Explore Exams
Login Signup
Sign in Open App
CBSE Class 9  >  Class 9 Test  >  Science New NCERT 2026-27 (New Syllabus)  >  Test: Describing Motion Around Us - 1 - Class 9 MCQ

Describing Motion Around Us - 1 - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Describing Motion Around Us - 1 (15 Questions)

You can prepare effectively for Class 9 Science Class 9 New NCERT 2026-27 (New Syllabus) with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Describing Motion Around Us - 1". These 15 questions have been designed by the experts with the latest curriculum of Class 9 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 15

Sign up on EduRev for free to attempt this test and track your preparation progress.

Test: Describing Motion Around Us - 1 - Question 1
Save

An athlete runs from O to A (100 m) and then returns back to B (60 m from A). What is the total displacement if B is 40 m from O in the positive direction?

Detailed Solution: Question 1

Displacement is the shortest distance from the initial position (O) to the final position (B). Since B is 40 m from O in the positive direction, displacement = 40 m. The total distance travelled = 100 + 60 = 160 m, but that is not displacement.

Test: Describing Motion Around Us - 1 - Question 2
Save

A car travels 20 km in the first hour, 40 km in the second hour, and 30 km in the third hour. What is its average speed?

Detailed Solution: Question 2

Average speed = Total distance / Total time = (20 + 40 + 30) / 3 = 90 / 3 = 30 km/h.

Clear all your doubts with EduRev
Test: Describing Motion Around Us - 1 - Question 3
Save

Sarang swims across a 25 m pool and returns to the starting point in 50 seconds. What is his average velocity?

Detailed Solution: Question 3

Average velocity = Displacement / Time. Since Sarang returns to the starting point, displacement = 0. Therefore, average velocity = 0/50 = 0 m/s. (Note: Average speed = 50/50 = 1 m/s, which is different.)

Test: Describing Motion Around Us - 1 - Question 4
Save

A car's speed increases from 40 km/h to 60 km/h in 5 seconds. What is its acceleration?

Detailed Solution: Question 4

u = 40 × 5/18 = 11.11 m/s, v = 60 × 5/18 = 16.66 m/s, t = 5 s. a = (v − u)/t = (16.66 − 11.11)/5 = 5.55/5 = 1.11 m/s².

Test: Describing Motion Around Us - 1 - Question 5
Save

Which of the following is a vector quantity?

Detailed Solution: Question 5

Displacement requires both magnitude and direction, making it a vector quantity. Distance, speed, and time only require magnitude (scalars).

Test: Describing Motion Around Us - 1 - Question 6
Save

A car starts from rest with a uniform acceleration of 0.1 m/s² for 4 minutes. What is the final speed of the car?

Detailed Solution: Question 6

u = 0 m/s, a = 0.1 m/s², t = 4 × 60 = 240 s. Using v = u + at: v = 0 + (0.1 × 240) = 24 m/s.

Test: Describing Motion Around Us - 1 - Question 7
Save

In a velocity-time graph, what does the area enclosed between the graph and the time axis represent?

Detailed Solution: Question 7

The area under a velocity-time graph gives the displacement of the object, not just distance. The slope of the velocity-time graph gives acceleration.

Test: Describing Motion Around Us - 1 - Question 8
Save

Brakes are applied to a car producing a deceleration of 6 m/s². The car stops in 2 seconds. What distance does it travel before stopping?

Detailed Solution: Question 8

v = 0, a = −6 m/s², t = 2 s. First, u = v − at = 0 − (−6 × 2) = 12 m/s. Then, s = ut + ½at² = 12 × 2 + ½(−6)(4) = 24 − 12 = 12 m.

Test: Describing Motion Around Us - 1 - Question 9
Save

For one complete revolution in uniform circular motion, which of the following is correct?

Detailed Solution: Question 9

In one full revolution, the object returns to the starting point so displacement = 0. The total path covered equals the circumference = 2πR. Hence distance = 2πR and displacement = 0.

Test: Describing Motion Around Us - 1 - Question 10
Save

What does a straight line parallel to the time axis on a position-time graph indicate?

Detailed Solution: Question 10

If the position does not change with time, the position-time graph is a horizontal straight line (parallel to time axis), indicating the object is stationary (at rest).

Test: Describing Motion Around Us - 1 - Question 11
Save

A body travels 4 km North and then 4 km East. What is the magnitude of the total displacement?

Detailed Solution: Question 11

The path forms a right-angled triangle with both legs = 4 km. Using the Pythagorean theorem: Displacement = √(4² + 4²) = √(16 + 16) = √32 = 4√2 ≈ 5.66 km.

Test: Describing Motion Around Us - 1 - Question 12
Save

Which kinematic equation directly relates final velocity, initial velocity, acceleration and displacement (without time)?

Detailed Solution: Question 12

The equation v² = u² + 2as relates final velocity (v), initial velocity (u), acceleration (a), and displacement (s) without involving time (t).

Test: Describing Motion Around Us - 1 - Question 13
Save

In uniform circular motion, which of the following statements is correct?

Detailed Solution: Question 13

In uniform circular motion, the speed (magnitude of velocity) remains constant. However, the direction of velocity changes continuously as it is always along the tangent to the circle. Since direction changes, velocity is not constant, and the object is accelerating.

Test: Describing Motion Around Us - 1 - Question 14
Save

An object moves with a velocity of 5 m/s at t = 10 s and 10 m/s at t = 20 s along a straight line. What is the displacement during this time interval?

Detailed Solution: Question 14

Using the area under the velocity-time graph (trapezium): Displacement = Area of rectangle + Area of triangle = (5 × 10) + ½ × 10 × (10 − 5) = 50 + 25 = 75 m.

Test: Describing Motion Around Us - 1 - Question 15
Save

Which of the following correctly describes non-uniform motion?

Detailed Solution: Question 15

Non-uniform motion is when an object travels unequal distances in equal intervals of time, meaning its speed is changing (increasing, decreasing, or varying). Uniform motion covers equal distances in equal time intervals. Option D describes uniform circular motion.

43 docs|5 tests
Join Course
Information about Test: Describing Motion Around Us - 1 Page
In this test you can find the Exam questions for Test: Describing Motion Around Us - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Describing Motion Around Us - 1, EduRev gives you an ample number of Online tests for practice
Download as PDF

About this Class 9 Practice Test

This test contains 15 MCQs on Describing Motion Around Us - 1 with detailed solutions for each question. It is part of the Science Class 9 New NCERT 2026-27 (New Syllabus) course on EduRev, designed to align with the current Class 9 syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

Explore more Class 9 Study Resources

If you found this Describing Motion Around Us - 1 MCQ Test helpful, you can further enhance your Class 9 preparation with in-depth courses on EduRev, for all the subjects and topics available in Science Class 9 New NCERT 2026-27 (New Syllabus) course. The course offers:
  • Video Lectures: covering all the topics of Science Class 9 New NCERT 2026-27 (New Syllabus)
  • Notes for Revision: offering revision notes, important questions, summaries, flashcards, cheatsheets & more for Class 9 preparation
  • MCQ Test: variety of questions as per the pattern of Class 9 exam
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily