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Mechanical Engineering Exam  >  Mechanical Engineering Tests  >  Test: Fluid Pressure At a Point & Pascal’s Law - Mechanical Engineering MCQ

Test: Fluid Pressure At a Point & Pascal’s Law - Mechanical Engineering MCQ


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10 Questions MCQ Test - Test: Fluid Pressure At a Point & Pascal’s Law

Test: Fluid Pressure At a Point & Pascal’s Law for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Fluid Pressure At a Point & Pascal’s Law questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Fluid Pressure At a Point & Pascal’s Law MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Fluid Pressure At a Point & Pascal’s Law below.
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Test: Fluid Pressure At a Point & Pascal’s Law - Question 1
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A Hydraulic press has a ram of 30 cm diameter and a plunger of of 2 cm diameter. It is used for lifting a weight of 35 kN. Find the force required at the plunger.

Detailed Solution for Test: Fluid Pressure At a Point & Pascal’s Law - Question 1

Explanation: F/a=W/A
F=(35000*3.142*.02*.02)/(3.142*0.3*0.3)
=155.5 kN.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 2
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The pressure at a point in the fluid is 4.9 N/cm2. Find height when the fluid under consideration is in oil of specific gravity of 0.85.

Detailed Solution for Test: Fluid Pressure At a Point & Pascal’s Law - Question 2

Explanation: Height=p/ρg
=48620/850*9.81
=5.83 m.

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Test: Fluid Pressure At a Point & Pascal’s Law - Question 3
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 An open tank contains water upto a depth of 350 cm and above it an oil of specific gravity 0.65 for a depth of 2.5 m. Find the pressure intensity at the extreme bottom of the tank. 

Detailed Solution for Test: Fluid Pressure At a Point & Pascal’s Law - Question 3

Explanation: p= (specific gravity of water* height of water + specific gravity of oil* height of oil) * 9.81
= 5.027 N/cm2.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 4
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The diameters of a small piston and a large piston of a hydraulic jack are 45 mm and 100 mm respectively.Force of 0.09 kN applied on smaller in size piston. Find load lifted by piston if smaller in size piston is 40 cm above the large piston. The density of fluid is 850 kg/m3 
Detailed Solution for Test: Fluid Pressure At a Point & Pascal’s Law - Question 4

Explanation: Pressure at bottom of tank =ρgh + F/a
=850*9.81*0.4 + 90/3.142*0.045*0.045
=60 N/cm2.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 5
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 In a hydraulic-brake system, a force of 25 N can be applied to a surface area of 5 cm2. What force can thus be exerted on each brake cylinder having an area of 100 cm2
Detailed Solution for Test: Fluid Pressure At a Point & Pascal’s Law - Question 5

Explanation:As per the statement of Pasca;l's Law, the pressure is uniformly distributed inside a fluid.

Firstly, we calculate the initial pressure exerted, i.e.

P= F/A

P=25/5 = 5 Pascals

Now, the output pressure at each brake will be equal to this pressure.

P= F/100

5= F/100

F= 100*5= 500 N

Test: Fluid Pressure At a Point & Pascal’s Law - Question 6
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 We can draw Mohr’s circle for a fluid at rest.
Detailed Solution for Test: Fluid Pressure At a Point & Pascal’s Law - Question 6

Test: Fluid Pressure At a Point & Pascal’s Law - Question 7
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If fluid is at rest in a container of a narrow mouth at a certain column height and same fluid is at rest at same column height in a container having broad mouth, will the pressure be different at certain depth from fluid surface?
Detailed Solution for Test: Fluid Pressure At a Point & Pascal’s Law - Question 7

Explanation: As per hydrostatic law, the pressure depends only on the height of water column and not its shape.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 8
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Calculate the hydrostatic pressure for water moving with constant velocity at a depth of 5 m from the surface.
Detailed Solution for Test: Fluid Pressure At a Point & Pascal’s Law - Question 8

Explanation: If fluid is moving with uniform velocity we treat it analytically same as if fluid is at rest
p= ρgh.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 9
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 Pressure distribution for fluid at rest takes into consideration pressure due to viscous force.
Detailed Solution for Test: Fluid Pressure At a Point & Pascal’s Law - Question 9

Explanation: Viscous force term in pressure expression for fluid at rest is absent as their is no motion of liquid.

Test: Fluid Pressure At a Point & Pascal’s Law - Question 10
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 Barometer uses the principle of fluid at rest or pressure gradient for its pressure calculation. 
Detailed Solution for Test: Fluid Pressure At a Point & Pascal’s Law - Question 10

Explanation: Principle of Barometer is Hydrostatic law.

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