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JEE Exam  >  JEE Tests  >  VITEEE PCME Mock Test - 15 - JEE MCQ

VITEEE PCME Mock Test - 15 - JEE MCQ


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30 Questions MCQ Test - VITEEE PCME Mock Test - 15

VITEEE PCME Mock Test - 15 for JEE 2024 is part of JEE preparation. The VITEEE PCME Mock Test - 15 questions and answers have been prepared according to the JEE exam syllabus.The VITEEE PCME Mock Test - 15 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for VITEEE PCME Mock Test - 15 below.
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VITEEE PCME Mock Test - 15 - Question 1
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The function which is neither decreasing nor increasing in (π/2, 3π/2) is

VITEEE PCME Mock Test - 15 - Question 2
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The area of the region bounded by the curve y = x - x2 between x = 0 and x = 1 is

Detailed Solution for VITEEE PCME Mock Test - 15 - Question 2


area=1/6

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VITEEE PCME Mock Test - 15 - Question 3
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If complex numbers z₁, z₂ and origin form an equilateral triangle then z₁2 + z₂2 =

VITEEE PCME Mock Test - 15 - Question 4
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The curve represented by Im (z2) = K where K is a non-zero real number is
VITEEE PCME Mock Test - 15 - Question 5
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The area of the curve |x|+|y|=4 is
VITEEE PCME Mock Test - 15 - Question 6
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VITEEE PCME Mock Test - 15 - Question 7
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 for x ≠ 5 and f is continuous at x = 5 then f(5) =
VITEEE PCME Mock Test - 15 - Question 8
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The order of differential equation (d2y/dx2)2 = (1+dy/dx)1/2 is
VITEEE PCME Mock Test - 15 - Question 9
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If the function f is defined by f(x)   = x/1 + | x | then at what points is f differentiable
VITEEE PCME Mock Test - 15 - Question 10
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If xy=e(x-y), (dy/dx)=
VITEEE PCME Mock Test - 15 - Question 11
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If c is parameter then the differential equation whose solution is y = c2 + c/x is
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 11

VITEEE PCME Mock Test - 15 - Question 12
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Let f(x) = [x], where [x] denotes the greatest integer contained in x. Which one of the following is correct?
VITEEE PCME Mock Test - 15 - Question 13
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Solution of (x+y-1) dx+(2x+2y-3) dy = 0 is
VITEEE PCME Mock Test - 15 - Question 14
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The equation of the curve passing through the origin and satisfying the differential equation dy/dx = (x − y)2 is
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 14

VITEEE PCME Mock Test - 15 - Question 15
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∫cos√x dx=
VITEEE PCME Mock Test - 15 - Question 16
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∫tan-1x dx =
VITEEE PCME Mock Test - 15 - Question 17
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If Tan-1x + 1 + Tan-1(x − 1)   =Tan-1(18/31) , then x =
VITEEE PCME Mock Test - 15 - Question 18
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The value of 

Detailed Solution for VITEEE PCME Mock Test - 15 - Question 18

VITEEE PCME Mock Test - 15 - Question 19
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VITEEE PCME Mock Test - 15 - Question 20
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If n is any odd number, which of the following is true about n +1?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 20

Every whole number is either odd or even.
A whole number is even if it can be divided evenly by two; the numbers 2, 4, 6, 8, 10, 12, . . . are even.
In this question we are given the information that n is an odd number.
Because n is odd, it must be one of the numbers 1, 3, 5, 7, 9, 11, 13, 15, and so on.
Now we have to reason mathematically.
If n is a member of this “odd” list, then what can we say for sure about n +1?
If we add 1 to each number in the odd list, we get the “ n +1 ” list: 2, 4, 6, 8, 10, 12, 14, 16, and so on, which are even numbers.

VITEEE PCME Mock Test - 15 - Question 21
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Directions: The question is based on the following pie chart.
Project implementation cost of ABC Ltd. (Rs. Crores)
Total project cost = Rs. 252 Crores

If the plant cost increases by 5% due to increase in construction cost, what will be approximate angle of the plant sector in the pie chart?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 21

Given plant cost = (100°/360°) × 252 crores = 70 crores
Plant cost increases by 5% of 70 crores = 3.5 crores.
∴ The Plant cost would be = 73.5 crores
∴ The total project cost would be 252 + 3.5 = 255.5 crores
Now, 255.5 is equivalent to 360°
∴ 73.5 will be $\displaystyle \frac{73.5\times 360}{255.5}$ = 103.6° (Approx)

VITEEE PCME Mock Test - 15 - Question 22
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Directions: The question is based on the following pie chart.
Project implementation cost of ABC Ltd. (Rs. Crores)
Total project cost = Rs. 252 Crores

If there is an escalation of 10% in Salaries& Wages and a reduction of 10% in land, what will be the new angle of salaries and wages?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 22

New angle of Salaries & Wages = 55° x 1.1 = 60.5° = 55 + 5.5
New angle of Land = 55° x 0.9 = 49.5° = 55 - 5.5
Since the increase in Salaries & Wages is the same as the decrease in Land, there will be no change in the total angle of the pie chart.
Thus, new angle of salaries and wages = 60.5°

VITEEE PCME Mock Test - 15 - Question 23
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Directions: The question is based on the following pie chart.
Project implementation cost of ABC Ltd. (Rs. Crores)
Total project cost = Rs. 252 Crores

If 5% of administrative costs are reduced and 10% of the remaining administrative costs are transferred to Others category, what is the angle of administrative costs now?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 23

Reduction in administrative cost 5% of 30° = 1.5°
Hence, remaining administrative cost = 30° - 1.5° = 28.5°
Transferred administrative cost 10% of 28.5° = 2.85°
∴ Hence, the remaining administrative cost 28.5° - 2.85° = 25.65°
Also, since 5% of the administrative costs (1.5°) are reduced, thus new pie angle = 360° - 1.5° = 358.5°
Hence, new angle of Administrative Cost = x 360 = 25.76°

VITEEE PCME Mock Test - 15 - Question 24
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Directions: The following diagrams show the cost price and selling price (in Rs.) of different fruits sold by a fruit vendor.

How much percentage profit can he earn from the apples?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 24

Cost price of apples = 35% of Rs. 11,500 = Rs. 4025
Selling price of apples = 40% of Rs. 16,000 = Rs. 6400
Profit = Rs. 6400 - Rs. 4025 = Rs. 2375
So, profit percentage = $\displaystyle \frac{Profit}{C.P.}\times 100$ =  × 100 = 59% (approx.)

VITEEE PCME Mock Test - 15 - Question 25
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Look at this series: 3, 4, 7, 8, 11, 12,...so on. What number should come next?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 25

This alternating addition series begins with 3.
► Then 1 is added to give 4,
► Then 3 is added to give 7,
► Then 1 is added to give 8,
► Then 3 is added to give 11,
► Then 1 is added to give 12,
► Then 3 is added to give 15.

VITEEE PCME Mock Test - 15 - Question 26
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Look at this series: 8, 22, 8, 28, 8,...so on. What number should come next?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 26

This is a simple addition series with a random number, 8, interpolated as every other number.

In the series, 6 is added to each number except 8, to arrive at the next number.

► 22 + 6 = 28,
► 28 + 6 = 34.

VITEEE PCME Mock Test - 15 - Question 27
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Look at this series: 1, 3, 6, 10, 15...so on. What number should come next?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 27

It is a triangular number series forming a triangular pattern.

► 1 = 1,
► 1+2 = 3,
► 1+2+3 = 6,
► 1+2+3+4 = 10,
► 1+2+3+4+5 = 15,
► 1+2+3+4+5+6 = 21.

VITEEE PCME Mock Test - 15 - Question 28
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After the division of a number successively by 3, 4 and 7, the remainders obtained are 2, 1 and 4 respectively. What will be the remainder if 84 divides the same number?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 28

Since after division of a number successively by 3, 4 and 7, the remainders obtained are 2, 1 and 4 respectively, the number is of form ((((4*4)+1)*3)+2)k = 53K.

Let k = 1; the number becomes 53

If it is divided by 84, the remainder is 53.

Therefore, the correct answer is Option D.

VITEEE PCME Mock Test - 15 - Question 29
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Teacher said that there were 100 students in his class, 24 of whom were boys and 32 were girls. Which base system did the teacher use in this statement?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 29

We are provided with the equation (32) + (24) = (100). Let us assume our base be 'b'
Then,we can say:

⇒ 32 = 3 x b1 + 2 x b0 = 3b+2
⇒ 24 = 2 x b1+ 4 x b0 = 2b+4
⇒ 100 = 1 x b2 + 0 x b1 + 0 x b0 = b2

Now, according to our question:

⇒ 32 + 24=100
⇒ (3b + 2) + (2b + 4) = (b2)
⇒ 5b + 6 = b2
⇒ b2 - 5b - 6 = 0
⇒ b2 - 6b + b - 6 = 0
⇒ b(b - 6) + 1(b - 6) = 0
⇒ (b - 6) * (b + 1) = 0
⇒ b = 6,- 1

Base can't be negative. Hence b = 6.
∴ Base assumed in the asked question must be 6.

VITEEE PCME Mock Test - 15 - Question 30
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Find the highest power of 24 in 150!
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 30

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