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CLAT Exam  >  CLAT Test  >  Daily Passage Practice  >  Daily Passage Test for CLAT - Jan 9 - CLAT MCQ

Daily Passage Test for CLAT - Jan 9 MCQs & solutions Free


MCQ Practice Test & Solutions: Daily Passage Test for CLAT - Jan 9 (5 Questions)

You can prepare effectively for CLAT Daily Passage Practice for CLAT with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Daily Passage Test for CLAT - Jan 9". These 5 questions have been designed by the experts with the latest curriculum of CLAT 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 5

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Daily Passage Test for CLAT - Jan 9 - Question 1
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Directions: Study the following information and answer the given question.

In a college, there are three student clubs (cricket club, football club, and hockey club). Number of students only in cricket club is 4 times the number of students in both football and hockey clubs. Ratio of students only in football club to the students only in hockey club is 3 : 2. While the ratio of students only in hockey club to the students only in cricket club is 1 : 2. 3 students are participating in all the clubs. The number of students in both cricket and football clubs is the same as that of students only in the hockey club. Students who are in both cricket and hockey clubs are 10 and the number of students in football and hockey clubs is twice. 75% of the students in the college are not in any of these clubs.

Q. Find the number of students in cricket and football only.

Detailed Solution: Question 1

Given:
Students participating in all the clubs are 3, i.e. m = 3 ...(1)

Number of students only in cricket is 4 times the number of students in both football and hockey clubs,
i.e. p = 4(m + c) ...(2)

Ratio of the number of students only in football club to the number of students only in hockey club is 3 : 2.
q/r = 3/2 ...(3)

Ratio of the number of students only in hockey club to the number of students only in cricket club is 1 : 2.
r/p = 1/2 ...(4)

The number of students in both cricket and football clubs is the same as the number of students only in the hockey club.
a + m = r ...(5)

The number of students in both cricket and hockey clubs are 10 and the number of students in football and hockey clubs is twice that number.
b + m = 10 ...(6)
m + c = 20 ...(7)

Putting the value of m from (1) in (6) and (7), gives:
b = 7
c = 17
Putting value of m + c from (7) in (2), gives:
p = 4(20)
p = 80

Putting 'p' in (4),
r = 40
And, putting 'r' in (3) gives q = 60.

Further, putting value of r in (5),
a + 3 = 40
a = 37

Total number of students = p + q + r + a + b + c + m
= 80 + 60 + 40 + 37 + 7 + 17 + 3
= 244

75% of the students in the college are not in any of these clubs, this means that 25% attend the club, i.e. 0.25(x) = 244,
where x = total no of students in college.
x = 976
The number of students in football and cricket only is 37.

Daily Passage Test for CLAT - Jan 9 - Question 2
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Directions: Study the following information and answer the given question.

In a college, there are three student clubs (cricket club, football club, and hockey club). Number of students only in cricket club is 4 times the number of students in both football and hockey clubs. Ratio of students only in football club to the students only in hockey club is 3 : 2. While the ratio of students only in hockey club to the students only in cricket club is 1 : 2. 3 students are participating in all the clubs. The number of students in both cricket and football clubs is the same as that of students only in the hockey club. Students who are in both cricket and hockey clubs are 10 and the number of students in football and hockey clubs is twice. 75% of the students in the college are not in any of these clubs.

Q. Find the number of students in cricket and hockey only.

Detailed Solution: Question 2

Given:
Students participating in all the clubs are 3, i.e. m = 3 ...(1)

Number of students only in cricket is 4 times the number of students in both football and hockey clubs,
i.e. p = 4(m + c) ...(2)

Ratio of the number of students only in football club to the number of students only in hockey club is 3 : 2.
q/r = 3/2 ...(3)

Ratio of the number of students only in hockey club to the number of students only in cricket club is 1 : 2.
r/p = 1/2 ...(4)

The number of students in both cricket and football clubs is the same as the number of students only in the hockey club.
a + m = r ...(5)

Students who are in both cricket and hockey clubs are 10 and twice the number of students are there in football and hockey clubs.
b + m = 10 ...(6)
m + c = 20 ...(7)

Putting the value of m from (1) in (6) and (7), gives:
b = 7
c = 17
Putting value of m + c from (7) in (2), gives:
p = 4(20)
p = 80

Putting 'p' in (4),
r = 40
And, putting 'r' in (3) gives q = 60.

Further, putting value of r in (5),
a + 3 = 40
a = 37

Total number of students = p + q + r + a + b + c + m
= 80 + 60 + 40 + 37 + 7 + 17 + 3
= 244

75% of the students in the college are not in any of these clubs, this means that 25% attend the club, i.e. 0.25(x) = 244,
where x = total no of students in college.
x = 976
The number of students in cricket and hockey only is 7.

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Daily Passage Test for CLAT - Jan 9 - Question 3
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Directions: Study the following information and answer the given question.

In a college, there are three student clubs (cricket club, football club, and hockey club). Number of students only in cricket club is 4 times the number of students in both football and hockey clubs. Ratio of students only in football club to the students only in hockey club is 3 : 2. While the ratio of students only in hockey club to the students only in cricket club is 1 : 2. 3 students are participating in all the clubs. The number of students in both cricket and football clubs is the same as that of students only in the hockey club. Students who are in both cricket and hockey clubs are 10 and the number of students in football and hockey clubs is twice. 75% of the students in the college are not in any of these clubs.

