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CBSE Class 8  >  Class 8 Test  >  Mathematics (Maths)   >  Test: Algebra Play - Class 8 MCQ

Algebra Play - Free MCQ Practice Test with solutions, Class 8 Maths


MCQ Practice Test & Solutions: Test: Algebra Play (10 Questions)

You can prepare effectively for Class 8 Mathematics (Maths) Class 8 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Algebra Play". These 10 questions have been designed by the experts with the latest curriculum of Class 8 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

Sign up on EduRev for free to attempt this test and track your preparation progress.

Test: Algebra Play - Question 1
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In the calendar magic trick, if your friend tells you the sum of a 2x2 grid is 44, what is the formula to express the sum of the numbers in the grid in terms of the top-left number, a?

Detailed Solution: Question 1

On a calendar, moving one square right adds 1 and moving one row down adds 7, so a 2×2 block with top-left entry a contains: a, a+1, a+7, a+8.

Sum = a + (a+1) + (a+7) + (a+8).

Sum = 4a + 16.

As a check, if the sum is 44 then a = (44 - 16)/4 = 7.

Test: Algebra Play - Question 2
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In the date trick, the final expression obtained is:
100M + 165 + D.
Why can the date be extracted correctly?

Detailed Solution: Question 2

100M shifts the month to the hundreds place and D occupies last two digits.

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Test: Algebra Play - Question 3
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How does the "3-Digit Cycling Trick" demonstrate properties of number divisibility?

Detailed Solution: Question 3

Let the 3-digit number be N = 100a + 10b + c.

The two cyclic permutations are 100b + 10c + a and 100c + 10a + b.

Their sum is (100a+10b+c)+(100b+10c+a)+(100c+10a+b) = 111(a+b+c).

Since 111 = 3 × 37, the sum is a multiple of 37. Hence the trick demonstrates divisibility by 37; option A is correct.

Test: Algebra Play - Question 4
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In a number pyramid, the bottom row is: a, b, c.
The top number is:

Detailed Solution: Question 4

Middle row: a+b , b+c
Top = (a+b)+(b+c) = a+2b+c

Test: Algebra Play - Question 5
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If you take a 3-digit number, cycle its digits, and add all three resulting numbers, what is the sum always divisible by?

Detailed Solution: Question 5

The sum of the three numbers formed by cycling the digits of a 3-digit number is always divisible by 37. This occurs because the sum can be expressed as 111(a + b + c), where a, b, and c are the digits, and since 111 is divisible by 37, the entire sum will also be divisible by 37, showcasing interesting properties of number manipulation.

Test: Algebra Play - Question 6
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If p < q < r, the largest product formed using pq × r, qp × r, rp × q is:

Detailed Solution: Question 6

Largest digit should be multiplier and others in decreasing order → qp × r

Test: Algebra Play - Question 7
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In a number pyramid, if a + b = 60, 12 + c = a and c + 8 = b, what is the value of c when these equations are solved?

  • 10
  • 40
  • 30
  • 20

Detailed Solution: Question 7

We have the three equations:

a + b = 60

12 + c = a

c + 8 = b

From the third equation, b = c + 8. Substitute into the first:

a + (c + 8) = 60 → a + c + 8 = 60 → a + c = 52.

But from the second equation, a = 12 + c. Substitute into a + c = 52:

(12 + c) + c = 52 → 12 + 2c = 52 → 2c = 40 → c = 20.

Test: Algebra Play - Question 8
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What is the largest product you can create using the digits 2, 3, and 5 in the format __ __ × __?

Detailed Solution: Question 8

Form a two-digit number from two of the digits and use the remaining digit as the multiplier; evaluate all possibilities.

53 × 2 = 106

35 × 2 = 70

52 × 3 = 156

25 × 3 = 75

32 × 5 = 160

23 × 5 = 115

The largest product is 160, achieved by 32 × 5.

Test: Algebra Play - Question 9
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In the "Addition Trick," the sum of a two-digit number and its reverse is always divisible by?

Detailed Solution: Question 9

Let the two-digit number be 10a + b, where a and b are its digits.

The reverse is 10b + a.

Sum = (10a + b) + (10b + a) = 11(a + b).

Therefore the sum is always divisible by 11; so option B is correct.

Test: Algebra Play - Question 10
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What is the final result of the classic "Think of a Number" trick when you follow these steps: think of a number, double it, add four, divide by two, and subtract the original number?

Detailed Solution: Question 10

Let the original number be x.

After doubling: 2x.

After adding 4: 2x + 4.

After dividing by 2: (2x + 4)/2 = x + 2.

After subtracting the original number: (x + 2) - x = 2.

Final result: 2.

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About this Class 8 Practice Test

This test contains 10 MCQs on Algebra Play with detailed solutions for each question. It is part of the Mathematics (Maths) Class 8 course on EduRev, designed to align with the current Class 8 syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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If you found this Algebra Play MCQ Test helpful, you can further enhance your Class 8 preparation with in-depth courses on EduRev, for all the subjects and topics available in Mathematics (Maths) Class 8 course. The course offers:
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