CLAT Exam  >  CLAT Test  >  Daily Passage Practice  >  Daily Passage Test for CLAT - Sep 27 - CLAT MCQ

Daily Passage Test for CLAT - Sep 27 MCQs & solutions Free


MCQ Practice Test & Solutions: Daily Passage Test for CLAT - Sep 27 (3 Questions)

You can prepare effectively for CLAT Daily Passage Practice for CLAT with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Daily Passage Test for CLAT - Sep 27". These 3 questions have been designed by the experts with the latest curriculum of CLAT 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 3

Sign up on EduRev for free to attempt this test and track your preparation progress.

Daily Passage Test for CLAT - Sep 27 - Question 1

Directions : Answer the questions on the basis of the information given below.
A rectangular park has length and breadth in the ratio 6 :
Ravi takes 2 minutes and 12 seconds to jog once around of the park at a speed of 5 feet/sec. At the centre of the park there is a circular water body, whereas the remaining area has a lawn. Ravi takes 1 minute and 28 seconds to jog once around the water body. There is a path of width 5 feet outside the perimeter and along the edges of the park.
Distance covered by Ravi in one round of the park = 5 x 132 = 660 feet
Let the length and breadth of the park be 6k and 5k respectively.
Perimeter = 2 x (6k + 5k) = 22k
⇒ 22k = 660 ⇒ k = 30
Length = 180 feet and breadth = 150 feet.
Total area of park = 180 x 150 = 27000 square feet. Circumference of water body = 5 x 88 = 440 feet 440
Radius = 70 feet
2n

The circular water body has a depth of five feet. What is the maximum volume water (in cubic feet) that can be contained in it?

Detailed Solution: Question 1

dArea of water body = n x 702 = 15400 square feet.
Volume of water = 5 x 15400 = 77000 cubic feet.

Daily Passage Test for CLAT - Sep 27 - Question 2

Directions : Answer the questions on the basis of the information given below.
A rectangular park has length and breadth in the ratio 6 :
Ravi takes 2 minutes and 12 seconds to jog once around of the park at a speed of 5 feet/sec. At the centre of the park there is a circular water body, whereas the remaining area has a lawn. Ravi takes 1 minute and 28 seconds to jog once around the water body. There is a path of width 5 feet outside the perimeter and along the edges of the park.
Distance covered by Ravi in one round of the park = 5 x 132 = 660 feet
Let the length and breadth of the park be 6k and 5k respectively.
Perimeter = 2 x (6k + 5k) = 22k
⇒ 22k = 660 ⇒ k = 30
Length = 180 feet and breadth = 150 feet.
Total area of park = 180 x 150 = 27000 square feet. Circumference of water body = 5 x 88 = 440 feet 440
Radius = 70 feet
2n

What is the ratio of the area of the lawn to the area of the path surrounding the park?

Detailed Solution: Question 2

Area of lawn = 27000 - 15400 = 11600 square feet.
Area of path = (190 x 160) - (180 x 150)
= 3400 square feet.
Ratio of the area of the lawn to the area of the path = 11600 : 3400 = 58 : 17.

Daily Passage Test for CLAT - Sep 27 - Question 3

Directions : Answer the questions on the basis of the information given below.
A rectangular park has length and breadth in the ratio 6 :
Ravi takes 2 minutes and 12 seconds to jog once around of the park at a speed of 5 feet/sec. At the centre of the park there is a circular water body, whereas the remaining area has a lawn. Ravi takes 1 minute and 28 seconds to jog once around the water body. There is a path of width 5 feet outside the perimeter and along the edges of the park.
Distance covered by Ravi in one round of the park = 5 x 132 = 660 feet
Let the length and breadth of the park be 6k and 5k respectively.
Perimeter = 2 x (6k + 5k) = 22k
⇒ 22k = 660 ⇒ k = 30
Length = 180 feet and breadth = 150 feet.
Total area of park = 180 x 150 = 27000 square feet. Circumference of water body = 5 x 88 = 440 feet 440
Radius = 70 feet
2n

What will be the total cost of paving the path surrounding the park at the rate of Rs.15 per square feet?

Detailed Solution: Question 3

Area of path = (190 x 160) - (180 x 150) = 3400 square feet.
Cost of paving the path = 3400 x 15 = Rs.51,000.

365 tests
Information about Daily Passage Test for CLAT - Sep 27 Page
In this test you can find the Exam questions for Daily Passage Test for CLAT - Sep 27 solved & explained in the simplest way possible. Besides giving Questions and answers for Daily Passage Test for CLAT - Sep 27, EduRev gives you an ample number of Online tests for practice
Download as PDF