Q. Total number of students in the college is

Detailed Solution: Question 3

Given:
Students participating in all the clubs are 3, i.e. m = 3 ...(1)

Number of students only in cricket is 4 times the number of students in both football and hockey clubs,
i.e. p = 4(m + c) ...(2)

Ratio of the number of students only in football club to the number of students only in hockey club is 3 : 2.
q/r = 3/2 ...(3)

Ratio of the number of students only in hockey club to the number of students only in cricket club is 1 : 2.
r/p = 1/2 ...(4)

The number of students in both cricket and football clubs is the same as the number of students only in the hockey club.
a + m = r ...(5)

Students who are in both cricket and hockey clubs are 10 and twice the number of students are there in football and hockey clubs.
b + m = 10 ...(6)
m + c = 20 ...(7)

Putting the value of m from (1) in (6) and (7), gives:
b = 7
c = 17
Putting value of m + c from (7) in (2), gives:
p = 4(20)
p = 80

Putting 'p' in (4),
r = 40
And, putting 'r' in (3) gives q = 60.

Further, putting value of r in (5),
a + 3 = 40
a = 37

Total number of students = p + q + r + a + b + c + m
= 80 + 60 + 40 + 37 + 7 + 17 + 3
= 244

75% of the students in the college are not in any of these clubs, this means that 25% attend the club, i.e. 0.25(x) = 244,
where x = total no of students in college.
x = 976

Total number of students in the college is 976.

Daily Passage Test for CLAT - Jan 9 - Question 4
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Directions: Study the following information and answer the given question.

In a college, there are three student clubs (cricket club, football club, and hockey club). Number of students only in cricket club is 4 times the number of students in both football and hockey clubs. Ratio of students only in football club to the students only in hockey club is 3 : 2. While the ratio of students only in hockey club to the students only in cricket club is 1 : 2. 3 students are participating in all the clubs. The number of students in both cricket and football clubs is the same as that of students only in the hockey club. Students who are in both cricket and hockey clubs are 10 and the number of students in football and hockey clubs is twice. 75% of the students in the college are not in any of these clubs.

Q. Find the number of students in football and hockey only.

Detailed Solution: Question 4

Given:
Students participating in all the clubs are 3, i.e. m = 3 ...(1)

Number of students only in cricket is 4 times the number of students in both football and hockey clubs,
i.e. p = 4(m + c) ...(2)

Ratio of the number of students only in football club to the number of students only in hockey club is 3 : 2.
q/r = 3/2 ...(3)

Ratio of the number of students only in hockey club to the number of students only in cricket club is 1 : 2.
r/p = 1/2 ...(4)

The number of students in both cricket and football clubs is the same as the number of students only in the hockey club.
a + m = r ...(5)

Students who are in both cricket and hockey clubs are 10 and twice the number of students are there in football and hockey clubs.
b + m = 10 ...(6)
m + c = 20 ...(7)

Putting the value of m from (1) in (6) and (7), gives:
b = 7
c = 17
Putting value of m + c from (7) in (2), gives:
p = 4(20)
p = 80

Putting 'p' in (4),
r = 40
And, putting 'r' in (3) gives q = 60.

Further, putting value of r in (5),
a + 3 = 40
a = 37

Total number of students = p + q + r + a + b + c + m
= 80 + 60 + 40 + 37 + 7 + 17 + 3
= 244

75% of the students in the college are not in any of these clubs, this means that 25% attend the club, i.e. 0.25(x) = 244,
where x = total no of students in college.
x = 976
The number of students in football and hockey only is 17.

Daily Passage Test for CLAT - Jan 9 - Question 5
Save

Directions: Study the following information and answer the given question.

In a college, there are three student clubs (cricket club, football club, and hockey club). Number of students only in cricket club is 4 times the number of students in both football and hockey clubs. Ratio of students only in football club to the students only in hockey club is 3 : 2. While the ratio of students only in hockey club to the students only in cricket club is 1 : 2. 3 students are participating in all the clubs. The number of students in both cricket and football clubs is the same as that of students only in the hockey club. Students who are in both cricket and hockey clubs are 10 and the number of students in football and hockey clubs is twice. 75% of the students in the college are not in any of these clubs.

Q. Total number of students in different clubs is

Detailed Solution: Question 5

Given:
Students participating in all the clubs are 3, i.e. m = 3 ...(1)

Number of students only in cricket is 4 times the number of students in both football and hockey clubs,
i.e. p = 4(m + c) ...(2)

Ratio of the number of students only in football club to the number of students only in hockey club is 3 : 2.
q/r = 3/2 ...(3)

Ratio of the number of students only in hockey club to the number of students only in cricket club is 1 : 2.
r/p = 1/2 ...(4)

The number of students in both cricket and football clubs is the same as the number of students only in the hockey club.
a + m = r ...(5)

Students who are in both cricket and hockey clubs are 10 and twice the number of students are there in football and hockey clubs.
b + m = 10 ...(6)
m + c = 20 ...(7)

Putting the value of m from (1) in (6) and (7), gives:
b = 7
c = 17
Putting value of m + c from (7) in (2), gives:
p = 4(20)
p = 80

Putting 'p' in (4),
r = 40
And, putting 'r' in (3) gives q = 60.

Further, putting value of r in (5),
a + 3 = 40
a = 37

Total number of students = p + q + r + a + b + c + m
= 80 + 60 + 40 + 37 + 7 + 17 + 3
= 244

75% of the students in the college are not in any of these clubs, this means that 25% attend the club, i.e. 0.25(x) = 244,
where x = total no of students in college.
x = 976

Total number of students in different clubs is 244.

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This test contains 5 MCQs on Daily Passage Test for CLAT - Jan 9 with detailed solutions for each question. It is part of the Daily Passage Practice for CLAT course on EduRev, designed to align with the current CLAT syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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