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CLAT Exam  >  CLAT Test  >  Daily Passage Practice  >  Daily Passage Test for CLAT - Aug 9 - CLAT MCQ

Daily Passage Test for CLAT - Aug 9 MCQs & solutions Free


MCQ Practice Test & Solutions: Daily Passage Test for CLAT - Aug 9 (5 Questions)

You can prepare effectively for CLAT Daily Passage Practice for CLAT with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Daily Passage Test for CLAT - Aug 9". These 5 questions have been designed by the experts with the latest curriculum of CLAT 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 5

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Daily Passage Test for CLAT - Aug 9 - Question 1
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Directions: Study the following information carefully and answer the questions given beside.
P, Q and R are three persons who repair a certain number of computers and Televisions.

P repaired 130 more computers as compared to R. Total number of computers and televisions repaired by Q is 575. R alone repaired 320 computers which is 95 more than the number of televisions repaired by Q. The number of televisions repaired by R is 40% more than the number of computers repaired by Q. The total number of computers and televisions repaired by all the persons together is 2150.

Q. The number of televisions repaired by Q is what percentage of the number of computers repaired by person P?

Detailed Solution: Question 1

From the common explanation, we have


Hence, Option D is correct.

Common explanation :

R alone repaired 320 computers which is 95 more than the number of televisions repaired by Q

Therefore, the number of televisions repaired by Q = 320 – 95 = 225

Total number of computers and televisions repaired by Q = 575

So, the number of computers repaired by Q = 575 – 225 = 350

The number of televisions repaired by R is 40% more than the number of computers repaired by Q 

So, the number of televisions repaired by R = 350 × (100 + 40)% = 350 × 140% = 490

The number of computers repaired by P = 320 + 130 = 450

Total number of computers and televisions repaired by P, Q and R = 2150

Total number of televisions repaired by P = 2150 – (450 + 350 + 320 + 490 + 225) = 2150 – 1835 = 315

Daily Passage Test for CLAT - Aug 9 - Question 2
Save

Directions: Study the following information carefully and answer the questions given beside.

P, Q and R are three persons who repair a certain number of computers and Televisions.

P repaired 130 more computers as compared to R. Total number of computers and televisions repaired by Q is 575. R alone repaired 320 computers which is 95 more than the number of televisions repaired by Q. The number of televisions repaired by R is 40% more than the number of computers repaired by Q. The total number of computers and televisions repaired by all the persons together is 2150.

Q. Find the ratio of the number of computers repaired by Q to that of televisions repaired by P.

Detailed Solution: Question 2

From the common explanation, we have

The required ratio = 350 : 315 = 10 : 9

Hence, Option D is correct.

Common explanation :

R alone repaired 320 computers which is 95 more than the number of televisions repaired by Q

Therefore, the number of televisions repaired by Q = 320 – 95 = 225

Total number of computers and televisions repaired by Q = 575

So, the number of computers repaired by Q = 575 – 225 = 350

The number of televisions repaired by R is 40% more than the number of computers repaired by Q 

So, the number of televisions repaired by R = 350 × (100 + 40)% = 350 × 140% = 490

The number of computers repaired by P = 320 + 130 = 450

Total number of computers and televisions repaired by P, Q and R = 2150

Total number of televisions repaired by P = 2150 – (450 + 350 + 320 + 490 + 225) = 2150 – 1835 = 315

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Daily Passage Test for CLAT - Aug 9 - Question 3
Save

Directions: Study the following information carefully and answer the questions given beside.

P, Q and R are three persons who repair a certain number of computers and Televisions.

P repaired 130 more computers as compared to R. Total number of computers and televisions repaired by Q is 575. R alone repaired 320 computers which is 95 more than the number of televisions repaired by Q. The number of televisions repaired by R is 40% more than the number of computers repaired by Q. The total number of computers and televisions repaired by all the persons together is 2150.

