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Practice Tests for AP Physics 1 - 5 Grade 11 MCQs & solutions - Free


MCQ Practice Test & Solutions: Practice Tests for AP Physics 1 - 5 (40 Questions)

You can prepare effectively for Grade 11 AP Physics 1 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Practice Tests for AP Physics 1 - 5". These 40 questions have been designed by the experts with the latest curriculum of Grade 11 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 80 minutes
  • - Number of Questions: 40

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Practice Tests for AP Physics 1 - 5 - Question 1

A position-time graph for a moving object shows a straight line with a constant positive slope. Which of the following physical quantities does the slope of this graph represent?

Detailed Solution: Question 1

Slope of a position-time graph equals velocity (Δx/Δt).

Practice Tests for AP Physics 1 - 5 - Question 2

Which of the following quantities is a scalar?

Detailed Solution: Question 2

Distance has magnitude only; velocity, displacement, acceleration are vectors.

Practice Tests for AP Physics 1 - 5 - Question 3

A ball is launched horizontally from the top of a cliff that is 20 m above the ground. Using g = 9.8 m/s², how long does the ball take to reach the ground?

Detailed Solution: Question 3

h = ½gt² → t = √(2×20/9.8) ≈ 2.0 s.

Practice Tests for AP Physics 1 - 5 - Question 4

A car decelerates uniformly from 20 m/s to rest over a time interval of 4.0 s. What is the magnitude of the car's acceleration?

Detailed Solution: Question 4

a = Δv/Δt = 20/4 = 5 m/s².

Practice Tests for AP Physics 1 - 5 - Question 5

A velocity-time graph for an object shows a horizontal straight line positioned above the time axis throughout the entire recorded interval. Which of the following best describes the object's motion?

Detailed Solution: Question 5

Horizontal v-t line means constant velocity; zero acceleration.

Practice Tests for AP Physics 1 - 5 - Question 6

A skier starts from rest at the top of a frictionless hill of height 10 m and slides to the bottom. What is the skier's speed at the bottom of the hill? (g = 9.8 m/s²)

Detailed Solution: Question 6

mgh = ½mv² → v = √(2×9.8×10) = √196 = 14 m/s.

Practice Tests for AP Physics 1 - 5 - Question 7

A student applies a horizontal force of 50 N to push a box along a horizontal floor. The force is directed at an angle of 90° to the box's displacement. How much work does this applied force do on the box?

Detailed Solution: Question 7

W = Fd cos90° = 0 J; force perpendicular to displacement does no work.

Practice Tests for AP Physics 1 - 5 - Question 8

A student compresses several springs - each by the same amount - but with different spring constants, and measures the elastic potential energy stored in each spring. Which of the following correctly identifies the independent variable in this experiment?

Detailed Solution: Question 8

The student changes spring constant (k); it is the manipulated independent variable.

Practice Tests for AP Physics 1 - 5 - Question 9

A 2.0 kg block slides from rest down a rough inclined surface, dropping a vertical height of 5.0 m. At the bottom of the incline, the block's speed is 8.0 m/s. How much mechanical energy was lost to friction during the slide? (g = 9.8 m/s²)

Detailed Solution: Question 9

PEi = 98 J; KEf = ½(2)(64) = 64 J; lost = 98 - 64 = 34 J.

Practice Tests for AP Physics 1 - 5 - Question 10

A motor does 600 J of work in 30 s at a constant rate. What is the power output of the motor?

Detailed Solution: Question 10

P = W/t = 600/30 = 20 W.

Practice Tests for AP Physics 1 - 5 - Question 11

A 0.50 kg ball moves at 6.0 m/s to the right and strikes a wall. It rebounds at 6.0 m/s to the left. Taking rightward as positive, which of the following correctly describes the impulse experienced by the ball?

Detailed Solution: Question 11

J = Δp = m(vf - vi) = 0.50(-6 - 6) = -6 N·s, i.e., 6 N·s to the left.

Practice Tests for AP Physics 1 - 5 - Question 12

A 3.0 kg cart moves to the right at 4.0 m/s and collides with a stationary 1.0 kg cart. The two carts stick together after the collision. What is the velocity of the combined carts immediately after the collision?

Detailed Solution: Question 12

pi = 3×4 = 12 kg·m/s; vf = 12/4 = 3.0 m/s to the right.

Practice Tests for AP Physics 1 - 5 - Question 13

A force-time graph for an object shows a rectangular region with a constant force of 10 N applied over a time interval of 3.0 s. Which physical quantity does the area under this force-time graph represent?

Detailed Solution: Question 13

Area under a force-time graph equals impulse (J = FΔt).

Practice Tests for AP Physics 1 - 5 - Question 14

Two skaters are initially at rest on a frictionless ice surface. Skater A (mass 60 kg) pushes off and moves to the left at 2.0 m/s. Skater B has a mass of 40 kg. What is Skater B's velocity after the push?

Detailed Solution: Question 14

ptotal = 0; 60(-2) + 40v = 0 → v = 3.0 m/s to the right.

Practice Tests for AP Physics 1 - 5 - Question 15

A force of 20 N is applied perpendicular to a wrench at a distance of 0.30 m from the pivot point. What is the magnitude of the torque produced about the pivot?

Detailed Solution: Question 15

τ = rF sin90° = 0.30 × 20 × 1 = 6.0 N·m.

