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VITEEE PCME Mock Test - 3 - JEE MCQ


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30 Questions MCQ Test - VITEEE PCME Mock Test - 3

VITEEE PCME Mock Test - 3 for JEE 2024 is part of JEE preparation. The VITEEE PCME Mock Test - 3 questions and answers have been prepared according to the JEE exam syllabus.The VITEEE PCME Mock Test - 3 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for VITEEE PCME Mock Test - 3 below.
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VITEEE PCME Mock Test - 3 - Question 1

The perimeter of a sector is p. the area of the sector is maximum when its radius is

Detailed Solution for VITEEE PCME Mock Test - 3 - Question 1

VITEEE PCME Mock Test - 3 - Question 2

The area, in square unit, bounded by the curves y = x3, y = x2 and the ordinates x = 1, x = 2 is

Detailed Solution for VITEEE PCME Mock Test - 3 - Question 2

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VITEEE PCME Mock Test - 3 - Question 3

Let z,w be complex numbers such that z̅ + iw ̅ = 0 and arg zw = π.Then arg z equals

VITEEE PCME Mock Test - 3 - Question 4

  for x ≠ 5 and f is continuous at x = 5 then f(5) =

VITEEE PCME Mock Test - 3 - Question 5

If (a+ib)(c+id)(e+if)(g+ih) = A+iB, then (a2+b2)(c2+d2)(c2+f2)(g2+h2) =

VITEEE PCME Mock Test - 3 - Question 6

Detailed Solution for VITEEE PCME Mock Test - 3 - Question 6

Put sin2x = t

Then sin2x dx = d t ; x = 0, π/2 ⇒ t = 0,1  

VITEEE PCME Mock Test - 3 - Question 7

VITEEE PCME Mock Test - 3 - Question 8

Let y = | x | + | x − 2 | . Then dy/dx at x = 2 is

VITEEE PCME Mock Test - 3 - Question 9

The solution of the equation (x-y2x)dx=(y-x2y)dy is

VITEEE PCME Mock Test - 3 - Question 10

Detailed Solution for VITEEE PCME Mock Test - 3 - Question 10

Multiply R1, R2, R3 by a, b, c respectively and divide by abc
Take abc common from C3 so that C1, C3 are identical

VITEEE PCME Mock Test - 3 - Question 11

The solution of dy/dx + 1 = eX+Y is

VITEEE PCME Mock Test - 3 - Question 12

The order of the differential equation 

VITEEE PCME Mock Test - 3 - Question 13

Integrating factor of 

VITEEE PCME Mock Test - 3 - Question 14

Differential of x6 w.r. to x3 is equal to

VITEEE PCME Mock Test - 3 - Question 15

Two functions f : R → R , g : R → R are defined as follows :

VITEEE PCME Mock Test - 3 - Question 16

If ∫(sin 2x - cos 2x)dx = (1/√2) sin (2x-a) + b

VITEEE PCME Mock Test - 3 - Question 17

What is the value of the integral  ∫ ex [ f'x + f x ] dx ?

VITEEE PCME Mock Test - 3 - Question 18

sin[(1/2)cos-1(4/5)] is equal to

VITEEE PCME Mock Test - 3 - Question 19

What is the value of 

VITEEE PCME Mock Test - 3 - Question 20

Detailed Solution for VITEEE PCME Mock Test - 3 - Question 20

VITEEE PCME Mock Test - 3 - Question 21

The statement "If x is divisible by 8, then it is divisible by 6" is false if x equals

Detailed Solution for VITEEE PCME Mock Test - 3 - Question 21

A sentence in "If....then..." form is called an implication. The only time when an implication is false is when the "If" part of the sentence is true and the "then" part of the sentence is false. The number 32 makes the first part of the statement true and the second part of the statement false.

VITEEE PCME Mock Test - 3 - Question 22

The system of equation
2x + y = 5
x - 3y = -1
3x + 4y = k
is consistent, when k is

VITEEE PCME Mock Test - 3 - Question 23

If A is a singular matrix then Adj A is

VITEEE PCME Mock Test - 3 - Question 24

Five digit number divisible by 3 is formed using the digits 0, 1 , 2, 3, 4 and 5 without repetition. Total number of such numbers is

Detailed Solution for VITEEE PCME Mock Test - 3 - Question 24

A number is divisible by 3 if and only if the sum of its digits are divisible by 3
Notice that 1 + 2 + 3 + 4 + 5 = 15, which is divisible by 3
The only other way we can have a sum of 5 digits divisible by 3 is to replace the 3 by the 0 making the sum 3 less:
1 + 2 + 0 + 4 + 5 = 12, which is divisible by 3
No other choice of 5 digits can have a sum divisible by 3, because there is no other way to make the sum 12 or 15, and we certainly can't have a sum of 9 or 18
So the number of 5-digit numbers that can be formed from the digits {1,2,3,4,5} is

Number of ways = 1 x 2 x 3 x 4 x 5 = 120
And the number of 5-digit numbers that can be formed from the digits {1, 2, 0, 4, 5} is figured this way

Number of ways = 1 x 2 x 3 x 4 x 4 = 96
Total Number of ways = 120 + 96 = 216

VITEEE PCME Mock Test - 3 - Question 25

If A and B are two events such that P(A ∪ B)   = 0 .65, P(A ∩ B)   = 0.15 then 

VITEEE PCME Mock Test - 3 - Question 26
For a B.D., the parameters n and p are 16 and 1/2 respectively. Then its S.D.σ is equal to
VITEEE PCME Mock Test - 3 - Question 27

You are given a box with 20 cards in it. 10 of these cards have the letter 1 printed on them. The other ten have the letter T printed on them. If you pick up 3 cards at random and keep them in the same order, the probability of making the word IIT is

VITEEE PCME Mock Test - 3 - Question 28

If to form a ΔABC it is given that a=5, b=7, sinA=( 3/4 ), then possible triangles are

Detailed Solution for VITEEE PCME Mock Test - 3 - Question 28

Given a = 5, b = 7 and sin A = 3/4
∴ b sin A = 7 x ( 3/4 ) = 21/4 > a (= 5),
Thus is this case no triangle in possible

VITEEE PCME Mock Test - 3 - Question 29

If the A.M. and G.M, of the roots of a quadratic equation in x are p and q respectively, then its equation is

VITEEE PCME Mock Test - 3 - Question 30

If v is the variance and σ is the standard deviation, then

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