Q. What is the difference between the number of televisions repaired by R and the number of computers repaired by Q?

Detailed Solution: Question 3

From the common explanation, we have

Required difference = (490 – 350) = 140

Hence, Option C is correct.

Common explanation :

R alone repaired 320 computers which is 95 more than the number of televisions repaired by Q

Therefore, the number of televisions repaired by Q = 320 – 95 = 225

Total number of computers and televisions repaired by Q = 575

So, the number of computers repaired by Q = 575 – 225 = 350

The number of televisions repaired by R is 40% more than the number of computers repaired by Q 

So, the number of televisions repaired by R = 350 × (100 + 40)% = 350 × 140% = 490

The number of computers repaired by P = 320 + 130 = 450

Total number of computers and televisions repaired by P, Q and R = 2150

Total number of televisions repaired by P = 2150 – (450 + 350 + 320 + 490 + 225) = 2150 – 1835 = 315

Daily Passage Test for CLAT - Aug 9 - Question 4
Save

Directions: Study the following information carefully and answer the questions given beside.

P, Q and R are three persons who repair a certain number of computers and Televisions.

P repaired 130 more computers as compared to R. Total number of computers and televisions repaired by Q is 575. R alone repaired 320 computers which is 95 more than the number of televisions repaired by Q. The number of televisions repaired by R is 40% more than the number of computers repaired by Q. The total number of computers and televisions repaired by all the persons together is 2150.

Q. Find the average number of televisions repaired by the combined persons P and Q together.

Detailed Solution: Question 4

From common explanation, we have


Hence, Option C is correct.

Common explanation :

R alone repaired 320 computers which is 95 more than the number of televisions repaired by Q

Therefore, the number of televisions repaired by Q = 320 – 95 = 225

Total number of computers and televisions repaired by Q = 575

So, the number of computers repaired by Q = 575 – 225 = 350

The number of televisions repaired by R is 40% more than the number of computers repaired by Q 

So, the number of televisions repaired by R = 350 × (100 + 40)% = 350 × 140% = 490

The number of computers repaired by P = 320 + 130 = 450

Total number of computers and televisions repaired by P, Q and R = 2150

Total number of televisions repaired by P = 2150 – (450 + 350 + 320 + 490 + 225) = 2150 – 1835 = 315

Daily Passage Test for CLAT - Aug 9 - Question 5
Save

Directions: Study the following information carefully and answer the questions given beside.

P, Q and R are three persons who repair a certain number of computers and Televisions.

P repaired 130 more computers as compared to R. Total number of computers and televisions repaired by Q is 575. R alone repaired 320 computers which is 95 more than the number of televisions repaired by Q. The number of televisions repaired by R is 40% more than the number of computers repaired by Q. The total number of computers and televisions repaired by all the persons together is 2150.

Q. The combined number of televisions repaired by Q and R together is what percentage more/less than that of computers repaired by P and Q together?

Detailed Solution: Question 5

From the common explanation, we have

The combined number of computers repaired by P and Q = (450 + 350) = 800

The combined number of televisions repaired by Q and R = (225 + 490) = 715

Hence, Option C is correct.

Common explanation :

R alone repaired 320 computers which is 95 more than the number of televisions repaired by Q

Therefore, the number of televisions repaired by Q = 320 – 95 = 225

Total number of computers and televisions repaired by Q = 575

So, the number of computers repaired by Q = 575 – 225 = 350

The number of televisions repaired by R is 40% more than the number of computers repaired by Q 

So, the number of televisions repaired by R = 350 × (100 + 40)% = 350 × 140% = 490

The number of computers repaired by P = 320 + 130 = 450

Total number of computers and televisions repaired by P, Q and R = 2150

Total number of televisions repaired by P = 2150 – (450 + 350 + 320 + 490 + 225) = 2150 – 1835 = 315

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This test contains 5 MCQs on Daily Passage Test for CLAT - Aug 9 with detailed solutions for each question. It is part of the Daily Passage Practice for CLAT course on EduRev, designed to align with the current CLAT syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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