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Mechanical Engineering Exam  >  Mechanical Engineering Test  >  Fluid Mechanics  >  Test: Fluid Pressure At a Point & Pascal’s Law - Mechanical Engineering MCQ

Fluid Pressure At a Point & Pascal’s Law - Free MCQ Practice Test


MCQ Practice Test & Solutions: Test: Fluid Pressure At a Point & Pascal’s Law (10 Questions)

You can prepare effectively for Mechanical Engineering Fluid Mechanics for Mechanical Engineering with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Fluid Pressure At a Point & Pascal’s Law". These 10 questions have been designed by the experts with the latest curriculum of Mechanical Engineering 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

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Test: Fluid Pressure At a Point & Pascal’s Law - Question 1
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A Hydraulic press has a ram of 30 cm diameter and a plunger of of 2 cm diameter. It is used for lifting a weight of 35 kN. Find the force required at the plunger.

Detailed Solution: Question 1

Explanation: F/a=W/A
F=(35000*3.142*.02*.02)/(3.142*0.3*0.3)
=155.5 kN.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 2
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The pressure at a point in the fluid is 4.9 N/cm2. Find height when the fluid under consideration is in oil of specific gravity of 0.85.

Detailed Solution: Question 2

Explanation: Height=p/ρg
=48620/850*9.81
=5.83 m.

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Test: Fluid Pressure At a Point & Pascal’s Law - Question 3
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 An open tank contains water upto a depth of 350 cm and above it an oil of specific gravity 0.65 for a depth of 2.5 m. Find the pressure intensity at the extreme bottom of the tank. 

Detailed Solution: Question 3

Explanation: p= (specific gravity of water* height of water + specific gravity of oil* height of oil) * 9.81
= 5.027 N/cm2.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 4
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The diameters of a small piston and a large piston of a hydraulic jack are 45 mm and 100 mm respectively.Force of 0.09 kN applied on smaller in size piston. Find load lifted by piston if smaller in size piston is 40 cm above the large piston. The density of fluid is 850 kg/m3 

Detailed Solution: Question 4

The correct answer is A: 6 N/cm2.


  • Calculate the area of the small piston: A1 = π(45/2 mm)2.

  • Calculate the area of the large piston: A2 = π(100/2 mm)2.

  • Find pressure on small piston: P = Force/Area = 0.09 kN / A1.

  • Pressure is transmitted equally: P = Load/A2.

  • Equate pressures to find load: Load = (0.09 kN * A2) / A1.

  • Convert the load to N/cm2 and choose 6 N/cm2.


    •  

Test: Fluid Pressure At a Point & Pascal’s Law - Question 5
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 In a hydraulic-brake system, a force of 25 N can be applied to a surface area of 5 cm2. What force can thus be exerted on each brake cylinder having an area of 100 cm2

Detailed Solution: Question 5

Explanation:As per the statement of Pasca;l's Law, the pressure is uniformly distributed inside a fluid.

Firstly, we calculate the initial pressure exerted, i.e.

P= F/A

P=25/5 = 5 Pascals

Now, the output pressure at each brake will be equal to this pressure.

P= F/100

5= F/100

F= 100*5= 500 N

Test: Fluid Pressure At a Point & Pascal’s Law - Question 6
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 We can draw Mohr’s circle for a fluid at rest.

Detailed Solution: Question 6

Test: Fluid Pressure At a Point & Pascal’s Law - Question 7
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If fluid is at rest in a container of a narrow mouth at a certain column height and same fluid is at rest at same column height in a container having broad mouth, will the pressure be different at certain depth from fluid surface?

Detailed Solution: Question 7

Explanation: As per hydrostatic law, the pressure depends only on the height of water column and not its shape.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 8
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Calculate the hydrostatic pressure for water moving with constant velocity at a depth of 5 m from the surface.

Detailed Solution: Question 8

Explanation: If fluid is moving with uniform velocity we treat it analytically same as if fluid is at rest
p= ρgh.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 9
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 Pressure distribution for fluid at rest takes into consideration pressure due to viscous force.

Detailed Solution: Question 9

Explanation: Viscous force term in pressure expression for fluid at rest is absent as their is no motion of liquid.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 10
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 Barometer uses the principle of fluid at rest or pressure gradient for its pressure calculation. 

Detailed Solution: Question 10

Explanation: Principle of Barometer is Hydrostatic law.

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About this Mechanical Engineering Practice Test

This test contains 10 MCQs on Fluid Pressure At a Point & Pascal’s Law with detailed solutions for each question. It is part of the Fluid Mechanics for Mechanical Engineering course on EduRev, designed to align with the current Mechanical Engineering syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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