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Test: Gray Body & Selective Emitters - Chemical Engineering MCQ


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10 Questions MCQ Test - Test: Gray Body & Selective Emitters

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Test: Gray Body & Selective Emitters - Question 1

When Stefan-Boltzmann law is applied to a black body, it takes the form

Detailed Solution for Test: Gray Body & Selective Emitters - Question 1

The constant is different for different bodies.

Test: Gray Body & Selective Emitters - Question 2

Consider two bodies, one absolutely back and the other non-black and let these be at same temperature. Which one of the following statement is correct?

Detailed Solution for Test: Gray Body & Selective Emitters - Question 2

The radiation spectrum for a non-black body may be similar or radically different from that of a black body.

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Test: Gray Body & Selective Emitters - Question 3

When the emissivity of non-black surface is constant at all temperatures and throughout the entire range of wavelength, the surface is called

Detailed Solution for Test: Gray Body & Selective Emitters - Question 3

The radiation spectrum for a grey body, though reduced in vertical scale, is continuous and identical to the corresponding curve for a perfectly black surface.

Test: Gray Body & Selective Emitters - Question 4

The emissivity of the gray surface may be expressed as

Detailed Solution for Test: Gray Body & Selective Emitters - Question 4

It is the ratio of radiating coefficient to that of black body radiating coefficient.

Test: Gray Body & Selective Emitters - Question 5

If a black body at 1000 K and a gray body at 1250 K emit the same amount of radiation, what should be the emissivity of the gray body?

Detailed Solution for Test: Gray Body & Selective Emitters - Question 5

E = (T b/T G) 4 = 0.4096.

Test: Gray Body & Selective Emitters - Question 6

The radiant heat transfer from a plate of 2.5 cm2 area at 1250 K to a very cold enclosure is 5.0 W. Determine the emissivity of the plate at this temperature

Detailed Solution for Test: Gray Body & Selective Emitters - Question 6

Emissivity = E/σ A T4 = 0.144.

Test: Gray Body & Selective Emitters - Question 7

A 100 W light bulb has a tungsten filament (emissivity = 0.30) which is required to operate at 2780 K. If the bulb is completely evacuated, calculate the minimum surface area of the tungsten filament

Detailed Solution for Test: Gray Body & Selective Emitters - Question 7

E = (Emissivity) σ A T4. So, A = 0.98 * 10 -4 m2.

Test: Gray Body & Selective Emitters - Question 8

The monochromatic emissivity € of a diffuse surface at 1600 K varies with wavelength in the following manner
€ = 0.4 for 0 < λ < 2
= 0.8 for 2 < λ < 5
Determine the total emissivity

Detailed Solution for Test: Gray Body & Selective Emitters - Question 8

Total emissivity = 0.4 (-0.3181 – 0.0000) + 0.8 (0.8563 – 0.3118) = 0.5578.

Test: Gray Body & Selective Emitters - Question 9

For a hemisphere solid angle is measured as

Detailed Solution for Test: Gray Body & Selective Emitters - Question 9

It should be measured in Steradian.

Test: Gray Body & Selective Emitters - Question 10

A gray body (E = 0.8) emits the same amount of heat as a black body at 1075 K. Find out the required temperature of the gray body

Detailed Solution for Test: Gray Body & Selective Emitters - Question 10

b= E T g4.

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