontaneous if it is accompained by a decrease of

BITSAT Chemistry Test - Question 12

An ionic solid is a poor conductor of electricity because

BITSAT Chemistry Test - Question 13

The equilibrium constant for the following reaction will be 3 A + 2 B → C

BITSAT Chemistry Test - Question 14

The decomposition of a substance follows first order kinetics. If its concentration is reduced to 1/8 of its initial value in 24 minutes, the rate constant of the decomposition process is

Detailed Solution: Question 14

Option D is correct.

For a first-order reaction, k = (1/t) ln([A]0/[A]t).

Using ln x = 2.303 log x, we get k = (2.303/t) log([A]0/[A]t).

Here [A]t = [A]0/8 so [A]0/[A]t = 8. Therefore k = (2.303/24) log 8 min-1, which is the expression given in option D.

Evaluating numerically: log 8 = 0.90309, so k = (2.303/24) × 0.90309 ≈ 0.08666 min-1.

BITSAT Chemistry Test - Question 15

An example of water soluble vitamin is

BITSAT Chemistry Test - Question 16

Which of the following species has the highest ionization potential?

Detailed Solution: Question 16

Li+ has highest ionization potential among the given species. The reason for this is after losing one electron, the Li+ ion has more stable inert gas configuration, i.e. 1s2 . Secondly, it has smallest size among all the species due to less number of electrons and high effective nuclear charge.

BITSAT Chemistry Test - Question 17

An adiabatic expansion of an ideal gas always has

BITSAT Chemistry Test - Question 18

Paracetamol is/are

BITSAT Chemistry Test - Question 19

A complex compound of Co3⁺ with molecular formula CoClxyNH₃ gives a total of three ions per molecule when dissolved in water. How many Cl⁻ ions satisfy primary as well secondary valencies in this complex?

BITSAT Chemistry Test - Question 20

What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?

BITSAT Chemistry Test - Question 21

Which of the following element belongs to the third row transition series?

Detailed Solution: Question 21

The third transition series or 5d series corresponding to the filling of 5d sublevel consists of the following 10 elements of the 6thperiod: La (Atomic No.=57); Hf (Atomic No.= 72), Ta, W, Re, Os, Ir, Pt, Au and Hg (Atomic No.=80). Hence Re belongs to third transition series.

BITSAT Chemistry Test - Question 22

The standard emf of the cell Zn + Cu2⁺ → Cu + Zn2 is 1.10 V at 25oC. The emf of the cell when 0.1 M Cu2⁺ and 0.1 M Zn2⁺ solutions are used will be

Detailed Solution: Question 22

The standard emf of the cell Zn / Cu2+ is 1.10 V at 25°C. When using solutions of 0.1 M Cu2+ and 0.1 M Zn2+, the emf can change due to concentration effects.

To calculate the emf under these conditions, we can apply the Nernst equation:

  • The standard emf is 1.10 V.
  • Both ions are at the same concentration, which will affect the overall emf.
  • The actual emf will be lower than the standard emf due to concentration.

Therefore, the emf of the cell with 0.1 M solutions will be:

  • 1.10 V

BITSAT Chemistry Test - Question 23

Hardness of water is due to which pair of ions ?

BITSAT Chemistry Test - Question 24

The compound that decolourises alkaline KMnO₄ is

BITSAT Chemistry Test - Question 25

Which one of the following will undergo meta-substitution on monochlorination ?

Detailed Solution: Question 25

(c) Ethyl benzoate  The −Cl of chlorobenzene is weakly deactivating but has ortho-para directing influence. The −OH group of phenol is strongly activating the −OC2​H5​ group of ethoxybenzene is moderately activating but the −COOC2​H5​ group of ethylbenzoate is moderately deactivating and exerts meta directing influence on account of −I effect and −R effect.Read more on Sarthaks.com - https://www.sarthaks.com/3552109/which-one-of-the-following-will-undergo-meta-substitution-on-monochlorination

BITSAT Chemistry Test - Question 26

The pH of gastric juice is normally

BITSAT Chemistry Test - Question 27

Nitrogen atom has an atomic number of 7 and oxygen has an atomic number 8. The total number of electrons in a nitrate ion will be

Detailed Solution: Question 27

BITSAT Chemistry Test - Question 28

Reaction C₂H₅I + C₅H₁₁I + 2Na → C₂H₅ - C₅H₁₁ + 2NaI is called

BITSAT Chemistry Test - Question 29

Molecular formula C5H12O will show :

BITSAT Chemistry Test - Question 30

Amongst the compounds Mg₃N₂, NH₃ and N₂O₃, nitrogen shows an oxidation state of +3 in

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