Practice Tests for AP Physics 1 - 5 - Question 16

A uniform rod of mass M and length L is pivoted at one end. A force F is applied perpendicular to the rod at its free end. The rotational inertia of the rod about its end is I = ML²/3. Which expression correctly gives the angular acceleration α of the rod?

Detailed Solution: Question 16

τ = FL; τ = Iα → α = FL ÷ (ML²/3) = 3F/(ML).

Practice Tests for AP Physics 1 - 5 - Question 17

A seesaw is balanced horizontally about its pivot. A child weighing 300 N sits 2.0 m to the left of the pivot. At what distance to the right of the pivot must a child weighing 400 N sit to maintain rotational equilibrium?

Detailed Solution: Question 17

τnet = 0: 300×2.0 = 400×d → d = 1.5 m.

Practice Tests for AP Physics 1 - 5 - Question 18

A student applies forces at varying distances from the pivot of a lever and records the resulting angular acceleration of the lever. The magnitude of the applied force and the rotational inertia of the lever are kept constant throughout the experiment. Which of the following is the independent variable in this experiment?

Detailed Solution: Question 18

The student varies the distance from pivot; that is the independent variable.

Practice Tests for AP Physics 1 - 5 - Question 19

A solid disk has a rotational inertia of 0.40 kg·m² and rotates at an angular velocity of 5.0 rad/s. What is the rotational kinetic energy of the disk?

Detailed Solution: Question 19

KErot = ½Iω² = ½(0.40)(25) = 5.0 J.

Practice Tests for AP Physics 1 - 5 - Question 20

A figure skater spinning on frictionless ice pulls her arms inward, reducing her rotational inertia from 4.0 kg·m² to 1.0 kg·m². Her initial angular velocity is 2.0 rad/s. What is her angular velocity after pulling in her arms?

Detailed Solution: Question 20

L = Iω conserved: 4.0×2.0 = 1.0×ωf → ωf = 8.0 rad/s.

Practice Tests for AP Physics 1 - 5 - Question 21

A ball of radius 0.10 m rolls without slipping along a flat surface. The center of mass of the ball moves at 3.0 m/s. What is the angular velocity of the ball?

Detailed Solution: Question 21

v = rω → ω = v/r = 3.0/0.10 = 30 rad/s.

Practice Tests for AP Physics 1 - 5 - Question 22

A satellite orbits a planet in a circular orbit. Gravitational force provides the centripetal force for the satellite's circular motion. Which of the following correctly describes the relationship between the satellite's orbital speed and its orbital radius?

Detailed Solution: Question 22

GMm/r² = mv²/r → v = √(GM/r); speed decreases as radius increases.

Practice Tests for AP Physics 1 - 5 - Question 23

A mass-spring oscillator has a spring constant of 100 N/m and a mass of 0.25 kg attached to the spring. What is the period of oscillation of this system?

Detailed Solution: Question 23

T = 2π√(m/k) = 2π√(0.0025) = 2π(0.05) ≈ 0.31 s.

Practice Tests for AP Physics 1 - 5 - Question 24

A student doubles the amplitude of oscillation of a mass-spring system. How does this change affect the period of the oscillator?

Detailed Solution: Question 24

T = 2π√(m/k); period is independent of amplitude. Period is unchanged.

Practice Tests for AP Physics 1 - 5 - Question 25

A simple pendulum of length 1.0 m oscillates with small amplitude on Earth where g = 9.8 m/s². The same pendulum is taken to a planet where g = 2.45 m/s². How does the period of the pendulum on the planet compare to its period on Earth?

Detailed Solution: Question 25

T ∝ 1/√g; ratio = √(9.8/2.45) = √4 = 2. Period on planet is twice Earth period.

Practice Tests for AP Physics 1 - 5 - Question 26

A position-time graph for a mass-spring oscillator shows a sinusoidal curve. At the instant when the object passes through its equilibrium position (displacement = 0), which of the following correctly describes the object's energies?

Detailed Solution: Question 26

At equilibrium: all energy is KE (maximum); elastic PE = 0.

Practice Tests for AP Physics 1 - 5 - Question 27

A tank of water (density 1000 kg/m³) is open to the atmosphere (P0 = 1.0 × 105 Pa). What is the absolute pressure at a depth of 4.0 m below the water's surface? (g = 9.8 m/s²)

Detailed Solution: Question 27

P = P0 + ρgh = 105 + 1000×9.8×4 = 1.392×105 Pa ≈ 1.39×105 Pa.

Practice Tests for AP Physics 1 - 5 - Question 28

Two open containers - one wide (Container A) and one narrow (Container B) - are both filled with water to the same depth. Which of the following correctly compares the pressure at the bottom of each container?

Detailed Solution: Question 28

P = P0 + ρgh; pressure depends on depth and fluid density, not container shape.

Practice Tests for AP Physics 1 - 5 - Question 29

A student submerges objects of different volumes - all made of the same material - in water and measures the buoyant force on each object. Which of the following is the dependent variable in this experiment?

Detailed Solution: Question 29

The student measures buoyant force as a result of varying volume - buoyant force is the DV.

Practice Tests for AP Physics 1 - 5 - Question 30

Water flows through a horizontal pipe that narrows from a cross-sectional area of A1 = 0.040 m² to A2 = 0.010 m². The water speed in the wider section is 2.0 m/s. What is the speed of the water in the narrower section?

Detailed Solution: Question 30

A1v1 = A2v2 → v2 = (0.040×2.0)/0.010 = 8.0 m/s.

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