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Test: Measures Of Central Tendency And Dispersion- 3 - CDS MCQ


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30 Questions MCQ Test - Test: Measures Of Central Tendency And Dispersion- 3

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Test: Measures Of Central Tendency And Dispersion- 3 - Question 1

 Geometric mean of 8,4,2 is 

Test: Measures Of Central Tendency And Dispersion- 3 - Question 2

The average age of 15 students of a class is 15 years. Out of them, the average age of 5 students is 14 years and that of the other 9 students is 16 years. The age of the 15th students is:

Detailed Solution for Test: Measures Of Central Tendency And Dispersion- 3 - Question 2

Age of the 15th student

= [15 * 15 - (14 * 5 + 16 * 9)]

= (225-214) = 11 years

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Test: Measures Of Central Tendency And Dispersion- 3 - Question 3

Sum of deviations of values from their mean is always

Test: Measures Of Central Tendency And Dispersion- 3 - Question 4

If mean = 5, Standard deviation = 2.6, median = 5 and quartile deviatiion = 1.5, then the coefficient of quartile deviation equals.

Test: Measures Of Central Tendency And Dispersion- 3 - Question 5

Which of the following measures of central tendency cannot be calculated by graphical method?

Test: Measures Of Central Tendency And Dispersion- 3 - Question 6

If the relationship between two variables u and v are given by 2u + v + 7 = 0 and if the AM of u is 10, then the AM is v is 

Detailed Solution for Test: Measures Of Central Tendency And Dispersion- 3 - Question 6


Test: Measures Of Central Tendency And Dispersion- 3 - Question 7

Find at the variance given that the Arithmetic Mean = ( 8 + 4)/2

Detailed Solution for Test: Measures Of Central Tendency And Dispersion- 3 - Question 7

We know that S. D = range/2

                                 = Max-min/2

                                 =8-4/2=2

                     And variance =  (sd)2

                                             = 22= 4

Test: Measures Of Central Tendency And Dispersion- 3 - Question 8

The price of average whose value can be determined graphically?

Test: Measures Of Central Tendency And Dispersion- 3 - Question 9

If the mean of a frequency distribution is 100 and coefficient of variation is 45% then standard deviation is:

Detailed Solution for Test: Measures Of Central Tendency And Dispersion- 3 - Question 9

Option (a) 45 is correct. 

Explanation :-

Mean is the sum of the sample values divided by the no. Of samples. 

Standard deviation  expresses by how much  the value of a no. diiffers  from the mean value. 

Here, direct formula is used. 

Coefficient of variation= 45/100 = 0.45

Coefficient of variation= standard variation / Mean

Or, 0.45 = standard deviation / 100

Or standard deviation = 100 * 0.45
So, the standard deviation is :- 45

Test: Measures Of Central Tendency And Dispersion- 3 - Question 10

In normal distribution mean, median and mode are 

Test: Measures Of Central Tendency And Dispersion- 3 - Question 11

The mean of the following data is 6.Find the value of 'P'.
x : 2  4  6  10  P+5
f :  3  2  3   1     2

Test: Measures Of Central Tendency And Dispersion- 3 - Question 12

For values lie close to the mean , the standard deviations are

Test: Measures Of Central Tendency And Dispersion- 3 - Question 13

Which of the following statement is true?

Test: Measures Of Central Tendency And Dispersion- 3 - Question 14

 What will be the probable value of mean deviation? When Q3 = 40 and Q1 = 15

Test: Measures Of Central Tendency And Dispersion- 3 - Question 15

The mean of the first three term is 14 and mean of next two terms is 18. The mean of all five terms is :

Detailed Solution for Test: Measures Of Central Tendency And Dispersion- 3 - Question 15

Since mean of first 3 terms = 14 

⇒ sum of first 3 terms = 14 × 3 = 42 

Also mean of next 2 terms = 18 

⇒ sum of next 2 terms = 18 × 2 = 36 

⇒ Mean of above 5 terms 

= sum of first 3 terms + sum of next 2 terms/5

Test: Measures Of Central Tendency And Dispersion- 3 - Question 16

 The median of following numbers, which are given is ascending order is 25. Find the value of X.11   13  15  19  (x+2)   (x+4)  30  35  39  46

Test: Measures Of Central Tendency And Dispersion- 3 - Question 17

Geometric Mean of three observations 40, 50 and X is 10. The value of X is 

Test: Measures Of Central Tendency And Dispersion- 3 - Question 18

 If standard deviation of first 'n' natural numbers is 2 then value of 'n' is 

Test: Measures Of Central Tendency And Dispersion- 3 - Question 19

For data on frequency distribution of weights:70, 73, 49, 57, 44, 56, 71, 65, 62, 60, 50, 55, 49, 63 and 45 If we assume class length as 5, the number of class intervals would be 

Detailed Solution for Test: Measures Of Central Tendency And Dispersion- 3 - Question 19

Correct Answer :- c

Explanation :  We could choose intervals of 5. We then begin the scale with 44 and end with 73.

Class Interval

44 – 48

49 – 53

54 – 58

59 – 63

64 – 68

69 – 73

Test: Measures Of Central Tendency And Dispersion- 3 - Question 20

The point of intersection of the "less than" and "more than" ogives correspond to 

Test: Measures Of Central Tendency And Dispersion- 3 - Question 21

If sum of squares of the values = 3390, N = 30 and standard deviation = 7, find out the mean.

Test: Measures Of Central Tendency And Dispersion- 3 - Question 22

 Which of the following measures of dispersion is used for calculating the consistency between two series?

Test: Measures Of Central Tendency And Dispersion- 3 - Question 23

 If the mode of a data is 18 and mean is 24, then median is _________.

Test: Measures Of Central Tendency And Dispersion- 3 - Question 24

The standard deviation of the weights (in kg) of the students of a class of 50 students was calculated to be 4.5 kg. Later on it was found that due to some fault in weighing machine, the weight of each student was under measured by 0.5 kg. The Correct standard deviation of the weight will be:

Test: Measures Of Central Tendency And Dispersion- 3 - Question 25

 The mean salary of a group of 50 persons is Rs. 5,850. Later on it is discovered that the salary of one employee has been wrongly taken as Rs.8,000 instead of Rs.7,800. The corrected mean salary is 

Test: Measures Of Central Tendency And Dispersion- 3 - Question 26

 For Normal distribution the relation between quartile deviation (Q.D) and standard deviation (S.D) is 

Test: Measures Of Central Tendency And Dispersion- 3 - Question 27

The average age of a group of 10 students was 20 years. The average age increased by two years when two new students joined the group. What is the average age of the two new students who joined the group?

Test: Measures Of Central Tendency And Dispersion- 3 - Question 28

 The standard deviation is independent of change of 

Test: Measures Of Central Tendency And Dispersion- 3 - Question 29

Coefficient of Standard deviation is equal to 

Test: Measures Of Central Tendency And Dispersion- 3 - Question 30

 The mode of the numbers 7, 7, 7, 9, 10, 11, 11, 11, 12, is

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