All Courses
Get the App Signup / Login
Sign in Open App
JEE Exam  >  JEE Tests  >  VITEEE PCME Mock Test - 15 - JEE MCQ

VITEEE PCME Mock Test - 15 - JEE MCQ


Test Description

30 Questions MCQ Test - VITEEE PCME Mock Test - 15

VITEEE PCME Mock Test - 15 for JEE 2024 is part of JEE preparation. The VITEEE PCME Mock Test - 15 questions and answers have been prepared according to the JEE exam syllabus.The VITEEE PCME Mock Test - 15 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for VITEEE PCME Mock Test - 15 below.
Solutions of VITEEE PCME Mock Test - 15 questions in English are available as part of our course for JEE & VITEEE PCME Mock Test - 15 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt VITEEE PCME Mock Test - 15 | 125 questions in 150 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
VITEEE PCME Mock Test - 15 - Question 1
Save

The function which is neither decreasing nor increasing in (π/2, 3π/2) is

VITEEE PCME Mock Test - 15 - Question 2
Save

The area of the region bounded by the curve y = x - x2 between x = 0 and x = 1 is

Detailed Solution for VITEEE PCME Mock Test - 15 - Question 2


area=1/6

1 Crore+ students have signed up on EduRev. Have you? Download the App
VITEEE PCME Mock Test - 15 - Question 3
Save

If complex numbers z₁, z₂ and origin form an equilateral triangle then z₁2 + z₂2 =

VITEEE PCME Mock Test - 15 - Question 4
Save

The curve represented by Im (z2) = K where K is a non-zero real number is
VITEEE PCME Mock Test - 15 - Question 5
Save

The area of the curve |x|+|y|=4 is
VITEEE PCME Mock Test - 15 - Question 6
Save

VITEEE PCME Mock Test - 15 - Question 7
Save

 for x ≠ 5 and f is continuous at x = 5 then f(5) =
VITEEE PCME Mock Test - 15 - Question 8
Save

The order of differential equation (d2y/dx2)2 = (1+dy/dx)1/2 is
VITEEE PCME Mock Test - 15 - Question 9
Save

If the function f is defined by f(x)   = x/1 + | x | then at what points is f differentiable
VITEEE PCME Mock Test - 15 - Question 10
Save

If xy=e(x-y), (dy/dx)=
VITEEE PCME Mock Test - 15 - Question 11
Save

If c is parameter then the differential equation whose solution is y = c2 + c/x is
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 11

VITEEE PCME Mock Test - 15 - Question 12
Save

Let f(x) = [x], where [x] denotes the greatest integer contained in x. Which one of the following is correct?
VITEEE PCME Mock Test - 15 - Question 13
Save

Solution of (x+y-1) dx+(2x+2y-3) dy = 0 is
VITEEE PCME Mock Test - 15 - Question 14
Save

The equation of the curve passing through the origin and satisfying the differential equation dy/dx = (x − y)2 is
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 14

VITEEE PCME Mock Test - 15 - Question 15
Save

∫cos√x dx=
VITEEE PCME Mock Test - 15 - Question 16
Save

∫tan-1x dx =
VITEEE PCME Mock Test - 15 - Question 17
Save

If Tan-1x + 1 + Tan-1(x − 1)   =Tan-1(18/31) , then x =
VITEEE PCME Mock Test - 15 - Question 18
Save

The value of 

Detailed Solution for VITEEE PCME Mock Test - 15 - Question 18

VITEEE PCME Mock Test - 15 - Question 19
Save

VITEEE PCME Mock Test - 15 - Question 20
Save

If n is any odd number, which of the following is true about n +1?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 20

Every whole number is either odd or even.
A whole number is even if it can be divided evenly by two; the numbers 2, 4, 6, 8, 10, 12, . . . are even.
In this question we are given the information that n is an odd number.
Because n is odd, it must be one of the numbers 1, 3, 5, 7, 9, 11, 13, 15, and so on.
Now we have to reason mathematically.
If n is a member of this “odd” list, then what can we say for sure about n +1?
If we add 1 to each number in the odd list, we get the “ n +1 ” list: 2, 4, 6, 8, 10, 12, 14, 16, and so on, which are even numbers.

VITEEE PCME Mock Test - 15 - Question 21
Save

Directions: The question is based on the following pie chart.
Project implementation cost of ABC Ltd. (Rs. Crores)
Total project cost = Rs. 252 Crores

If the plant cost increases by 5% due to increase in construction cost, what will be approximate angle of the plant sector in the pie chart?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 21

Given plant cost = (100°/360°) × 252 crores = 70 crores
Plant cost increases by 5% of 70 crores = 3.5 crores.
∴ The Plant cost would be = 73.5 crores
∴ The total project cost would be 252 + 3.5 = 255.5 crores
Now, 255.5 is equivalent to 360°
∴ 73.5 will be $\displaystyle \frac{73.5\times 360}{255.5}$ = 103.6° (Approx)

VITEEE PCME Mock Test - 15 - Question 22
Save

Directions: The question is based on the following pie chart.
Project implementation cost of ABC Ltd. (Rs. Crores)
Total project cost = Rs. 252 Crores

If there is an escalation of 10% in Salaries& Wages and a reduction of 10% in land, what will be the new angle of salaries and wages?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 22

New angle of Salaries & Wages = 55° x 1.1 = 60.5° = 55 + 5.5
New angle of Land = 55° x 0.9 = 49.5° = 55 - 5.5
Since the increase in Salaries & Wages is the same as the decrease in Land, there will be no change in the total angle of the pie chart.
Thus, new angle of salaries and wages = 60.5°

VITEEE PCME Mock Test - 15 - Question 23
Save

Directions: The question is based on the following pie chart.
Project implementation cost of ABC Ltd. (Rs. Crores)
Total project cost = Rs. 252 Crores

If 5% of administrative costs are reduced and 10% of the remaining administrative costs are transferred to Others category, what is the angle of administrative costs now?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 23

Reduction in administrative cost 5% of 30° = 1.5°
Hence, remaining administrative cost = 30° - 1.5° = 28.5°
Transferred administrative cost 10% of 28.5° = 2.85°
∴ Hence, the remaining administrative cost 28.5° - 2.85° = 25.65°
Also, since 5% of the administrative costs (1.5°) are reduced, thus new pie angle = 360° - 1.5° = 358.5°
Hence, new angle of Administrative Cost = x 360 = 25.76°

VITEEE PCME Mock Test - 15 - Question 24
Save

Directions: The following diagrams show the cost price and selling price (in Rs.) of different fruits sold by a fruit vendor.

How much percentage profit can he earn from the apples?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 24

Cost price of apples = 35% of Rs. 11,500 = Rs. 4025
Selling price of apples = 40% of Rs. 16,000 = Rs. 6400
Profit = Rs. 6400 - Rs. 4025 = Rs. 2375
So, profit percentage = $\displaystyle \frac{Profit}{C.P.}\times 100$ =  × 100 = 59% (approx.)

VITEEE PCME Mock Test - 15 - Question 25
Save

Look at this series: 3, 4, 7, 8, 11, 12,...so on. What number should come next?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 25

This alternating addition series begins with 3.
► Then 1 is added to give 4,
► Then 3 is added to give 7,
► Then 1 is added to give 8,
► Then 3 is added to give 11,
► Then 1 is added to give 12,
► Then 3 is added to give 15.

VITEEE PCME Mock Test - 15 - Question 26
Save

Look at this series: 8, 22, 8, 28, 8,...so on. What number should come next?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 26

This is a simple addition series with a random number, 8, interpolated as every other number.

In the series, 6 is added to each number except 8, to arrive at the next number.

► 22 + 6 = 28,
► 28 + 6 = 34.

VITEEE PCME Mock Test - 15 - Question 27
Save

Look at this series: 1, 3, 6, 10, 15...so on. What number should come next?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 27

It is a triangular number series forming a triangular pattern.

► 1 = 1,
► 1+2 = 3,
► 1+2+3 = 6,
► 1+2+3+4 = 10,
► 1+2+3+4+5 = 15,
► 1+2+3+4+5+6 = 21.

VITEEE PCME Mock Test - 15 - Question 28
Save

After the division of a number successively by 3, 4 and 7, the remainders obtained are 2, 1 and 4 respectively. What will be the remainder if 84 divides the same number?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 28

Since after division of a number successively by 3, 4 and 7, the remainders obtained are 2, 1 and 4 respectively, the number is of form ((((4*4)+1)*3)+2)k = 53K.

Let k = 1; the number becomes 53

If it is divided by 84, the remainder is 53.

Therefore, the correct answer is Option D.

VITEEE PCME Mock Test - 15 - Question 29
Save

Teacher said that there were 100 students in his class, 24 of whom were boys and 32 were girls. Which base system did the teacher use in this statement?
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 29

We are provided with the equation (32) + (24) = (100). Let us assume our base be 'b'
Then,we can say:

⇒ 32 = 3 x b1 + 2 x b0 = 3b+2
⇒ 24 = 2 x b1+ 4 x b0 = 2b+4
⇒ 100 = 1 x b2 + 0 x b1 + 0 x b0 = b2

Now, according to our question:

⇒ 32 + 24=100
⇒ (3b + 2) + (2b + 4) = (b2)
⇒ 5b + 6 = b2
⇒ b2 - 5b - 6 = 0
⇒ b2 - 6b + b - 6 = 0
⇒ b(b - 6) + 1(b - 6) = 0
⇒ (b - 6) * (b + 1) = 0
⇒ b = 6,- 1

Base can't be negative. Hence b = 6.
∴ Base assumed in the asked question must be 6.

VITEEE PCME Mock Test - 15 - Question 30
Save

Find the highest power of 24 in 150!
Detailed Solution for VITEEE PCME Mock Test - 15 - Question 30

View more questions
Information about VITEEE PCME Mock Test - 15 Page
In this test you can find the Exam questions for VITEEE PCME Mock Test - 15 solved & explained in the simplest way possible. Besides giving Questions and answers for VITEEE PCME Mock Test - 15, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE

Important Questions for VITEEE PCME Mock Test - 15

Find all the important questions for VITEEE PCME Mock Test - 15 at EduRev.Get fully prepared for VITEEE PCME Mock Test - 15 with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the VITEEE PCME Mock Test - 15 syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of VITEEE PCME Mock Test - 15 resources.

VITEEE PCME Mock Test - 15 MCQs with Answers

Prepare for the VITEEE PCME Mock Test - 15 within the JEE exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for VITEEE PCME Mock Test - 15

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace VITEEE PCME Mock Test - 15 with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup